• Tidak ada hasil yang ditemukan

solution of home work math

N/A
N/A
fitri suci

Academic year: 2024

Membagikan " solution of home work math "

Copied!
3
0
0

Teks penuh

(1)

Question:

✍ None You can view the question in original Chegg URL page.

Expert answer:  0  0

✍ None

Step: 1

Given:

A Venn diagram displays the probabilities of events A, B, and C.

Explanation

Conditional probability represents the likelihood of an event when another event has occurred.

Step: 2

a. The Probability P(A|B) is calculated as,

P(A|B) = (P(B|A) ∗ P(A))/(P(B))

= (0.9 ∗ 0.1)/(0.2)

(2)

Explanation

Bayes' theorem is a fundamental principle in probability theory that describes how probabilities are updated or revised based on new evidence or information.

Step: 3

b. The Probability P(C|B) is calculated as,

c. The probability P(B|A U C) is calculated as,

= 0.09/0.2

= 0.45

P(C|B) = (P(B|C) ∗ P(C))/(P(B))

= (0.8 ∗ 0.2)/0.2

= 0.16/0.2

= 0.8

P(B|AUC) = (P(B|A). P(A) + P(B|C). P(C))/(P(AUC

= (0.9 ∗ 0.1 + 0.8 ∗ 0.2)/(0.1 + 0.2 − 0.2)

= (0.09 ∗ 0.16)/(0.1)

= 0.144

(3)

Step: 4

d. The Probability P(B|A,C) is calculated as,

Explanation

The probability of event B happening given that both event A and C.

Final Answer

a. P(A|B)=0.45 b.P(C|B)=0.8

c.P(B|A U C)=0.144 d. P(B|A,C)=P(B|A∩ C)

 None

P(B|A, C) = (P(C|B, A). P(B|A))/(P(C|A))

= (0.8 ∗ 0.9)/0.8

= 0.9

Referensi

Dokumen terkait