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Volume 2012, Article ID 293765,29pages doi:10.1155/2012/293765

Research Article

Conformal Mapping of Unbounded Multiply Connected Regions onto Canonical Slit Regions

Arif A. M. Yunus,

1, 2, 3

Ali H. M. Murid,

1, 2

and Mohamed M. S. Nasser

4, 5

1Department of Mathematical Sciences, Faculty of Science, Universiti Teknologi Malaysia, Johor, 81310 Johor Bahru, Malaysia

2Ibnu Sina Institute for Fundamental Science Studies, Universiti Teknologi Malaysia, Johor, 81310 Johor Bahru, Malaysia

3Faculty of Science and Technology, Universiti Sains Islam Malaysia, Negeri Sembilan 71800, Bandar Baru Nilai, Malaysia

4Department of Mathematics, Faculty of Science, King Khalid University, P.O. Box 9004, Abha, Saudi Arabia

5Department of Mathematics, Faculty of Science, Ibb University, P. O. Box 70270, Ibb, Yemen

Correspondence should be addressed to Ali H. M. Murid,[email protected] Received 22 May 2012; Accepted 18 July 2012

Academic Editor: Matti Vuorinen

Copyrightq2012 Arif A. M. Yunus et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We present a boundary integral equation method for conformal mapping of unbounded multiply connected regions onto five types of canonical slit regions. For each canonical region, three linear boundary integral equations are constructed from a boundary relationship satisfied by an analytic function on an unbounded multiply connected region. The integral equations are uniquely solvable. The kernels involved in these integral equations are the modified Neumann kernels and the adjoint generalized Neumann kernels.

1. Introduction

In this paper, we present a new method for numerical conformal mapping of unbounded multiply connected regions onto five types of canonical slit regions. A canonical region in conformal mapping is known as a set of finitely connected regions S such that each finitely connected nondegenerate region is conformally equivalent to a region in S. With regard to conformal mapping of multiply connected regions, there are several types of canonical regions as listed in 1–4. The five types of canonical slit regions are disk with

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concentric circular slits Ud, annulus with concentric circular slits Ua, circular slit regions Uc, radial slit regions Ur, and parallel slit regions Up. One major setback in conformal mapping is that only for certain regions exact conformal maps are known. One way to deal with this limitation is by numerical computation. Trefethen5has discussed several methods for computing conformal mapping numerically. Amano6and DeLillo et al.7 have successfully map unbounded regions onto circular and radial slit regions. Boundary integral equation related to a boundary relationship satisfied by a function which is analytic in a simply or doubly connected region bounded by closed smooth Jordan curves has been given by Murid8and Murid and Razali9. Special realizations of this integral equation are the integral equations related to the Szeg ¨o kernel, Bergmann kernel, Riemann map, and Ahlfors map. The kernels arise in these integral equations are the Neumann kernel and the Kerzman-Stein kernel. Murid and Hu 10 managed to construct a boundary integral equation for numerical conformal mapping of a bounded multiply connected region onto a unit disk with slits. However, the integral equation involves unknown radii which lead to a system of nonlinear algebraic equations upon discretization of the integral equation.

Nasser11–13produced another technique for numerical conformal mapping of bounded and unbounded multiply connected regions by expressing the mapping function in terms of the solution of a uniquely solvable Riemann-Hilbert problem. This uniquely solvable Riemann Hilbert problem can be solved by means of boundary integral equation with the generalized Neumann kernel. Recently, Sangawi et al. 14–17 have constructed new linear boundary integral equations for conformal mapping of bounded multiply region onto canonical slit regions, which improves the work of Murid and Hu 10 where in10, the system of algebraic equations are nonlinear. In this paper, we extend the work of14–17 for numerical conformal mapping of unbounded multiply connected regions onto all five types of canonical slit regions. These boundary integral equations are constructed from a boundary relationship satisfied by an analytic function on an unbounded multiply connected region.

The plan of this paper is as follows: Section 2 presents some auxiliary material.

Section 3 presents a boundary integral equation related to a boundary relationship. In Sections4–8, we present the derivations for numerical conformal mapping for all five types of canonical regions. InSection 9, we give some examples to illustrate the effectiveness of our method. Finally,Section 10presents a short conclusion.

2. Auxiliary Material

Let Ω be an unbounded multiply connected region of connectivity m. The boundary Γ consists ofmsmooth Jordan curvesΓj,j1,2, . . . , mand will be denoted byΓ Γ1∪Γ2∪ · · · ∪ Γm. The boundariesΓj are assumed in clockwise orientationseeFigure 1 . The curveΓj is parameterized by 2π-periodic twice continuously differentiable complex functionηjt with nonvanishing first derivative, that is,

ηjt jt

dt /0, tJj 0,2π, k1, . . . , m. 2.1

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ΓM

Γ2

Γ1

Ω

Figure 1: An unbounded multiply connected regionΩwith connectivitym.

