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(1)

!" "#$ #!%&'(

!" "#$ #!%&'(

1 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)&%)*!+* & )!$+*

(2)
(3)

5 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

(4)
(5)

9 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

(6)
(7)

$%+,($+ )!# #!(! -&!.($+

13 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)!# #!(!

)!# #!(! /($%+$

/($%+$00 )-+!+$+

)-+!+$+

.(1(% *),2(/+ *) 1&$+$+ $),#/(3

1)!# #!(! $)") (

+%)!%#*(! &/)' ,&.#/#$ )/($%+$+%($ %(!('0

+%)!%#*(! &/)' ,&.#/#$ )/($%+$+%($ %(!('0

&!.+$+ %(* %) . (+!($) #!. (+!). 0

#

&!.+$+ %) . (+!($) . (+!). 0

.

(8)

)!# #!(!

)!# #!(! /($%+$

/($%+$

σ

σ

σ

σ

σ

σ

σ

σ

Q

Q

E

ρ

4

σ

4

ε

5

15

E

H

H

εεεε

z

Kondisi umum tegangan

dan regangan

E

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

εεεεεεεε

z

z

.dz

.dz

0

0

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

( (,(%)

/($%+$+%($0 ),1#!"

( (,(%)

/($%+$+%($0 ),1#!"

+1+*(/ !+/(+

#

),1#!" 4 /#!(*

6

* (

),1#!" *) ($ 4

6

* (

),1#!" *(*# 4

6

* (

),1#!" $(!"(% *(*# 4

6 7

* (

Kondisi

Kondisi tak

tak terdrainase

terdrainase

),1#!" $(!"(% *(*# 4

6 7

* (

+1+*(/

#

8

#

),#( 9)!+$ /),1#!" 4

6

+1+*(/ (!"(* &+$$&!

ν

#

(9)

( (,(%)

( (,(%)

/($%+$+%($

/($%+$+%($00 ($+

($+

+1+*(/ !+/(+

.

◦◦

66

* (

* (

◦◦

66

* (

* (

◦◦

66

* (

* (

Kondisi

Kondisi terdrainase

terdrainase

◦◦

66

* (

* (

◦◦

66 ;

;

* (

* (

+1+*(/ (!"*( &+$$&!

ν

.

◦◦

◦◦

17 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

+$% +2#$+

+$% +2#$+ )"(!"(!

)"(!"(! 00 <)2(!

<)2(! +%+*

+%+*

)& + <&#$$+!)$=

z

z

Q

Q

σ

σ

σ

σ

= Q I

ψ

ψ

ψ

ψ

rr

R

R

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

σ

σ

σ

σ

σ

σ

σ

σ

θ

θ

θ

θ

θ

θ

θ

θ

σ

σ

σ

σ

σ

σ

σ

σ

rr

σ

σ

σ

σ

z

= Q I

σ

σ

σ

σ

z

2

II

σ

σ

σ

σ

σ

σ

σ

σ

=

= 3

3

1

1

2

2

π

π

π

π

π

π

π

π

[1+(r/z)

[1+(r/z)

2

2

]]

5/2

5/2

II

σ

σ

σ

σ

σ

σ

σ

σ

=

= faktor

faktor pengaruh

pengaruh

tegangan

tegangan

ψ

ψ

ψ

ψ

(10)

+$% +2#$+

+$% +2#$+ )"(!"(!

)"(!"(! 00 <)2(!

<)2(! +!"*( (!

+!"*( (!

d

d

θ

θ

θ

θ

θ

θ

θ

θ

dr

dr

load, q

load, q

By integration of

By integration of

Boussinesq

Boussinesq

19

d

d

θ

θ

θ

θ

θ

θ

θ

θ

rr

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

a

a

Boussinesq

Boussinesq

solution over

solution over

complete area:

complete area:

σ

σ

σ

σ

σ

σ

σ

σ

z

z

= q [1

= q [1--

1

1 ] = q.I

] = q.I

σ

σ

σ

σ

σ

σ

σ

σ

[1+(a/z)

[1+(a/z)

2

2

]]

3/2

3/2

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

+$% +2#$+

+$% +2#$+ )"(!"(!

)"(!"(! 00 <)2(!

<)2(! ) $)"+

) $)"+

)!""#!(*(! 1 +!$+1 2)2(! %+%+*3

.+,(!( 2)*) 9( 1(.( $(/(' $(%#

#9#!" 2)!%#* 1) $)"+!>(

)!%#*(

.(!

B

B

L

L

)!%#*(

.(!

)/)$(+*(! .)!"(! " (-+*

)?,( * (%(# 1) $(,((! 0

I

σ

σ

σ

σ

= 1 2mn(m

2

+n

2

+1)

1/2

. m

2

+n

2

+2

+ tan

-1

2mn(m

2

+n

2

+1)

1/2

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

σ

σ

σ

σ

σ

σ

σ

(11)

0

1

2

0

0.05

0.1

0.15

0.2

0.25

) #2('(!

