HOP LY HOA P H A N I J N G KET CAU LOI ClJNG NHA NHIEU TANG CHIU TAI TRONG OONG DAT
ABSTRACT
The bambo can stand in front of the Storms without falling down, because of its elastic and durability. Learning about working state of the core and seeking to raise its stiffness by effect on side of bamboo are the problems that we must research.
PGS. TS Nguyen Van Hung Th.SNinhSijrcThuan TrUdng dai hoc xay difng
1 .Oat van 3e
May nam gan day, nha nhieu tang d nudc ta phat trien manh, sd tang va chieu cao ngay cang Idn hPn, hinh dang ngay cang phUe tap. IVIat khae khdng chi trong eae thanh phd Idn ma ca trong cac thanh phd vUa va nhd, nha nhieu tang eung dupc xay dung manh me. Trong nha nhieu tang Idi cUng ddng vai trd quan trpng vi nd vUa chiu tai trpng ngang va tai trpng dQng. Khi chju tai trpng ngang Idi cQng khdng chi ehju udn ma edn chiu xoan. Do dd tim hieu trang thai lam viec thQc cua Idi cUng va tim each nang eao dp cUng eua nd va cua ca nha khi chiu tai trpng ngang la van de can phai nghien cUu
Khi Idi cUng chiu xoan mat eat ngang bi venh ngoai mat phang va chu vi mat cat ngang bi thay ddi hinh dang (trU trUdng
Nguyen Van Hiing Ninh DilTc Thuan
hpp tiet dien hinh trdn). Neu chung ta ngan can dupc viec nay thi kha nang chiu xoan eua cau kien 6iJac nang cao. Chung ta gan san vao Idi cUng hoac tao ra vanh cQng thi hieu qua chdng xoan se tang len.
Trong bai bao [1] da phat hien ra hieu Ung dot tre va dac biet tiet dien ngang eua cay tre la hinh trdn nen kha nang chiu xoan cang eao. Mac du cd chieu cao tQpng ddi Idn nhQng chiu dQpc nhQng tran gid bao rat Idn ma khdng gay bdi vi cay tre cd dp dan hdi, dp ben rat eao va eau true dot tre dQpc chia thanh cac doan vdi cac ddt cd dp cQng nhat dinh.
"Hieu Qng ddt tre" cua Idi cQng chinh la SLf ket hpp giQa san va Idi cUng tai tUng tang trong nha nhieu tang nham hpp ly hda phan Qng ket cau Idi cQng nha nhieu tang chiu tai trpng ddng dat.
J,
Bien Loi
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GiCra 1 GiCra 2
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Hinh 1: Mat bang ket cau nha co tong chieu cao tang H=78 m
7 2 ^'i^niiiVMl 8.2010
Bang 1: Bang chpn sd lieu tinh toan trong eae edng trinh nha nhieu tang
STT
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
NhipL(m)
6.5
6.5
6.5
6.5
sd nhip
3
3
3
3
Be rdng B(m)
19.5
19.5
19.5
