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EQUATION IN ECONOMICS

(Course 3)

JURUSAN AGRIBISNIS

FAKULTAS PERTANIAN

UNIVERSITAS RIAU

OLEH

SYAIFUL HADI

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INTRODUCTION

An equation is a statement that two expressions

are equal to one another.

In economic modelling we express relationships

are equations and then use them to obtain

analytical result. Solving the equations gives us

values for which the equations are true.

We can express the condition for market

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REWRITING AND SOLVING

EQUATIONS

 When rewriting equation:

1. Add to or subtract from both sides.

2. Multiply or divide through the whole or each side (but don’t divide by 0).

3. Square or take the square root of each side. 4. Use as many stages as you wish.

5. Take care to get all the signs correct.

 Example: Plot the equations y = -5 + 2x and y = 30 - 3x. At what

values of x and y do they cross ? Find also the algebraic solution by setting the two expressions in x equal to one other.

 We are asked to plot two linier functions, so plotting two points on each then connecting them will suffice.

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y=-5+2x

y=-30-3x

x 0 2 4 6 8 10 12

y=-5+2x -5 -1 3 7 11 15 19

y=30-3x 30 24 18 12 6 0 -6

For algebraic solution, the two y value are equal so

equate the right hand sides of the expressions and solve for x:

-5 + 2x = 30 – 3x We want term in ix on the left-hand side but not on the right, so add 3x to both sides since -3x + 3x = 0. We then have:

-5 + 2x + 3x = 30

or -5 + 5x = 30

To remove the constant term from the left side we now add 5 to each side, giving:

Lines intersect at (7, 9)

5x = 35

And so, dividing by 5, we have x = 7

We then find the value for y by substi tuting x=7 in either of the equations. Using y=30 – 3x gives:

y = 30 – 21 = 9

Which confirms the graphical

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SOLUTION IN TERMS OF OTHER

VARIABLES

 Not all the equations you deal with have numerical solutions.

Sometimes when you solve and equation for x you obtain and expression containing other variables.

 Use same rules to transpose the equation.

 Remember that in the solution x will not occur on the right-hand side

and will be on its own the left-hand side.

 If you are given a relationship in the form y=f(x), rewriting the

equation in the form x=g(y) is called finding the inverse function.

 To be able to find the inverse there must be just one x value

corresponding to each y value.

 For non linier function there can be difficulties in finding an inverse,

but we may be able to do so for restricted set values.

 The function y=x2 has two x values (one positive and one negative)

corresponding to every y value, but if we consider the restricted function y=x2, x>0 this function has the inverse x=y.

 For the linier functions often use in economic models inverse functions

can always be found. One reason for finding the inverse function can always be found. One by y is conventionally plotted in economic on the horizontal axis.

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 Solve for x in term of z

x = 60 + 0.8x + 7z

 At first glance you seem to already have a solution for x, but

notice that x occurs also on the right-hand side of the

equation. We must collect terms in x on the left-hand, so we subtract 0.8x from both sides and obtain:

x - 0.8x = 60 + 7z

since both left-hand side terms contain x we may write: (1 – 0.8)x = 60 + 7z

which gives

0.2x = 60 + 7z

To get x with a coefficient of 1 we divide both sides by 0.2 = 1/5, which is the same thing as multiplying both sides by 5. This gives:

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 Given y = x + 5, obtain an expression for x in term of y.

 Begin by interchanging the side so that the sides with x is on

the left of the equation. We then have:

x + 5 = y

Next subtract 5 from both sides, giving:

x = y – 5

To find x we must square both sides. This means that the whole of the right-hand side is multiplied by itself, so use brackets. We obtain:

x = (y – 5)2

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SUBSTITUTION

 When two expression are equal to one another, either can

be substituted for the other.

 The technique is used  the effect of the imposition of a per

unit tax on a good and to solve simultaneous equations.

 When substituting, always be sure to substitute the whole

of the new expression and combine it with the other term in exactly the same way the expression it replaces was

combined with them.

 For example, if y = x2 + 6 and x = 30 - , find an

expression for y in term of . Substituting 30 -  for x we

obtain:

y = (30 - )2 + 6

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DEMAND AND SUPPLY

 Demand and supply function in economics express

the quantity demanded or supplied as a function of price, Q = f (P).

 According to mathematical convention the dependent

variable (Q) should be plotted on the vertical axis.

 Economic analysis, however, use the horizontal axis

as the Q and for consistency we follow that approach. So that we can determine the points on graph in the usual way, before plotting a demand or supply

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 Find the inverse function for the demand equation Q = 80 – 2P

and sketch the demand curve.

 Adding 2P to both sides of the demand equation we get

2P + Q = 80

Subtracting Q from both sides we obtain: 2P = 80 – Q

Dividing each side by 2 gives the inverse function P = (80 – Q)/2 = 40 – (Q/2)

The demand function is linier, so it suffices to plot two point. Selected values of Q are shown in the table together with corresponding value for P.

Q 0 20 40 60 80

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MARKET EQULIBRIUM

 Market equilibrium occurs when the quantity supplied

equals the quantity demanded of a good.

 The supply and demand curves cross at the equilibrium

price and quantity.

 If you plot both the demanded and supply curves you

can of approximate equilibrium values from the graph.

 Another approach is to solve algebraically for the point

where the demand and supply equation are equal. This gives exact value. Suppose we wish to find the

equilibrium price and quantity when demand is given by

Demand: Q = 96 – 4P And the supply equation is

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 For an algebraic solution we can use the equation in this form.

Since in equilibrium then quantity supplied equals the quantity demanded, the right-hand side of the supply equation must

equal the right-hand side of the demand equation. This gives an equation in P:

Supply Q = Demand Q (in equilibrium), so 8P = 96 – 4P

Adding 4P to both sides gives 12P = 96

Dividing by 12 we find P = 8 which is the equilibrium price. We can then substitute this into either equation, say the equation. This gives:

Q = 8 x 8 = 64

(13)

Jawaban QUIS I

1. Sketch the total cost function: TC = 300 + 40Q – 10Q2 + Q3,

write expressions for AC, FC, VC and AVC !

AC = 300/Q + 40 – 10Q +

Q2

FC = 300

VC = 40Q – 10Q2 + Q3

AVC = 40 – 10Q + Q2

TC=3 00+4

0Q

-10Q

2+Q 3

Q 0 1 2 3 4 5 6 7 8 9 10 11 12

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(15)

Jawaban QUIS I

3. A firm in perfect competition sells it output at a price Rp 12. Plot it total revenue function (TR) = 12Q !

 Price constant, TR a line through the origin

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-QUIS II

Rewriting these equations expressing

P as a function of Q then plot them on

a graph

Supply : Q = 4P

Referensi

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