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MUHAMMAD ARIF NAUFAL - Assignment 4 time value of money part 4 (IP)

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Assignment 4 Muhammad Arif Naufal

18522032

1. A man deposit $500 in a credit union at the end of each year for five years. The credit union pays 5% compounded annually. At the end of five years, immediately following his fifth deposit, how much will he have in his account?

A=$500, i=5%, n=5

Year Principal Interest (5%)

Amount owned

Amount paid USD

500

1 USD

25

USD 525

2 USD

26

USD 551

3 USD

28

USD 579

4 USD

29

USD 608

5 USD

30 USD

638 USD

638

So, the amount of money owned by the man after 5 years is 638 US Dollar.

2. On January 1, a man deposits $5000 in a credit union that pays 8% interest compounded annually. He wishes to withdraw all the money in five equal end of year sum, beginning December 31st of the first year. How should he withdraw each year?

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Year Principal Interest (8%)

Amount owned

Amoun t paid $

5.000

1 $

400 $

5.400

2 $

432 $

5.832

3 $

467 $

6.299

4 $

504

$ 6.802

5 $

544

$ 7.347

$ 7.347

The withdrawal for each year would be $5400 for year 1, $5832 for year 2, $6299 for year 3, $6802 for year 4, and $7347 for year 5.

3. Consider the following cash flow diagram if the interest rate is 12%, calculate the P value

!

P = A(1+ i)-1 + A(1+ i)-2 + ……+ A(1 + i)-n

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=(6000*(1+12)^-1)+(10000*(1+12)^-2)+(3000*(1+12)^-3)+(12000*(1+12)^- 4)+(8000*(1+12)^-5

= $522,52

So, the P value is $522,52.

4. The amount of money that must be saved from next year to the 6th year in the same amount so that at the end of the 10th year, the money collected is Rp. 20 million (if i = 10% / year ) is?

=20000000*(10/(((1+10)^10)-1))

= $522,52

5. If you save your money in a bank from next year to the 5th year of Rp. 20 million per year, how much money will you get in year 10th?

N1=5 N2=10

F1=20000000

It means, there’s no “i”. And we can assume with common sense presumption, that the P value is 10000000. And the A cumulative after 5 years is 10000000. So, the interest for each year valued about 10000000/5=2000000. If we stretch it to 10 years, means that the additional cumulative interest would be valued about 2000000x5=10000000. Then, the value after 10 years would be 20000000+10000000=30000000.

6. A man purchased a new automobile. He wishes to set aside enough money in a bank account to pay the maintenance on the car for the first five years. It has been estimated that the maintenance cost of an automobile for the first year is $120 and will increase

$300 each year. Assume the maintenance costs occur at the end of each year and that the bank pays 5% interest. How much should he deposit in the bank now?

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A1 120

G 300

i 5

n 5

Pt=120(P/A,5,5)+300(P/G,5,5)

(P/A,5,5)= 120*((((1+5)^5)-1)/(5*((1+5)^5)))

=23,99691358

(P/G,5,5)= (300/5)*((((1+5)^5)-1)/(5*((1+5)^5)))-(5/((1+5)^5))

=11,99781379

Pt=120*23,99691358+300*11,99781379

=8638,811728 Note:

So, the money that has to be deposited is $8638,811728.

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