The total parameter domain J is the disjoint union of m intervals J1, . . . , Jm. We define a parameterizationηof the whole boundaryΓonJby

ηt

⎧⎪

⎪⎨

⎪⎪

η1t , tJ1 0,2π, ...

ηmt , tJm 0,2π.

2.2

Let Φz be the conformal mapping function that maps Ω onto U, where U represents any canonical region mentioned above,z1 is a prescribed point located insideΓ1, zmis a prescribed point insideΓmandβis a prescribed point located inΩ. In this paper, we determine the mapping functionΦz by computing the derivatives of the mapping function Φηt and two real functions on J, that is, the unknown function ϕt and a piecewise constant real function Rt . LetH be the space of all real H ¨older continuous 2π-periodic functions andSbe the subspace ofHwhich contains the piecewise real constant functions Rt . The piecewise real constant functionRt can be written as

Rt

⎧⎪

⎪⎨

⎪⎪

R1, tJ1 0,2π, ...

Rm, tJm 0,2π,

2.3

briefly written asRt R1, . . . , Rm . LetAt be a complex continuously differentiable 2π- periodic function for alltJ. We define two real kernels formed withAas18

Ns, t 1 πIm

As At

ηt ηtηs

,

Ms, t 1 π Re

As At

ηt ηtηs

.

2.4

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The kernelNs, t is known as the generalized Neumann kernel formed with complex-valued functionsAandη. The kernelNs, t is continuous with

Nt, t 1 πIm

ηt

ηtAt At

. 2.5

The kernelMs, t has a cotangent singularity

Ms, t − 1

2πcotst

2 M1s, t , 2.6 where the kernelM1s, t is continuous with

M1t, t 1 π Re

1 2π

ηt

ηtAt At

. 2.7

The adjoint functionAofAis defined by

A ηt

At . 2.8

The generalized Neumann kernelNs, t and the real kernelMformed withA are defined by

Ns, t 1 π Im

As At

ηt ηtηs

,

Ms, t 1 πRe

As At

ηt ηtηs

.

2.9

Then,

Ns, tNs, t , Ms, tMs, t , 2.10 whereNs, t Nt, s is the adjoint kernel of the generalized Neumann kernelNs, t . We define the Fredholm integral operators Nby

Nυt

J

Nt, s υs ds, tJ. 2.11

Integral operatorsM,N, andMare defined in a similar way. Throughout this paper, we will assume the functionsAandAare given by

At 1, At ηt . 2.12

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It is known thatλ1 is not an eigenvalue of the kernelNandλ−1 is an eigenvalue of the kernelNwith multiplicitym18. The eigenfunctions ofNcorresponding to the eigenvalue λ−1 are{χ1, χ2, . . . , χm}, where

χjξ

1, ξ∈Γj,

0, otherwise. j1,2, . . . , m. 2.13

We also define an integral operator J bysee14

Jμs :

J

1 2π

m j0

χjs χjt μt dt. 2.14

The following theorem gives us a method for calculating the piecewise constant real function ht in connection with conformal mapping later. This theorem can be proved by using the approach as in19, Theorem 5.

Theorem 2.1. Let i√

−1,γ,μHandhSsuch that

Af γhiμ 2.15

are the boundary values of a functionfz analytic inΩ. Then the functionh h1, h2, . . . , hm has each element given by

hj γ, ρj

1 2π

Γγt ρtdt, 2.16 whereρtis the unique solution of the integral equation

INJ ρjχj, j 1,2, . . . , m. 2.17

3. The Homogeneous Boundary Relationship

Suppose we are given a functionDz which is analytic inΩ, continuous onΩ∪Γ, H ¨older continuous onΓandD∞ is finite. The boundaryΓjis assumed to be a smooth Jordan curve.

The unit tangent toΓat the pointηt ∈Γwill be denoted byTηt ηt /|ηt |. Suppose further thatDηt satisfies the exterior homogeneous boundary relationship

D ηt

ct T ηt 2

D ηt P

ηt , 3.1

wherect andPare complex-valued functions with the following properties:

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1 Pz is analytic inΩand does not have zeroes onΩ∪Γ, 2 P/0,D∞ is finite,

3 ct /0,Pηt /0.

Note that the boundary relationship3.1 also has the following equivalent form:

P ηt

ct T

ηt 2 D ηt 2 D

ηt 2. 3.2

Under these assumptions, an integral equation forDηt can be constructed by means of the following theorem.

