Pembahasan Soal UN Matematika SMP Tahun 2014 Paket 2 www.olimattohir.blogspot.com

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+ −  + −

= + −

= −

=

= 8

1,2 jam  80 km/jam

1 jam x km/jam

=

, x = 80 × 1,2

x = 96 km/jam

= = =

:  × : ×

= × : ×

=

= ×

=

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Banyak anggota Q = 6

Banyak himpunan bagian dari Q adalah 26 = 64

40

12

23

-1

2

=

1

40 – (11 + 12) = 40 – 23 = 17

Menulis cerpen = 17 + 12 = 29

f(x) = 8 – 2x f(k) = 8 – 2k

–10 = 8 – 2k

–18 = –2k

 9 = k

 k = 9

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m = 3

Memotong sumbu-y di titik (0, –2)

m = = 3

m = =

Memotong sumbu-ybukan di titik (0, –2)

m =

− = –2

m =

− = −

Memotong sumbu-ybukan di titik (0, –2)

m1 = −₊ = =

m1 =m2 =

m2 =

A. m2 = 3 B. m2 =

C. m2 = −

D. m2 = – 3

Paket 2

atau

y–y1 = m2(x–x1)

y + 0 = (x + 6)

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m1 = − −_{− −} =−₋ = 2

y –y1= m(x–x1), (ambil x1 = 1 dan y1 = 5) y – 5 = 2(x– 1)

y – 5 = 2x– 2

y = 2x + 3

y = 2x + 3 , titik R (3, a)

a = 2(3) + 3

a = 6 + 3 a = 9

2x – 5y = 18  ×3  6x – 15y = 54 5x – 3y = 26  ×5  25x – 15y = 130

–19x = –76 x = 4 sehingga y = – 2

Nilai 4x– 7y = 4(4) – 7(–2) = 16 + 14 = 30

2k + 4g = 7.000  ×7  14k + 28g = 49.000 5k + 7g = 13.000  ×4  20k + 28g = 52.000 – 6k = 3.000

k = 500 1 lusin Kelereng = 12 × 500 = 6000

Panjang tali = + = × =

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K L

N M

B C D

A

K L

N M

B C D

A 8cm

cm

8

cm

10

cm

10

cm

10

Luas daerah yang diarsir = × Luas persegi KLMN

= × (8)2 = 16 cm2

(32 + 33 + 11) × 2 = (76) × 2 = 152 cm

Paket 2

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V = � ×� × t

= × × 24

= (16 × 10) × 24

V = 3.840

Dengan menggunakan teorema pythagoras didapat panajang TE = 20 cm

L = luas alas + 4 × luas sisi tegak = 242 + 4 × × 24 × 20 = 576 + 960

L = 1.536 cm2

24 cm

TO=16 cm

E O

LP = Luas tabung tanpa tutup + luas selimut kerucut = (πr2_{+ 2πrt) + π}

rs

= ( ×72 + 2× ×7×12) + ×7×25 = (22×7 + 2×22×12) + 22×25 = (154 + 528) + 550

= (682) + 550

LP = 1.232 cm2

s = +

s = s = 25 s

24

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Paket 2

4, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10

Median = + = 6,5

Bisa jadi, rata-ratanya = 130

Bisa jadi, rata-ratanya = 130 Bisa jadi, rata-ratanya = 130

Bisa dipastikan, rata-ratanya = 130

Rata-rata = × + +

+ + = = 130

4 10 42 84 48 18  206

 30 _{Rata-rata =} _{= 6, 87}

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Pukul 16.00  38oC Pukul 17.00  38,20oC

Pukul 18.00  38,10oC Jadi, Pukul 18.30  38,50oC Pukul 19.00  39oC

Pukul 20.00  38,20oC

Nomor bola ganjil  1, 3, 5, 7, 9  ada 5

P = � �

� =

Disusun oleh : Mohammad Tohir Jika ada saran, kritik maupun masukan silahkan kirim ke- My email: [email protected]

Terima kasih. My blog : http://m2suidhat.blogspot.com/