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Available online at: http://ejournal.radenintan.ac.id/index.php/desimal/index Desimal: Jurnal Matematika, 1 (3), 2018, 381-384

Copyright © 2018, Desimal, Print ISSN: 2613-9073, Online ISSN: 2613-9081

General Formula for Limit of Square Function at Infinity

Bonno Andri Wibowo 1 *, Ikhsan Maulidi 2 ,Windiani Erliana 3

1,3 Institut Pertanian Bogor. Jalan Raya Dramaga, Bogor 16680, Indonesia.

2 Universitas Syiah Kuala. Jalan Teuku Nyak Arief Darussalam, Banda Aceh 23111, Indonesia.

* Corresponding Author. E-mail: [email protected] Received : 13-08-2018; Revised : 19-09-2018; Accepted : 30-09-2018

Abstrak

Penentuan nilai limit dari suatu fungsi merupakan hal yang penting dilakukan. Sejatinya, nilai limit fungsi digunakan untuk melihat sifat fungsi di sekitar titik limitnya. Dalam artikel ini, diberikan rumus umum limit fungsi akar di takhinggaan. Rumus umum ini merupakan pengembangan dari rumus dasar dari limit fungsi akar di ketakhinggaan. Pengembangan yang dilakukan menggunakan teorema aljabar sederhana. Rumus umum limit fungsi akar di takhinggaan yang diperoleh mirip dengan rumus dasarnya.

Kata kunci: Fungsi Akar, Limit di Ketakhinggaan, Rumus Umum.

Abstract

Determination of the limit value of a function is an important things. Basically, the limit is used to look at the "properties" function value around the point. In this paper, we provide the general formula for the limit of square root function at infinite. This general formula comes from the development of a commonly known base formula. We use some simple algebra theorems to develop it. The result is very similar to the basic formula for limit of square root function at infinite.

Keywords: General Formula, Limit at Infinity, Square Function.

INTRODUCTION

Determination of the limit value of a function is an important aspect not only for calculus but also for other applied mathematics. Basically, the limit is used to look at the "properties" function value around the point. Limit at infinite is often used to see the convergence of a function. A function is said to be convergent if

𝑥→∞lim𝑓(𝑥) = 𝐿 < ∞. One of research article about limit at infinity is about behaviour analysis for the solution of a problem (Kaewkhao, A. & Intep, 2013). One particular form of square root function which is often discussed on popular calculus books is

𝑥→∞lim√𝑎𝑥2+ 𝑏𝑥 + 𝑐 − √𝑝𝑥2+ 𝑞𝑥 + 𝑟

= {

𝑏−𝑞

2√𝑎 ; 𝑎 = 𝑝

; 𝑎 > 𝑝

−∞ ; 𝑎 < 𝑝

(1) (Steward, 2011).

The Proof is omitted.

This study is a development of (1) to obtain the general formula of the square root function limit at infinite. Proof of general formula of the function by using algebraic properties of series and limit.

Development is does gradually to see the pattern of proof.

Algebraic properties of series and limit which be used are

∑(𝑎𝑖+ 𝑏𝑖)

𝑛

𝑖=1

= ∑ 𝑎𝑖

𝑛

𝑖=1

+ ∑ 𝑏𝑖

𝑛

𝑖=1

∑ 𝑎𝑖𝑝

𝑛

𝑖=1

= 𝑝 ∑ 𝑎𝑖

𝑛

𝑖=1 𝑛→∞lim(𝑎𝑛+ 𝑏𝑛) = lim

𝑛→∞𝑎𝑛+ lim

𝑛→∞𝑏𝑛

Proof. (Bartle, R.G. & Shebert, 2010)

(2)

Desimal, 1 (3), 2018 - 382

Bonno Andri Wibowo, Ikhsan Maulidi, Windiani Erliana

Copyright © 2018, Desimal, Print ISSN: 2613-9073, Online ISSN: 2613-9081

METHODS

This research is a literature review and the development of basic concepts of limit functions. Firstly, we provide some technical Lemmas which are useful for proving the main Theorem. Then the main theorem was given and we give some examples for result of this article.