Theorem 3.1. If the functionDηt satisfies the exterior homogeneous boundary relationship3.1 , then

φt

J

Ks, t φs dsνt , 3.3

where

φt D ηt

ηt ,

Ks, t 1 2πi

⎢⎣ ηt

ηtηsct cs

ηt ηtηs

⎥⎦,

νt Dηt ct ηt D

P.

3.4

Proof. Consider the integralI1ηt ,

I1 ηt

1 2πi

J

D ηs

ηsηt ds. 3.5

Since the boundary is in clockwise orientation andDis analytic inΩ, then by20, p. 2we have

I1 ηt

D ηt

2 −D. 3.6

Now, let the integralI2ηt be defined as

I2

ηt 1

2πi

J

ct T ηt 2

D ηs cs

ηsηt T

ηs |ds|. 3.7

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Using the boundary relationship3.1 and the fact thatTηt |dt|dtandPηt does not contain zeroes, then by20, p. 2we obtain

I2 ηt

ct T

ηt 2D ηt P

ηt ct T

ηt 2D

P. 3.8

Next, by takingI2ηtI1ηt with further arrangement yields

D ηt

1 2πi

J

⎣ 1

ηtηsct cs

T ηt 2 ηtηs

D ηs

|ds|

Dct T

η2D

P.

3.9

Then multiplying3.9 withTηt and|ηt |, subsequently yields3.3 . Theorem 3.2. The kernelKs, t is continuous with

Kt, t 1

2πImηt ηt − 1

2πi ct

ct . 3.10

Proof. Let the kernelKs, t be written as

Ks, t K1s, t K2s, t , 3.11

where

K1s, t 1 2πi

ηt

ηtηsηt ηtηs

,

K2s, t 1 2πi

ct cs

ηt

ηtηs ηt ηtηs

1

2πi ηt cs

csct ηtηs

.

3.12

Notice thatK1s, t is the classical Neumann kernel withK1t, t 1/2π Imηt t . Now forK2s, t , as we take the limitstwe have,

K2t, t 1 2πilim

st

ηt cs lim

st

csct ηtηs

− 1 2πi

ct ct .

3.13

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Hence, by combiningK1t, t andK2t, t , we obtain Kt, t 1

2π

Imηt ηt −1

i ct

ct

. 3.14

Note that whenct 1, the kernelKs, t reduces to the classical Neumann kernel.

We define the Fredholm integral operator K by

Kυt 1 2πi

J

Ks, t υs ds, tJ. 3.15

Hence,3.3 becomes

IK φt νt . 3.16

The solvability of the integral equation 3.16 depends on the possibility of λ −1 being an eigenvalue of the kernel Ks, t . For the numerical examples considered in this paper, λ −1 is always an eigenvalue of the kernelKs, t . Although there is no theoretical proof yet, numerical evidence suggests thatλ −1 is an eigenvalue ofKs, t . If the multiplicity of the eigenvalueλ −1 ism, then one need to add m conditions to the integral equation to ensure the integral equation is uniquely solvable.

4. Exterior Unit Disk with Circular Slits

The canonical regionUd is the exterior unit disk along withm−1 arcs of circles. We assume thatw Φz maps the curveΓ1onto the unit circle|w|1, the curveΓj, wherej 2,3, . . . , m, onto circular slit on the circle|w|Rj, whereR2, R3, . . . , Rmare unknown real constants. The circular slits are traversed twice. The boundary values of the mapping functionΦare given by

Φ ηt

Rt eiθt , 4.1 whereθt represents the boundary correspondence function andRt 1, R2, . . . , Rm . By differentiating4.1 with respect to tand dividing the result obtained by its modulus, we have

Φ ηt

ηt Φ

ηt

ηt i sign θt

eiθt . 4.2

Using the fact that unit tangentTηt ηt /|ηt | and eiθt Φηt /Rt , it can be shown that

Φ ηt

sign

θt Rt i T

ηt Φ ηt Φ

ηt . 4.3

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Boundary relationship4.3 is useful for computing the boundary values ofΦz provided θt , Rt , andΦηt are all known. By taking logarithmic derivative on4.1 , we obtain

ηt Φ ηt Φ

ηt iθt . 4.4

The mapping functionΦz can be uniquely determined by assuming Φ∞ ∞, c Φ∞ lim

z→ ∞

Φz

z >0. 4.5

Thus, the mapping function can be expressed as12

Φz czz1 eFz , 4.6

whereFz is an analytic function andF∞ 0. By taking logarithm on both sides of4.6 , we obtain

