Review Of
Basic
Hydrogeology
Principles
Types of Terrestrial Water Types of Terrestrial Water
Groundwater Groundwater
SoilSoil Moisture Moisture Surface
Water
Unsaturated Zone – Zone of Aeration
Pores Full of Combination of Air and Water
Zone of Saturation Pores Full Completely with Water
Porosity Porosity
Primary Porosity
Primary Porosity Secondary Porosity Secondary Porosity
Sediments Sediments
Sedimentary Rocks Sedimentary Rocks
Igneous Rocks Igneous Rocks Metamorphic Rocks Metamorphic Rocks
Porosity Porosity
n = 100 (Vv / V) n = 100 (Vv / V)
n = porosity (expressed as a percentage) n = porosity (expressed as a percentage) Vv = volume of the void space
Vv = volume of the void space
V = total volume of the material (void + rock) V = total volume of the material (void + rock)
= =
Porosity Porosity
Permeability Permeability
VS VS
Ability to hold water Ability to transmit water Size, Shape, Interconnectedness Porosity
Porosity
PermeabilityPermeabilitySome rocks have high porosity, but low permeability!!
Some rocks have high porosity, but low permeability!!
Vesicular Basalt Vesicular Basalt
Porous Porous
But Not Permeable But Not Permeable
ClayClay
Porous Porous
But Not Permeable But Not Permeable
High Porosity,
High Porosity, but Low Permeability but Low Permeability
Interconnectedness
Interconnectedness Small PoresSmall Pores
SandSand
The Smaller the Pore Size The Smaller the Pore Size The Larger the Surface Area The Larger the Surface Area
The Higher the Frictional Resistance The Higher the Frictional Resistance
The Lower the Permeability The Lower the Permeability
HighHigh
LowLow
Darcy’s Experiment Darcy’s Experiment
He investigated the flow of water in a column of sand He investigated the flow of water in a column of sand He varied:
He varied: Length and diameter of the columnLength and diameter of the column Porous material in the column
Porous material in the column
Water levels in inlet and outlet reservoirs Water levels in inlet and outlet reservoirs Measured the rate of flow (Q): volume / time
Measured the rate of flow (Q): volume / time
K = constant of proportionality
Q = -KA (
Q = -KA ( h / L) h / L) Darcy’s Law Darcy’s Law
Empirical Law – Derived from Observation, not from Theory Empirical Law – Derived from Observation, not from Theory
Q = flow rate; volume per time (L3/T) A = cross sectional area (L2)
h = change in head (L) L = length of column (L)
LL33 x L x L T x L
T x L22 x L x L
What is K?
What is K?
K = Hydraulic Conductivity = coefficient of permeability K = Hydraulic Conductivity = coefficient of permeability
K = QL / A (-
K = QL / A (- h) h) / /
/ / / /
LL TT
What are the units of K?
What are the units of K?
= =
The larger the K, the greater the flow rate (Q) The larger the K, the greater the flow rate (Q) KK is a function of both: is a function of both:
Porous medium Porous medium
The Fluid
The Fluid
ClayClay 1010-9-9 – 10 – 10-6-6 SiltSilt 1010-6-6 – 10 – 10-4-4
Silty Sand
Silty Sand 1010-5-5 – 10 – 10-3-3 Sands
Sands 1010-3-3 – 10 – 10-1-1 Gravel
Gravel 1010-2-2 – 1 – 1
Sediments have wide range of values for K (cm/s) Sediments have wide range of values for K (cm/s)
Clay Clay Silt Silt
Sand Sand Gravel Gravel
Not a true velocity as part of the column is filled with sediment Not a true velocity as part of the column is filled with sediment
Q = -KA (
Q = -KA ( h / L) h / L)
Rearrange Rearrange
Q Q A A
q = q = = -K = -K ( ( h / L) h / L)
q = specific discharge (Darcian velocity) q = specific discharge (Darcian velocity)
““apparent velocity” –velocity water would move through an aquifer apparent velocity” –velocity water would move through an aquifer
if it were an open conduitif it were an open conduit
Average linear velocity = v = Average linear velocity = v =
True Velocity – Average Mean Linear Velocity?
True Velocity – Average Mean Linear Velocity?