19.5
Ty sd H/B
4
4
4
4
Chieu cao H (m)
78
78
78
78
Sd tang va chieu cao tang
26 tang cao 3 m 26 tang cao 3 m 26 tang eao 3 m 26 tang cao 3 m 24 tang cao 3.25 m 24 tang cao 3.25 m 24 tang cao 3.25 m 24 tang eao 3.25 m 22 tang eao 3.55 m 22 tang eao 3.55 m 22 tang cao 3.55 m 22 tang cao 3.55 m 20 tang cao 3.9 m 20 tang eao 3.9 m 20 tang cao 3.9 m 20 tang cao 3.9 m
Chieu day san (m)
0.24 0.22 0.2 0.18 0.24 0.22 0.2 0.18 0.24 0.22 0.2 0.18 0.24 0.22 0.2 0.18
0 0,01 0,02 0,03 0,04 0,05 0,06 Chuyen vj ngang (m)
- * - 3 6 x 3 (5=0.24) - " - 26x3 (S=0.221 - 1 1 - 26x3 (5=0.22) 2 6 K 3 15-0.16)
^— 24x3.25 (5=0.24) -*- 24x3.25 15=0.22)
— 24x3.2515-0.20)
^ 2 4 x 3 . 2 5 ( 5 = 0 . 1 8 ) 22x3.55 (5=0.24) -^~ 22x3.55 (5=0.22) -o- 22x3.55 (5=0.20) - ^ - 2 2 x 3 . 5 5 ( 5 = 0 . 1 8 ) 20x3.9(5=0.24)
— 20x3.9 15=0.22) - ° - 20x3.9 15=0.20) 20x3.915=0.18)
20
o, 15
10
5
-IE-OS 0
J
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g^^-^:—J^ "
J ^ ; ^ ^ S
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^ E ^ f ^
lE-05 2E-05 3E-05 4E-05 5E-05 6E-05 7E -05 Chuyen Vl xoay (rad)
- * - 26x3 (S-0.24) -»~ 26x3 (S=0.22) -!^ 26x3 (5=0.20) 26x3(5=0.18) 24x3.25(5=0.24) - ^ 24x3.25 (5=0.221 24x3.25 (5=0.20)
^ 24x3.25(5=0.18)
• 22x3.55 1S=0.24) - - 2 2 x 3 . 5 5 ( 5 = 0 . 2 2 ) - ^ 22x3 55 (5=0.20) - t - 2 2 x 3 . 5 5 ( 5 - 0 . 1 8 ) 20x3.9 (5=0.24)
— 20x3.9(5=0.22) -°--20x3.9(5=0.20) - - 20x3.9(5=0.18)
Hinh 2: Bieu do chuyen vi ngang doi vdi cac nha co tong chieu cao H=78 m Hinh 3: Bieu do chuyen vi xoay doi vai cac nha co tdng chieu cao H=78 m
• 26»(3 (S=0.22)
'
2,35
2.30
2,25-
2,20
2,15 J
2,10
2,00
Ji •
• •
1 •
I •
I
I — n 26x3 (S^O.20)
J"
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il rl •
ill 11 H
III
— 1 :J26X3(S=0.18) 1 ^ i H •24x3.25(5=0.24) L ^ ^ ^ ^ l n 24x3.25
^ ^ ^ ^ ^ 1 •
^ ^ ^ ^ ^ 1 • 22x355
^ ^ ^ ^ ^ H G 22x3.55
^^^^^1
• 20x3.9)5=0,18) C h u k y T l ( s )
Hinh 4: Bieu do chu ky dao dong Tl doi voi cac nha co tong chieu cao H=78 m
2.Tinh toan khao sat cToi vci nha co tong chieu cao 78m Nha vay, hieu utig ddt tre da tao kha nang ehju tai trpng ngang cua Idi CLfng tang len dang ke va sU lien ket giCfa san va Idi eung chinh la "ddt tre". Chung tdi se tim hieu thdng qua khao sat dudi day de tim ra hieu ufTig ddt tre tdi Uu cung nhU sii phdi hpp lam viec khdng gian cua Idi cCmg, cdt, san.
