IF3111 - Operasi Aljabar Relasional

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IF-ITB/WD dari Silberschatz, modifikasi TW/6 Okt’03 IF3111 – Aljabar Relasional

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I F3111 - Operasi Aljabar Relasional

Wikan Danar

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Relational Algebra

• Procedural language

• Six basic operators

– select

– project

– union

– set difference

– cartesian product

– rename

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Select Operation

• Notation:

σ

_p

(

r

)

• pis called the selection predicate • Defined as:

σ

p

(

r) = {t | t ∈ r and p(t)}

Wherep is a formula in propositional calculus consisting of terms connected by : ∧ (and), ∨(or), ¬ (not)

Each t erm is one of:

< attribute> op < attribute> or < constant>

• Example of selection:

σ

_{branch- name= “Perryridge}_”(account)

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Project Operation

• Notation:

∏A1, A2, …,Ak(r)

where A₁, A₂are attribute names and r is a relation name. • The result is defined as the relation of kcolumns obtained by

erasing the columns that are not listed

• Duplicate rows removed from result, since relations are sets • E.g. To eliminate the branch -nameattribute of account

∏account-number, balance(account)

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1. r, smust have the same arity(same number of attributes)

2. The attribute domains must be compatible(e.g., 2nd column of r

deals with the same type of values as does the 2nd column of s)

• E.g. to find all customers with either an account or a loan

∏customer-name(depositor) ∪ ∏customer-name (borrower)

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Set Difference Operation

• Notation

r – s

• Defined as:

r – s = {t | t ∈ randt ∉s}

• Set differences must be taken between

compatible

relations.

– r and smust have the same arity

– attribute domains of r and s must be compatible

r – s:

A B

α α β

1 2 1

A B

α β 23

r s A B

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Cartesian-Product Operation

• Notationr x s

• Defined as:

rx s = {t q | t ∈r and q ∈s}

• Assume that attributes of r(R) and s(S) are disjoint. (That is,

R∩S= ∅).

• I f attributes of r ( R)and s(S) are not disjoint, then renaming must be used.

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Rename Operation

• Allows us to name, and therefore to refer to, the

results of relational-algebra expressions.

• Allows us to refer to a relation by more than one

name.

Example:

ρ

_x

(

E

)

returns the expression

E

under the name

X

I f a relational-algebra expression

E

has arity

n

, then

ρ

_x₍A1, A2, …, An)

(

E

)

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Composition of Operations

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Banking Example

• branch (branch-name, branch-city, assets)

• customer (customer-name, customer-street,

customer-only)

• account (account -number, branch-name,

balance)

• loan (loan-number, branch-name, amount)

• depositor (customer-name, account-number)

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Example Queries

• Find all loans of over $1200:

σ

amount > 1200

(

loan

)

– Find the loan number for each loan of an amount greater than $1200

∏

loan- number

(

σ

amount > 1200

(

loan

))

• Find the names of all customers who have a

loan, an account, or both, from the bank

∏customer-name(borrower) ∪ ∏customer- name(depositor)

– Find the names of all customers who have a loan and an account at bank.

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Example Queries (Cont.)

• Find the names of all customers who have a loan

at the Perryridge branch.

n Find the names of all customers who have a loan at the Perryridge branch but do not have an account at any branch of the bank.

∏_{customer-name}(

σ

_{branch- name = “ Perryridge”}

(

σ

_{borrower.loan -number = loan.loan -number}(

borrower x loan

))) –

∏_{customer- name}(

depositor

)

∏

_{customer- name}

(

σ

_{branch-name=“ Perryridge}_”

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Example Queries (Cont.)

• Find the names of all customers who have a loan at the

Perryridge branch.

− Query 2

∏c u s t o m e r - n a m e(σl o a n . l o a n- n u m b e r = b o r r o w e r . l o a n - n u m b e r( (σ_{b r a n c h- n a m e = “ P e r r y r i d g e ”}(loan)) x borrower)) − Query 1

∏c u s t o m e r - n a m e(σbranch- n a m e = “ P e r r y r i d g e ” (

σb o r r o w e r . l o a n- n u m b e r = l o a n . l o a n- n u m b e r(borrower x loan)))

• Find the largest account balance

• Rename

account

relation as

d

∏b a l a n c e(account) -∏a c c o u n t . b a l a n c e

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Formal Definition

• A basic expression in the relational algebra consists

of either one of the following:

– A relation in the database – A constant relation

• Let

E

₁

and

E

₂

be relational-algebra expressions; the

following are all relational-algebra expressions:

– _E1 ∪_E2 – _E1 -_E2 – _E1 x _E2

– σ_p (_E1), Pis a predicate on attributes in _E1

– ∏_s(_E1), Sis a list consisting of some of the attributes in _E1

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Additional Operations

Some additional operations are defined that do

not add any power to the relational algebra,

but that simplify common queries.

