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মডেল টেস্ট ( অর্ধ-বার্ষিক পর্বের )

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(1)

w`bvRcyi Kv‡j±‡iU ¯‹zj GÛ K‡jR cvV cwiKíbv-2016

‡kÖwY t Z…Zxq evsjv cÖ‡kœi aviv I gvbe›Ub t

*cÖ`Ë Aby‡”Q`/KweZvsk co Ges 1, 2, 3, 4 I 5 bs cÖ‡kœi DËi `vI (cvV¨eB ewnf©~Z ) t

1. mwVK DËiwU DËic‡Î wjL t (5wU ) 1 X 5 =05

2. k~b¨¯’vb c~iY t 1 X 5 =05

3. hy³eY©¸‡jv †f‡O †`LvI Ges cÖwZwU hy³eY© w`‡q GKwU K‡i evK¨ MVb t 2 X 5 =10

4. cÖkœ¸‡jvi DËi wjLb t 3 X5=15

*cÖ`Ë Aby‡”Q`/KweZvsk c‡o 6, 7, 8 I 9 bs µwg‡Ki cÖkœ¸‡jvi DËi †jL ( cvV¨eB †_‡K ) t

5. Av‡e`b cÎ / wPwV wjLb t 05

6. mwVK DËiwU DËic‡Î †jL t 05

7. wb‡Pi cÖkœ¸‡jvi ms‡¶‡c DËi wjLb| 1+2+2=5 8. k㸇jvi A_© wjLb t 05

9. Aby‡”Q`/KweZvs‡ki mvivsk †jL t 05

10.weivg wPý t 05

11.wecixZ kã /mgv_©K kã t 05

12.GK K_vq cÖKvk / wµqvc‡`i PwjZ iƒc t 05

13.(K) KweZvi PiY¸‡jv mvwR‡q †jL t 06

(L) KweZvskUzKz †Kvb KweZvi Ask ? 01

(M) KweZvwUi Kwei bvg ? 01

(N) KweZvsk †_‡K (1/2 wU ) cÖkœ 02

14.dig c~iY t 05 15.iPbv wjLb ( 200 k‡ãi g‡a¨ -ms‡KZ ev Bw½Z †`qv _vK‡e ) t 10

‡gvU = 100

g‡Wj †U÷ ( Aa©-evwl©K c‡e©i )

M`¨ t (1) Qwe I K_v, (2) fvlv kwn`‡`i K_v, (3) cvwL‡`i K_v, (4) KvbvgvwQ

†fuv †fuv, (5) cvjøv †`Iqvi Lei, (6) k‡ãi A_© †R‡b †bB|

c`¨ t (1) nv‡U hve, (2) Pj& Pj& Pj&, (3) Nywo|

e¨vKiY t e¨vKiY, eY©, kã, fvlv, wecixZ kã, GKK_vq cÖKvk, mgv_©K kã, weivgwPý, dig c~iY, hy³eY©, c`|

wPwV I `iLv¯Í t (1) eB †Kbvi Rb¨ UvKv †P‡q wcZvi wbKU GKLvbv cÎ wjL| (2)

†Zvgvi eo †ev‡bi we‡q‡Z Avgš¿b Rvwb‡q †Zvgvi evÜex/eÜz‡K GKwU cÎ wjL|

(3) Rwigvbv gIKz‡di Rb¨ Aa¨‡ÿi wbKU `iLv¯Í wjL| (4) Amy¯’Zvi Kvi‡b we`¨vj‡q Abycw¯’wZi Rb¨ cÖavb wkÿ‡Ki wbKU GKwU `iLv¯Í wjL|

iPbv t (1) Miæ, (2) Avgv‡`i we`¨vjq, (3) kxZKvj, (4) evsjv‡`‡ki RvZxq cvwL|

Aa©-evwl©K cixÿv

M`¨ t (1) Avgv‡`i GB evsjv‡`k, (2) ivRv I Zvi wZb Kb¨v, (3) GKvB GKwU

`~M©, (4) Kz‡Rv eywoi Mí|

c`¨ t (1) Zvj MvQ, (2) Av`k© †Q‡j, (3) eo †K ?