F ηt

lnRt

c iθ−log

ηtz1

. 4.7

Hence4.7 satisfies boundary values2.15 inTheorem 2.1withAt 1, ht

ln1

c,lnR2

c , . . . ,lnRm

c

, γt −lnηtz1. 4.8

Hence, the values ofRjcan be calculated by

Rjehjh1 forj 1,2, . . . , m. 4.9 To findθt , we began by differentiating4.7 and comparing with4.4 which yields

iθt F ηt

ηtηt

ηtz1. 4.10

In view ofA ηt and lettingfz Fz −1/zz1 , wherefz is analytic function in Ω,4.10 becomes

Af ηt

iθt . 4.11

By18, Theorem 2c , we obtainIN θ 0 which implies

IN θ0. 4.12

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However, this integral equation is not uniquely solvable according to18, Theorem 12. To overcome this, since the image of the curveΓ1 is clockwise oriented and the images of the curvesΓj, j 2,3, . . . , mare slits so we haveθ12πθ10 −2π andθj2πθj0 0, which implies

Jθt ht −1, 0, . . . ,0 . 4.13

By adding this condition to4.12 , the unknown functionθt is the unique solution of the integral equation

INJ θt ht . 4.14 Next, the presence of signθt in4.3 can be eliminated by squaring both sides of4.3 , that is,

Φ ηt 2

Rt 2T

ηt 2 Φ ηt 2 Φ

ηt 2. 4.15 Upon comparing4.15 with3.2 , this leads to a choice ofPηt Φηt 2,P∞ ∞, Dηt Φηt ,Dc,ctRt 2. Hence,

φt Φ ηt

ηt 4.16

satisfies the integral equation3.16 with

νt Φηt . 4.17

Numerical evidence shows thatλ −1 is an eigenvalue ofKs, t of multiplicitym, which means one needs to addmconditions. SinceΦz is assumed to be single-valued, it is also required that the unknown mapping functionΦz satisfies4

Jj

φt dt

Γj

Φ η

0, j1,2, . . . , m, 4.18

that is,

Jφ0. 4.19

Then,φt is the unique solution of the following integral equation

IKJ φt νt . 4.20

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By obtainingφt , the derivatives of the mapping function,Φt can be found using Φt φt

ηt . 4.21

By obtaining the values of Rt , θt and Φηt , the boundary value of Φηt can be calculated by using4.3 .

5. Annulus with Circular Slits

The canonical regionUa consists of an annulus centered at the origin together with m−2 circular arcs. We assume thatΦz maps the curveΓ1onto the unit circle|Φ| 1, the curve Γmonto the circle|Φ|RmandΓjonto circular slit|Φ|Rj, wherej 2,3, . . . , m−1. The slit are traversed twice. The boundary values of the mapping functionΦare given by

Φ ηt

Rt eiθt , 5.1 whereθt represents the boundary correspondence function andRt 1, R2, . . . , Rm is a piecewise real constant function. By using the same reasoning as inSection 4, we get

Φ ηjt

sign

θt Rjt i T

ηjt Φ ηjt Φ

ηjt , 5.2

ηt Φ ηt Φ

ηt iθt . 5.3

The mapping functionΦz can be uniquely determined by assumingc Φ∞ > 0. Thus, the mapping function can be expressed as12

Φz czzm

zz1eFz . 5.4

By taking logarithm on both sides of5.4 , we obtain F

ηt

lnRt

c iθ−logηtzm

ηtz1

. 5.5

Hence,5.5 satisfies boundary values2.15 inTheorem 2.1withAt 1, ht

ln1

c,lnR2

c , . . . ,lnRm

c

, γt −ln

ηtzm ηtz1

. 5.6 By obtaininghj, the values ofRjcan be computed by

Rjehjh1, j 2,3, . . . , m. 5.7

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By differentiating5.5 and comparing with5.3 yields

iθt F ηt

ηt ηt

ηtzmηt

ηtz1. 5.8

In view oft andfηt Fηt 1/ηtzm −1/ηtz1 , wherefz is analytic inΩ,5.8 is equivalent to

Af ηt

iθt . 5.9

By18, Theorem 2c , we obtain

IN θt 0. 5.10

Note that the image of the curve Γ1 is counterclockwise oriented,Γm is clockwise oriented and the images of the curvesΓj, j 2,3, . . . , m−1 are slits so we haveθ12πθ10 2π, θm2πθm0 −2πandθj2πθj0 0, which implies

Jθt ht 1, 0, . . . ,−1 . 5.11

Hence, the unknown functionθt is the unique solution of the integral equation

INJ θt ht . 5.12

Next, the presence of signθt in 5.2 can be eliminated by squaring both sides of the equation, that is,

Φ ηt 2

Rt 2T

ηt 2 Φ ηt 2 Φ

ηt 2. 5.13 Comparing5.13 with3.2 leads to a choice ofPηt Φηt 2,Pc2,Dηt Φηt ,D∞ 0,ctRt 2. Hence,

