Particle
kinematics?
KineticsCarviline
NormTanImpulse
-Momentum MiscellaneousT=i=i
-=
mv At =0.3048mCore Formulas
G
>
a =
2
v= Rectangular 92
=9,
+Fdt
qus =32.2 ft/s2Sp
=Sot Vot+ Iat I=xi +yy ner Haute ener
H-=IqCO
Impulsewired
·N - Sec
Relative Motion *
I=x4 +y)A a=iei +vien I =Ex
mi
558↑
- - - xAng Velocity
#A
=FB
+FAI
-
a=x4 +
jj
torm
sinin i danus in the
SVdt I
whereI
=FouroraCircular
MotionsOactex=
-1+x2Non-Uniform
Accelerationo
an=r0=r0==j Sa
=(iron) et en = Exma
=EMo ⑰
smallOe(since in
S
=Sot rot+/ Y"alt" dt'dt'
at=I
=r0 0=dine
1Fl
=rmv= mr2wd
VF=Vot
15 act')
dt' *er
=-en arc=Ora
a=acs) -> rdw- ads
Ai= I=
v8e+ ie (10)
=(H),
+uodT
=I e
ris)-
a(s) ds Friction work'sEnergy Tr= loco
Remindusa =
a(r) IFfs) IMsNI
work! dU=E.
diVg
=mg
↳Read
Carefully
=Fdr as O ↳Visualize
I: "dt=
t[VIt3 Iffx)
=(MN) T
=2m2 Vs
==
bx2 ↳ ListEqusUAI=
1, Efu
ds ↳ Havefun((t')
dt=1s =s(t)
N=my
nos OCoefficient
of Restitution e =-Cut the
Rigid Body
Kinematics Instantaneous CenterRigid Body
KineticsRigid
-BodyDiagram
General
FormulasGeneral
Plane Motion AA Y=
wxras
--werent
BIAAaro
IF=maa [Ma=Iq -=woren Farnet -
Io=Ig+md2 Bcan see it
=I
T =ImY,+ Iqw2
=
wXY
+x
T =E
IIcW2dw=x
dO
wheelsG
=mr, F,
=IqWA
E
or=
= WX it. For indo Damped
Oscillation Base Excitationi
=MSO I=
Emin
Absolute
MotionAnalysis
Relative MotionAnalysis
x, =wn(-3
+VEE1)
Xi
sin an amplitude
① Locate Pointon
body ①
KinematicDiagram
12=
Wn(-5-1) Undamped
BE②Define s=f(0)
(geometry) ②
Crossproduct, equate;
Y +2 [Wnx +Wi=0 A i +wix =Ei(t
③ Apply
derivatives③
Solve. X =A,e
x,t+AzeAzt Xp =Xsin(rt)Amplitude
Vibrations? Time Response Frequency:
WavelengthA,to
reponses-
F
2π
Undamped
Oscillation ONEId= 2π
Des +wnx
=0,an e
fr=
E,
=inA=
ie Xp
=Fes
sin(art)-
-H
Waoverdamped
Static DeflectionX,
=Acos(Wut)
+Bsin(Wnt)
331,
X,,X2DistinctSo
T =E,
= -X2=Csin(Wnt +
4)
d SsTA:
Csin4
B:Cros4 C:VEB2 Critically Damped
Magnification Amplitude3=1 x,=Yz M
=
E
=FTE)
Yo
=Brn=Ccos4Wn Vibration ofParticles =1:
M- 0(Resonance
4=arctan
(E)
x +2wnx +w =wt)
ReachesEquilibrium
fastestUnderdemped
DNF-C-wnVI-5:
Rotation of
Rigid
Bodies Fo'sDriving I<1, WdIwn=
Frequency X=csin(Wat +4) e'eWnt
0 +
wO
=0o
Mass Moments of Inertia
Cylinder
Thin Plate zIg
=m
- > radius of gyrationIx
=Emr2 Iy,
z==m(2
+3r2) Pr
X Ix=72m(b+hz) a Go 3Iy=iz me hW 7 X
Solid
Sphere
Z Slender Rod C z Thin Disk Iz=Emb2 -b
I ab z
Ix,y,
z =Emr2 a. Iy,z
=Fm2 -"X Ix
==mr2·
Brick erIx=12m ↑ y
In,
z =7mr2 Is it e *a
X& Determine Values of a forwhich ②
a) 3=0.5
m=500Ky b) I=1.5
" "atoos. e
③
at
bartenenat line in
·
the C
~
reai-1200
kb,where
an atte
Sin X=I
?
(um] RYAI
Assumption of X=bsin(t) bedisplacent icecim-s--
amplitude cic cos(X-90)SFx =mi=-ux-2cx wewant:0+
2zWnO+
wiO=0⑩ - b - e
[MB=IBx =(Iq+md")x
i(mxtw*x
(Fqt
md")a= ky1COSO(a) +cyccos0(2a) ·9-
20 =
2 ZV
were main re intric nee
I=2asino wa s aO Iradians) ebi Ithen since
Wee
ma dYA=asing anapproximationforsinceE
W ~VI "I>XE =3mV- Velocity,so use the
jc =2a0
I
fact that Wn=w
Ax-were at (
⑤ d for critically damped so, " +(CSO)0 +(cosol0=0 ⑨A
RI
⑥
on and most
e ⑦ A*
Ay mv,():IAW2
I
S I mr.(B)=(I,+mra)We-never
W=mg 93 x (l)e =a Vv↓
**(w=
W=- -50ton+15mc+MvV - >ebfV(z)are
↓by
0.94 ->0.9*sthe ↑
⑫ycute
d1 e rar, e
IF=ma=T-mg +2=x2+n)
DTc=em,wh
1V=0
=strit--ex
S
·is
LinearUtm: G=mYait list in. We
12+('L=y2 Va =VB +WxVa/B
i=a=(X2-i2)I SV=-Wush I VA =VB +W XVA/B
DTc+Vc+Tr+1V=0 11) -ur
It's I 14
=0 =MIV - Mrs, e
Ho=vao at an
⑨
, =
↓m2=1m homentumconserved( Ho = 2Moa t0=0.
X=1m ⑧
(73(0.35)kN(3310.25kg
13(0.4)kN ⑪ -2"-x=(180-120)
EBDEE
-200mm - 36 = 83.5-
- e m=690my M
I
&A
I FoI
**, ie
(0)putye" to
a=
bot.
E >3060* ↑ 1.625m↓ ↓i
c)- - - -AIiz"
>40 LX NA W=mg
↓man
ABIA3BOn
MusEt
=E
AngularUtm-Imp:HAs*EMAdt"
=HALWe fine a
AB=GA+ AB/AEFx =maax=
Fats
mur=e-solveI100 WImg ag=dA+A9/A (0)-(1)
⑳t
M2
N
IMA=
En egrestu - mgcs6o(E)
1.5mg=FdtFA+FB
myg hot the e
⑫A=Ig+ muna[Fy=0 =NA+NB-134-mg
notrotating!
[Ma=8=13k(0.35)(1.625)-NA(1.625) n=
1, I
[Fx=Ma,=F,ws60-Tws 30 +Ni(1.385)-73k(0.4)(1.355)
[Fy=0 =F,sin60-Tain30-mg