p-ISSN: 2086-0382; e-ISSN: 2477-3344
Almost Surjective Epsilon-Isometry in The Reflexive Banach Spaces
Minanur Rohman
Department of Islamic Studies, Faculty of Tarbiyah, STAI MaβHad Aly Al
-Hikam,
Malang, Indonesia
Email:
[email protected]
ABSTRACT
In this paper, we will discuss some applications of almost surjective π-isometry mapping, one of them is in Lorentz space (πΏπ,π-space). Furthermore, using some classical theorems of π€β-topology and concept of closed subspace πΌ-complemented, for every almost surjective π-isometry mapping f : X β Y, where Y is a reflexive Banach space, then there exists a bounded linear operator T : Y β X with βπβ β€ πΌ such that
βππ(π₯) β π₯β β€ 4π for every π₯ β π.
Keywords: almost surjectivity; π-isometry; Lorentz space; reflexive space.
INTRODUCTION
Suppose πand π be real Banach spaces. A mapping π: π β π is called an isometry if
βπ(π₯) β π(π¦)β
π= βπ₯ β π¦β
π, πππ πππ π₯, π¦ β π.
Mazur-Ulam showed that if π is a surjective isometry, then π is affine. In other word, a surjective isometry mapping can be translated. This result lead to the following definition.
Definition 1.1.
Let
π
and
π
be real Banach spaces. A mapping
π: π β π
is called an
π
-isometry if there exists
π β₯ 0
such that
|βπ(π₯) β π(π¦)β
πβ βπ₯ β π¦β
π| β€ π, πππ πππ π₯, π¦ β π.
If π = 0, then 0-isometry is just an isometry. There are other names of π-isometry, some of them are nearisometry [13], approximate isometry ([1], [7]), and perturbed metric preserved [3]. To simplify, the norm fuction is just written as βββ without mentioning the vector space.
Definition 1.1 above begs a question, βfor every π-isometry f, does always exist an isometry mapping U and πΎ > 0 such that
βπ(π₯) β π(π₯)β β€ πΎπ
(1.1)
for all π₯ β π?β.
satisfying (1.1) with πΎ = 10. Some years later, D. G Bourgin studied π-isometry mapping in the Lebesgue space with πΎ = 12.
In 1983, Gevirtz delivered πΎ = 5 which was hold for any Banach space X and Y [6]. This
result was sharpened by OmladiΔ and Ε emrl [10].
Theorem 1.2.
Let X and Y be Banach spaces and f
:
X
β
Y is a surjective
π
-isometry, there
exists a linear surjective isometry mapping U
:
X
β
Y such that
βπ(π₯) β π(π₯)β β€ 2π, πππ ππ£πππ¦ π₯ β π.
There are many applications of π-isometry mapping, such as Dai-Dong who use π-isometry
mapping to determine the smoothness and rotundity of Banach spaces. Ε emrl and VΓ€isΓ€lΓ€
proposed a definition of almost surjective mapping as follows [13].
Definition 1.3. Let f : X β Y is a mapping, π1 is a closed subspace of Y, and πΏ β₯ 0. A mapping f is called almost surjective onto Y if for every π¦ β π1, there exists π₯ β π with βπ(π₯) β π¦β β€ πΏ and for every π’ β π, there exists π£ β π1 with βπ(π’) β π£β β€ πΏ.
Using Definition 1.3, Ε emrl and VΓ€isΓ€lΓ€ weakened the surjective condition become almost
surjective [13] (see also [14]).
Theorem 1.4. Let E and F be Hilbert spaces and f : E β F is an almost surjective π-isometry with
π(0) = 0 that satisfies
sup
βπ¦β=1|π‘|ββliminf βπ‘π¦ β
π(πΈ)
π‘ β < 1 , (1.2)
then there exists a linear surjective isometry π: πΈ β πΉ such that
βπ(π₯) β π(π₯)β β€ 2π, πππ ππ£πππ¦ π₯ β πΈ.
Ε emrl and VΓ€isΓ€lΓ€ showed that this result is true for E and F are Lebesgue spaces [13]. Vestfrid decrease the value 1 become Β½ in (1.2) and is valid for any Banach space [15].
On the other hand, Figiel proved that for any isometry mapping U : X β Y with U(0) = 0, there exists an operator π βΆ π πππΜ Μ Μ Μ Μ Μ Μ π(π₯) β π with βπβ = 1 such that π Β° π = πΌ, the identity on X
[5].
Using Figielβs theorem, Cheng et. al. Give the following lemma [2] (see also Qian [11]).
Lemma 1.5. If f : β β πis a surjective π-isometry with f(0) = 0, then there exists π β πβ with βπβ =
1 such that
|β©π, π(π‘)βͺ β π‘| β€ 3π, πππ πππ¦ π‘ β β.
