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FLUID MECHANICS SCHAUM S

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McGraw-Hill and its licensors do not warrant or guarantee that the functions contained in the work will meet your requirements or that their operation will be uninterrupted or error-free. McGraw-Hill has no responsibility for the content of any information obtained through the work.

INTRODUCTION

DIMENSIONS, UNITS, AND PHYSICAL QUANTITIES

Note that if the leading number in an answer is 1, it does not count as a significant figure, e.g. 1248 has three significant figures. Note that a calculator will provide 19.924 N, which contains four significant figures (the leading 1 does not count).

Table 1.1 Basic Dimensions and Their Units
Table 1.1 Basic Dimensions and Their Units

GASES AND LIQUIDS

PRESSURE AND TEMPERATURE

Note that we do not use the degree symbol when expressing temperature in degrees Kelvin, nor do we capitalize the word 'kelvin'. We read '100 K' as 100 Kelvin in the SI system (remember that the SI system is a special metric system).

PROPERTIES OF FLUIDS

The velocity of the inner cylinder is RO and the velocity of the outer cylinder is zero. If the pressure is below the vapor pressure, the molecules will escape the liquid; it is called boiling when water is heated to the temperature at which the vapor pressure equals the atmospheric pressure.

Figure 1.4 Fluid being sheared between two long cylinders.
Figure 1.4 Fluid being sheared between two long cylinders.

THERMODYNAMIC PROPERTIES AND RELATIONSHIPS

The car is driven in Arizona where the temperature of the tire on the asphalt reaches 65–C. Calculate the shear stress at (a) the wall of the pipe, (b) at a radius where is 0.2 cm, and (c) at the centerline of the pipe.

INTRODUCTION

PRESSURE VARIATION

In a fluid at rest there is no acceleration, so the pressure variation of Eq. If the pressure variation in the atmosphere is desired, then Eq. 2.9) would be used with the ideal gas law p¼rRT to give.

Figure 2.2 Forces acting on an element of fluid.
Figure 2.2 Forces acting on an element of fluid.

MANOMETERS

In the troposphere (between the earth's surface and an altitude of about 10 km) where the temperature (in kelvin) is T¼28820:0065z, Eq. 2.12) can be integrated to give the pressure change. Since point 4 is shown to be open to the atmosphere, the pressure there is zero pressure: p4 ¼0.

Figure 2.3 A U-tube manometer using water and mercury.
Figure 2.3 A U-tube manometer using water and mercury.

FORCES ON PLANE AND CURVED SURFACES

2.6(b) and 2.6(c), the desired forces can be calculated, provided that the force FW acting through the centroid of the area can be found. The forces FHandFV are the horizontal and vertical components of the force of the water acting on the gate.

Figure 2.6 Forces on a curved surface: (a) the gate, (b) the water and the gate, and (c) the gate only.
Figure 2.6 Forces on a curved surface: (a) the gate, (b) the water and the gate, and (c) the gate only.

ACCELERATING CONTAINERS

What rotational speed is required so that the water just touches point A? Also find the force on the bottom of the cylinder. The force of the water on the gate is given by Eq. Giving moments about the hinge.

Figure 2.10 The rotating container and the top view of the infinitesimal element.
Figure 2.10 The rotating container and the top view of the infinitesimal element.

INTRODUCTION

FLUID MOTION

The vorticity and angular velocity components are 0 for an irrotational flow; the fluid particles do not rotate, they only deform. It is the deformation of fluid particles that leads to the internal stresses in a flow.

Figure 3.1 A streamline.
Figure 3.1 A streamline.

CLASSIFICATION OF FLUID FLOWS

Yet it would be a laminar flow, because there would be no mixing of fluid particles. The airflow can be assumed to be incompressible if the velocity is sufficiently low.

Figure 3.4 One-dimensional flow. (a) Flow in a pipe; (b) flow in a wide channel.
Figure 3.4 One-dimensional flow. (a) Flow in a pipe; (b) flow in a wide channel.

BERNOULLI’S EQUATION

This flow is very turbulent at this Reynolds number, in contrast to our observation of the calm flow. Determine the rate of change of temperature of a liquid particle in the stream at point (2, 1.22) at t¼2 s. 3.19.

Figure 3.11 Pressure probes: (a) the piezometer, (b) a pitot tube, and (c) a pitot-static tube.
Figure 3.11 Pressure probes: (a) the piezometer, (b) a pitot tube, and (c) a pitot-static tube.

INTRODUCTION

SYSTEM-TO-CONTROL-VOLUME TRANSFORMATION

3 Figure 4.1 System and fixed control volume. where we simply added and subtracted E1ðtþDtÞ in the last row. Note that the first relation in the last line above refers to the control volume, so that.

