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Lattices: …to Cryptography - CSE-IITM

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(1)

Trick #2: Inverting an Easy Function

I A special parity-check matrix: letgt= [1 2 4 · · · 2k 1 2q]and

G= 2 66 64

· · ·gt· · ·

· · ·gt· · · . ..

· · ·gt· · · 3 77

752Zn⇥nkq .

8 / 12

Define

(2)

Put G in Ciphertext ) FHE

[GSW’13]

I Secret key s2Zn, public keyA satisfiesstA⇡0.

I Encrypt µ2{0,1} asC=AR+µG. Decryption relation is stC⇡µ·stG.

I Homomorphic mult: C=C1·G 1(C2).

stC=stC1·G 1(C2)

⇡µ1·stG·G 1(C2)

⇡µ1µ2·stG

Error in C is et1·G 1(C2) +µ1·et2.

Asymmetry allows homom mult with additive noise growth. [BV’13]

11 / 12

(3)

Put G in Ciphertext ) FHE

[GSW’13]

I Secret key s2Zn, public keyA satisfiesstA⇡0.

I Encrypt µ2{0,1} asC=AR+µG. Decryption relation is stC⇡µ·stG.

I Homomorphic mult: C=C1·G 1(C2).

stC=stC1·G 1(C2)

⇡µ1·stG·G 1(C2)

⇡µ1µ2·stG

Error in C is et1·G 1(C2) +µ1·et2.

Asymmetry allows homom mult with additive noise growth. [BV’13]

11 / 12

(4)

Put G in Ciphertext ) FHE

[GSW’13]

I Secret key s2Zn, public keyA satisfiesstA⇡0.

I Encrypt µ2{0,1} asC=AR+µG. Decryption relation is stC⇡µ·stG.

I Homomorphic mult: C=C1·G 1(C2).

stC=stC1·G 1(C2)

⇡µ1·stG·G 1(C2)

⇡µ1µ2·stG

Error in C is et1·G 1(C2) +µ1·et2.

Asymmetry allows homom mult with additive noise growth. [BV’13]

11 / 12

(5)

Put G in Ciphertext ) FHE

[GSW’13]

I Secret key s2Zn, public keyA satisfiesstA⇡0.

I Encrypt µ2{0,1} asC=AR+µG. Decryption relation is stC⇡µ·stG.

I Homomorphic mult: C=C1·G 1(C2).

stC=stC1·G 1(C2)

⇡µ1·stG·G 1(C2)

⇡µ1µ2·stG

Error in C is et1·G 1(C2) +µ1·et2.

Asymmetry allows homom mult with additive noise growth. [BV’13]

11 / 12

(6)

Put G in Ciphertext ) FHE

[GSW’13]

I Secret key s2Zn, public keyA satisfiesstA⇡0.

I Encrypt µ2{0,1} asC=AR+µG. Decryption relation is stC⇡µ·stG.

I Homomorphic mult: C=C1·G 1(C2).

stC=stC1·G 1(C2)

⇡µ1·stG·G 1(C2)

⇡µ1µ2·stG

Error in C is et1·G 1(C2) +µ1·et2.

Asymmetry allows homom mult with additive noise growth. [BV’13]

11 / 12

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