Chapter I: A Gluing Theorem for the Kapustin-Witten Equations with a Nahm
1.6 Moduli Theory
Corollary 1.5.21. If the cylindrical end of X has the formS3× [0,+∞), we have Ind+X(P)=−3χ(X) −3, Ind−X(P)=−3χ(X)+3. (1.48) Proof. Denote by ¯X a smooth compactification ofXover the tubeS3× [0,+∞)and denote by ¯Pthe extension of the bundle P.
By Proposition 1.5.18, we have
Ind+X(P)+Ind−W = IndX¯(P),¯ Ind−X(P)+Ind+W =IndX¯(P¯). In addition, by Proposition 1.5.16, we know that
IndX¯(P)¯ =−3χ(X)¯ = −3χ(X) −3.
We get the result we want.
Definition 1.6.1. Given a smooth Nahm pole solution(A0,Φ0), we define the framed configuration spaceCp,λf r as follows:
Cp,λf r :={(A0,Φ0)+(a,b) | (a,b) ∈ yλ+p1H01,p(Ω1(gP) ×Ω1(gP))}. (1.49) Here yλ+1pH01,p(Ω1(gP) ×Ω1(gP))is the completion of smooth 1-forms with respect to the normyλ+1pH01,p.
We have some basic properties of the framed configuration space:
Proposition 1.6.2. (1) Any(A,Φ) ∈ Cp,λf rsatisfies the Nahm pole boundary condition.
(2) AssumeXhas non-vanishing boundary and cylindrical end which identified with Y × (0,+∞). Let P be anSU(2) bundle over it, let (A1,Φ1)be a connection pair satisfying the Nahm pole boundary condition, denote
Í3 j=1ejt1j
y is the leading part of Φ1. If(A1,Φ1−
Í3 j=1ejt1j
y ) ∈ H01,p(X),then there exists a global gauge transformation g ∈ Gsuch thatg(A1,Φ1) ∈ Cp,λf r.
Proof. For (1), as forλ∈ [1− 1p,1),p >2, any differential form which blows-up as y−1is not contained inyλ+1pH01,p, the result follows immediately.
For (2), for i = 0,1, (Ai,Φi) both satisfies the Nahm pole boundary condition (Definition 1.2.1). Then there exists orthogonal basis ej ∈ T?Y and tij ∈ gP for
j = 1,2,3 such that [tij
1,tij
2] = j1j2j3tij
3 where j1j2j3 is the Kronecker symbol of j1, j2, j3. In addition, let the asymptotic expansion of Φi at y = 0 to be
Í3 j=1ejtij
y +
O(y). By the commutation relation of tij, there exists a ˆg : Z → SU(2) such that ˆg(
Í3 j=1ejt1j
y )gˆ−1 = Í3j=1yejt0j. By the Hopf theorem, the homotopy type of maps from Y3 to SU(2) is totally determined by the degree. Given ˆg : Z → SU(2), considerYT0 =Y × {T0} ⊂ X, we can choose a band to connect Z andY which is homeomorphic to Z]YT0. We can choose a map ˆg0 : YT0 → SU(2) whose degree equals minus degree ofgand extend these two maps toZ]YT0 and denote as ˜g. Then g˜has degree zero and can be extended to whole X, which we denote asg.
By the assumption that(Ai,Φi)are smooth, we haveg(A1,Φ1)−(A0,Φ0) ∈ yλ+1pH01,p. Remark. For a general compact 4-dimensional manifold with boundary, Proposi- tion 1.6.2 is not true. ForD4, the 4-dimensional unit disc, a choice of frame gives a
map fromS3 → SO(3)which isπ3(SO(3)). Two frames corresponding to different elements inπ3(SO(3))can not be globally gauge equivalent.
As we fixed a base connection(A0,Φ0)to define the framed configuration space, we can also consider the gauge group that preserves the frame.