Xet 16 nha ed sd lieu nha bang 1, cd mat bang nhu hinh ve 1 vdi
ChukyT2(s)
a 26x3 (S=024)
• 26x3 (5^0.22) a 26x3 (S=0.20) 0 26x3(5=0.181
• 2 4 x 3 . 2 5 ( 5 = 0 . 2 4 ) D 2 4 x 3 2 5 ( 5 = 0 2 2 )
• 2 4 x 3 . 2 5 ( 5 = 0 2 0 ) 0 2 4 x 3 2 5 ( 5 = 0 . 1 8 )
• 2 2 x 3 . 5 5 ( 5 = 0 . 2 4 )
• 2 2 x 3 . 5 5 ( 5 = 0 2 2 ) D 2 2 x 3 . 5 5 ( 5 = 0 20) 0 2 2 x 3 . 5 5 ( 5 = 0 - 1 8 )
• 2 0 x 3 . 9 (5=0.24)
• 20x3.9 (5=022)
• 20x3.9(5=0.20)
• 20x3,9(5=0.18)
Hlnh 5: Bieu do chu ky dao dpng T2 doi vdi cac nha co tong chieu cao H=78 m
cdt tiet dien 1100x1100 mm ddi vdi cac cdt d 1/3 sd tang d dadi, cdt 1000x1000 mm ddi vdi cac cdt d 1/3 sd tang d giiJa, C(Dt 900x900 mm ddi vdi cac cdt d 1/3 sd tang d tren cijng, Idi cutig day 30mm va cd Id cda 2150x1800mm, dam bien ed tiet dien 300x800 mm
Tinh tai: gdm trpng lupng ban than ket cau cdt dam, san va tinh tai phan bd deu tren mat san: 200 kg/ml Hoat tai san: 240 kg/m^
Tai trpng ngang tinh vdi tai trpng diDng dat bang phuong phap
8.201 O^E^Rin^l 7 3
ChukyT3(5)
• 26x3 (S=0.24)
• 26x3 (S=0,22) :: 26x3 (5=0.20) Q 26x3 (5=0.18)
• 24x3.25 (5=0.24) D 24x3.25 (5=0.22)
• 24x3.25 (5=0.20) D 24x3.25(5=0.18)
• 22x3-55 (5=0.24)
• 22x3.55 (5=0.22) D 22x3.55 (5=0.20) 0 22x3.55(5=0.18)
• 2 0 x 3 . 9 ( 5 = 0 . 2 4 )
• 2 0 x 3 . 9 ( 5 = 0 . 2 2 )
• 2 0 x 3 . 9 1 5 = 0 , 2 0 )
• 2 0 x 3 , 9 ( 5 = 0 . 1 8 )
Hinh 6:Bieu do chu ky dao dpng T3 doi vdi cac nha co tong chieu cao H=78 n^i
- 1 . 5 0 -LOO ^0,.50 0 . 0 0 0 . 5 0 i.OO Bii!'u dd mO men M22 iTm)
- • - Di<;mbLon(S=0-24) - • - D i e m g i i h i 1 (S=0.24) - i ^ D i C m g i i i j 2 ( 5 = 0 . 2 4 )
— ^ D i e m ^iui litin k t l vui loi t i m g (5=0.24)
— D i t m h i i ' i i ( S = 0 . : 2 ) - * ~ Dicm piifii 1 (5=0.22)
DiOmgiii'a 2 (5=0.22)
— — DiOm s i n tii:ii U-i vai liii tuiij; (S=0.22) D i C m b i e n ( S = ( l . 2 0 i
- ^ D i i i m g i a u 1 (S=0.20) - o - D i e m giOu 2 ( 5 = 0 . 2 0 )
- i i - DiCm -Jm liOn kei voi ir.i tiing (S=0.20>
— Di<;mbii;n(S=0.!8)
^ D i i ' m g i B a 1 (S=0 18) - o — D i < : m g i O . , 2 i S = n . 1 f i )
Dit'ni siiri lien kOi vm If.i t i m g (S=(I.IK)
Hmh 7:Bieu do mo men M22 ddi vdi nha 26 tang {moi tang cao 3m)
-1,00 -0,50 0,00 0.50 1.00 Blew JiMiidriH-n M:2(Tm]
--*- DiOmbiOn (5=0.24) - • - Diem giOii 1 (S=0.24)
—cr— D i i m giua 2 (5=0.24) Diem san lit-n kei \ m I6i cijng (5=0.24)
— — D i e m bien (S=0.22) - ^ Diem iiiira I (5=0.22)
^ Diem yiua 2 ( 5 = 0 . 2 2 )
-— Diem -..in lien ket vcri \(>i cimg (S=lV22i Diim bien (5=0.20)
--— DiC-mgiiJa 1 (5=0.20) -c^- Diem glim 2 (S=0.20)
—a- DiCm s i n lien kei vai loi ciing (S=0.20l
^ D i e m h i e n ( S = 0 , ! S )
— D i e m siua 1 (5=0.18)
" t ^ Diiim giua 2 (5=0.1H) Diem s i n lien kei viTi ldi ciing (5=0.1 Ni
Hinh 9:Bieu do mo men M22 doi vdi nha 24 tang (moi tang cao 3.25m) pho phan ufng theo phaong X theo tieu chuan TCXDVN 375: 2006.