e¨vKiY t wecixZ kã, GKK_vq cÖKvk, cÖwZkã, c`, dig c~iY, evbvb ï×KiY, wµqvc‡`i PwjZ iƒc, weivgwPý|

wPwV I `iLv¯Í t (1) MÖx‡®§i QzwU †Kgb KvwU‡qQ Zv Rvwb‡q †Zvgvi evÜex/eÜz‡K GKLvbv cÎ wjL|

(2) Amy¯’Zvi Kvi‡b Z…Zxq N›Uvi ci we`¨vjq Z¨v‡Mi Rb¨ cÖavb wkÿ‡Ki wbKU Av‡e`b cÎ wjL|

iPbv t (1) Avgv‡`i we`¨vjq, (2) el©vKvj, (3) Kw¤úDUvi, (4) ¯^vaxbZv w`em|

evwl©K cixÿv

M`¨ t (1) ¯^vaxbZv w`em‡K wN‡i, (2) GKRb cUzqvi K_v, (3) w÷gv‡ii wmwU, (4) wbivc‡` Pjv, (5) fvlv kwn`‡`i K_v, (6) GKvB GKwU `~M©|

c`¨ t (1) Avgvi cY, (2) Avgv‡`i MÖvg, (3) eo †K ? (4) Av`k© †Q‡j|

e¨vKiY t wecixZ kã, GKK_vq cÖKvk, mgv_©K kã, c` wbY©q, dig c~iY, evbvb ï×KiY, wµqvc‡`i PwjZ iƒc, weivgwPý, Aby‡”Q` wjLb|

(2)

wPwV I `iLv¯Í t (1) eb‡fvR‡bi Avgš¿b Rvwb‡q †Zvgvi eÜz/evÜex‡K GKwU cÎ

†jL| (2) cixÿvi djvdj Rvwb‡q †Zvgvi wcZvi wbKU GKLvbv cÎ wjL| (3) eo

†ev‡bi we‡qi Rb¨ wZbw`‡bi AwMÖg QzwU †P‡q Aa¨‡ÿi wbKU Av‡e`b cÎ wjL|

iPbv t (1) ¯^vaxbZv w`em‡K wN‡i, (2) Avgv‡`i we`¨vjq, (3) evsjv‡`‡ki RvZxq dzj, (4) Avgvi gv|

cÖv_wgK MwYZ cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t 1X24 =24

2. ms‡ÿ‡c DËi `vI t 1X 10=10

3. Pvi cÖwµqvwfwËK 3wU cÖkœ t 3 X 8 =24 A_ev,

Pvi cÖwµqvwfwËK 3wU cÖkœ t 3 X 8 =24 4. AsK _vK‡e 4wU Ges cÖ‡Z¨KwU cÖ‡kœi 1wU K‡i A_ev cÖkœ _vK‡e t Pvi

cÖwµqvwfwËK 3wU cÖkœ t 4 X 8 =32

5. R¨vwgwZ t 10

‡gvU= 100 g‡Wj †U÷ ( Aa©-evwl©K c‡e©i )

cvV¨cy¯ÍK t cvV-1 t msL¨v, cvV-2 t †hvM, cvV-3 t we‡qvM, cvV-4 t ¸Y|

R¨vwgwZ t we›`y, †iLv, Zj, †KvY, mg‡KvY, m~²‡KvY, ¯’‚j‡KvY|

Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

cvV-3 t we‡qvM, cvV-4 t ¸Y, cvV-5 t fvM,

cvV-6 t †hvM, we‡qvM, ¸Y I fvM m¤úwK©Z mgm¨v|

R¨vwgwZ t †KvY, mg‡KvY, m~²‡KvY, ¯’‚j‡KvY, we›`y, ‡iLv, Zj|

evwl©K cixÿv cvV¨cy¯ÍK t

cvV-5 t fvM,

cvV-6 t †hvM, we‡qvM, ¸Y I fvM m¤úwK©Z mgm¨v, cvV-7 t evsjv‡`kx gy`ªv I †bvU,

cvV-8 t fMœvsk, cvV-9 t cwigvc,

R¨vwgwZ t we›`y, †iLv, Zj, †KvY, mg‡KvY, m~²‡KvY, ¯’‚j‡KvY, PZzf©~R, eM©, AvqZ, e„Ë|