Using Vestfridβs theorem and Lemma 1.5, Minan et. al. showed that the following lemma
is true [12].
Theorem 1.6. Let X and Y be real Banach spaces, f : X β Y is an π-isometry with f(0) = 0. If the mapping f satisfies almost surjective condition, i. e.
sup
π¦βππ lim
|π‘|ββinf βπ‘π¦ β
π(π) π‘ β <
1 2,
RESULTS AND DISCUSSION
We will discuss some applications of Theorem 1.6. Therefore, this paper will be organized as follows. Firstly, we will discuss two applications of Theorem 1.6, one of them is to determine the stability of almost surjective π-isometry in πΏπ,π-spaces (also called as Lorentz spaces). Next, we will discuss the stability of almost surjective π-isometry in reflexive Banach spaces.
The used notations and terminology are standard. π€β(pronounced βweak starβ) topology
of the dual of normed space X is the smallest topology of πβ such that for every π₯ β π, the linear functional π₯ββ π₯βπ₯ on πβ is continuous.
The author is greatly indebted to anonymous referee for a number of important suggestions that help the author to simplify the proof.
1. Applications of Theorem 1.6
Let X and Y be Banach spaces and π β π (π, π). For bounded set πΆ βX, is defined βπβπΆ =
sup{βππ₯β βΆ π₯ β πΆ}. If there is π β πΆ such that βππβ = βπβπΆ, the T attains its supremum over C. Operator T is called as norm-attaining operator.
Recall that π and π are strictly convex, so π(π₯0) β π(π₯) = β |πππ=1 π|π(π₯π) and π₯0β π₯ = of equivalence classes of real valued measured function over (Ξ©, β, π). The distribution πΏπ(π ) for
π β πΏ(Ξ©) is defined as
πΏπ(π ) βΆ= π(|π| > π )
πΏπ,π-spaces are collections of all measured function over Ξ© such that
βπβπ,πβΆ= (ππ β« πβ(π‘)ππ‘(
πΏπ(Ξ©). The following theorem shows that there exists an isomorphism operator [8] in πΏπ,π-spaces.
Theorem 2.2. Suppose that 1 β€ π,π β€ β, π β π, π β 1, π β 2. Then there exists no weakly sequence
Now, using Theorem 2.2, the author will show that the following theorem is true.
Theorem 2.3. Let X =πΏπ,π and Y be Banach space. If f : X β Y is an almost surjective π-isometry with f(0)= 0, then there exists an operator S : Y β X with βπβ = 1 such that
βππ(π₯) β π₯β β€ 4π, πππ ππ£πππ¦ π₯ β π.
Let S : Y β X is defined by S(y) = β©ππ‘, π(π₯)βͺππ‘ = π₯0. Clearly βπβ = 1 and
βππ(π₯) β π₯βπ,π = (ππ β«(π₯0(π‘)πβ π₯(π‘)π)π‘(
π π) β 1ππ‘
1
0
) 1 π
β€ sup
π‘β(0,1)|β©ππ‘, π(π₯)βͺ β β©π₯π‘
β, π₯βͺ| β€ 4π . β
2. Almost Surjective πΊ-Isometry in The Reflexive Banach Spaces
A normed space is reflexive if the natural mapping π(π₯) from π into πββ which is defined by π(π₯) : f β f(x) where π β πβ, is onto πββ, or π β πββ. Therefore, every reflexive normed space is Banach space. In addition, every closed subspace of reflexive Banach space is reflexive [4].
Proposition 3.1 (Megginson [9], Proposition 1.11.11). Let X be reflexive normed space. Every functional π₯ββ πβ is norm-attaining functional.
The following definitions are classic (for more detail see [4]). Let X be Banach space and
π β π. The polar set of M is πββΆ= { π₯ββ πββΆ β©π₯β, π₯βͺ β€ 1, πππ πππ π₯ β π}. Conversely,
πΒ°βΆ= { π₯ β π βΆ β©π₯β, π₯βͺ β€ 1, πππ πππ π₯ββ πΒ°}
Β° . The annihilator of M is πβ₯βΆ= { π₯ββ πββΆ β©π₯β, π₯βͺ =
0, πππ πππ π₯ β π}, and preannihilator πβ₯ is β₯πβ₯βΆ= { π₯ β π: β©π₯β, π₯βͺ = 0 πππ πππ π₯ββ πβ₯}. For an almost surjective π-isometry mapping f : X β Y with f(0) = 0 and π > 0, πΆ(π) is a closed convex hull of f(X), E is an annihilator of subspace Fβ πβ where F is a set of all bounded functionals over πΆ(π), and
ππ βΆ= {π β πβ: π ππ πππ’ππππ ππ¦ π½π ππ£ππ πΆ(π), πππ π½ > 0}.