φt Φ ηt

ηt 5.14

satisfies the integral equation3.16 with

νt 0, . . . ,0 . 5.15

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Numerical evidence shows thatλ−1 is an eigenvalue ofKs, t of multiplicitym1, which implies one needs to addm1 conditions. SinceΦz is assumed to be single-valued, hence it is also required that the unknown mapping functionΦz satisfies4

Jj

φs ds

Γj

Φ η

0, j1,2, . . . , m, 5.16

that is,

Jφ0. 5.17

Since we assume the mapping functionΦz can be uniquely determined byc Φ∞ >0, hence by20

Φ∞ c 1 2π

J

ηt θt

ηz1φt dt. 5.18

If we define the Fredholm operator G as

Gμs 1 2π

J

ηt θt

ηz1

μt dt, 5.19

thenφt is the unique solution of the following integral equation:

IKJG φt c. 5.20

By obtainingφηt , the derivatives of the mapping function,Φt can be obtained by

Φt φ ηt

ηt . 5.21

6. Circular Slits

The canonical regionUcconsists ofmslits along the circle|Φ|Rjwherej 1,2, . . . , mand R1, R2, . . . , Rmare unknown real constants. The boundary values of the mapping functionΦ are given by

Φ ηt

Rt eiθt , 6.1

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whereθt represents the boundary correspondence function andRt 1, R2, . . . , Rm . By using the same reasoning as inSection 4, we get

Φ ηjt

sign

θt Rjt i T

ηjt Φ ηjt Φ

ηjt , 6.2

ηt Φ ηt Φ

ηt iθt . 6.3

The mapping functionΦz can be uniquely determined by assumingΦβ 0,Φ∞ ∞ andΦ∞ 1. Thus, the mapping functionΦcan be expressed as12

Φz zβ

eFz . 6.4

By taking logarithm on both sides of6.4 , we obtain F

ηt

lnRt iθ−log

ηtβ

. 6.5

Hence,6.5 satisfies boundary values inTheorem 2.1withAt 1,

ht lnR1,lnR2, . . . ,lnRm , γt −lnηtβ. 6.6

By obtaininghj, the values ofRjcan be obtained by

Rjehj. 6.7

By differentiating6.5 and comparing with6.3 yields

iθt F ηt

ηt ηt

ηtβ. 6.8

In view oft ,ft Fηt andgt 1/ηtβ wherefz is analytic inΩand gz is analytic inΩ, we rewrite6.8 as

Af ηt

iθtAg ηt

. 6.9

LetAgt ψiϕ. Then by18, Theorems 2c and 2d , we obtain IN

θtϕt

Mψt , 6.10

IN ϕt Mψt . 6.11

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Subtracting6.11 from6.10 , we get

IN θt 2ϕt . 6.12

Since the images of the curveΓ1,Γ2, . . . ,Γmare slits, we haveθj2πθj0 0. Thus

Jθt 0,0, . . . ,0 . 6.13

Hence the unknown functionθt is the unique solution of the integral equation

INJ θt 2ϕt , 6.14

where

ϕt Im At g

ηt Im

ηt

ηtβ . 6.15

By squaring both sides of6.2 and dividing the result byηtβ 2, we obtain Φ

ηt 2

ηtβ2Rt 2 ηtβ2T

ηt 2 Φ ηt 2

Φ

ηt 2. 6.16 Upon comparing 6.16 with 3.2 leads to a choice of Pηt Φηt 2/ηtβ 2, P∞ 1,Dηt Φηt ,D∞ 1,ctRt 2/ηtβ2 . Hence,

φt Φ ηt

ηt 6.17

satisfies the integral equation3.16 with νtRt 2

ηtβ2ηt ηt . 6.18

Numerical evidence shows thatλ−1 is an eigenvalue ofKs, t of multiplicitym, thus one needs to addmconditions. SinceΦz is assumed to be single-valued, it is also required that the unknown mapping functionΦz satisfies4

Jj

φt dt

Γj

Φ η

0, j1,2, . . . , m, 6.19

that is,

Jφ0. 6.20

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Then,φt is the unique solution of the integral equation

IKJ φt νt . 6.21

By obtainingφηt , the derivatives of the mapping function,Φt can be obtained by Φt φ

ηt

ηt . 6.22

7. Radial Slits

The canonical regionUrconsists ofmslits alongmsegments of the rays with argΦ θj, j 1,2, . . . , m. Then, the boundary values of the mapping functionΦare given by

Φ ηt

rt eiθt eRt eiθt , 7.1 where the boundary correspondence functionθt θ1, θ2, . . . , θm now becomes real con- stant function andRt is an unknown function. By taking logarithmic derivative on7.1 , we obtain

