Senior Lecturer Department of GED
Daffodil International University
Differentiation (Part – 3)
(Technique of Differentiation)
Example:
2
�
�� ( 1 ) = 0 ;
Constant Rule:
If is a constant, then
�
�� ( � ) = 0 ;
�
�� ( 1000 ) =0 ;
�
�� ( � ) =0.
Example: Find for the function
3
Given that,
��
�� = �
�� ( √ � )
Taking derivative with respect to on both sides,
¿ �
��
(
�1 2
)
¿ 1 2 �
1 2 −1
��
�� = 1 2 �−
1
2
∴ ��
�� = �
� √ �
¿ 1 2
1
�
1 2
Power Rule:
Sum or Difference Rule:
If and are functions of x, ( and ), then
4
Given that,
�
�� ( �
�) = � �
�−1
��
�� = �
��
( √3 � − √1� )
Taking derivative with respect to on both sides,
¿ �
��
(
�1
3
)
− ���
(
�−1 2
)
¿ 1 3 �
1 3−1
−
(
− 12 �−1 2−1
)
��
�� =1
3 �−
2
3+ 1
2 �−
3
2
∴ ��
�� = 1 3
1
√
3�
2+
1 2
1
√ �
3
¿ 1 3
1
�
2 3
+ 1 2
1
�
3 2
Example 1: Find for the function
Example 2: Find for the function
5
Given that,
�
�� ( ��� � ) = 1
�
��
�� = �
��
(
��+2��� �− 12 ��� �)
Taking derivative with respect to on both sides,
¿ �
��
(
��)
+ ��� (2 ��� �)− �
��
(
12 ��� �)
¿ �
�+ 2 �
�� ( ��� � ) − 1 2
�
�� ( ��� � )
∴ ��
�� = �
�+ 2 cos � − 1 2 �
¿ �
�+ 2 cos � − 1 2
1
�
�
�� ( �
�) = �
�
�
�� ( sin � ) = cos �
�
�� ( � ± � ) = �
�� ( � ) ± �
�� ( � )
Sum or Difference Rule: (Cont...)
�
�� ( �� ) = � �
�� ( � )
Example: Find for the function
6
Given that,
��
�� = �
�� ( �
2���
−1� )
Taking derivative with respect to on both sides,
¿ �
2�
�� ( ���
−1� ) + ���
−1� �
�� ( �
2)
¿ �2 1
1+�2 +���−1 � . (2� )
∴ ��
�� = ��
�+ �� +�� tan−��
�
��
(
���−1 �)
= 11+ �2
Product Rule:
If and are functions of x, ( and ), then
Example: Find for the function
7
Quotient Rule:
If and are functions of x, ( and ), then
Given that,
��
�� = �
��
(
5−3��� ��)
Taking derivative with respect to on both sides,
¿
(5−��� �) �
�� (3 �)−3 � �
�� (5−��� �) (5−��� �)2
¿
(5−��� �)3 �
�� ( �)−3 � �
�� (5−��� �) (5−��� �)2
∴ ��
�� = ��−���� �+� � �����
(
�−��� �)
�
�
�� ( � )=1
�
�� ( ��� � ) = ���
2�
��
�� = (5−��� �)3(1)− 3�
(
0− ���2�)
(5−��� �)2
�
�� ( � ) =0
8
Chain Rule:
If is a function of , () and is a function of x, (), then
Example: Find for the function
Given that,
��
�� = �
�� (��)∙ �
��
(
2���−1�)
By Chain Rule,
¿��∙2 �
��
(
���−1�)
∴ ��
�� =−������−��
√
�− ��
�
�� ( �
�) = �
�
�
�� ( cos
−1� ) = − 1
√ 1 − �
2
��
�� =
(
�2���−1 �)
∙2 −1√
1− �2
Suppose
So
��
�� = ��
�� ∙ ��
��
Find for the functions and
9
Given parametric equations, and
��
� � = �
� � ( � cos � +� sin � )
¿ �
� � ( � cos � ) + �
� � ( � sin � )
¿ � �
�� ( cos � ) + � �
� � ( sin � )
��
�� = ��
� � ∙ � �
�� =� cos � ∙ 1
� cos � − asin �
� �
� � = �
� � ( � sin � )
¿
a (− sin � )+ � cos �
∴ ��
� � = � cos � − asin �
Again , � =� sin �
¿ � �
� � ( sin � )
∴ � �
�� =� cos �
∴ ��
�� = � ��� �
���� � − ���� �
By Chain Rule,
Example: Find for the function
10
Function as Power of another Function:
If and are functions of x, ( and ), then
Given that,
�
��
(
��)
+ ���
(
��)
= ��� (1)
Taking derivative with respect to on both sides,
⇒ �� �
�� (� ln �)+ �� �
�� ( � ln �)=0
⇒ ��
(
� 1� +ln � ����
)
+ ��(
� �1��
�� +ln �
)
=0
⇒ �� � �−1+�� ln � ��
�� + �� � �−1 ��
�� + ��ln �=0
��
��
(
�� ln �+ ��−1 �)
=− ��−1� − ��ln �
∴ ��
�� =−
(
��−1� +� ��� �)
�� �� �+ ��−1 �
��
�� =−��−1 � −�� ln �
�� ln �+ ��−1 �
⇒ ��−1 �+�� ln � ��
�� + ��−1� ��
�� + �� ln �=0
�
�� ( �� ) =� �
�� ( � ) + � �
�� ( � )
Exercise
11
(a) Find the derivative of the following functions :
(b) Find of the parametric equations:
and .