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(a) Let P(z) = (z−z1)· · ·(z−zn)∈C[z].Show that P0(z) P(z) = n X j=1 1 z−zj

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Membagikan "(a) Let P(z) = (z−z1)· · ·(z−zn)∈C[z].Show that P0(z) P(z) = n X j=1 1 z−zj "

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(1)

1. HW 5 (1) Exercise 8.3, 8.4

(2) Supplementary Exercise on Page 70, 71, all.

(3) Exercise 8.6, 8.7, 8.10, 8.12,

(4) Supplementary Exercise on Page 75, 76, all.

(5) Let ∆ be the Laplace operator onC ∼=R2 and f be a C2-function on an open set D⊂C.Show that

∆|f(z)|2 = 4|f0(z)|2.

(6) Letf, g, andh be holomorphic functions on a region1 Ω.

(a) Suppose |f(z)|=|g(z)|on Ω.Show that there is c∈Cso that f(z) =cg(z) on Ω.

(b) Suppose that |f(z)|2+|g(z)|2 = 1 on Ω.Show that both f and g are constant functions on Ω.

(c) Suppose that |f(z)|2 +|g(z)|2 = |h(z)|2 on Ω. Show that f, g, h are linearly dependent in Hol(Ω).(The space of holomorphic functions on Ω forms a vector space.)

(7) Letz1,· · · , zn, w1,· · ·, wm be distinct complex numbers.

(a) Let P(z) = (z−z1)· · ·(z−zn)∈C[z].Show that P0(z)

P(z) =

n

X

j=1

1 z−zj

.

Remark: You can not take lnP(z) at this moment yet because ln-function is not defined yet. Here is a hint: Consider

H(z) =P0(z)−

n

X

i=1

P(z) z−zj

. Show thatH(z) is the zero polynomial.

(b) LetDbe a closed disk centered at 0 of radiusRcontainingz1,· · · , znandC be its boundary. Compute

1 2πi

I

C

P0(z) P(z)dz.

(c) A rational function R(z) over C is a quotient of two complex polynomials P(z)/Q(z), i.e. R(z) = P(z)/Q(z) with P(z), Q(z) ∈ C[z]. Suppose that P(z) = (z−z1)· · ·(z−zn) and Q(z) = (z−w1)· · ·(z−wm). Let D be as above and also assume thatDcontainsw1,· · · , wm.Show that

R0(z)

R(z) = P0(z)

P(z) −Q0(z) Q(z) and compute

1 2πi

I

C

R0(z) R(z)dz.

Furthermore, letf(z) be a holomorphic function onD.Show that 1

2πi I

C

f(z)R0(z) R(z)dz =

n

X

i=1

f(zi)−

m

X

j=1

f(wj).

1An open connected set inCis called a region.

1

(2)

2

LetR(z) = (z−11)(z−12)· · ·(z−20)

(z−1)(z−2)· · ·(z−10) .Compute I

C

z2R0(z) R(z)dz.

(d) Let Ω be a region containing all w1,· · ·, wm whose boundary is denoted by

∂Ω = Γ.Show that I

Γ

R(z)dz = 2πi

m

X

i=1

P(zi)

(wi−w1)· · ·(wi−wi−1)(wi−wi+1)· · ·(wi−wn).

(e) Let R(z) = 5z2−z+ 2

z(z+ 1)(z−i).Use residues ofR(z) to find A, B, C such that R(z) = 5z2−z+ 2

z(z+ 1)(z−i) = A z + B

z+ 1+ C z−i. Also compute

I

Γ

R(z)dz and I

Γ

R0(z)

R(z)dz. Here Γ ={z:|z|= 100}.

(f) LetR(z) = 1

z4+ 1.Find all of its poles and their orders. Compute the residues of R at poles. Compute

Z

C

R(z)dz where C is the circle |z|= 2 with positive orientation.

(8) Using the Taylor expansion of 1−cosz atz= 0,we knowz= 0 is a zero of 1−cosz of order 2.Hence the function

f(z) = ez 1−cosz

has pole of order 2 atz= 0.In a deleted neighborhood ofz= 0,we write f(z) = a−2

z2 +a−1

z +a0+a1z+a2z2+· · · . (a) Use the Taylor expansion ofez atz= 0 and of 1−cosz and

ez = (1−cosz) a−2

z2 + a−1

z +a0+a1z+a2z2+· · ·+

to determinea−2, a−1, a0. (b) Compute

I

C

f(z)dz whereC is the unit circle|z|= 1 with positive orientation.

(9) Let P(z) be a complex polynomial of degree n and Q(x) = (z−a)m for m > n.In fact, we can write P(z) = a0+a1(z−a) +· · ·+an(z−a)n. It is very easy to see thatai =P(i)(a)/n!.Then we can write.

P(z)

(z−a)m = a0

(z−a)m + a1

(z−a)m−1 +· · ·+ an (z−a)n−m.

(a) Use this idea to find the expansion of the following rational functionz3+ 3z2+z+ 1 (z−1)5 in the power of (z−1)−1.

(b) Use similar idea (use the Taylor expansion of cosz at π) to find the series expansion of cosz

(z−π)5 in a neighborhood ofπ.

(c) Suppose f1(z), f2(z) are complex polynomials so that g.c.d(f1, f2) = 1, i.e. the greatest common divisor off1 andf2 is 1.Using division algorithm, we can find h1(z), h2(z) so that

f1(z)h1(z) +f2(z)h2(z) = 1.

(3)

3

SupposeF(z) =f1(z)f2(z) andG(z) are complex polynomials. Use this prop- erty and the division algorithm to show that there exist complex polynomials H(z) and g1(z), g2(z) so that

G(z)

F(z) =H(z) + g1(z)

f1(z) +g2(z) f2(z).

For example, ifa6=bthen (z−a)m and (z−b)nare relatively prime (g.c.d = 1).

Then

G(z)

(z−a)m(z−b)n =H(z) + g1(z)

(z−a)m + g2(z) (z−b)n.

Using this idea, we obtain the partial fraction expansion of G(z)/F(z) for a generalG(z)/F(z).An example is given below.

(d) Let g1(z), g2(z) be polynomials so that ((z−1)3 and (z2 + 1)2 are relatively prime.)

f(z) =2z6−4z5+ 5z4−3z3+z2+ 3z

(z−1)3(z2+ 1)2 = g1(z)

(z−1)3 + g2(z) (z2+ 1)2.

Furthermore,z2+ 1 = (z−i)(z+i).There are polynomialsh(z), k(z) so that g2(z)

(z2+ 1)2 = h(z)

(z−i)2 + k(z) (z+i)2. FindA1, A2, A3, B1, B2, C1, C2 so that

g1(z)

(z−1)3 = A1

z−1 + A2

(z−1)2 + A3 (z−1)3 h(z)

(z−i)2 = B1

z−i+ B2 (z−i)2 k(z)

(z+i)2 = C1

z+i+ C2 (z+i)2.

By definition, the residues of f(z) at 1, i,−iare A1, B1, C1 respectively. Com- pute

I

C

f(z)dz where C is the circle|z|= 2.

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