King Abdul Aziz University Department of Statistics
Assignment 1(SPSS part) (Answer Model) Stat 210 LAB
Term 1, 2015 I. Tahani Baseer
Name:______________________________
ID:_________________________________
Section:_____________________________
Marks Obtained: 7
Please print output sheet separated by questions
The due date Wednesday 12/1/1436 H
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Question#1:
The following information for students in a kindergarten in Jeddah:
Define the previous questions in SPSS and save the file by name “Kindergarten”. (Print variable view)
Solution:
For any error, the mark decrease by 0.25
1. Student Name: □□□□□□□□□□□□□□□□2. Gender: □ Male □ Female
3. Birthday Date of student: □□/□□/□□ [dd.mm.yy]
4. Student level:□ Nursery □ KG1 □ KG2 □ KG3 5. Weight of student: ……… kg
6. Height of student: ……… cm
7. Number of brothers and sisters: ………..
8. Family’s monthly income ……… SR
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Question#2:
From the file car_sales.sav Solve the following questions:
(Hint: In version 22 the file can be obtain from local disk(c) →Program files →IBM → SPSS → Statistics →22 →Samples → English → car_sales.sav )
Find 15% discount of prices of BMW cars (Print Data View)
Recode the variable price to:
1 if price < 20,000 2 if 20,000 ≤ price < 40,000 3 if 40,000 ≤ price < 60,000 4 if price ≥ 60,000
and name the new variable price2 (Print Data View)
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From previous statement (b.) how many cars have prices less than 20,000?
Answer: 55 cars
Describe the variable type (by graph) (Print Graph with interpretation)
OR:
From the bar graph:
The number of automobile cars is 116, while truck cars is 41, which mean that the automobile cars more than the trucks
From the pie graph:
The percentage of automobile cars is 73.89%, while truck cars is 26.11, which mean that the automobile cars more than the trucks
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Find the best central tendency and dispersion measures for variable length (Print Output with interpretation)
Answer: Since there is outliers noted from boxplot, then the best central tendency and dispersion are median = 187.9 and IQR = 18.6
Descriptives
Statistic Std.
Error
Length Mean 187.344 1.0754
95% Confidence Interval for Mean
Lower Bound 185.219 Upper Bound 189.468
5% Trimmed Mean 187.426
Median 187.900
Variance 180.412
Std. Deviation 13.4318
Minimum 149.4
Maximum 224.5
Range 75.1
Interquartile Range 18.6
Skewness -.059 .194
Kurtosis .303 .386
Find the stem and leaf of variable wheelbas, then how many cars have wheelbase between 96 and 99. (Print Graph with interpretation)Answer: 6 + 9 = 15 cars have
wheelbase between 96 and 99Interpretation: there is 4 outliers for cars
have
wheelbase greater than or equal 127, minimum value of wheelbase is 92 and the most cars that have wheelbase 96 and 970.25 0.5
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Test the normality of variable resale (Print Graph with interpretation)Interpretation: From histogram, we note that the distribution of resale is right skeweed, then the resale data not follow normal distribution.
From the following boxplot, obtain median, shape of distribution, third quartile and inter-quartile range (IQR).
Answer:
Median approximately = 54 Third quartile approximately = 61
inter-quartile range (IQR) approximately= 61 - 49 = 12 Shape of distribution is left skeweed.
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Question#3:
Choose the correct answer for the following statements: (Please print this page with your answer)
1. If the skewness of a distribution is 1.56 and its kurtosis is -6.31, then the shape of this distribution is:
a. Flat and right skewed b. Flat and left skewed c. Thin and right skewed d. Thin and left skewed
2. from the following boxplots:
a. The median of engine size of automobile is less than the median of engine size of truck b. The engine size of automobile has outlier
c. The range of engine size of truck less than the range of engine size of automobile d. All of above
3. Suppose the following data: 33 26 38 37 37 33 24 29 31 39 then:
a. There is no mode b. The data is unimodal c. The data is bimodal d. The data is multimodal
4. Which central tendency measure(s) can be use in qualitative data?
a. Mean, median and mode b. Mode and median c. Only mode d. None of above
Best Wishes I. Tahani Baseer 0.25
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