Technical Lemmas

In this section, we provide some lemmas to be used in prooving of the Theorem

Lemma 1:

Let 𝑎, 𝑏, 𝑐, 𝑝𝑗, 𝑞𝑗, 𝑟𝑗∈ 𝑅 and 𝑎, 𝑝𝑗> 0. If √𝑎 = ∑𝑛 √𝑝𝑗

𝑗=1 then

𝑥→∞lim(√𝑎𝑥2+ 𝑏𝑥 + 𝑐 − ∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) =2√𝑎𝑏 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1 .

Proof:

𝑥→∞lim(√𝑎𝑥2+ 𝑏𝑥 + 𝑐 − ∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(√𝑎√𝑥2+𝑏𝑥

𝑎 +𝑐

𝑎− ∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑛 √𝑝𝑗

𝑗=1 √𝑥2+𝑏𝑥

𝑎 +𝑐

𝑎

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑ √𝑝𝑗𝑥2+𝑝𝑗𝑏𝑥

𝑎 +𝑝𝑗𝑐

𝑎

𝑛𝑗=1

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞ (√𝑝𝑗𝑥2+𝑝𝑗𝑏𝑥

𝑎 +𝑝𝑗𝑐

𝑎

𝑛𝑗=1

√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)

= ∑ lim

𝑥→∞(√𝑝𝑗𝑥2+𝑝𝑗𝑏𝑥

𝑎 +𝑝𝑗𝑐

𝑎

𝑛𝑗=1

√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = ∑ ( 𝑝𝑗𝑏

2𝑎√𝑝𝑗 𝑞𝑗

2√𝑝𝑗)

𝑛𝑗=1

= ∑ 𝑝𝑗𝑏

2𝑎√𝑝𝑗

𝑛𝑗=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1 = 𝑏

2𝑎𝑛 √𝑝𝑗

𝑗=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

= 𝑏

2𝑎√𝑎 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

= 𝑏

2√𝑎− ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1 .

This completes the proof of Lemma 1.

Lemma 2.

Let 𝑎𝑖, 𝑏, 𝑐, 𝑝𝑗, 𝑞𝑗, 𝑟𝑗∈ 𝑅 and 𝑎𝑖, 𝑝𝑗> 0. If 𝑚 √𝑎𝑖

𝑖=1 = ∑𝑛 √𝑝𝑗 𝑗=1 then

lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑎𝑖𝑏𝑥 + 𝑎𝑖𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)

= ∑ 𝑏𝑖

2√𝑎𝑖

𝑚𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

(2)

Proof:

𝑥→∞lim(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑎𝑖𝑏𝑥 + 𝑎𝑖𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖√𝑥2+ 𝑏𝑥 + 𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑛𝑗=1√𝑝𝑗√𝑥2+ 𝑏𝑥 + 𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞𝑛𝑗=1(√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗

√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)

= ∑ lim

𝑥→∞(√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗

𝑛𝑗=1

√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)

= ∑ (𝑏𝑝𝑗

2√𝑝𝑗 𝑞𝑗

2√𝑝𝑗)

𝑛𝑗=1

= ∑ 𝑏𝑝𝑗

2√𝑝𝑗

𝑛𝑗=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

=𝑏

2𝑛 √𝑝𝑗

𝑗=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

=𝑏

2𝑚 √𝑎𝑖

𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

= ∑ 𝑏√𝑎𝑖

2

𝑚𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1 .

This completes the proof of Lemma 2.

RESULTS AND DISCUSSION Theorem

Let 𝑎𝑖, 𝑏𝑖, 𝑐𝑖, 𝑝𝑗, 𝑞𝑗, 𝑟𝑗, 𝑏, 𝑐 ∈ 𝑅 and 𝑎𝑖, 𝑝𝑖> 0 also let 𝑏𝑖= 𝑏𝑎𝑖 and 𝑐𝑖= 𝑐𝑎𝑖. (3) Then

𝑥→∞lim(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑏𝑖𝑥 + 𝑐𝑖

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)

