52°07′N 1°04′E / 52.11°N 01.06°E / 52.11; 01.06
vol20_pp20-52. 280KB Jun 04 2011 12:06:07 AM
... p = w(B). If the k-th stripe of B is full for 3 ≤ k ≤ p−1, then B is striped. Otherwise the (p − 1)-th stripe is not full. Thus there exist two entries meeting the hypotheses of Lemma 3.6 or its ...
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article06_4. 180KB Jun 04 2011 12:06:52 AM
... = n − 24, is due to Gaborit. Lattices with minimum k + 1 and shortest characteristic vectors of norm n − 8k were defined as k-extremal in Section 8 of [5]; it was shown that for any given k, the ...
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article05_5. 209KB Jun 04 2011 12:06:52 AM
... be in the image of Ψ. Then a is squarefree when we ignore prime ideals lying over 2. In other words p 2 | a implies that the prime ideal p contains 2. The ideal b is squarefree when we ignore prime ideals lying above ℓ. ...
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article05_6. 208KB Jun 04 2011 12:06:52 AM
... By (2.1) and Lemma 5.1 below, it is easy to see that (1.4) is sharp : for arbitrarily large constant c, there exist (exp( − 2πc/ √ 6) + o(1))p(n) partitions of n containing 1 as summand 2[c √ ...
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article05_7. 214KB Jun 04 2011 12:06:52 AM
... R´ esum´ e. On dit qu’un corps est de Hilbert-Speiser en un premier p si toute extension mod´er´ee ab´elienne finie de degr´e p admet une base normale enti`ere. On dit qu’un corps est de Hilbert-Speiser ...
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article06. 267KB Jun 04 2011 12:06:52 AM
... 3.2. Explicit factors of f n E (X ). Let E be an elliptic curve. Suppose that we have some modular polynomial Φ[f ](X, J ) for a function f on Γ 0 (ℓ). Then a root v of Φ[f ](X, j(E)) gives ...
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article06_2. 190KB Jun 04 2011 12:06:52 AM
... For an arbitrary countable Hilbertian field K of characteristic 0 we fur- ther denote the maximal Galois extension of K in ˜ K( σ ) by ˜ K[ σ ]. We know that for almost all σ ∈ Gal(K) e the field ˜ K[ σ ] is PAC ...
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article06_3. 256KB Jun 04 2011 12:06:52 AM
... R´ esum´ e. Nous ´etudions la famille infinie des courbes elliptiques associ´ees aux “simplest quartic fields”. Si le rang de telles courbes vaut 1, nous d´eterminons la structure compl`ete du groupe de ...
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article06_5. 204KB Jun 04 2011 12:06:52 AM
... R´ esum´ e. On montre qu’il n’existe pas de corps de nombres pri- mitif de degr´e 9 ramifi´e en un unique premier petit. Il n’existe donc pas de corps de nombres de degr´e 9 ramifi´e en ...
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article06_6. 277KB Jun 04 2011 12:06:52 AM
... en revenant aux d´efinitions de ces formes (voir la proposition 5.1 et la proposition-d´efinition 4.1), et en notant f (n, l) les coefficients de Fourier de la forme ψ (1) 0,1 , une formule du type “formule ...
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article06_7. 204KB Jun 04 2011 12:06:52 AM
... In [4, Theorem 2.1], G´omez Ayala gave a necessary and sufficient condi- tion for a tame Kummer extension of prime degree to have a NIB (in the usual sense). In [8, Theorem 2], we generalized it for a tame cyclic Kummer ...
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article07. 234KB Jun 04 2011 12:06:52 AM
... strongly N -modular lattices which also implies that there are only finitely many such s-extremal lattices with even ...strongly N -modular lattice, we show that the second ...Let N ∈ L and let L be ...
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ppl2_5401409117_R112_1349743160. 175.46KB 2013-07-11 22:15:52
... Berdasarkan hasil pelaksanaan PPL di SMK N 1 Pekalongan, diperoleh simpulan yaitu berupa pengalaman mengajar yang sebenarnya. Tugas utama guru meliputi merencanakan dan mengaktualisasikan diri apa yang ...
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ppl2_5401409119_R112_1349835355. 280.37KB 2013-07-11 22:15:52
... SMK N 1 Pekalongan sangat besar. Salah satu contoh di SMK N 1 Pekalongan yang memiliki beberapa jurusan lain selain Jasa boga, misalkan untuk praktek siswa di SMK N 1 Pekalongan ...
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ppl2_5401409120_R112_1349761007. 310.16KB 2013-07-11 22:15:52
... SMP N 1 TULIS BATANG yang diharapkan dapat mengembangkan dan mendapatkan pengalaman baru dalam proses pendidikan terhadap calon-calon guru tenaga ...
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ppl2_5401409125_R112_1349785774. 204.53KB 2013-07-11 22:15:52
... SMP N 1 Kandeman pembelajaran tata busana sudah sangat baik, hal itu didukung oleh tersedianya media pembelajaran yang memadai seperti mesin jahit dan peralatan ...
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article05. 264KB Jun 04 2011 12:06:52 AM
... = 1, and 1 > λ 2 , it follows that points for which min n 1+tv v , 1+tv | t | o < 1 2 must satisfy t < 0 and v > ...
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article05_2. 214KB Jun 04 2011 12:06:52 AM
... esum´ e. Nous r´epondons `a trois questions concernant la r´educti- bilit´e (ou irr´eductibilit´e) de 0, 1-polynˆomes, polynˆomes qui n’ont pour seuls coefficients que 0 ou ...0, ...
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article05_4. 184KB Jun 04 2011 12:06:52 AM
... R´ esum´ e. Nous calculons des bornes sup´erieures et inf´erieures pour l’approximation de fonctions hyperboliques aux points 1/s (s = 1, 2, . . . ) par des rationnels x/y, tels que x, y satisfassent ...
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article05_3. 192KB Jun 04 2011 12:06:52 AM
... = 1, car ∅ ∗ = { 0 } ...a 1 donn´e. Si L contient moins de δ − 1 ´el´ements qui ne sont pas congrus ` a 0 modulo δ, on note D cette famille et on remarque que tout ´el´ement de ( L\D ) ♯ est ...
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