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Set-I ntersection Operation

• Notation:

r

∩

s

• Defined as:

• r

∩

s

= {

t

|

t

∈

r

and

t

∈

s

}

• Assume:

– r, shave the same arity

– attributes of r and s are compatible

• Note:

r

∩

s

=

r

- (

r

-

s

)

A B α α β

1 2 1

A B

α β 23

r s A B

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Division Operation

• Notasi:

r

÷

s

• Suited to queries that

include the phrase “for

all”.

relation on schema

R– S = (A_{1, …,}_Am)

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Assignment Operation

• The assignment operation (←) provides a convenient way to express complex queries.

– Write query as a sequential program consisting of

• a series of assignments

• followed by an expression whose value is displayed as a result o f the query.

– Assignment must always be made to a temporary relation variable.

• Example: Write r÷ sas

temp1← ∏_R-S(r)

temp2 ← ∏_R-S ((t emp1 x s) – ∏_R-S,S(r))

result = temp1 –temp2

– The result to the right of the ←is assigned to the relation variable on the left of the ←.

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Example Queries

• Find all customers who have an account from at least

the “Downtown” and the Uptown” branches.

where CNdenotes customer-name and B Ndenotes

branch -name. Query 1

∏_CN(

σ

B N=“Downtown”(depositor account)) ∩ ∏C N(

σ

B N=“U p t o w n”(depositor account))

Query 2

∏customer- name, branch- n a m e(depositor account)

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Extended Relational-Algebra-Operations

• Generalized Projection

• Outer Join

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Generalized Projection

• Extends the projection operation by allowing

arithmetic functions to be used in the projection list.

∏

F1, F2, …, Fn

(

E

)

• E

is any relational-algebra expression

• Each of

F

₁

,

F

₂

, …,

F

_n

are are arithmetic expressions

involving constants and attributes in the schema of

E

.

• Given relation

credit-info(customer-name, limit,

credit-balance),

find how much more each person

can spend:

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Aggregate Functions and Operations

• Aggregation functiontakes a

collection of values and returns a single value as a result.

avg: average value min: minimum value max: maximum value sum: sum of values count: number of values

• Aggregate operationin relational

algebra

G1, G2, …, Gn

g

F1( A1), F2( A2),…, Fn( An)(E)

– Eis any relational-algebra expression

– G₁, G₂ …, G_n is a list of attributes on which to group (can be empty) – Each F_iis an aggregate function – Each A_iis an attribute name

Result of aggregation does not have a name

Can use rename operation to give it a name

branch-name

g

sum

(balance)

as

sum-balance

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Outer Join

• An extension of the join operation that avoids

loss of information.

• Computes the join and then adds tuples form

one relation that does not match tuples in the

other relation to the result of the join.

• Uses

null

values

Uses nullvalues:

•null signifies that the value is unknown or does not exist

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Outer Join (Cont.)

3000

customer-n a m e branch -name

loan borrower

loan-n u m b e r amount

customer-n a m e

Jones

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Null Values

• I t is possible for tuples to have a null value, denoted

by

null

, for some of their attributes

• null

signifies an unknown value or that a value does

not exist.

• The result of any arithmetic expression involving

null

is

null.

• Aggregate functions simply ignore null values

– I s an arbitrary decision. Could have returned null as result instead.

– We follow the semantics of SQL in its handling of null values

• For duplicate elimination and grouping, null is treated

like any other value, and two nulls are assumed to be

the same

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Null Values

• Comparisons with null values return the special truth

value

unknown

– If false was used instead of unknown, then not (A < 5)

would not be equivalent to A > = 5

• Three-valued logic using the truth value

unknown

:

– OR: (unknown or t rue) = t r u e,

(unknown orfalse) = unknown

(unknown orunknown) = unknown

– AND: ( t rueand unknown) = unknown,

(false and unknown) = false,

(unknown andunknown) = unknown

– NOT: (not unknown) = unknown

– I n SQL “Pis unknow n” evaluates to true if predicate P

evaluates to unknown

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Modification of the Database

• The content of the database may be

modified using the following operations:

– Deletion

– I nsertion

– Updating

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Deletion

• A delete request is expressed similarly to a query, except instead of displaying tuples to the user, the selected tuples are removed from the database.