English cÖ‡kœi aviv I gvbe›Ub t

Read the given text carefully and answer the questions 1, 2, 3 and 4 :

1. Multiple Choice Question : 1×1=10

2. Matching 1×5=05

3. Answer the following questions. 2×5=10 4. Short composition (Competency Based) 10 Read the text and answer the questions 4, 5, 6, 7, 8 & 9:

5. Write only the answer on the answer paper: 1×10=10 6. Fill in the blanks with given words. 1×5=05 7. Answer the following questions: 2×5=10

(3)

8. Read the text and write a short composition (Competency

Based) 10

9. Letter (competency Based) 10 10.Situation based “Short Question” with clues. (Competency

Based) 05

11.“Short Question” with clues. (Competency Based) 05 12.Re-arrange the following Sentences that make Sense.

1×5=05 13.Fill out form given below: 05

Total = 100 Model Test

Text Book : (Seen 1, 2, 3 and 4) Unit : 1 – 10 & 34,

Unseen -(5, 6, 7, 8 and 9 -Suggested by Class Teacher) A Book of Funtional Communicative English Grammar and Composition

Part – One

Lesson- 3 (Word), Lesson- 4 ( Syllable), Lesson-5 (Sentence), Lesson- 6 ( Subject and Predicate), Lesson- 18 ( Gender)

Part – Three Lesson – 2 (Completing Simple Form 1, 2, 3 )

* Model Question 1 and 2

Question no 10, 11 and 12 – Suggested by Class Teacher.

Half Yearly Text Book : (Seen 1, 2, 3 and 4)

Unit : 13, 15, 17-21, 23, 25, 33

Unseen -(5, 6, 7, 8 and 9 -Suggested by Class Teacher) A Book of Funtional Communicative English Grammar and Composition

Part – One

Lesson- 7 (Parts of Speech), Lesson- 8 ( Noun), Lesson-9 (Pronoun), Lesson- 17 ( Conjugation of Verbs)

Part – Two Lessn-7 (sentence)

Part – Three

Lesson – 2 (Completing Simple Form 4, 5, 6, 7 )

* Model Question 3, 4 and 5

Question no 10, 11 and 12 – Suggested by Class Teacher.

Final Exam Text Book : (Seen 1, 2, 3 and 4)

Unit : 26, 28-30, 32, 35-40

Unseen -(5, 6, 7, 8 and 9 -Suggested by Class Teacher) A Book of Funtional Communicative English Grammar and Composition

Part – One

Lesson- 10 (Adjective), Lesson- 12 ( Verb), Lesson-13 (Adverb), Lesson- 25 ( Similar and Opposite Words)

Note : Including Model Test and Half Yearly exam.

* Model Question 6, 7, 8

Question no 10, 11, 12 and 13 – Suggested by Class Teacher.

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Bmjvg I ˆbwZK wkÿv cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t (50wU ) 1X50 =50 2. GKK_vq DËi wjL (mswÿß cÖkœ) t 1X15 =15 3. iPbvg~jK cÖkœ (†hvM¨ZvwfwËK mn †gvU mvZwU cÖ‡kœi DËi w`‡Z n‡e )t

5X7 =15

‡gvU = 100 g‡Wj †U÷ (Aa©-evwl©K c‡e©i)

cvV¨cy¯ÍK t

cÖ_g Aa¨vq Ñ (m¤ú~Y© ), wØZxq Aa¨vq Ñ (m¤ú~Y© ) Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

