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CE 415 Design of steel structures

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CE 318

STRUCTURE ANALYSIS AND DESIGN II LAB

LECTURE 6

RCC COLUMN DESIGN

SEMESTER: SPRING 2021

COURSE TEACHER: SAURAV BARUA CONTACT NO: +8801715334075

EMAIL: [email protected]

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LECTURE PLAN

2 copyright @Saurav Barua

Column load calculation

Contributory area

Bending factor

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COLUMN LAYOUT

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COLUMN CONTRIBUTORY AREA

copyright @Saurav Barua 4

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CONTRIBUTORY AREA

• Take ½ span from each side to calculate contributory area

• Then designate columns of similar column contributory into same name, i.e. C1, C2, C3 and C4

• Contributory area of corner column C1 = (½ x 15’) x (1/2 x 16’)

= 7’-6” x 8’ = 60 sft

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CONTRIBUTORY AREA

• Contributory area of edge column C2 = (½ x (15’+18’)) x (1/2 x 16’)

= 16’-6” x 8’ = 132 sft

• Contributory area of edge column C3 = (½ x 15’)x (1/2 x (16’+16’))

= 7’-6” x 16’ = 120 sft

• Contributory area of central column C4 = (½ x (15’+18’)) x (1/2 x (16’+16’))

= 16’-6” x 16’ = 264 sft

copyright @Saurav Barua 6

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DEAD LOAD CALCULATION

• Slab weight = 6/12 x 0.15 = 0.075 ksf

• Wall load (WL) = 80psf = 0.08ksf

• Floor finish (FF) = 25psf = 0.025ksf

• Beam weight = [(15’ + 18’+ 15’) x 3 + (16’+ 16’) x 4] x (12 x 18)/144 x 0.15

= [48 x 3 + 32 x 4] x (12 x 18)/144 x 0.15

= 61.2 kip/ (48 x 32) = 0.04ksf [Explained in class!!]

Column weight = 12 x 20 /144 x 10 x 12x 0.15 [ 12 nos. column of 12”x 20” assumed]

= 30kip/ (48 x 32) = 0.02ksf

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• DL = 0.075 + 0.08 + 0.025 + 0.04 + 0.02

= 0.24ksf

LL = 40 psf = 0.04 ksf

Since, we will design column considering axially loaded column formula For central column C4 factor for bending moment = 1.0

For edge columns C2, C3 factor for bending moment = 1.1 For corner column C1 factor for bending moment = 1.3 This will reduce original effect of biaxial bending

Consider 10% of DL for Earthquake load and 15% of DL for Wind load.

copyright @Saurav Barua 8

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Column

Contributory

area (sft) Story Total contributory area (sft)

C1 60 6 360

C2 132 6 792

C3 120 6 720

C4 264 6 1584

Total contributory area = contributory area x story

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• Consider wind and earthquake combined 25% of DL and apply this load as part of DL. So, multiply DL by 1.25.

copyright @Saurav Barua 10

DL (ksf)

Factor for WL and

EQ

Calculated DL

C1 0.24 1.25 0.3

C2,C3 0.24 1.25 0.3

C4 0.24 1.25 0.3

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DL (ksf) LL (ksf)

Factored 1.4 DL+

1.7 LL (ksf)

bending factor

factored load

considering bending,

ksf

C1 0.3 0.04 0.49 1.3 0.63

C2,C3 0.3 0.04 0.49 1.1 0.54

C4 0.3 0.04 0.49 1 0.49

C1 corner column; C2, C3 edge column and C4 middle column

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