Nen mong cpc khoan nhoi be tong cot thep tiia tren nen dat loai B (cat, cuoi soi rat chat), gia toe dinh dat nen tham chieu tai khu vUc Ha Noi = 0.1081 g.To hop tai trong theo tieu chuan TCXD 198:1997.
Tien hanh khao sat anh hacfng sU ket hop cua san va loi cuTig, sa thay doi chieu cao tang thong qua chuyen vj ngang, chuyen vi xoay, cac chu ky dao dong co ban va khao sat npi lac san tai diem bien, diem giCra 1,diem giCfa 2, diem san lien ket vdi loi ciTng thong qua momen M11,M22
- SO" dung chaong trinh tfnh toan ETAB 9.20 de tinh toan vdi cac he
ll"-
n
-H.OO -6.00 -4.00 -2.00 0,00 2.00 -i.fK) Bieu il6 mo men M i l (Tin)
—•— D i e m bien (5=0.24) - » - D i e m g m a U S = 0 . 2 4 ) -fi— D i e m giira 2 (5=0.241
D i e m s i n iien kei \ . ' . loi eung (S
^ D i i i m bien (5=0.22) - • — D i t ^ m giim 1 (S=0.22) - ^ D i e m giua 2 (5=0.22)
D i e m s i n lien kCt v6i loi eung (i Dii^m bien (5=0.20)
— - D i e m giihi I (5=0.20) - o ~ D i e m giua 2 (5=0.20) - i . — D i e m s i n lien kCl viii I6i tiing {'.
— D i e m bien (S=0.18)
— D i e m giua 1 ( S = 0 . I 8 ) - o - D i e m g i 0 a 2 ( S = 0 . 1 K )
DjOm .sin lien kei vcri loi eung (!
Hinh 8:Bieu do mo men Ml 1 doi vai nha 26 tang (moi tang cao 3m)
•-f^
I'f
1 r 1 r[;: :
1 1 l"
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1 •' 1
I ill III t III III
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t * 1111 ll
-X.{)0 - 6 . 0 0 . 4 , 0 0 -2.0O 0 , 0 0 2 , 0 0 4 , 0 0 Bieiuli'^ m o men M i l (Tm)
- . - Diiim bien (S=0 24) - • - D J i m giirj I (S=0.24) - c - Diam giQa 2 (S=0,24)
Diii'm san lifn kci vdi loi t i m g 1S=0.14)
— ^ D i e m bien (S=0.22) - • — Djiim giiia I (S^0,22)
D i e m giila 2 (S=0.22) D i e m siin lien l(tfi v('n 15i i-ijmg (S=0 22) D i e m bien (S=0.20(
- : — D i e m g i i i a 1 lS=0.20) - ^ - D i e m giQa 2 (S=0-20l
~i-~ DiL'm Sim lien ke) \6\ lui eOng (S=0,20) D i e m bien ( S = 0 . I 8 I
. ^ Diem giua I (S=0.1«)
^ ^ D i e m g i Q a 2 ) S = 0 . I H |
DiOm siin lien kei vcri Itii eihig lS=0.18)
Hinh 10:Bieu do md men Mil doi vai nha 24 tang (moi tang cao 3.25m) l<et cau nha tren ta co l<et qua the hien trong bang tinh sau:
a, Ket qua tinh toan chuyen vj ngang, chuyen vi xoay, chu ky dao dpng CO ban v6i cac nha c6 tong chieu cao H = 78 m.
b, Ket qua npi lUc cua san d vung xung quanh loi cOfng.