Z…Zxq Aa¨vq Ñ ( m¤ú~Y© )

evwl©K cixÿv cvV¨cy¯ÍK t

PZz_© Aa¨vq Ñ (m¤ú~Y©), cÂg Aa¨vq Ñ (m¤ú~Y© ) wn›`yag© I ˆbwZK wkÿv cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t (50wU ) 1X50 =50 2. GKK_vq DËi wjL (mswÿß cÖkœ) t 1X15 =15 3. iPbvg~jK cÖkœ (†hvM¨ZvwfwËK mn †gvU mvZwU cÖ‡kœi DËi w`‡Z n‡e )t

5X7 =15

‡gvU = 100 g‡Wj ‡U÷ (Aa©-evwl©K c‡e©i )

cvV¨cy¯ÍK t

cÖ_g Aa¨vq Ñ ¯ªóv I m„wó

Z…Zxq Aa¨vq Ñ gnvcyiæl I gnxqmx bvix Ges ag©MÖš’

mßg Aa¨vq Ñ ¯^v¯’¨iÿv I Avmb

Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

wØZxq Aa¨vq Ñ †`e-‡`ex I c~Rv lô Aa¨vq Ñ mZZv I mZ¨evw`Zv Aóg Aa¨vq Ñ †`k‡cÖg

evwl©K cixÿv cvV¨cy¯ÍK t

PZy_© Aa¨vq Ñ mngwg©

cÂg Aa¨vq Ñ b¤ªZv, f`ªZv I AMÖwaKvi beg Aa¨vq Ñ gw›`i I Zx_©‡ÿÎ

c~e© cv‡Vi c~Y© Av‡jvPbv|

mvaviY Ávb cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t (10wU ) 1X20 =20 2. GKK_vq DËi wjL (mswÿß cÖkœ) t 1X10 =10 3. iPbvg~jK cÖkœ ( †h‡Kvb PviwU cÖ‡kœi DËi w`‡Z n‡e )t 5X4 =20

‡gvU = 50 g‡Wj †U÷ (Aa©-evwl©K c‡e©i)

cvV¨cy¯ÍK t

(2) evsjv‡`‡ki RvZxq cZvKv, (5) fvlv Av‡›`vjb, (6) evsjv‡`‡ki ¯^vaxbZv I gyw³hy‡×i K_v, (7) exi‡kÖ‡ôi K_v, (8) evsjv‡`‡ki ¯§ibxq e¨w³eM©, (11) evsjv‡`‡ki weL¨vZ kni, e›`i,Rbc` I `k©bxq ¯’vb, (12) evsjv‡`‡ki cÖ_g, e„nËg, `xN©Zg I ÿz`ªZg|

Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

(14) evsjv‡`‡ki wefvM I †Rjv mg~n, (15) evsjv‡`‡ki b`-b`x, (16) c„w_ex I

†mŠiRMr, (17) gnv‡`k, gnvmvMi cwiwPwZ, (19) mvK©, (20) c„w_exi wewfbœ †`k, ivRavbx, †jvKmsL¨v I gy`ªvi bvg|

evwl©K cixÿv cvV¨cy¯ÍK t

(5)

(22) we‡k¦i K‡qKwU †`‡ki ¯^vaxbZv I RvZxq w`em, (23) c„w_exi Avðh©

welqmg~n, (24) c„w_exi D”PZg, e„nËg, `xN©Zg I ÿz`ªZg, (26) RxeRMr, (27) gvbe‡`n, (30) we‡k¦i K‡qKRb weL¨vZ weÁvbx, (31) wewfbœ ˆeÁvwbK Avwe®‹vi|

cÖv_wgK weÁvb cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t (50wU ) 1X50 =50 2. GKK_vq DËi wjL (mswÿß cÖkœ) t 1X15 =15 3. iPbvg~jK cÖkœ (†hvM¨ZvwfwËK mn †gvU mvZwU cÖ‡kœi DËi w`‡Z n‡e )t