) #2('(! )"(!"(!

)"(!"(! &%(/

&%(/

II

σ

σ

σ

σ

σ

σ

σ

σ

2

3

4

5

6

7

8

L/B = 1

L/B = 2

L/B = 10

21

z/B

z/B

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)!"'+%#!"(!

)!"'+%#!"(! )!# #!(!

)!# #!(!

)!%#*(! )"(!"(! :) %+*(/ 0

#,/('*(! )"(!"(! %+(1 /(1+$(! 0

z

z

Q

Q

ψ

εεεε

=

1 [

σ

σ

σ

σ

-

ν

ν

ν

ν

(

σ

σ

σ

σ

+

σ

σ

σ

σ

)]

rr

R

R

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

σ

σ

σ

σ

σ

σ

σ

σ

θ

θ

θ

θ

θ

θ

θ

θ

σ

σ

σ

σ

σ

σ

σ

σ

rr

ψ

εεεε

z

=

1 [

σ

σ

σ

σ

z

-

ν

ν

ν

ν

(

σ

σ

σ

σ

r

+

σ

σ

σ

σ

θ

θ

θ

θ

)]

E

εεεε

z

= Q .

(1

+

ν

ν

ν

ν

).

cos

3

ψ.

ψ.

ψ.

ψ.

(3

cos

2

ψ

ψ

ψ

ψ

-2

ν

ν

ν

ν

)

2pz

2

E

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

εεεεεεεε

z

z

..dz

dz

0

0

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

= Q

=

Q

(1

(1

--

ν

ν

ν

ν

ν

ν

ν

ν

2

2

))

π

π

π

π

π

π

π

(12)

)!# #!(!

)!# #!(! &!.($+

&!.($+ +!"*( (!

+!"*( (!

d

d

θ

θ

θ

θ

θ

θ

θ

θ

dr

dr

Beban

Beban,

, q

q

Di

Di pusat

pusat ::

ρ

ρ

ρ

ρ

= 2

q

(1-

ν

ν

ν

ν

2

).

a

23

d

d

θ

θ

θ

θ

θ

θ

θ

θ

rr

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

a

a

Di

Di tepi

tepi ::

ρ

ρ

ρ

ρ

= 4

q

(1-

ν

ν

ν

ν

2

).

a

π

π

π

π

π

π

π

π

E

E

ρ

ρ

ρ

ρ

= 2

q

(1-

ν

ν

ν

ν

2

).

a

E

E

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)!# #!(!

)!# #!(! .+

.+

9#!"

9#!" &!.($+

&!.($+ ) $)"+

) $)"+

B

B

L

L

Metode

Metode Schleicher’s

Schleicher’s

1

1 --

ν

ν

ν

ν

ν

ν

ν

ν

2

2

z

z

σ

σ

σ

σ

σ

σ

σ

σ

z

z

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

q.B

q.B

1

1 --

ν

ν

ν

ν

ν

ν

ν

ν

E

E

II

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

II

=

=

1

1

m ln + ln

m ln + ln

1

1

+ m

+ m

2

2

+ 1

+ 1

m

m

+ m

+ m

2

2

+ 1

+ 1

(13)

nz

z

σz= q.I σ x Area covered with uniform normal load, q mz y z

Note: m and n are interchangeable

m = oc

m = 3.0

m = 2.5

m = 2.0

m = 1.8

m = 1.6

m = 1.4 m = 1.2

m = 1.0

m = 0.9

m = 0.8

m = 0.7

m = 0.6

m = 0.5

m = 0.4

0.26

0.24

0.22

0.20

0.18

0.16

0.14

0.12

I

σ

σ

σ

σ

m = 0.3

m = 0.2

m = 0.1

m = 0.0

0

0.01

2 3 4 5

0.1

2

3

4

5

1.0

2 3 4 5

10

0.10

0.08

0.06

0.04

0.02

VERTICAL STRESS BELOW A CORNER OF A UNIFORMLY LOADED FLEXIBLE

RECTANGULAR AREA.

25 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)!# #!(!

)!# #!(! .+

.+ )!"('

)!"(' &!.($+

&!.($+ ) $)"+

) $)"+

B

B

L

L

L/2

L/2

B

B

B/2

B/2

ρ

ρ

ρ

ρ

centre

= 4

q.B

2

1

1 --

ν

ν

ν

ν

ν

ν

ν

ν

2

2

E

E

II

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

Superposisi untuk titik

yang berbesa

(14)

)!# #!(!

)!# #!(! .+2(?('

.+2(?(' (!('

(!('

#(

#(

/(1+$(!

/(1+$(! 00 )%&.)

)%&.) %)+!2 )!!)