3. Nhan xet
- Ve quy luat thay doi chuyen vi ngang, chuyen vi xoay, chu ky dao dpng cd ban doi vdi cac cong trinh co tong chieu cao 78m ufng vdi chieu day san thay doi la tuong doi giong nhau.
- Ve gia tri cua dai luong nghien cOu, vol cac cong trinh co so luong tang va chieu cao tang giong nhau, khi chieu day san tang len thi gia tri chuyen vi ngang 6 dinh giam dan va chu ky dao dpng Tl giam dan.
NhUvay v6i cung 1 cong trinh co chieu cao tang giong nhau, taco the chpn chieu day san theo xu hudng co lpi cho tinh khang chan cua cong trinh.
- Su thay doi chieu cao tang va chieu day san la yeu to anh hudng nhieu nhat den quy luat thay doi cOng nhiJ gia tri cua cac dai lupng nghien curu. Tren hinh 2 cho thay vdi 16 cong trinh 3 nhip L=6.5m vdi tong chieu cao cong trinh la 78m khi thay doi chieu day san, chieu cao tang, neu chpn chuyen vi dinh cho phep la 0.545 m thi cd 8 cong trinh dap ufng dupc dp cufng cho phep la cong trinh 26 tang (moi tang cao 3m va chieu day san 0.24m), cong trinh 24 tang (moi tang cao 3.25m vdi chieu day san 0.24m, 0.22m), cong trinh 22 tang (moi tang cao 3.55m vdi chieu day san 0.24m, 0.22m), cong trinh 20 tang (moi tang cao 3.9m va chieu day san 024m, 0.22m, 0.2m). Tif dd cd the chpn ra cong trinh dap ufng dufpc chuyen vj nho nhat trong cac cong trinh tren.
- Nhu vay cd the dung chieu day san va chieu cao tang cua cong
74iB«ejni[i^i 8.2010
- • — D i e m bien (S=0.24) - • — D i e m giua I (S=0.24l - o — D i e m giirj 2 (S=0 241
— Diem bin lien kit MV !•
— D i e m bien iS=0.22)
—•— D i e m giiia I (S=0.22(
- Dier •(S=0.2
D i e m san liCn fce[ vtii loi cung i S=0.2 D i ^ m b i e n ( S = 0 , 2 0 )
— ^ Die'm giua I (S=0.20) - o — D i e m giSa 2 <S=0.20)
- D i e n l i e :(S=0.2
-8.(K) -6.00 -4.00 -2.00 0.00 2.00 4.00 Bie'u do m6 men M11 (Tm)
Diem bien (S=0.IS)
— ^ D i i i m g i u a 1 ( S = 0 . I 8 ) - * — D i e m giua 2 (S=0.1S | - - Diem bim lien ki ctiioi
Hinhn:Bieud6m6menM22d6ivdi nha22tang(m6i tangcao3.55m)
- 1 . 5 0 - 1 . 0 0 - 0 . 5 0 0 . 0 0 0.5 B i e u J , > m i > m e n M 2 2 i T m i
- • - Diem bien (S=0.24) - • — Dii-m giua 1 (S=0.24) - l l — Diem giua 2 (S=0 24)
