• Tidak ada hasil yang ditemukan

UNIT OPERASI BIOPROSES (UOB)

N/A
N/A
Protected

Academic year: 2018

Membagikan "UNIT OPERASI BIOPROSES (UOB)"

Copied!
38
0
0

Teks penuh

(1)

UNIT OPERASI

BIOPROSES (UOB)

TPE4211

(2)

MATERI KULIAH

No Pokok Bahasan Sub Pokok Bahasan Waktu (Jam)

1. Pengantar

2. Satuan dimensi Sistem satuan, dimensi dan konversi

2 x 50 3 Kesetimbangan Massa 2 x 50

4. Kesetimbangan Energi 2 x 50

5. Kesetimbangan Unsteady-State Massa dan Energi

2 x 50

6. Dasar-dasar perpindahan momentum

Viskositas dan macam-macam fluida, fluida statis, aliran fluida, tipe aliran dan faktor

gesekan

2 x 50

7. Lanjutan Pengukuran aliran fluida, kebutuhan tenaga untuk aliran, persamaan Bernoilli dan penerapannya

(3)
(4)

Energy is expensive….

Effective use of energy is important task for

bioprocess engineers.

Topics of this chapter

Energy balance

Energy and energy transfer

Forms of energy : Kinetic / Potential / Internal Energy

Energy transfer : Heat and Work

Using tables of thermodynamic data

(5)

Unlike many chemical processes, bioprocesses are not particularly energy intensive. Fermenters and enzyme reactors are operated at temperatures and pressures close to ambient; energy input for downstream processing is minimized to avoid damaging heat-labile products. Nevertheless, energy effects are important because biological catalysts are very sensitive to heat and changes in temperature. In large-scale processes, heat released during reaction can cause cell death or denaturation of enzymes if it is not quickly removed. For rational design of temperature-control facilities, energy flows in the system must be determined using energy balances. Energy effects are also important in other areas of bioprocessing such as steam sterilisation.

(6)

The law of conservation of energy means that an energy accounting system can be set up to determine the amount of steam or cooling water required to maintain optimum

process temperatures. In this chapter, after the necessary

thermodynamic concepts are explained, an energy-conservation equation applicable to biological processes is derived.

(7)
(8)
(9)

Forms of Energy

The First Law of Thermodynamics

A balance on conserved quantity (i.e. mass, energy,

momentum) in a process system may be written as:

(10)

Forms of Energy

The First Law of Thermodynamics

Forms of energy

Kinetic energy : due to the motion of the system

Potential energy : due to the position of the system

Internal energy : due to the motion of internal molecules

U : from thermodynamic calculation

(11)

Forms of Energy

The First Law of Thermodynamics

Change in kinetic energy:

Change in potential energy

(12)

How energy can be transferred between a system and its surroundings?

- Heat energy that flows as a result of temperature difference between a system and its surrounding ; heat is

defined positive when it is transferred to the system from the surroundings.

-Work energy that flows in response to any driving force

other than a temperature difference. ; work is defined positive when it is done by the system on the surroundings.

Forms of Energy

(13)

Forms of Energy

The First Law of Thermodynamics

Types of Work

• Flow work (Wfl) - energy carried across the boundaries of a system with the mass flowing across the boundaries (i.e.

internal, kinetic & potential energy)

(14)
(15)

Energy balance on closed systems

There is no mass transfer into a closed system

The only way energy can get into or out of a closed system is by heat transfer or work

Q

Ws

a. Heat transfer (Q) b. Work (Ws)

Note: * Work is any boundary interaction that is not heat (mechanical, electrical, magnetic, etc.)

(16)

The law of conservation of energy

can be written as:

energy in through system boundaries

energy out through system boundaries

energy accumulated within the system

(17)

Balance equation

(Final System Energy)

(Initial System Energy)

= (Net Energy Transfer)

Initial System Energy

Final System Energy

Net Energy Transfer

ki pi

i E E

U  

kf pf

f E E

U   W Q

W

Q

E

E

U

p

k

The first law of thermodynamics for closed systems

Energy balance on closed systems

(18)

W

Q

E

E

U

p

k

For a closed system what is ∆E equal to?

Is it adiabatic? (if yes, Q = 0)

Are there moving parts, e.g. do the walls move? (if no, Ws = 0)

Is the system moving? (if no, ∆KE = 0)

Is there a change in elevation of the system? (if no, PE = 0 )

Does temperature, phase, chemical composition change, or

pressure change less than a few atmospheres ? (if no to all, ∆U = 0)

Energy balance on closed systems

(19)
(20)

Energy Balance Procedures

Solve material balance

Get all the

flow rate of streams

Determine the specific enthalpies of each

stream components

Using tabulated data

Calculation

Construct energy balance equation and

solve it.

s k

p

E

Q

W

E

H

(21)

Exercise

A closed system of mass 5 kg undergoes a process in which there is work of magnitude 9 kJ to the system from the

surroundings. The elevation of the system increases by 700m during the process. The specific internal energy of the system decreases by 6 kJ/kg and there is no change in kinetic energy of the system. The acceleration of gravity is constant at

g=9.6m/s2.

