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Unit 3 - Week 2 :
Analysis of Variance
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Week 1 : Quality Engineering, Quality Function Deployment
Week 2 : Analysis of Variance
Lecture 06:
Confidence Interval III and the introduction to Hypothesis Testing Lecture 07:
Hypothesis Testing Lecture 08: The Analysis of Variance (ANOVA) - I Lecture 09: The Analysis of Variance (ANOVA) - II Lecture 10: The Analysis of Variance (ANOVA) - III Quiz : Assignment-02 Assignment-02 (Solution) Total Quality Management -
Due on 2019-02-13, 23:59 IST.
1) 1 point
2) 1 point
3) 1 point
Assignment-02
The due date for submitting this assignment has passed.
As per our records you have not submitted this assignment.
Which of the following is a biased estimator?
No, the answer is incorrect.
Score: 0
Accepted Answers:
In t-distribution for two independent samples n1 = n2 = n, then the degrees of freedom is equal to:
2n–1 2n–2 2n+1 n–1
No, the answer is incorrect.
Score: 0
Accepted Answers:
2n–2
If the population standard deviation σ is known and the sample size n is more than 30, the confidence interval for the population mean µ is:
= X
¯ ¯¯¯ ∑Xn
= p ˆ
Xn=
s
2∑
ni=1 ( −Xn−1i X¯ ¯¯¯¯)2=
s
2∑
ni=1 ( −XinX¯ ¯¯¯¯)2=
s
2∑
ni=1 ( −XinX¯ ¯¯¯¯)2± ( )
X
¯ ¯¯¯Z
α/2 √σnA project of In association with
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Total Quality Management - II - - Unit 3 - Week 2... https://onlinecourses.nptel.ac.in/noc19_mg19/un...
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Week 3 : Introduction to Design of Experiments
Week 4 : Factorial Design
Week 5 : Factorial Design of Experiments
Week 6 : Design and Analysis Topics for Factorial and Fractional Factorial Designs
Week 7 :Factorial and Fractional Factorial Designs Introduction to Linear Regression Models
Week 8 : Fitting Regression Models
Slides and Reading Material
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II : Feedback For Week 2
4) 1 point
5) 1 point
No, the answer is incorrect.
Score: 0
Accepted Answers:
If we have normal populations with known population standard deviations σ1 and σ2, the confidence interval estimates for the difference between two population means (μ1 - μ2) is:
No, the answer is incorrect.
Score: 0
Accepted Answers:
If n1,n2 ≤ 30, the confidence interval estimate for the difference of two population means (μ1 - μ2) when population standard deviation σ1,σ2 are unknown but equal in case of pooled variates is:
No, the answer is incorrect.
Score: 0
Accepted Answers:
± ( )
X
¯ ¯¯¯Z
α/2 √sn± ( ) X
¯ ¯¯¯t
α/2 s√n
± ( )
X
¯ ¯¯¯Z
α/2 √n−1σ± ( )
X
¯ ¯¯¯Z
α/2 √σn( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2 s21+s22 + n1 n2− − −−−
√ ( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2− −
σn−−
121σn222√
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2−
ns−−−−
211+
ns−
222√
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2−
σn−−−−−
121+
σn−
222√
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2−
σn−−−−−
112+
σn−
222√
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2−
ns−−−−
211+
ns−
222√ ( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± t
α/2−
ns−−−−
211+
ns−
222√
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2S
P−
n1−−−−
1+
n−
12√ ( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2−
σn−−−−−
121+
σn−
222√
Total Quality Management - II - - Unit 3 - Week 2... https://onlinecourses.nptel.ac.in/noc19_mg19/un...
2 of 4 Friday 10 May 2019 10:35 AM
6) 1 point
7) 1 point
8) 1 point
9) 1 point
The confidence interval estimate for the difference of two population means μ1 - μ2 = μd in case of paired observations small sample (n ≤ 30) is:
No, the answer is incorrect.
Score: 0
Accepted Answers:
A hypothesis test is done in which the alternative hypothesis is that more than 10% of a
population is left-handed. The p-value for the test is calculated to be 0.25. Which statement is correct?
We can conclude that more than 10% of the population is left-handed.
We can conclude that more than 25% of the population is left-handed.
We can conclude that exactly 25% of the population is left-handed.
We cannot conclude that more than 10% of the population is left-handed.
No, the answer is incorrect.
Score: 0
Accepted Answers:
We cannot conclude that more than 10% of the population is left-handed.
It is known that for right-handed people, the dominant (right) hand tends to be stronger. For left-handed people who live in a world designed for right-handed people, the same may not be true. To test this, muscle strength was measured on the right and left hands of a random sample of 15 left-handed men and the difference (left - right) was found. The alternative hypothesis is one-sided (left hand stronger). The resulting t-statistic was 1.80. Assuming the conditions are met, based on the t-statistic of 1.80 the appropriate conclusion for this test using α=0.05 is:
Df = 14, p-value < 0.05 and the null hypothesis can be rejected.
Df = 14, p-value > 0.05 and the null hypothesis cannot be rejected.
Df = 28, p-value < 0.05 and the null hypothesis can be rejected.
Df = 28, p-value > 0.05 and the null hypothesis cannot be rejected.
No, the answer is incorrect.
Score: 0
Accepted Answers:
Df = 14, p-value < 0.05 and the null hypothesis can be rejected.
A test to screen for a serious but curable disease is similar to hypothesis testing, with a null hypothesis of no disease, and an alternative hypothesis of disease. If the null hypothesis is rejected treatment will be given. Otherwise, it will not. Assuming the treatment does not have serious side effects, in this scenario it is better to increase the probability of:
( X
¯ ¯¯¯1− X
¯ ¯¯¯2) ± Z
α/2S
P−
n1−−−−
1+
n1−
2√
± ( )
X
¯ ¯¯¯Z
α/2 sd√n
± ( )
X
¯ ¯¯¯t
α2(n−1) √sdn±
X
¯ ¯¯¯t
α2(n−1)− ( −−−−
s21+ns22− )
√
± ( )
X
¯ ¯¯¯t
α2(n−2)s
b± ( )
X
¯ ¯¯¯t
α2(n−1) √sdnTotal Quality Management - II - - Unit 3 - Week 2... https://onlinecourses.nptel.ac.in/noc19_mg19/un...
3 of 4 Friday 10 May 2019 10:35 AM
10) 1 point making a Type 1 error, not providing treatment when it is needed.
making a Type 1 error, providing treatment when it is not needed.
making a Type 2 error, providing treatment when it is not needed.
making a Type 2 error, not providing treatment when it is needed.
No, the answer is incorrect.
Score: 0
Accepted Answers:
making a Type 1 error, providing treatment when it is not needed.
A random sample of 25 college males was obtained and each was asked to report their actual height and what they wished as their ideal height. A 95% confidence interval for µd= average difference between their ideal and actual heights was 0.8" to 2.2". Based on this interval, which one of the null hypotheses below (versus a two-sided alternative) can be rejected?
H0: µd=0.5 H0: µd=1.0 H0: µd=1.5 H0: µd=2.0
No, the answer is incorrect.
Score: 0
Accepted Answers:
H0: µd=0.5
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