TUGAS 1 STATISTIK DAN PROBABILITAS (KELAS B) 6 SEPTEMBER 2023

TUGAS 1

STATISTIK DAN PROBABILITAS (KELAS B)

6 SEPTEMBER 2023

Nama : Rudianto NIM : 210401040

1. STEM AND LEAF

The following data are the numbers of cycles to failure of aluminum test coupons subjected to repeated alternating stress at 21,000 psi, 18 cycles per second. Construct a stem and-leaf display for these data. Calculate the median and quartiles of these data.

Jawab :

Stem Leaf Frequenc

y Total Data (n) = 70

3 75 1 1

7 06, 58, 85, 98 4 1 + 4 = 5

8 45, 65, 85 3 5 + 3 = 8

9 10, 90 2 8 + 2 = 10

10 00, 15, 16, 18, 20, 55, 85 7 10 + 7 = 17

11 02, 02, 09, 15, 20 5 17 + 5 = 22

19 10, 40 2 63 + 2 = 65

20 23 1 65 + 1 = 66

21 00, 30 2 66 + 2 = 68

22 16, 65 2 68 + 2 = 70

 Median = (Data ke−35+Data ke−36)

2 =1421+1452

2 =2873

2

=

^1436,5

 Kuartil Bawah : n_Q1=1

4(n+1)=1

4(70+1)=1

4(71)=17,75 Menggunakan interpolasi, maka :

Total Data (n) Data

17 1085

17,75 Q₁

18 1102

Q₁−1085

1102−1085=17,75−17 18−17 Q₁=1097, 75

 Kuartil Atas : n_Q3=3

4(n+1)=3

4(70+1)=3

4(71)=53,25 Menggunakan interpolasi, maka :

Total Data (n) Data

53 1730

53,25 Q₃

54 1750

Q₃−1085

1102−1085=17,75−17 18−17 Q₃=1735

2. Construct a stem-and-leaf display for these data. calculate the median and quartiles of these data.

7.9

8e

8.2, 8.3, 8.3, 8.3, 8.4, 8.5, 8.5, 8.6, 8.6, 8.7, 8.9, 9.0, 9.2, 9.3, 9.3, 9.6,

9.7, 9.8, 9.8, 9.9, 9.9

21 13 + 21 = 34

9z

0.0, 0.1, 0.1, 0.1, 0.3, 0.4, 0.4, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.5, 1.6, 1.6,

1.8, 1.8

26 34 + 26 = 60

9t 2.2, 2.2, 2.2, 2.3, 2.6, 2.7, 2.7, 2.7,

3.0, 3.2, 3.3, 3.3, 3.4, 3.7 14 60 + 14 = 74

9f 4.2, 4.2, 4.4, 4.7 4 60 + 14 = 74

9s 6.1, 6.5 2 78 + 2 = 80

9e 8.8 1 80 + 1 = 81

10z 0.3 1 81 + 1 = 82

 Median ¿(Data ke−41+Data ke−42)

2 =90.4+90.4

2 =¿ 90.4

 Kuartil Bawah : n_Q1=1

4(n+1)=1

4(82+1)=1

4(83)=20. 75 Menggunakan interpolasi, maka :

Total Data (n) Data

20 88.5

20,75 Q₁

21 88.6

Q₁−88.5

88.6−88.5=20.75−20 21−20 Q₁=88.575

 Kuartil Atas : n_Q3=3

4(n+1)=3

4(82+1)=3

4(82)=62.25 Menggunakan interpolasi, maka :

Total Data (n) Data

62 92.2

62.25 Q₃

63 92.2

Q₃−92.2

92.2−92.2=62.25−62 63−62 Q₃=92.2