%)+!2 )!!)

q

q

X

X

ρ

ρ

ρ

ρ

corner

=

q.B

1

1 --

ν

ν

ν

ν

ν

ν

ν

ν

2

2

E

E

II

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

II

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

F

F

1

1

+

+

F

F

2

2

1

1--

ν

ν

ν

ν

ν

ν

ν

ν

1

1--2

2

ν

ν

ν

ν

ν

ν

ν

ν

27

H

H

B

B

E

E

Kaku

X

X

Y

Y

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8

2

L/B = 1

L/B = 2 F1

Values of F ( ) and F ( )

1 2

=

H

/B

(*%&

(*%&

)!"( #'

)!"( #'

)%&.)

)%&.)

%)+!2 )!!)

%)+!2 )!!)

4 6 8 10

L/B = 5

L/B = 10

L/B = oo

L/B = 1

L/B = 2

L/B = 5

L/B = 10 L/B = oo

(15)

)!# #!(!

)!# #!(! .+2(?('

.+2(?(' (!('

(!(' <) /(1+$

<) /(1+$ 00

q

q

H

H

B

B

E

E

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

((

H

H

1

1

,,

E

E

1

1

) +

) +

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

((

H

H

1

1

+

+

H

H

2

2

,,

E

E

2

2

)

) --

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

((

H

H

1

1

,,

E

E

2

2

)

)

29

H

H

1

1

E

E

1

1

Rigid

Rigid

H

H

2

2

E

E

2

2

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

#1) 1&$+$+

#1) 1&$+$+ ,)!""#!(*(!

,)!""#!(*(!

)%&.)

)%&.)

%)+!2 )!!)

%)+!2 )!!)

L

L

B

B

(16)

)!"( #'

)!"( #'

).#!"

).#!" @(!"

@(!" <) .)*(%(!

<) .)*(%(!

31 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

&!.($+

&!.($+ /)*$+2)/

/)*$+2)/

(*#

(*#

F

F

F

F

Tegangan

Tegangan

Defleksi

Defleksi

Defleksi

(17)

(*%&

(*%&

& )*$+

& )*$+ ).(/(,(!

).(/(,(!

)1%'

)1%'

(8%&

(8%&

0.9

1

1.1

F

a

c

to

r

B

B

z

z

33

0.5

0.6

0.7

0.8

0

2.5

5

7.5

10

D

e

p

th

F

z/B

B

B

z

z

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

$%+,($+ )!# #!(! -&!.($+

(18)

&!$&/+.($+

+,)

#(%# -)!&,)!( 1) #2('(! :&/#,) >(!" .(1(% %) 9(.+

1(.( %(!(' 1($+ .(! /),1#!"

)2+' $) +!" +.)!%+* %) 9(.+ 1(.( /(1+$(! /),1#!"

+ *)/#( .( + %(!(' 2) $(,((! .)!"(! ,)!+!"*(%!>(

%)"(!"(! )-)*%+- .(! *#(% ")$)

%)"(!"(! )-)*%+- .(! *#(% ")$)

,&#!% 8(! 2) )($&!(2/> )$%+,(%). +! /(23 2#% (%) +$

&-%)! 1&& /> )$%+,(%). +! /(2

(!>( .(1(% *),2(/+ *) $),#/( $)8( ( $)2("+(!

35 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

9+9+

).&,)%)

).&,)%)

(2& (%& +#,

(2& (%& +#,

) #2('(! %+!""+ 2)!.( #9+

'

<)2(!

!"*( 1& + )

)"(!"(!

σ

Pengukuran/data :

Hubungan

Hubungan yang

yang

dicari

dicari

<)2(!

(19)

# :( 1) #2('(! %+!""+ .(! ?(*%#

# :( 1) #2('(! %+!""+ .(! ?(*%#

h

h

o

o

T

in

g

g

i

T

in

g

g

i

Interval

Interval Waktu

Waktu pengukuran

pengukuran t :15s

t :15s, 30s,

, 30s,

1m, 2m, 3m, 5m, 10m, 15m, 30m, 1h, 2h,

1m, 2m, 3m, 5m, 10m, 15m, 30m, 1h, 2h,

3h, 6h, 12h, 24h, 36h, 48h, 60h ….etc.

3h, 6h, 12h, 24h, 36h, 48h, 60h ….etc.

37

log

log tt

Elastis

Elastis

Konsolidasi

Konsolidasi

utama

utama

Konsolidasi

Konsolidasi sekunder

sekunder

Dibuat

Dibuat untuk

untuk tegangan:12.5

tegangan:12.5, 25, 50, 100, 200, 400, 800 and 1600

, 25, 50, 100, 200, 400, 800 and 1600 KPa

KPa

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

ff

e

e

1.00

1.00

e = 0.8

e = 0.8

Volume

Volume relatif

relatif

Berat

Berat jenis

jenis

1

1

2.65

2.65

1 + e

1 + e

1.917

1.917

e = 0.8

e = 0.8

h = 1.9 cm

h = 1.9 cm

diameter

diameter = 6.0 cm

= 6.0 cm

W = 103.0 g

W = 103.0 g

(20)

0

1

2

0

0.05

0.1

0.15

0.2

0.25

) #2('(!