5X7 =15 ‡gvU = 100 g‡Wj †U÷ (Aa©-evwl©K c‡e©i )

cvV¨cy¯ÍK t

(1) Avgv‡`i cwi‡ek, (2) Rxe I Ro, (3) wewfbœ ai‡bi c`v_©, (4) Rxe‡bi Rb¨

cvwb, (7) Lv`¨|

Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

(1) Avgv‡`i cwi‡ek, (2) Rxe I Ro, (3) wewfbœ ai‡bi c`v_©, (4) Rxe‡bi Rb¨

cvwb, (7) Lv`¨, (8) ¯^v¯’¨wewa|

evwl©K cixÿv cvV¨cy¯ÍK t

(5) gvwU, (6) evqy, (9) kw³, (10) cÖhyw³i m‡½ cwiPq, (11) Z_¨ I †hvMv‡hvM, (12) RbmsL¨v I cÖvK…wZK cwi‡ek|

Kw¤úDUvi cÖ‡kœi aviv I gvbe›Ub t

1. mwVK DËiwU DËic‡Î wjL t (50wU ) 1X50 =50 2. GKK_vq DËi wjL (mswÿß cÖkœ) t 1X15 =15 3. iPbvg~jK cÖkœ (†hvM¨ZvwfwËK mn †gvU mvZwU cÖ‡kœi DËi w`‡Z n‡e )t

5X7 =15 ‡gvU = 100 g‡Wj †U÷ (Aa©-evwl©K c‡e©i )

cvV¨cy¯ÍK t

(1) Kw¤úDUvi wK I cÖKvi‡f`, (2) †ggwi wWfvBm, (3) Kw¤úDUv‡i nvW©Iq¨vi, (4) UvBc Kiv|

Aa©-evwl©K cixÿv cvV¨cy¯ÍK t

(1) AvDUcyU wWfvBm, (2) Kw¤úDUv‡i †jLv †có/‡evì I †Uwej ˆZwi, (3) Kw¤úDUv‡i fvBivm, (4) gvwjwgwWqv|

evwl©K cixÿv cvV¨cy¯ÍK t

(1) †bUIqvK© I B›Uvi‡bU, (2) Kw¤úDUv‡ii ˆewkó¨, (3) DB‡ÛvR, (4) Kw¤úDUvi

†cÖvMÖvwgs|

Qwe AuvKv (AsKb ) cÖ‡kœi aviv I gvbe›Ub t

1. `ywU WªBs is Qvov t 2X5 =10

2. `ywU WªBs Ki‡Z n‡e is mn t 2X10=20

3. GKwU MÖvg evsjvi `„k¨ AvuK‡Z n‡e t 10

‡gvU = 50 g‡Wj †U÷ (Aa©-evwl©K c‡e©i )

1| †cw݇j WªBs t kvcjv, AvBmwµg, Zvj, MvRi|

2| WªBs K‡i is t jvD, †cu‡c, Av‡cj, MvRi|

3| MÖvg evsjvi `„k¨|

(6)

Aa©-evwl©K 1| †cw݇j WªBs t †Xim, evwZ, Kjv, †e¸b|

2| WªBs K‡i is t Wve, ZigyR, Kvc I †cqvjv, †e¸b|

3| MÖvg evsjvi `„k¨|

evwl©K cixÿv 1| †cw݇j WªBs t AvBmwµg, jvD, ZigyR, Kjv|

2| WªBs K‡i is t †cu‡c, Av‡cj, kvcjv, Kvc I †cqvjv, Zvj|

3| MÖvg evsjvi `„k¨|

Referensi

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Бишкек, Кыргызстан; e-mail: [email protected] ОЦЕНКИ СНИЗУ РЕШЕНИЙ ЛИНЕЙНОГО ИНТЕГРО-ДИФФЕРЕНЦИАЛЬНОГО УРАВНЕНИЯ ЧЕТВЕРТОГО ПОРЯДКА ТИПА ВОЛЬТЕРРА Статья посвящена решению задачи