Q Q A A
q = q = = -K = -K ( ( h / L) h / L)
Only account for area through which flow is occurring Only account for area through which flow is occurring
Flow area = porosity x area Flow area = porosity x area
Water can only flow through the pores Water can only flow through the pores
Q Q nA nA q q
n n = =
Aquifers
Aquifer – geologic unit that can store and transmit water at rates fast enough to
supply reasonable amounts to wells
Confining Layer – geologic unit of little to no permeability
Aquitard, Aquiclude
Gravels
Clays / Silts
Sands
Water table aquifer
Confined aquifer
Types of Aquifers
Unconfined Aquifer
high permeability layers to the surface
overlain by
confining layer
Homogeneity – same properties in all locations
Homogeneous vs Heterogenous
Variation as a function of Space
Heterogeneity
hydraulic properties change spatially
Anisotropic
changes with direction
Isotropy vs Anisotropy
Variation as a function of direction Isotropic
same in direction
In Arid Areas: Water table flatter
In Humid Areas: Water Table Subdued Replica of Topography
Regional Flow
Subdued replica of topography
Discharge occurs in topographically low spots
Water Table Mimics the Topography
Need gradient for flow
If water table flat – no flow occurring Sloping Water Table – Flowing Water
Flow typically flows from high to low areas
Q = -KA (
Q = -KA ( h / L h / L ) )
Discharge vs Recharge Areas
Recharge Downward Vertical Gradient Discharge
Upward
Vertical Gradient
Discharge Topographically High Areas
Deeper Unsaturated Zone Flow Lines Diverge
Recharge
Topographically Low Areas Shallow Unsaturated Zone
Flow Lines Converge
Equations of Groundwater Flow
Fluid flow is governed by laws of physics
Any change in mass flowing into the small volume of the aquifer must be balanced by the corresponding change
in mass flux out of the volume or a change in the mass Law of Mass Conservation
Continuity Equation
Matter is Neither Created or Destroyed Darcy’s Law
Balancing your checkbook
$
My Account
Let’s consider a control volume
dx
dy
dz
Confined, Fully Saturated Aquifer
dx
dy
dz
qx
qy
qz
q = specific discharge = Q / A
dx
dy
dz
qx
qy
qz
w = fluid density (mass per unit volume)
Change in Mass in Control Volume = Mass Flux In – Mass Flux Out
Conservation of Mass
The conservation of mass requires that the change in mass stored in a control volume over time (t) equal the difference between the mass that enters the control volume and that
which exits the control volume over this same time increment.
dx
dy dz
- (wqx) dxdydz
-
(
xwqx + ywqy +z wqz)
dxdydzx
- ( wqy) dxdydz
y
- ( wqz) dxdydz
z (wqx) dydz
Volume of control volume = (dx)(dy)(dz)
Volume of water in control volume = (n)(dx)(dy)(dz) Mass of Water in Control Volume = (w)(n)(dx)(dy)(dz)
Change in Mass in Control Volume = Mass Flux In – Mass Flux Out
dx
dy
n dz
[(w)(n)(dx)(dy)(dz)]
M
t
t
=
[(w)(n)(dx)(dy)(dz)]
t =
Change in Mass in Control Volume = Mass Flux In – Mass Flux Out
-
(
xwqx + ywqy +z wqz)
dxdydzDivide both sides by the volume [(w)(n)]
t = -
(
xwqx +ywqy +z wqz)
If the fluid density does not vary spatially [(w)(n)]
t = -
(
xqx+yqy+zqz)
1
w
q
x= - K
x( h/ x) q
y= - K
y( h/ y) q
z= - K
z( h/ z)
xqx+
yqy+
zqz
Remember Darcy’s Law
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ +
dx
dy dz
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ +
[(w)(n)]
t 1
=
(
-
)
[(w)(n)]
t 1
w
After Differentiation and Many Substitutions (wg + nwg) h
t
= aquifer compressibility
= compressibility of water
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ +
(wg + nwg) h =
t
Ss = wg ( + n)
But remember specific storage
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ + =
S
sht
3D groundwater flow equation for a confined aquifer
If we assume a homogeneous system
K S
sht
2h
x2 + 2h +
y2 2h
z2 =
( )
transient anisotropic
heterogeneous
x
(
K
x hx) K
yy(
hy)
z
(
K
z hz)
+ + =
S
sht If we assume a homogeneous, isotropic system
Transient – head changes with time
Steady State – head doesn’t change with time Homogeneous – K doesn’t vary with space
Isotropic – K doesn’t vary with direction: Kx = Ky = Kz = K
Let’s Assume Steady State System
Laplace Equation
Conservation of mass for steady flow in an Isotropic Homogenous aquifer
2h
x2 + 2h +
y2 2h
z2 = 0
If we assume there are no vertical flow components (2D)
Kb S
sb
ht
2h
x2 + 2h
y2 =
( )
S T
ht2h
x2 + 2h
y2 =
K S
sht
2h
x2 + 2h +
y2 2h
z2 =
( )
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ + = 0
Heterogeneous Anisotropic Steady State
K S
sht
2h
x2 + 2h +
y2 2h
z2 =
( )
Homogeneous Isotropic Transient
2h
x2 + 2h +
y2 2h
z2 = 0
Homogeneous Isotropic Steady State
Unconfined Systems
Water is derived from storage by vertical drainage
Sy
Pumping causes a
decline in the water table
In a confined system, although potentiometric surface declines, saturated thickness (b) remains constant
In an unconfined system,
saturated thickness (h) changes And thus the transmissivity changes
Water Table
x
( K
xhx)
y( K
yhy)
z
( K
z hz)
+ + =
S
sht Remember the Confined System
x
( hK
xhx)
+ y( hK
y hy)
=S
yht Let’s look at Unconfined Equivalent
Assume Isotropic and Homogeneous
x
( h
hx)
+ y( h
hy)
=S
yK
h
t
Boussinesq Equation
Nonlinear Equation
K R y
h x
h 2
2 2 2 2
2 2
K R y
v x
v 2
2 2 2
2
Let v = h2
For the case of