Figure 4.2 Differential volume elements from Fig. 4.1.
Figure 4.2 Differential volume elements from Fig. 4.1.

CONSERVATION OF MASS

It leaves the volume through two tubes, one 2 cm in diameter and the other with a mass flow of 10 kg=s. If the velocity out of the 2 cm diameter tube is 15 m=s, determine the rate at which the mass inside the volume is changing.

THE ENERGY EQUATION

Also predict the pressure just upstream of the nozzle (the losses through the nozzle can be neglected). If the correct units are included at the points in our equations, the units will come out as expected, i.e. the units of WW_T must be J=s.

Figure 4.3 Solution: The energy equation is written in the form
Figure 4.3 Solution: The energy equation is written in the form

THE MOMENTUM EQUATION

EXAMPLE 4.7 The relatively fast water flow in a horizontal rectangular channel can suddenly 'jump' to a higher level (an obstruction downstream can be the cause). Determine the force components of the water on the nozzle and the magnitude of the resultant force.

Figure 4.4 A stationary deflector.
Figure 4.4 A stationary deflector.

INTRODUCTION

It is often easier to solve problems using cylindrical or spherical coordinates; the differential equations using those two coordinate systems are presented in Table 5.1.

THE DIFFERENTIAL CONTINUITY EQUATION

It would be necessary if there are temperature differences at the boundaries, or if viscous effects are so great that temperature gradients develop in the flow. 0:80 ¼215 m=ðs·mÞ The best estimate of the density gradient, using the given information, is then.

THE DIFFERENTIAL MOMENTUM EQUATION

Finally, if an incompressible flow is assumed, then HHHHH·V¼0;the Navier-Stokes equations result rDu. where the z direction is vertical. The differential momentum equations (the Navier-Stokes equations) can be solved with relative ease for some simple geometries.

Table 5.1 The Differential Continuity, Momentum Equations, and Stresses for Incompressible Flows in Cylindrical and Spherical Coordinates
Table 5.1 The Differential Continuity, Momentum Equations, and Stresses for Incompressible Flows in Cylindrical and Spherical Coordinates

THE DIFFERENTIAL ENERGY EQUATION

Assume a plane flow in which only the x-andy components are nonzero and viscous and gravity effects are negligible. Experiments show that a stagnant fluid region exists in the face of a sudden increase in the height of the bottom of a channel in a stratified flow.

INTRODUCTION

DIMENSIONAL ANALYSIS

When temperature is required, as in the flow of a compressible gas, an equation of state such as: can be expressed dimensionally as. where the brackets mean 'the dimensions of'. The RT product does not introduce any additional dimensions. EXAMPLE 6.1 It is assumed that the pressure drop over a length of a pipe depends on the average velocity V, the diameter of the pipe D, the average height of the roughness elements of the pipe wall, the fluid density and the fluid viscosity.

Figure 6.2 Drag force versus velocity. (a) L, m, r fixed and (b) R, m, r fixed.
Figure 6.2 Drag force versus velocity. (a) L, m, r fixed and (b) R, m, r fixed.

SIMILITUDE

Estimate the flow rate and pressure rise that would be expected in the model study. What speed should be chosen for the model study and what drag force would be expected on the prototype if a force of 80 N is measured on the model.

Figure 6.3 Similitude.
Figure 6.3 Similitude.

INTRODUCTION

ENTRANCE FLOW

A laminar flow cannot exist for Re.7700; a value of 1500 is used as the limit for a conventional flow. The pressure variation for the laminar flow is higher in the inlet region than in the fully developed region due to the larger wall shear and the increasing momentum flux.

Figure 7.1 The laminar-flow entrance region in a pipe or between parallel plates.
Figure 7.1 The laminar-flow entrance region in a pipe or between parallel plates.

LAMINAR FLOW IN A PIPE

In terms of Reynolds number, the friction factor for laminar flow is (Combine Eqs. EXAMPLE 7.1 The pressure drop across a 30 m length of 1 cm diameter horizontal pipe carrying water at 20–C is measured to be 2 kPa .

LAMINAR FLOW BETWEEN PARALLEL PLATES

If both plates are stationary and the flow is due only to a pressure gradient, it is a Poiseuille flow. The same result can be obtained by solving the appropriate Navier-Stokes equation; if that is not important, go directly to Sec. EXAMPLE 7.2 The thin layer of rain at 20°C flows at a relatively constant depth of 4 mm over a parking lot.

LAMINAR FLOW BETWEEN ROTATING CYLINDERS

Estimate (a) the flow velocity, (b) the surface shear, (c) the Reynolds number, and the surface velocity. The velocity profile can be assumed to be half of the profile shown in Fig.