ηt Φ ηt Φ

ηt Rt . 7.2

It can be shown that the mapping functionΦz can be determined using Φ

ηt

ηt Φ ηt

Rt . 7.3

The mapping functionΦz can be uniquely determined by assumingΦβ 0,Φ∞ ∞ andΦ∞ 1. Thus, the mapping functionΦz can be expressed as12

Φz zβ

eiFz . 7.4

By taking logarithm on both sides of7.4 and multiplying the result by−i, we obtain F

ηt

θ−iRt ilog

ηtβ

. 7.5

Hence,7.5 satisfies boundary values inTheorem 2.1withAt 1, ht θ1, θ2, . . . , θm , γt −Arg

ηtβ

. 7.6

By obtaininght , one can obtain the values ofθt by

θj hj forj 1,2, . . . , m. 7.7

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Then, by differentiating7.5 and comparing with7.2 yields

iRtF ηt

ηt i ηt

ηtβ. 7.8

In view ofA ηt ,ft Fηt andgt i/ηtβ wherefz is analytic inΩand gz is analytic inΩ, we rewrite7.8 as

Af ηt

iRtAg ηt

. 7.9

LetAgt ψiϕ. Then by18, Theorems 2c and 2d , we obtain IN

ϕtRt

Mψt ,

IN ϕt Mψt . 7.10

Adding these equations, we get

IN Rt 2ϕt . 7.11

Since the images of the curveΓ1,Γ2, . . . ,Γmare slits, we haveRj2πRj0 0. Therefore JRt 0,0, . . . ,0 . 7.12

Hence, the unknown functionRt is the unique solution of the integral equation

INJ Rt 2ϕt , 7.13

where

ϕt Im At g

ηt Im

iηt

ηtβ . 7.14

The boundary relationship7.3 can be rewritten as Φ

ηt

±eiθjT

ηt Φ

ηt . 7.15 Squaring both sides of7.15 yields

Φ ηt

e2iθjT ηt 2

Φ ηt

. 7.16

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Upon comparing 7.16 with 3.1 leads to a choice ofPηt 1, P∞ 1, Dηt Φηt ,D∞ 1,ct ei2θj. Hence,

φt Φ ηt

ηt 7.17

satisfies the integral equation3.16 with

νt e2iθjt ηt ηt . 7.18

Numerical evidence shows thatλ −1 is an eigenvalue ofKs, t of multiplicitym, which suggests one needs to addmconditions. SinceΦz is assumed to be single-valued, hence it is also required that the unknown mapping functionΦz satisfies4

Jj

φt dt

Γj

Φ η

0, j1,2, . . . , m, 7.19

that is,

Jφ0. 7.20

Then,φt is the solution of the following integral equation

IKJ φt νt . 7.21

By obtainingφηt , the derivatives of the mapping functionΦt can be found using

Φt φ ηt

ηt . 7.22

8. Parallel Slits

The canonical regionUpconsists of amparallel straight slits on thew-plane. LetBeiπ/2−θ , then the boundary values of the mapping functionΦare given by

BΦ ηt

Rt iδt , 8.1

where θ is the angle of intersection between the lines ReBΦ Rj and the real axis.

Rt R1t , R2t , . . . , RMt is a piecewise real constant function andδt is an unknown function. It can be shown that8.1 can be written as

BΦ ηt

ηt iδt . 8.2

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The mapping function Φz can be uniquely determined by assuming Φ∞ ∞ and limz→ ∞Φzz0. Thus, the mapping functionΦcan be expressed as12

Φz zBFz , 8.3

whereFz is an analytic function withF∞ 0. By multiplying both sides of8.3 withB, we obtain

F ηt

BΦ ηt

Bηt . 8.4

Hence,8.4 satisfies the boundary values inTheorem 2.1withAt 1,

ht R1, R2, . . . , Rm γtBηt . 8.5 Differentiating8.4 and comparing the result with8.2 yield

iδt t ηt F ηt

. 8.6

In view ofA ηt ,ft Fηt andgt B, wherefz is analytic inΩ andgz is analytic inΩ, we rewrite8.6 as

Af ηt

iδtAg ηt

. 8.7

AssumingAgt ψiϕ, then by18, Theorems 2c and 2d , we obtain IN

δtϕt

Mψt ,

IN ϕt Mψt . 8.8

These two equations yields

IN δt 2ϕt . 8.9

Note that, the images of the curvesΓ1,Γ2, . . . ,Γmare slits, so we haveδj2πδj0 0, which implies

Jδt 0,0, . . . ,0 . 8.10

Hence, the unknown functionδt is the unique solution of the integral equation

INJ δt 2ϕt , 8.11

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where

ϕt Im At g

ηt Im!