= {

𝑚𝑖=12√𝑎𝑏𝑖𝑖− ∑ 𝑞𝑗

2√𝑝𝑗

𝑛𝑗=1 ; ∑𝑚 √𝑎𝑖

𝑖=1 = ∑𝑛 √𝑝𝑗 𝑗=1

; ∑𝑚 √𝑎𝑖

𝑖=1 > ∑𝑛 √𝑝𝑗 𝑗=1

−∞ ; ∑𝑚 √𝑎𝑖

𝑖=1 < ∑𝑛 √𝑝𝑗 𝑗=1

(4)

Proof:

Case 1: 𝑚 √𝑎𝑖

𝑖=1 = ∑𝑛 √𝑝𝑗 𝑗=1 𝑥→∞lim(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑏𝑖𝑥 + 𝑐𝑖

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑎𝑖𝑏𝑥 + 𝑎𝑖𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) (5) Substitute (2) to (5)

= ∑ 𝑏√𝑎𝑖

2

𝑚𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

From (3) we have

(3)

Desimal, 1 (3), 2018 - 383

Bonno Andri Wibowo, Ikhsan Maulidi, Windiani Erliana

Copyright © 2018, Desimal, Print ISSN: 2613-9073, Online ISSN: 2613-9081

= ∑ 𝑏𝑖

𝑎𝑖

√𝑎𝑖 2

𝑚𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1

= ∑ 𝑏𝑖

2√𝑎𝑖

𝑚𝑖=1 − ∑ 𝑞𝑗

2√𝑝𝑗 𝑛𝑗=1 .

Case 2: 𝑚 √𝑎𝑖

𝑖=1 > ∑𝑛 √𝑝𝑗 𝑗=1

Let:𝑚𝑖=1√𝑎𝑖= ∑𝑛 √𝑝𝑗

𝑗=1 + 𝐾 with 𝐾 > 0

𝑥→∞lim(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑏𝑖𝑥 + 𝑐𝑖

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑎𝑖𝑏𝑥 + 𝑎𝑖𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖√𝑥2+ 𝑏𝑥 + 𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞((∑𝑛 √𝑝𝑗

𝑗=1 + 𝐾)√𝑥2+ 𝑏𝑥 + 𝑐 −

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗+

√𝐾𝑥2+ 𝑏𝐾𝑥 + 𝑐𝐾 − ∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞[√𝐾𝑥2+ 𝑏𝐾𝑥 + 𝑐𝐾 +

𝑛𝑗=1(√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗− √𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)]

= ∞.

Case 3: 𝑚𝑖=1√𝑎𝑖< ∑𝑛 √𝑝𝑗 𝑗=1

Let:𝑚 √𝑎𝑖

𝑖=1 = ∑𝑛 √𝑝𝑗

𝑗=1 − 𝐿 with 𝐿 > 0

𝑥→∞lim(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑏𝑖𝑥 + 𝑐𝑖

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖𝑥2+ 𝑎𝑖𝑏𝑥 + 𝑎𝑖𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑚𝑖=1√𝑎𝑖√𝑥2+ 𝑏𝑥 + 𝑐

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞((∑𝑛 √𝑝𝑗

𝑗=1 − 𝐿)√𝑥2+ 𝑏𝑥 + 𝑐 −

𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞(∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗

√𝐿𝑥2+ 𝑏𝐿𝑥 + 𝑐𝐿 − ∑𝑛𝑗=1√𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗) = lim

𝑥→∞[−√𝐿𝑥2+ 𝑏𝐿𝑥 + 𝑐𝐿 +

𝑛𝑗=1(√𝑝𝑗𝑥2+ 𝑏𝑝𝑗𝑥 + 𝑐𝑝𝑗− √𝑝𝑗𝑥2+ 𝑞𝑗𝑥 + 𝑟𝑗)]

= −∞.

This completes the proof of Theorem.

Appendix

In this section, the authors provide examples of the use of the obtained formula and compare the results with Laurent series approach.

Example of Lemma 1

Lim𝑥→∞(√4𝑥2+ 𝑥 − 1 − √𝑥2− 𝑥 + 1 − √𝑥2− 2𝑥 + 3)

= 1

2√4 −1

2√1 −2

2√1=7

4.