Figure 7.6 Flow between concentric cylinders.
Figure 7.6 Flow between concentric cylinders.

TURBULENT FLOW IN A PIPE

The outer edge of the wall region can be as low as uty=n¼3000 for a low Reynolds number flow. The viscous wall layer does not play a role for a rough pipe. Solution: First, the average velocity and Reynolds number are V¼Q. a) To find the wall shear stress, let us first find the friction factor. e) The height of the roughness elements is given as 0.0015 mm (drawn pipe), which is less than the thickness of the viscous layer.

Figure 7.7 The three velocity components in a turbulent flow at a point where the flow is in the x-direction so that v ¼ w ¼ 0 and u 6¼ 0.
Figure 7.7 The three velocity components in a turbulent flow at a point where the flow is in the x-direction so that v ¼ w ¼ 0 and u 6¼ 0.

OPEN CHANNEL FLOW

Both EGL and HGL are tilted downstream due to tube losses. Determine the flux using (a) Moody's diagram and (b) the alternative equation. and head loss is.

Figure 7.12 Flow in an open channel.
Figure 7.12 Flow in an open channel.

INTRODUCTION

The boundary layer is so thin that it can be ignored when solving for the inviscid flow. The impure flow solution provides the lift, which is not significantly affected by the viscous boundary layer, and the pressure distribution at the surface of the body, as well as the velocity at that surface (since the inviscid solution ignores viscosity effects, the fluid does not stick to the boundary, but slips off the edge).

FLOW AROUND BLUNT BODIES .1 Drag Coefficients

Free-stream innocuous flow is usually non-rotating, although it may be a swirling flow with vorticity, eg, the flow of air near the ground around a tree trunk or water near the ground around a pole in a river; the water digs a hole in the sand in front of the pole, and the air digs a similar hole in the snow in front of the tree, quite an interesting observation. The moment due to the drag force, which acts at the center of the sign, is.

Figure 8.2 Drag coefficients for flow around spheres and long cylinders.
Figure 8.2 Drag coefficients for flow around spheres and long cylinders.

FLOW AROUND AIRFOILS

The lift and drag on aerofoils will not be calculated from the flow conditions, but from graphical values ​​of the lift and drag coefficients. Lift is directly proportional to angle of attack until just before stall is encountered.

Figure 8.7 Lift and drag coefficients for a conventional airfoil at Re ¼ 9 · 10 6 .
Figure 8.7 Lift and drag coefficients for a conventional airfoil at Re ¼ 9 · 10 6 .

POTENTIAL FLOW .1 Basics

For a real flow, there would be a separated region at the rear of the cylinder, but the flow over the front (perhaps over the entire front half, depending on the Reynolds number) can be approximated by the potential flow shown in outline. To create flow around a rotating cylinder, as in Fig. 8.10, add a vortex to the stream function of Eq. recognizing that the radius of the cylinder remains unchanged since a vortex does not affect vr.

Figure 8.8 Four simple plane potential flows.
Figure 8.8 Four simple plane potential flows.

BOUNDARY-LAYER FLOW .1 General Information

Estimate the shear velocity, the thickness of the viscous wall layer and the boundary layer thickness at the end of the plate (assume a turbulent layer from the leading edge). At the end of the plate, estimate (a) the wall shear stress, (b) the maximum value of the boundary layer, and (c) the flow rate through the boundary layer.

Figure 8.11 A boundary layer.
Figure 8.11 A boundary layer.

INTRODUCTION

SPEED OF SOUND

9.2(b) the source is moving at a subsonic speed, which is less than the speed of sound, i.e. the source. High-amplitude waves called shock waves, which emanate from the leading edge of blunt-nosed airfoils, also form zones of calm, but the angles are greater than those created by the Mach waves.

Figure 9.2 The propagation of sound waves from a source: (a) a stationary source, (b) a moving source with M , 1, and (c) a moving source with M
Figure 9.2 The propagation of sound waves from a source: (a) a stationary source, (b) a moving source with M , 1, and (c) a moving source with M

ISENTROPIC NOZZLE FLOW

The case of a convergent-divergent nozzle allows a supersonic flow to occur provided the receiver pressure is sufficiently low. If the receiver pressure is equal to the reservoir pressure, no flow occurs, represented by curve A.

Figure 9.4 A supersonic nozzle.
Figure 9.4 A supersonic nozzle.

NORMAL SHOCK WAVES

Gambar

Table 1.2 Derived Dimensions and Their Units
Figure 1.6 Free-body diagrams of (a) a droplet and (b) a bubble.
Figure 2.5 The force on an inclined plane area.
Figure 2.6 Forces on a curved surface: (a) the gate, (b) the water and the gate, and (c) the gate only.
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