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Experiment (5): conduction on solid materials (temperature dependence of noble metal Resistor )

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Solid state Lab PHYS 485 King Abdulaziz University

Experiment (5): conduction on solid materials (temperature dependence of noble metal Resistor )

Name:โ€ฆโ€ฆโ€ฆ.. ID: โ€ฆโ€ฆโ€ฆ

Day:โ€ฆโ€ฆโ€ฆ

ูŠุฏู„ุงุจู„ุง ุฉุดุฆุงุน.ุฃ

The purpose:

๏€ 

๏€ ๏€  ๏‚ท ๏€ Measuring the Ohmic resistance of a noble metal as a function of temperature at various points.

๏‚ท Determining the temperature coefficient of resistanceฮฒ

.

Theory:

The following equation applies to the resistance of โ€œnormalโ€ metals within the first degree of approximation:

๐‘…

๐œƒ

= ๐‘…

0

(1 + ๐›ฝ๐œƒ) (1)

where

R0= Resistance at 0 ,ฮธ: Temperature in Co R๏ฑ: Resistance at the temperature ๏ฑ0C ,๐›ฝ : is the temperature coefficient of the resistor (resistance change per degree).

In the experiment described here, it will be demonstrated that the functional relationship between ohmic resistance Rฮธ and

temperature ฮธ is linear function, as required by equation 1. The ohmic resistance of a noble metal resistor will be measured at various

temperatures (intervals from +25 to +230) using a Wheatstone bridge circuit, consisting of a noble metal resistor, a resistance box and a measuring bridge.

If the Wheatstone bridge is balanced for the set temperature, i.e. the bridge branch AB is current- free, then R๏ฑ is given by:

๐‘น๐œฝ = (๐’๐Ÿ

๐’๐Ÿ) ๐‘น (๐Ÿ)

(2)

Solid state Lab PHYS 485 King Abdulaziz University

Experiment (5): conduction on solid materials (temperature dependence of noble metal Resistor )

Name:โ€ฆโ€ฆโ€ฆ.. ID: โ€ฆโ€ฆโ€ฆ

Day:โ€ฆโ€ฆโ€ฆ

ูŠุฏู„ุงุจู„ุง ุฉุดุฆุงุน.ุฃ

when a noble metal resistor is used a linear relation is obtained as the temperature rises.the temperature coefficient ฮฒ is determined from the slope of the line:

๐œท =๐’”๐’๐’๐’‘๐’† ๐‘น๐ŸŽ

Result:

๏ฑ

0

C L

1

cm L

2

cm R

๏ฑ

๏— 120

110 100 90 80 70 60 50 40 30 20

1- Plot ๏ฑ vs. R

๏ฑ

and find the slope Slope =

โˆ†๐‘นโˆ†๐œฝ๐œฝ

=

2- Find R

0

= * ุชุงุฏุงุตู„ุง ู†ู… ุนูˆุทู‚ู…ู„ุง ุกุฒุฌู„ุง*

3- Find ฮฒ =

๐’”๐’๐’๐’‘๐’† ๐‘น

๐ŸŽ

=

0

C

-1

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