) #2('(! )"(!"(!

)"(!"(! &%(/

&%(/

II

σ

σ

σ

σ

σ

σ

σ

σ

2

3

4

5

6

7

8

L/B = 1

L/B = 2

L/B = 10

39

z/B

z/B

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

) #2('(!

) #2('(! )*(!(!

)*(!(! & +

& + .(!

.(!

)"(!"(!

)"(!"(! -)*%+-

-)*%+-∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

=

=

u +

u +

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

′′′′′′′′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

ff

Pada

Pada t

t = 0 :

= 0 :

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

=

=

u

u

Pada

(21)

)"(!"(!

)"(!"(!

&!

&!66 +!+)

+!+)

q

q

net

net

41

z

z

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

)"(!"(!

)"(!"(!

&!

&!66 +!+)

+!+)

1

1.1

1.2

C

C

rr

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

Σ

Σ

Σ

Σ

Σ

Σ

Σ

Σ

1+

1+

C

C

r

r

e

e

H

H

log + log

log + log

o

o

C

C

c

c

H

H

1+

1+

e

e

c

c

p

p

′′′′′′′′

c

c

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

ii

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

ff

p

p

′′′′′′′′

c

c

0.4

0.5

0.6

0.7

0.8

0.9

10

100

1000

Clay

C

C

c

c

p

p

′′′′′′′′

c

c

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

ii

σ′

σ′

σ′

σ′

σ′

σ′

σ′

σ′

ff

e

e

σ

σ

σ

σ

σ

σ

σ

σ

v

v

(22)

&)-+$+)!

&)-+$+)! ),(,1(%(!

),(,1(%(! A&/#,)

A&/#,)

1

1.1

1.2

Clay

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

=

=

Σ

Σ

Σ

Σ

Σ

Σ

Σ

Σ

m

m

v

v

..

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

∆σ

′′′′′′′′

..

H

H

43

0.4

0.5

0.6

0.7

0.8

0.9

0

200

400

600

800

1000

(1+

(1+

e

e

o

o

).

).

m

m

v

v

e

e

σ

σ

σ

σ

σ

σ

σ

σ

v

v

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

(9#

(9# &!$&/+.($+

&!$&/+.($+

Flow

Flow

h = H

h = H

Flow

Flow

h = H

h = H

/ 2

/ 2

T = c

T = c

v

v

tt

ii

/

/

H

H

2

2

(23)

&)-+$+)! &!$&/+.($+

&)-+$+)! &!$&/+.($+

&)-+$+)! *&!$&/+.($+3 8: , >

($+/ #9+ /(2& (%& +#, .+*)!(/

,),2) +*(! '($+/ >(!" /)2+' )!.('

#!.) )$%+,(%)

#!.) )$%+,(%)

<) "(!%#!" 1(.( ,)%&.) #!%#*

,)!)!%#*(! 8: >(!" 2) "(!%#!" 1(.(

1)!)!%#(! -(*%& ?(*%# : ,+$(/ #!%#*

,)!8(1(+ B C *&!$&/+.($+

45 Dr.Eng. Agus S. Muntohar Department of Civil Engineering

&!$&/+.($+ )*#!.)

α

)2("(+ -)!&,)!( (>(1(! 8 ))1

+.(* %) 9(.+ 1) #2('(! %)*(!(! 1& +

#/(+ %) 9(.+ 1(.( (*'+ *&!$&/+.($+ 1 +,)

#/(+ %) 9(.+ 1(.( (*'+ *&!$&/+.($+ 1 +,)

α

c

c

α

α

α

α

α

α

α

α

=

=

e

e

log

log

((

tt

2

2

/ t

/ t

1

1

))

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

= log

= log

((

tt

2

2

/t

/t

1

1

))

c

c

α

α

α

α

α

α

α

α

H

H

(1+

(1+

e

e

p

p

))

(24)

)!# #!(!

)!# #!(! &%(/

&%(/

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

tot

tot

=

=

RF

RF

x

x

DF

DF

(

(

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

elas

elas

+

+

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

pr.con

pr.con

+

+

ρ

ρ

ρ

ρ

ρ

ρ

ρ

ρ

sec

sec

))

47

RF = roughness factor (0.8 ~ 1)

DF = depth factor

Dr.Eng. Agus S. Muntohar Department of Civil Engineering

&!%&'

&!%&' )!"'+%#!"(!

)!"'+%#!"(!

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