ηt B"

. 8.12

From8.1 , we introduce an analytic functionϑηt such that

ϑ ηt

eFz eBηt eRt iδt , 8.13

whereϑ∞ 1. By differentiating8.13 with respect tot, we obtain

ϑ ηt

ηt

iδtt ϑ

ηt

. 8.14

Letσt be an analytic function such that it has the following representation

σ ηt

ϑ ηt

ηt

, 8.15

where σB. From 8.13 –8.15 it can be shown that, the functionϑηt can be re- written as

ϑ ηt

eRjeReBηt signδt

i T

ηt σ ηt σ

ηt . 8.16 By squaring both sides of8.16 , the signδt is eliminated, that is,

ϑ ηt 2

e2Rje−2 ReBηt T

ηt 2 σ ηt 2

σηt 2. 8.17

Comparing 8.17 with 3.2 leads to a choice of Pz ϑz 2, P∞ 1, Dz σz , DB,cte2Rje−2 ReBηt . Hence,

φt σ ηt

ηt 8.18

satisfies the integral equation3.16 with

νte2Rje−2 ReBηt ηt BBηt . 8.19

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Numerical evidence shows thatλ −1 is an eigenvalue ofKs, t of multiplicitym, which suggests one needs to addmconditions. Sinceejt ϑηjt |2π0 0, hence we can havem additional conditions for the integral equation above as in the following:

Jj

d dt

ejt ϑj ηjt

dt0, 2π

0

ejt ϑj

ηjt

ηjt

ηt dt0, 2π

0

ejt σ

ηjt

ηt dt0, 2π

0

ejt φ ηjt

dt0, q1,2, . . . , m.

8.20

We define Fredholm operator L as

Lμs

Jj

ejt μt dt. 8.21

Then,φt is the solution of the following integral equation:

IKL φt νt . 8.22

Hence, by obtainingφηt , the functionσt can be found by

σt φ ηt

ηt . 8.23

This allows the value for ϑηt to be calculated from 8.16 , which in turn allows the boundary values for the mapping functionΦηt to be calculated by

Φ ηt

ηt Blogϑ ηt

. 8.24

9. Numerical Examples

Since the boundaries Γj are parameterized by ηt which are 2π-periodic functions, the reliable method to solve the integral equations are by means of Nystr ¨om method with trapezoidal rule21. Each boundary will be discretized bynnumber of equidistant points.

The resulting linear systems are then solved by using Gaussian elimination. For numerical examples, we choose regions with connectivities one, two, three and four. For the region

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Table 1: Error norm wjwj forExample 9.1.

n Uc Ur Up,π/3

32 6.2×10−12 4.6×10−14 8.8×10−16

64 9.1×10−14 9.6×10−15

with connectivity one, we compare our result with the analytic solution given in12. All the computations were done by using MATLAB R2008a software.

Example 9.1. Consider an unbounded regionΩbounded by a unit circle

Γ1t e−it, 0≤t≤2π . 9.1

We choose the special pointβ2.51.5i. The exact mapping function forUc, Ur, andUpare given respectively by12

wczβ βz 1−βz,

wr zβzβ βz ,

wp z e2iθ z .

9.2

For this example, we compare the error for each boundary value between our method and the exact mapping function. SeeTable 1for Error Norm of||wjwj||.

Example 9.2. Consider an unbounded regionΩbounded by a circle and an ellipse Γ1t 2ie−it, 0≤t≤2π ,

Γ2t −2cost−2i sint, 0≤t≤2π . 9.3

Figure 2shows the region and its five canonical images by using our proposed method.

Example 9.3. Consider an unbounded regionΩbounded by 3 circles Γ1t 2e−it, 0≤t≤2π ,

Γ2t −1i√

30.5e−it, 0≤t≤2π , Γ3t −1−i√

31.5e−it, 0≤t≤2π .

9.4

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−5 −4 −3 −2 −1 0 1 2 3 4

−4

−3

−2

−1 0 1 2 3 4

−6 −5 −4 −3 −2 −1 0 1 2

−4

−3

−2

−1 0 1 2

−1 0 0.5 1

−1

−0.8

−0.6

−0.4

−0.2 0 0.2 0.4 0.6 0.8 1

−4 −3 −2 −1 0 1 2 3 4

−3

−2

−1 0 1 2 3

−6 −4 −2 0 2 4

−5

−4

−3

−2

−1 0 1 2 3 4 5

−4 −3 −2 −1 0 1 2 3

−3

−2

−1 0 1 2 3

−0.5

Figure 2: The original regionΩand its canonical images withθpπ/3 for parallel slits.