Definition 1.6.3. The framed gauge groupGf r is defined as follows:
Gf r := {g ∈ Aut(P) | g|Y = 1}. (1.50) Giveng ∈ Gf r, the action ofgon(A0,Φ0)will be
g(A0,Φ0)= (A0−dA0g g−1,gΦ0g−1). (1.51) Then, we have
g(A0,Φ0) − (A0,Φ0)=(−dA0g g−1, [g,Φ0]g−1). (1.52) We consider the following weighted frame gauge groupGpf r,λ:
Gp,λf r = {g ∈ Gf r | dA0g g−1∈ yλ+1pH01,p(Ω1), [g,Φ0]g−1∈ yλ+1pH01,p(Ω1)}. (1.53) For convenience, we denote d0(ξ) := d(0A
0,Φ0)(ξ) = (dA0ξ,[Φ0, ξ])and we have the following lemma on the weighted frame gauge groupGp,λf r.
Lemma 1.6.4. Gp,λf r = {g ∈ Gf r | ∇0g ∈ yλ+p1Lp, ∇2
0g ∈ yλ+1p−1Lp, [Φ0,g] ∈ yλ+1pLp, ∇0[Φ0,g] ∈ yλ+p1−1Lp}.
Proof. Obviously{g ∈ Gf r | d0g ∈ yλ+p1Lp, ∇0(d0)g ∈ yλ+1p−1Lp} ⊂ Gp,λf r. For the other side, we argue as follows: take α := dA0gg−1, then α ∈ yλ+1pH01,p ,→ yλ+1p−1L2p.BydA0g = αg, we have∇0g ∈ yλ+1p−1L2psince the pointwise norm of gis 1. In addition,∇0dA0g =(∇0α)g+α∇0g.As∇0α∈ yλ+1p−1Lpand the pointwise norm ofgis 1, we have∇0αg ∈ yλ+1p−1Lp. Asα ∈ yλ+1p−1L2p,∇0g ∈ yλ+1p−1L2p, we haveα∇0g ∈ yλ+1p−1Lp. For[g,Φ0]g−1 ∈ yλ+p1H01,p(Ω1), we have[g,Φ0]g−1 ∈ yλ+1pLp. Lettingβ =[g,Φ0]g−1, then β ∈ yλ+p1Lpimplies βg =[g,Φ0] ∈ yλ+1pLp. In addition, β ∈ yλ+1pH01,pimplies∇0β ∈ yλ+p1Lpand β ∈ yλ+1p−1L2p. In addition, we have∇0g ∈ yλ+1p−1Lp, thus∇0[g,Φ0]=∇0(βg)=(∇0β)g+β∇0g ∈ yλ+1p−1Lp. Therefore,Gp,λf r ⊂ {g ∈ Gf r | ∇0g ∈ yλ+1pLp, ∇2
0g ∈ yλ+1p−1Lp}.
Thus we can rewriteGp,λf r asGp,λf r ={g ∈ Gf r |d0g ∈yλ+1pLp, ∇0d0g ∈ yλ+1p−1Lp}.
Lemma 1.6.5. The space yλ+p1+1H02,p(gP) is an algebra and yλ+p1H01,p(gP) is a module over this algebra.
Proof. For the algebra statement, we only need to proveu1u2 ∈ yλ+1p+1H02,p(gP), or equivalently,u1u2∈ yλ+1p+1Lp,∇0(u1u2) ∈ yλ+1pLp,∇2
0(u1u2) ∈ yλ+1p−1Lp. Since ui ∈ yλ+1p+1H02,p, we have ui ∈ yλ+p1+1Lp, ∇0ui ∈ yλ+p1Lp and ∇2
0ui ∈ yλ+1p−1Lp.
By Proposition 1.5.6,ui ∈ yλ+p1+1H01,p,→ yλ+p1L1p,→ yλ+p1L2p.By Corollary 1.5.7, we have u1u2 ∈ yλ+1p+1Lp. In addition, we know ∇0ui ∈ yλ+1pH01,p ,→ yλ+p1−1L2p andui ∈ yλ+1pL2p. Asλ ≥ 1−1p, we haveλ+1p+λ+1p−1≥ λ+ 1p. By the Hölder inequality in Proposition 1.5.6, we have∇0u1u2 ∈ yλ+p1Lp.