D i e m - i n lien kei v m f o i c
— D i e m bien (&=0.22) - • — Die'm giira I (S=0.22)
D i e m giOa 2 (5=0.22) Diem s i n l i t n fciTi vdi loi c
Di<*mbien(S=0.20)
— . ^ Diiim giQa I (S=0.20) -Tl— Die'm giua 2 (5=0.20) - i r - D i e m san liCn kei \<3i loi c
— D i e m bien iS=0.IK)
— D i e m g i i h i I | S = 0 . I « ) - ° — D i e m g i u a 2 l S = 0 . I S )
D i e m s;m lien kci ven loi c
ff t P
.1 L
• ' I 1 1
M l [
u i
4'^ I
vv.i
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rt IJ i 11 «i i |
I II 111
1 '' if
I iii 111 1 «i « I % 1
1 J j
1 i lit ft H t l
fs ' I'l
SI 1 «I
t > I'l
- t - Diem bien (S=0.24) - • - D i e m giua I iS=0.24i
—•^ D i e m g i u - j 2 i S = 0 . 2 4 )
—— Diem iun lien kei V.T, j
- Dier (S=0.2
-S.OO - 6 , 0 0 - 4 , 0 0 - 3 , 0 0 0 . 0 0 2 . 0 0 4 . 0 0 Bieu d r t n i u men M i l (Tm)
D i e m san lien ket vm i Die'm b i e n ( S ^ I . 2 0 i
— — D i e m giua 1 [S=0.20) - o — D i e ' m giiia 2 (S=0.20) -cr- Diiim san lien kei VOT I
— Diem bien ( S = 0 . I 8 ) - ^ D i i i m giira I (S=0.1S) - < ! ^ D i e m g i i n 2 ( S = 0 . 1 8 ) Diem san hen kei voi I
Hinh 12;Bieu do mo men Ml 1 doi vdi nha 22 tang {moi tang cao 3.55m)
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-X.OO .6.00 -4.(1(1 -2.00 0.00 2 00 4.00 BiLiud.. ITU. i n ^ n M l l i T m i
- D i f m h i c n ( S = 0 . 2 4 i
- Diiim giira 1 (S=0.24l - D i e n i u i i r j 2 ( S = 0 24i - Dicin sill lien kOi vui i.M cimg i S = 0 . 2 - Diembic-n(S=(l,22i - Dicmgii"iu I (S=(1.22l - D i e m g i u a 2 ( S = 0 . 2 2 l - Diiim s i n tidn kil-t voi loi Li'mg (S=0,2, - Di(.<m bien (S=0.20)
- Die'm giiia I (S=0.20) - D i e m giira 2 (S=0.201 - D i e m siin lien kSl vdi ldi viing IS=0.2I - D i e m b i e n ( S = O . I 8 )
- D i e m g i t t a I (S=O.IK) - D i e m g i i r a 2 ( S = ( l . l J i l - D i e m sitn lien kei vdi ldi cimg (S=0-11
Hinhl3:Bieud6m6menM22d6ivdii nha 20 tang (moi tang cao 3,9m) Hinh14:Bieua6m6menlVll1d6ivdi nha 20 tang (moi tang cao 3,9m)
trinh de dieu khien cac phan uTig cua ket cau chiu lufc dpng dat va bang each tinh toan thuc nghiem cd the chpn ra dUdc chieu day san va chieu cao tang hpp ly cd loi cho tinh khang chan cua ket cau.
