Turbulent Boundary-Layer Flows (3)
Contents
25.1 Power Law Formulas for Smooth Walls 25.2 Laws for Rough Walls
Objectives
- Study wall turbulence
- Derive equations of velocity distribution and friction coefficient for both smooth and rough walls
Logarithmic equations for velocity profile and shear-stress coeff .
~ universal
~ applicable over almost entire range of Reynolds numbers
Power-law equations
~ applicable over only limited range of Reynolds numbers
~ simpler
~ explicit relations for and
~ explicit relations for in terms of Re and distance 25.1.1 Power-law formulas: Smooth walls
/
u U cf
x
i) Except very near the wall, mean velocity is closely proportional to a root of the distance y from the wall.
ii) Shear stress coeff. cf is inversely proportional to a root of Re
where n, A = constants; m = fraction
(A)
(25.1)
1
u ∝ yn
1 , Re
f Rem
c U
∝
f m
c A
U
The power laws stem from two facts that hold for turbulent boundary layers with negligible pressure gradients when Re U 5 105
[Cf] Eq. (25.1) is similar to equation for laminar boundary layer,
Derivation of power equation Combine Eqs. (24.16) and (25.1)
(24.16):
(25.2)
3.32
f Re c
* 2
cf
u U
2
*
2 2
m
f
U U
u c A
1 2 2
*
2
m m
U
u A
1 2 2
*
*
2
m m
U u u A
2
*
*
m
u m
U B
u
f m
c A
U
Assume depends on y by the same relation, Eq. (25.2), replacing with y
Divide (25.3) by (25.2)
2
*
*
m
u y m
u B
u (25.3)
(25.4)
2 m
u y m
U u
This result indicates that all profiles are similar and can be represented by a single dimensionless curve like laminar boundary layer profile.
However, turbulent profiles are not truly similar, so Eq. (25.4) will apply for different Reynolds number ranges only if the constant m is varied.
Boundary-layer measurements shows that For 3,000 < Re < 70,000;
(25.5)
(25.6)
(25.7)
(25.8)
1 , 0.0466 , 8.74
m 4 A B
1
u y 7
U
1 7
*
*
8.74 u U
u
1 7
*
*
8.74 u y u
u
1 4
0.0466 cf
Re
(25.10)
u y
U F
Rex1/2
x
[Re] The Blasius solution for laminar boundary layer flows
For steady laminar flow over a flat plate with zero pressure gradient, Prandtl's (1904) 2-D boundary-layer equations become as follows:
2 2 ,
u u u
u v
x y y
u v 0
x y
Blasius (1908) obtained the solution to above PDE by assuming similar profiles along the plate at every x
Blasius obtained the solution in the form of power series after he introduced a stream function for y
(25.9)
(25.11)
Blasius, H. (1883-1970): Prandtl’s student
Relation for
Adopt integral-momentum eq. for steady motion with
~ integration of Prandtl's 2-D boundary-layer equations
where θ = momentum thickness
Substitute Eq. (25.5) into (A) and integrate
(25.12)
0h u 1 u
U U dy
p 0 x
2
2 2
0
2 0 2
f f
U c U c U
x
(A)
Substitute Eqs. (25.8) and (25.13) into (25.12) and integrate w.r.t. x
Integrate (25.15) over whole length, l , to get average coefficient (25.13)
7
0 1
7 0.1
72
y y dy
1 1
5 5
0.318 0.318 Rex
x x
Ux
1 5
0.059 Re
f
x
c
Rex 107 (25.14)
Rex 107 (25.15)
,
,
(25.16)
1 5
0.074 Re
f
l
C Re 107
, l
[Re] Derivation of (25.14) and (25.15)
Substitute (25.13) and (25.8) into (B)
(B)
2 2
f 2
U c U
x
2 cf
x
1 4
1 1
4 4
1 4
7 1
0.0466 / (Re )
72 2
7 0.0233 0.0233
72 Re
0.2397 x
x U
x U
Integrate once w.r.t. x
B.C.: at x = 0
→
1 4
0.2397
x C U
0
1 4
0.2397
0 0 C
U
0 C
1 4
0.2397 x U
5 5
4 4
1 4
0.2397 x Ux
→ Eq. (C)(25.14)
4 4
5 5 5
4
1 1
4 5
0.2397 (0.2397)
x x
Ux Ux
1 1
5 5
0.318 0.318 Rex
x x
Ux
1 1
4 4
0.0466 0.0466 Re
cf
U
(25.17): (C)
Substitute (25.14) into (C)
Integrate (25.15) over
→ (25.15)
1 1 1
4
4 4 1 4
4 5 1
5 1
5