(22)

Energy balance on open systems

2

How are open systems control volumes different from closed systems

(23)
(24)
(25)

Energy balance on open systems

*Steady State

Flow work and shaft work

Flow work : work done on system by the fluid itself at the inlet and the outlet

Shaft work : work done on the system by a moving part within the system

f s W

W W  

Process Unit ) / ( ) / ( 2 3 m N P s m V in in ) / ( ) / ( 2 3 m N P s m V out out out out in in

f P V P V

W  

(26)
(27)

The Steady-State Open System Energy Balance

W Q E

E

U  p  k  

f s W

W W  

out out out in in in

f m P V m P V

W  ˆ  ˆ

c K g mv E 2 2    h g g m E c

K  

U m U  ˆ

V

P U

Hˆ  ˆ  ˆ

s k

p E Q W

E

H    

(28)

Air at 300oC and 130 kPa flows through a horizontal 7 cm

ID pipe at a velocity of 42 m/s

a) Write and simplify the energy balance

b) Calculate the rate of kinetic energy, if the air is heated to 400oC at

constant pressure, assuming ideal gas behaviour

c) Why would be correct to say that the rate of heat transfer to the gas equals the rate of change of kinetic energy? Why?

(29)
(30)
(31)

Enthalpy

It is convenient to define the following property

for the calculation of energy balance for

flowing systems.

Enthalpy

Specific Enthalpy

PV U

H   V P U

(32)

What is the enthalpy of 150 g formic acid at

70

o

C and 1 atm relative to 25

o

C and 1 atm?

(33)

Tables of Thermodynamic Data

U, H, S, V,…

Thermodynamic function

Tables of Thermodynamic Data

Tabulation of values of thermodynamic functions (U, H, V,..) at various condition (T and P)

It is impossible to know the absolute values of U , H for process materials Only changes are important ( U, H,…)

Reference state

(34)

Steam Tables

(35)

(i) Steady-stateflow process. At steady state, all properties of the system are invariant. Therefore, there can be no

accumulation or change in the energy of the system: AE = 0

(ii) Adiabatic process. A process in which no heat is

transferred to or from the system is termed adiabatic; if the system has an adiabatic wall it cannot receive or

(36)

Water at 25

o

C enters an open heating tank

at a rate of 10 kg h

-1

. Liquid water leaves

the tank at 88

o

C at a rate of 9 kg h

-1

;

1 kg h

-1

water vapor is lost from the system

through evaporation. At steady state, what is

the rate of heat input to the system?

(37)

Exercise

1. Assemble

(i) Select units for the problem. kg, h, kJ, oC

(ii) Draw the flow sheet showing all data and units.

(38)

Referensi

Dokumen terkait

Apabila kumparan medan dialiri oleh arus tetapi kumparan jangkar tidak dialiri oleh arus, maka dengan mengabaikan pengaruh celah udara, jalur fluksi ideal untuk

Pengaruh Motivasi, Metode Pembelajaran dan Lingkungan terhadap Prestasi Belajar Akuntansi Pada Siswa Kelas X SMAN 12 (Semarang. UNNES: Skripsi).. Di dalam kelas guru

Tujuan: Menganalisis pengaruh pemberian diet oat (Avena sativa L.) dalam menghambat ekspresi VCAM-1 sel endotel arkus aorta dan ketebalan tunika intima-media pada arkus

yang diamati adalah berat badan akhir, kadar lemak daging, lernak abdomen, trigliserida darah da:: h*n# hati' Data dianalisis keragamannya pada laraf 5%o. Hasil

menjawab rumusan masalah yang telah dikemukakan pada bab sebelumnya, yaitu: “Bagaimana ide-ide matematis yang terkandung dalam ritual Nutu Nganyaran masyarakat adat

Sehubungan dengan adanya kesalahan dalam penginputan data pada Pengumuman Lelang non e-proc yang telah ditayangkan khususnya untuk POKJA KONSTRUKSI, maka bersama

Manual Prosedur Surat Ijin Keikutsertaan Dosen dalam Konferensi Nasional atau Internasional ini adalah prosedur yang mengatur pengajuan ijin bagi para dosen yang

Monodon Pilar Nusantar Nomor : 02/PT.MPN/P-MHN/V/2017 tanggal 15 Mei 2017 perihal permohonan perpanjangan permbuktian klarifikasi administrasi, teknis dan legalitas