This example has also been considered in6,12.Figure 3shows the regions and its five canonical images by using our proposed method. SeeTable 3for numerical comparison between our parameter values see Table 2 those in 12. Note that our method has considered exterior unit disk with slits as a canonical region while12has considered interior

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−5 0 5

−4

−3

−2

−1 0 1 2 3

−5 −4 −3 −2 −1 0 1 2 3

−3

−2

−1 0 1 2 3

−1 −0.5 0 0.5 1

−1

−0.8

−0.6

−0.4

−0.2 0 0.2 0.4 0.6 0.8 1

−4 −3 −2 −1 0 1 2 3 4 5

−3

−2

−1 0 1 2 3

−4 −3 −2 −1 0 1 2 3 4 5

−6

−5

−4

−3

−2

−1 0 1 2

−6 −4 −2 0 2 4 6

−6

−5

−4

−3

−2

−1 0 1 2 3 4

Figure 3: The original regionΩand its canonical images withθpπ/2 for parallel slits.

unit disk with slits. Thus, in computing the error forUd, we need to change the values for Ud to 1/|Φz |. See Table 4for Error Norm of max1≤j≤3||wjwj||. We also compared the condition number of our linear system for eachnwith6,12, see Figures4and5. The results show that for our integral equations for findingΦz that is,4.20 ,5.20 ,6.21 ,7.21 and 8.22 , the condition numbers are almost constant except for5.20 . This is because the kernel

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Table 2: The values for approximated parameters inExample 9.3withn256.

j RjUd RjUa RjUc θjUr RjUp,π/2

1 1.0000000000 1.0000000000 2.6958524041 −0.23582974094 1.32203173492 2 2.9672620504 0.3515929850 2.9121788457 2.24673051228 −0.78705294688 3 2.7249636495 0.1792099292 2.2653736950 −2.00502589294 −0.69725704737

Table 3: Error norm max1≤j≤3 RjRj of our method with12forExample 9.3.

n Ud Ua Uc Ur Up,π/2

32 2.7×10−11 3.4×10−11 2.9×10−01 1.6×10−01 2.0×10−10 64 5.6×10−17 1.1×10−16 4.4×10−05 2.0×10−05 2.2×10−16 128 7.8×1016 4.7×1016 2.2×1009 4.1×1010 8.9×1016 256 1.6×10−15 9.99×10−16 3.8×10−12 5.2×10−13 1.3×10−15

Table 4: Error norm max1≤j≤3 wjwj of our method with12forExample 9.3.

n Ud Ua Uc Ur Up,π/2

32 1.1×10−07 1.1×10−07 0.15 0.16 1.5×10−06

64 6.1×10−14 2.9×10−14 6.2×10−05 2.0×10−05 1.1×10−13 128 7.5×10−14 2.1×10−14 2.2×10−09 4.2×10−10 4.4×10−12 256 2.2×10−13 4.7×10−13 3.3×10−12 4.1×10−12 9.5×10−12

102 101

102 103

n Ud

Ua

Uc

Ur

Up

Condition number

Figure 4: Condition numbers of the matrices for our method forUd, Ua, Uc, UrandUp.

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102 102

104 106 108

n G.N.K.

Adj. G.N.K

C.S. circular C.S. radial

Condition number

Figure 5: Condition number of the matrices for generalized Neumann kernelG.N.K , adjoint generalized Neumann kernelAdj.G. N. K , charge simulation for circular slitsC.S. circular and charge simulation for radial slitsC.S. radial .

involvesθt , which varies with the number of collocation points,n. However, this does not have any effect on the accuracy of the method.

Example 9.4. Consider an unbounded regionΩof 4-connectivity with boundaries

Γ1t 32ie−it, 0≤t≤2π , 9.5 Γ2t −32ie−it, 0≤t≤2π , 9.6 Γ3t −3−2i0.7 cost−1.4i sint, 0≤t≤2π , 9.7 Γ4t 3−2i0.7 cost−1.4i sint, 0≤t≤2π . 9.8

Figure 6shows the region and its five canonical images by using our proposed method.

10. Conclusion

In this paper, we have constructed a unified method for numerical conformal mapping of unbounded multiply connected regions onto canonical slit regions. The advantage of this method is that the integral equations are all linear which overcomes the nonlinearity problem encountered in 10. From the numerical experiments, we can conclude that our method works on any finite connectivity with high accuracy. By computing the boundary values of the mapping function, the exterior points will be calculated by means of Cauchy’s integral formula.

Gambar

Figure 1: An unbounded multiply connected region Ω − with connectivity m.
Table 1: Error norm w j − w  j ∞ for Example 9.1.
Figure 2 shows the region and its five canonical images by using our proposed method.
Figure 2: The original region Ω − and its canonical images with θ p  π/3 for parallel slits.
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