0.0466 0.062
0.318 cf
U U x
Ux U
1 1 1 1
1
5 5 1 5 5
4
5 1
20
0.062 0.062 0.062 0.062
Rex
U Ux
U x
x U
1 1 1 1 1
0 0 0
5 5 5 5 5
1 0.062 0.062 1 0.062 1 0.076
Re Re
l l l
f
x l
C dx dx dx
l l
Ux U x
l
l
Effects of roughness
Rough walls:
- Velocity distribution and resistance = f (Reynolds number, roughness) [Cf] Smooth walls:
- velocity distribution and resistance = f (Reynolds number)
▪ For natural roughness, k is random, and statistical quantity
→ k = ks = uniform sand grain 25.2.1 Effects of roughness
▪ Measurement of roughness effects
a) experiments with sand grains cemented to smooth surfaces - Nikuradse b) evaluate roughness value ≡ height ks
c) compare hydrodynamic behavior with other types and magnitude of roughness
▪ Effects of roughness i)
~ roughness has negligible effect on the wall shear
→ hydrodynamically smooth
= laminar sublayer thickness
' 1
ks
'
*
4 u
ii)
~ roughness effects appear
~ roughness disrupts the laminar sublayer
~ smooth-wall relations for velocity and Cf no longer hold
→ hydrodynamically rough
iii) > 15 ~25
~ friction and velocity distribution depend only on roughness rather than Reynolds number
→ fully rough flow condition
' 1
ks
'
ks
▪ Critical roughness, kcrit
If x increases, then cf decreases, and ' increases.
Therefore, for a surface of uniform roughness, it is possible to be hydrodynamically rough upstream, and hydrodynamically smooth downstream.
Re
'
*
4 4
/ 2
crit
x f
k
u U c x
1
f Re
x
c
k ' k
(2) Rough-wall velocity profiles
Assume roughness height k accounts for magnitude, form, and distribution of the roughness. Then
*
u y
u f k (25.18)
Make f in Eq. (25.18) be a logarithmic function to overlap the velocity- defect law, Eq. (24.14), which is applicable for both rough and smooth boundaries.
(24.14):
i) For rough walls, in the wall region
where C5 = constant = f (size, shape, distribution of the roughness)
*
5.6 log 2.5, 0.15
U u y y
u
* 5
*
5.6 log , 50 ~ 100, 0.15
rough
u k u y y
u y C (25.19)
ii) For smooth walls, in the wall region (24.11):
where C2= 4.9
Subtract Eq. (25.19) from Eq. (24.11)
→ Roughness reduces the local mean velocity in the wall region
where C5 and C6 → Table 9-4 (D&H)
(25.20)
* *
2
*
5.6 log , 30 ~ 70, 0.15
smooth
u u y u y y
u C
*
6
* *
5.6 log
smooth rough
u u u k
u C
u u
u
(3) Surface-resistance formulas: rough walls Combine Eqs. (25.19) and (24.14)
(25.21)
(25.22)
5.6 log 2.5 , 0.15
*
5.6 log
* 5
5.6 log
* 7
U u y y
u
u k
u y C
U C
u k
7
*
2 5.6 log
f
U C
u c k
8
1 3.96 log
f
k C c
[Ex 25.1] Rough wall velocity distribution and local skin friction coefficient - Comparison of the boundary layers on a smooth plate and a plate
roughened by sand grains
▪ Given: t0 0.485 lb /ft2 on both plates U = 10 ft /sec past the rough plate
ks= 0.001 ft
Water temp. = 58 F on both plates
From Table 1-3 (D&H):
; Eq. (24.16)
1.938 slug ft/ 3 1.25 10 5ft2 / sec
0
*
0.485
0.5 / sec 1.938
u ft
2 2
* 0.5
2 2 0.005
f 10 c u
U
*
5
0.5(0.001) 1.25 10 40 u ks
Eq. (25.20): *
*
5.6 log u ks 3.3 u
u
0.5{5.6 log 40 3.3} 2.83 / sec
u ft
ii) For smooth plate, Eq. (24.11):
Check → same result as (a) (b) Velocity on each plate at y =0.007 ft
i) For rough plate Eq. (25.19):
u
*
5.6 log 8.2
u y
u k
0.007
0.5(5.6 log 8.2) 6.47 / sec 0.001
u ft
*
*
5.6 logu y 4.9 u
u
*
5
0.5(0.007) 1.25 10 280 u y
0.5{5.6 log(280) 4.9} 9.3 / sec
u ft
9.3 6.47 2.83 u
(c) Boundary layer thickness on the rough plate Eq. (25.22):
1 3.96 log 7.55
f ks
c
1 1
log 7.55 1.66
3.96 0.005 ks
46 0.046 0.52 1.4
s
ft in cm
k