Obviously, πΆ(π) is symmetric, then ππ is linear subspace of πβ with ππ = ββπ=1ππΆ(π)Β°. Therefore, πΈ = β{ππππ βΆ π β π}. The following lemma is easy to be proved (see [2]).
Lemma 3.2. Let Y be Banach space, the following statements are equicalence.
(1)πΆ(π) β πΈ + πΉfor a bounded π΅ β π; (2)ππis π€β-closed;
(3)ππis closed.
For every almost surjective π-isometry f, is defined a linear mapping β :πββ 2πβby
βπ₯ββΆ= {π β πβ: |β©π, π(π₯)βͺ β β©π₯β, π₯βͺ| β€ π½π, πππ π½ > 0 πππ πππ π₯ β π}.
Since β is a linear mapping, the definition of ππ implies
β0 = {π β πβ: |β©π, π(π₯)βͺ β β©0, π₯βͺ| β€ π½π}
= {π β πβ: |β©π, π(π₯)βͺ| β€ π½π}
= {π β πβ: π ππ πππ’ππππ ππ¦ π½π ππ£ππ πΆ(π)} = ππ and
βπ₯β= β(π₯β+ 0) = βπ₯β+ β0 β π + β0 = π + π π.
Lemma 3.3. If π₯ββ π¦β, then βπ₯ββ© βπ¦β= β .
Proof. Suppose that βπ₯ββ© βπ¦β is nonempty, then there exists π β βπ₯ββ© βπ¦β. Assume
ππ₯β= {π β πβ: |β©π, π(π₯)βͺ β β©π₯β, π₯βͺ| β€ π½π, πππ πππ π₯ β π)
ππ¦β = {π β πβ: |β©π, π(π₯)βͺ β β©π¦β, π₯βͺ| β€ π½π, πππ πππ π₯ β π).
For π₯ββ π¦β, there exists π β βπ₯ββ© βπ¦β such that ππ₯β= ππ¦β. This is impossible because π is a linear functional and the proof is complete. β
Let π β π (π, π). Then πββ π (πβ, πβ) is called an adjoint operator such that β©ππ₯, πβͺ =
β©π₯, πβπβͺ for all π₯ β π. Two results below are classic.
Proposition 3.4 (Fabian et. al. [4], Proposition 2.6).Let M is a closed subspace of Banach space X. Then (π/π)β is isometric with πβ₯ and πβ is isometric with πβ/πβ₯.
Theorem 3.5 (Megginson [9], Proposition 3.1.11).Let X and Y be normed spaces. If π β π (π, π), then πβ is π€β-to-π€β continuous. Conversely, if π is π€β-to-π€β linear continuous operator from πβ to
πβ, then there exists π β π (π, π) such that πβ= π.
Now, using Proposition 3.4 and Theorem 3.5, we will show that the following theorem is true.
Theorem 3.6. Let X and Y be Banach spaces, f : X β Y is an almost surjective π-isometry with f(0) = 0, and π = βΜ 0. Then
(1)π: πββ πβ/π, which is defined by ππ₯β= βπ₯β+ π, is linear isometry. (2) If M is π€β-closed, then π is an adjoint operator of π: πΈ β π with βπβ = 1.
Proof.(1) From Lemma 3.3 and definition of β, it is clear that π is linear. Lemma 3.2 implies π =
βΜ 0 = πΜ Μ Μ Μ π. For every π₯ββ πβ,
βππ₯ββ = inf{βπ β πβ : π β βπ₯β, π β π}
= inf{βπ β πβ : π β βπ₯β, π β ππ}. From definition of βπ₯β and ππ, we have
βππ₯ββ = inf{βπβ : π β βπ₯β}.
Theorem 1.6 gives
inf{βπβ : π β βπ₯β} β€ βπ₯ββ. (3.1)
To show the conversely, from definition of β, there exists π½ > 0 such that
|β©π, π(π₯)βͺ β β©π₯β, π₯βͺ| β€ π½π, πππ πππ π₯ β π.
For any πΏ > 0, we can choose π₯0β ππ such that
β©π₯β, π₯
0βͺ > βπ₯ββ β πΏ.
For all π β β, we get
|β©π,π(ππ₯π0)βͺ β β©π₯β, π₯
0βͺ| β€π½ππ
As π β β,
βπβ β₯ lim sup
π |β©π,
π(ππ₯0)
Since πΏ is arbitrary, then
βπβ β₯ βπ₯ββ. (3.2)
From (3.1) and (3.2), then βπβ = βπ₯ββ which shows that π is an isometry.