• Can delete only whole tuples; cannot delete values on only particular attributes

• A deletion is expressed in relational algebra by:

r←r – E

where r is a relation and Eis a relational algebra query.

Delete all accounts at branches located in Needham.

r₁←

σ

_{b r a n c h - c i t y = “ N e e d h a m ”} (account branch)

r₂← ∏_{b r a n c h- n a m e , a c c o u n t - n u m b e r , b a l a n c e}(r₁)

r₃← ∏_{c u s t o m e r - n a m e , a c c o u n t - n u m b e r} (r₂ depositor)

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I nsertion

• To insert data into a relation, we either:

– specify a tuple to be inserted

– write a query whose result is a set of tuples to be inserted

• in relational algebra, an insertion is expressed by:

r ← r ∪ E

where r is a relation and Eis a relational algebra expression.

• The insertion of a single tuple is expressed by letting Ebe a constant relation containing one tuple.

Provide as a gift for all loan customers in the Perryridge branch, a $200 savings account. Let the loan number serve

as the account number for the new savings account.

r₁←(σ

b r a n c h -n a m e = “P e r r y r i d g e”(borrower loan))

account ← account∪ ∏_{branch -name, account -number,200}(r₁)

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Updating

• A mechanism to change a value in a tuple without

charging

all

values in the tuple

• Use the generalized projection operator to do this task

r

← ∏

_F_1,_F_{2, …,}_F_I,

(

r

)

• Each

F

_i

is either

– the ith attribute of r, if the ith attribute is not updated, or, – if the attribute is to be updated F_i is an expression, involving

only constants and the attributes of r, which gives the new value for the attribute

Pay all accounts with balances over $10,000 6 percent interest and pay all others 5 percent

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Views

• I n some cases, it is not desirable for all users to

see the entire logical model (i.e., all the actual

relations stored in the database.)

• Consider a person who needs to know a

customer’s loan number but has no need to see

the loan amount. This person should see a

relation described, in the relational algebra, by

∏

_{customer-name, loan-number}

(

borrower loan

)

• Any relation that is not of the conceptual model

but is made visible to a user as a “virtual

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View Definition

• A view is defined using the

create view

statement

which has the form

create view

v

as

<

query expression>

where < query expression> is any legal relational

algebra query expression. The view name is

represented by

v.

• Once a view is defined, the view name can be used

to refer to the virtual relation that the view

generates.

• View definition is not the same as creating a new

relation by evaluating the query expression

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View Examples

• Consider the view (named

all-customer

)

consisting of branches and their customers.

n We can find all customers of the Perryridge branch by writing:

create view all-customer as

∏b r a n c h- n a m e , c u s t o m e r - n a m e(depositor account)

∪ ∏b r a n c h - n a m e , c u s t o m e r - n a m e(borrower loan)

∏b r a n c h- n a m e

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Updates Through View

• Database modifications expressed as views must be

translated to modifications of the actual relations in

the database.

• Consider the person who needs to see all loan data in

the

loan

relation except

amount.

The view given to

the person,

branch-loan,

is defined as:

create view branch - loan as∏_{branch-name, loan-number} (loan)

• Since we allow a view name to appear wherever a

relation name is allowed, the person may write:

branch -loan ←branch -loan ∪ { (“ Perryridge” , L-37)}

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Updates Through Views (Cont.)

• An insertion into

loan

requires a value for

amount

. The

insertion can be dealt with by either.

– rejecting the insertion and returning an error message to the user.

– inserting a tuple (“L-37” , “ Perryridge” , null) into the loan

relation

• Some updates through views are impossible to translate

into database relation updates

– create view v as

σ

_{branch -name}₌_{“ Perryridge” (}account)) v ←v ∪(L-99, Downtown, 23)

• Others cannot be translated uniquely

– all- customer←all-customer ∪ { (“ Perryridge” , “ John” )}

• Have to choose loan or account, and create a new loan/ account number!