Laurent series approach:

√4𝑥2+ 𝑥 − 1 − √𝑥2− 𝑥 + 1 − √𝑥2− 2𝑥 + 3

=7

4105

64𝑥 591

512𝑥2+ 𝑂 ((1

𝑥)3) .

So

Lim𝑥→∞[√4𝑥2+ 𝑥 − 1 − √𝑥2− 𝑥 + 1 − √𝑥2− 2𝑥 + 3]

= Lim

𝑥→∞

7 4105

64𝑥 591

512𝑥2+ 𝑂 ((1

𝑥)3) =7

4.

Example of Lemma 2/Theorem

Lim𝑥→∞[ (√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 128𝑥 − 64) − (√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 + √16𝑥2+ 8𝑥 − 3)]

= 2√12 + 128

2√64 −3

2√4 5

2√9 8

2√16=95

12.

Laurent series approach:

(√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 128𝑥 − 64) − (√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 +

√16𝑥2+ 8𝑥 − 3)

=95

1218421

1728𝑥+ 1129361

124416𝑥2+ 𝑂 ((1

𝑥)3).

So

Lim𝑥→∞[ (√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 128𝑥 − 64) − (√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 + √16𝑥2+ 8𝑥 − 3)]

= Lim

𝑥→∞

95 1218421

1728𝑥+ 1129361

124416𝑥2+ 𝑂 ((1

𝑥)3) =95

12.

Other Example (When 𝑏𝑖 and 𝑐𝑖 values which do not depend on 𝑎𝑖 values)

Lim𝑥→∞[ (√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 16𝑥 − 64) −

(√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 + √16𝑥2+ 8𝑥 − 3)]

= 2√12 + 16

2√64 −3

2√4 5

2√9 8

2√16=11

12 .

Laurent series approach:

(√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 128𝑥 − 64) − (√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 +

√16𝑥2+ 8𝑥 − 3) =11

1211617

1728𝑥+ 197213

124416𝑥2+ 𝑂 ((1

𝑥)3).

So

Lim𝑥→∞[ (√𝑥2+ 2𝑥 − 1 + √64𝑥2+ 128𝑥 − 64) − (√4𝑥2− 3𝑥 + 3 + √9𝑥2+ 5𝑥 + 10 + √16𝑥2+ 8𝑥 − 3)]

= Lim

𝑥→∞

11 1211617

1728𝑥+ 197213

124416𝑥2+ 𝑂 ((1

𝑥)3) =11

12.

CONCLUSION AND SUGGESTION

The general formula of the square root function limit at infinte in (4) is very similar with the basic formula of square root function limit in (1). The author strongly

(4)

Desimal, 1 (3), 2018 - 384

Bonno Andri Wibowo, Ikhsan Maulidi, Windiani Erliana

Copyright © 2018, Desimal, Print ISSN: 2613-9073, Online ISSN: 2613-9081

believes that although 𝑏𝑖, and 𝑐𝑖 are independent of 𝑎𝑖 values, we still can use this general formula. In the appendix section, the author gives examples of limit function and compare the results of calculations with the calculation of the limit value using Laurent series approach method (Rodriguez, R.E, Kra, I.,& Gilman, 2012).

Further researchs that can be done is to provide a mathematical proof for 𝑏𝑖 and 𝑐𝑖 values which do not depend on 𝑎𝑖 values or giving a counter example for the general formula.

REFERENCES

Bartle, R.G. & Shebert, D. R. (2010).

Introduction to Real Analysis. (I. John Wiley & Sons, Ed.) (4th ed.). Urbana.

Kaewkhao, A. & Intep, S. (2013). End Behavior Analysis for Solutions of Limit at Infinity. International Journal of Pure and Applied Mathematics, 89(1), 89–94.

Rodriguez, R.E, Kra, I.,& Gilman, I. . (2012).

Complex Analysis: In the Spirit of Lipman Bers. (Springer, Ed.) (2nd ed.).

New York.

Steward, J. (2011). Calculus. (C. Learning, Ed.) (7th ed.). Belmont.

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