(2) Since π is π€β-closed, then π = { πβ₯ }β₯= { πβ₯ π}β₯= πΈβ₯. Therefore, πβ/π = πβ/πΈβ₯. From definitions of πΈ and ππ, Proposition 3.4 implies πβ/πΈβ₯= πΈβ.
We will prove that π is π€β-to-π€βcontinuous over the unit ball π΅πβ. Let πΌ is an index set and
πΌ β πΌ. Suppose there exists net (π₯β) β π΅πβ which is π€β-converging to π₯ββ πβ. Using Theorem 1.6, there exists net (ππΌ) β πβ with βππΌβ = βπ₯πΌββ = ππΌβ€ 1 such that
|β©ππΌ, π(π₯)βͺ β β©π₯πΌβ, π₯βͺ| β€ 4πππΌ, πππ πππ π₯ β π.
Since (ππΌ) is π€β-compact, then there exists π€β-limit point β πβ such that
|β©π, π(π₯)βͺ β β©π₯β, π₯βͺ| β€ 4ππ, πππ πππ π₯ β π
Therefore, ππ₯πΌβ = βπ₯πΌβ + π = ππΌ+ π is π€β-convergence to π + π = ππ₯β. This result shows that π: π΅πβ β πΈβ is π€β-to-π€β continuous. From Theorem 3.5, there exists π: πΈ β π such that πβ= π. Definition of πΈ shows that π is a surjective mapping. Since πβ= π is a linear
isometry, then βπβ = 1. β
Before discussing the stability of an almost surjective π-isometry in reflexive Banach space, we need some resuls below.
Proposition 3.7 (Fabian et. al. [4], Proposition 3.114). Let Y be reflexive Banach space. If π is a closed subspace of Y, then π is Banach space.
Corollary 3.8. If Y be reflexive Banach space, then the mapping π in Theorem 3.6 is an adjoint operator.
Proof. Since Y is reflexive, from Proposition 3.7, π is π€β-closed. The proof can be completed by Theorem 3.6.
Definition 3.9. Let X be Banach space and 0 β€ Ξ± < β. A closed subspace π β π is called πΌ -complemented in X if there is a closed subspace π β π with π β© π = {0} and projection π: π β
π πππππ π such that π = π + π and βπβ β€ πΌ.
Theorem 3.10. Let X and Y be Banach spaces where Y is reflexive, and f : X β Y is an almost surjective
π-isometry, then there exists a bounded linear operator T : Y β X and βπβ β€ πΌ such that
βππ(π₯) β π₯β β€ 4π, πππ πππ π₯ β π.
Proof. Since Y is reflexive, from Corollary 3.8 and Theorem 3.6, there exists a surjective operator
π: πΈ β π with βπβ = 1 such that π = πβ. Since πΈ is πΌ-complemented in Y, there is a closed subspace πΉ β π and πΈ β© πΉ = {0} such that πΈ + πΉ = π and projection π: π β πΈ πππππ πΉ satisfies
βπβ β€ πΌ. Let π = ππ, then
βπβ = βππβ β€ βπββπβ = βπβ β€ πΌ.
Furthermore,
β©ππ₯β, ππ¦βͺ = β©ππ₯β, π¦βͺ
|β©ππ₯β, ππ(π)βͺ β β©π₯β, π₯βͺ| = |β©ππ₯β, π(π)βͺ β β©π₯β, π₯βͺ| β€ 4πβπ₯ββ, (3.3)
for all π₯ β π and π₯β β πβ. Definition of adjoint operator gives
β©ππ₯β, ππ(π)βͺ = β©π₯β, πβππ(π)βͺ
= β©π₯β, πππ(π)βͺ = β©π₯β, ππ(π)βͺ. (3.4)
Substitute (3.4) into (3.3), then
|β©π₯β, ππ(π)βͺ β β©π₯β, π₯βͺ| = |β©π₯β, ππ(π) β π₯βͺ| β€ 4πβπ₯ββ
for all π₯ β π and π₯β β πβ. In addition,
|β©π₯β, ππ(π) β π₯βͺ| β€ βπ₯βββππ(π) β π₯β
β€ 4πβπ₯ββ
or
βππ(π) β π₯β β€ 4π
for all π₯ β π. β
CONCLUSION
In this paper, the author has shown simple applications of Theorem 1.6. In addition, almost surjective π-isometries are remain stable in the reflexive Banach spaces.
Open Problem 1.This paper has shown that almost surjective π-isometries are stable in Lorentz spaces when the conditions in Theorem 2.2 are satisfied. Is it possible to generalize these restrictions?
Open Problem 2.According to the results of this paper, is it possible to determine the stability of almost surjective π-isometries in the higher dual of Banach spaces?
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