-Tai mufc san d tung tang npi lUc tai diem san lien ket vdi Idi cufng Idn hon nhieu so vdi tai diem bien trong cac trudng hpp vdi chieu day san thay doi la 0.18m, 0.2m, 0.22m, 0.24m.£)6i vdi nha 26 tang (moi tang cao 3m) mo men I\/I22 tai iJiem san lien ket vdi Idi cdng Idn hon (Jiem bien tuf 2.33 den 19 lan, md men IVll 1 tai iJiem san lien ket vdi Idi cuTig Idn hon diem bien tC/ 2.52 den 6.23 lan. Doi vdi vdi nha 24 tang (moi tang cao 3.25m) md men M22 tai diem san lien ket vdi loi cufng Idn hpn (Jiem bien tCf 2.23 den 21.2 lan, mo men M i l tai <iiem san lien ket vdi Idi cuTig Idn hon diem bien tCf 2.45 den 6.01 lan. Doi vdi nha 22 tang (moi tang cao 3.55 m) mo men IV)22 tai (Jiem san lien ket vdi Idi cufng l<Jn hon diem bien tuf2.15 den 20.8 lan, mdmen M i l tai diem san lien ket vdi Idi cufng Idn hdn diem bien tCf 2.37 den 5.89 lan. Doi vdi nha 20 tang (moi tang cao 3.9m) mo men IV122 tai diem san lien ket vdi loi cung Idn hon (Jiem bien tif 2.05 den 18.5 lan, mo men M l 1 tai (Jiem san lien ket vdi loi cung Idn hon diem bien tij'2.3 den 5.65 lan.
4. Ket luan
- Khi san lam viec dong thdi vdi ldi cdng thi dp cung tong the cua cdng trinh se tang len. Dp cung cua san cd anh hudng den chuyen vi xoay chuyen vi dinh cua cdng trinh, khi cd xet den san se lam giam chuyen vi xoay va chuyen vi dinh cua cdng trinh, lam tang dp cung cua cdng trinh.
- Viec thay doi chieu day san va chieu cao tang de dieu khien phan ufng cua cdng trinh trong tinh toan vdi so dd khdng gian dufa tren hieu ling dot tre, vdi tai trpng di?ng dat de tim dupc phuong an hpp ly cua ket
cau la miDt y tudng mdi va phu hpp vdi phUdng phap tinh hien tai cd suf ho trp cua may tinh dien tuf. Vdi chieu cao va be rdng cong trinh khdng doi chung ta cd the chpn ra dupc chieu day san va chieu cao tang vdi so tang hpp ly cd ldi cho tinh khang chan cua ket cau cdng trinh.
-Trang thai ndi lufc cua san xung quanh Idi cufng la phufc tap, mo men cd gia tri Idn va ddi dau, npi lufc tai (Jiem san lien ket vdi Idi cdng Idn hdn nhieu so vdi tai diem bien va (Jiem giufa d san.Trong cung miDt so do ket cau, tai vi tri san lien ket vdi Idi cufng ket qua khao sat cho thay gia tri md men tang dan theo chieu cao trong khi tinh toan theo ly thuyet dan hdi thi gia trj mo men la khdng doi theo cac tang.Tufdd, kien nghi khi thiet ke nha nhieu tang can cau tao, bo tri cot thep lien ket san va loi cufng de chiu ufng suat tap trung cue bd, lam tang kha nang lam viec tuong hogiiJasan va Idi cufng, tang kha nang chiu lufc ngang cua nha nhieu tang, nang cao dp cufng, dp on dinh cua toan nha.
-Vdi cac cong trinh gia (Jinh da chpn tai Ha Ndi de tinh toan, khi thay doi chieu day san, chieu cao tang, ket qua dat dupc qua khao sat, so sanh cd the tim dupc m(Dt giai phap ket cau hop ly cho phan ufng cdng trinh vdi tai trpng ddng dat. Neu cd (Jieu kien, tiep tuc tinh toan thuf nghiem them cac thdng sd tinh toan nda, van cd the tim dddc phudng an hpp ly
cho ket cau theo tifng trudng hpp cu the. •
TAI LIEU THAM KHAO
1. PGS.TS.Nguyen Van HJng, Th.S Ninh GiJc Thuan - (jng dung hieu ifng dot tre de danh gia Slf anh hifflng ciia san den ket cau loi cirng thi cong bang bien phap cop pha trUOt trong nha nhieu tang. Tap chi Xay dung - Bo Xay Difng, 2007,
2. Hoi dap thiet ke va thi cong ket cau nha cao tang - Trieu Tay An va nhom tac gia - Nha xuat ban Xay difng, 1996.
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