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FACULTY OF ENGINEERING AND TECHNOLOGY

Department of Mechanical Engineering

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MEPS102:Strength of Material Lecture 23

Topic:Shear stresses in beams

Instructor:

Aditya Veer Gautam

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When a beam is in pure bending, the only stress resultants are the bending moments and the only stresses are the normal stresses acting on the cross sections.

Most beams are subjected to loads that produce both bending moments and shear forces (nonuniform bending). In these cases, both normal and shear stresses are developed in the beam.

Introduction

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Consider a beam of rectangular cross section (width b and height h) subjected to a positive shear force V

Assumptions

The shear stresses τ acting on the cross section are parallel to the shear force

the shear stresses are uniformly distributed across the width of the beam, although they may vary over the height.

For purposes of analysis, we isolate a small element mn of the beam by cutting between two adjacent cross sections and between two horizontal planes

We know that shear stresses acting on one side of an element are accompanied by shear stresses of equal magnitude acting on perpendicular faces of the element

Vertical and Horizontal Shear Stresses

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there are horizontal shear stresses acting between horizontal layers of the beam as well as vertical shear stresses acting on the cross sections.

At any point in the beam, these complementary shear stresses are equal in magnitude.

The equality of the horizontal and vertical shear stresses acting on an element leads to an important conclusion regarding the shear stresses at the top and bottom of the beam.

If we imagine that the element mn is located at either the top or the bottom, we see that the horizontal shear stresses must vanish, because there are no stresses on the outer surfaces of the beam. It follows that the vertical shear stresses must also vanish at those

locations; in other words, where = ±

Vertical and Horizontal Shear Stresses

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Shear Formula

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From last diagram we can write

=

Now

= d = d

= d = ( + d )

d

If the shear stresses are uniformly distributed across the width b of the beam, the force F3 is also equal to the following

= d = + d

d − d

= d d

1 d

Shear Formula

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Now we know that = and ∫ d = first moment of area

=

This equation, known as the shear formula, can be used to determine the shear stress at any point in the cross section of a rectangular beam. Note that for a specific cross section, the shear force V, moment of inertia I and width b are constants. However, the first moment Q (and hence the shear stress ) varies with the distance y1 from the neutral axis.

Shear stresses in a rectangular beam vary quadratically with the distance ( ) from the neutral axis.

Shear Formula

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We usually use the area above the level y1 when the point where we are finding the shear stress is in the upper part of the beam, and we use the area below the level y1 when the point is in the lower part of the beam.

= ( )

= ℎ

( ) =

First Moment Q

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Shear stresses in a rectangular beam vary quadratically with the distance ( ) from the neutral axis

Shear Stresses in Beams of Rectangular Cross Section

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Question

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Referensi

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