Forui ∈ yλ+1p+1H02,p, as p > 2 and λ ≥ 1− 1p, we haveui ∈ yλ+1p−1L2p ,→ C0and
∇2
0u∈ yλ+1p−1Lp. Therefore, we have∇2
0u1u2∈ yλ+1p−1Lp.
The module statement can also be proved in a similar way.
Fix a base pointp0 ∈ Xand define a system of neighborhoods of the identity inGP as
U = {g ∈ Gf r | kd0gk
yλ+p1Lp ≤ , k∇0d0gk
yλ+1p−1Lp ≤ , |g(p0) −1| ≤ }.
(1.54) This topology is independent of the base pointp0.
With the previous lemma, we can establish a Lie group structure onGf r: Corollary 1.6.6. (1)Gp,λf r is a Lie group with Lie algebra
Lie(Gp,λf r)= yλ+1p+1H02,p(gP).
(2)Gp,λf r acts smoothly onCp,λf r.
Proof. This result follows immediately from Lemma 1.6.4 and Lemma 1.6.5.
Now, we have the following proposition of the framed configuration spaceCp,λf r and the framed gauge groupGf r
p,λ:
Proposition 1.6.7. For any(A,Φ) ∈ Cp,λf r, we haveKW(A,Φ) ∈ yλ+p1−1Lp(Ω2⊕Ω0),
Proof. By the definition of Cpf r,λ, there exists (a,b) ∈ yλ+1pH01,p(Ω1(gP) ×Ω1(gP)) such that(A,Φ)=(A0,Φ0)+(a,b).
By Proposition 1.2.9, we haveKW(A,Φ)= KW(A0,Φ0)+L1(a,b)+{(a,b), (a,b)}. Here {(a,b), (a,b)} is a quadratic term. By theorem 1.5.4, we have L1(a,b) ∈ yλ+1p−1Lp(Ω2×Ω0).By the embeddingyλ+1pH01,p,→ yλ+1p−1L1p,→ yλ+1p−1L2p, we have{(a,b),(a,b)} ∈ yλ+1p−1Lp. Now we will study the behavior of the gauge group (1.53) over the cylindrical end.
We have the following proposition which describes the limit behavior of the group Gp,λf r. We need the hypothesis that ρ is acyclic. Let (Aρ,Φρ) be the flat SL(2;C) connection associate to ρ.
Recall that d(A,Φ)0 (ξ) = (dAξ,[Φ, ξ])and ρacyclic implies Ker d(0A
ρ,Φρ) = 0 and the connectiondAρ itself may still be a reducibleSU(2)connection.
We have the following lemma over the cylindrical end:
Lemma 1.6.8. SupposeXis a manifold with boundary and cylindrical end which is identified withY × (0,+∞), for(A0,Φ0)a reference connection whichL1pconverges to(Aρ,Φρ)over the cylindrical end forp >2, then forT is large enough, we have (1)d(A0
0,Φ0) :L2p(Y × (T−1,T+1)) → L1p(Y× (T −1,T +1))is injective, (2)kξkLp
2(Y×(T−1,T+1)) ≤ Ckd(A0
0,Φ0)ξkLp
1(Y×(T−1,T+1)).
Proof. For convenience, during the proof, we writeLkpshort forLkp(Y×(T−1,T+1)).
(1) Denote(a,b)=(Aρ,Φρ) − (A0,Φ0), then for anyξ ∈ L2p, we have kd(0Aρ,Φρ)ξ−d(A0
0,Φ0)ξkLp
1 ≤ C(k[a, ξ]kLp
1 +k[b, ξ]kLp
1) ≤C(kakLp
1 +kbkLp
1)kξkLp
2. Ifξ ∈Kerd(A0
0,Φ0), we obtain kd(A0ρ,Φρ)ξkLp
k
≤ C(kakLp
1 +kbkLp
1
)kξkLp
2. ForTis large enough,C(kakLp
1+kbkLp
1)is smaller than the operator norm ofd(A0
0,Φ0), which impliesξ =0.
(2) If the inequality is not true, then there exists a sequence{ξn}with kξnkLp
1 = 1, lim
n→∞kd(A0
0,Φ0)ξnkLp
1 =0, which implieskξnkLp
2 is bounded.
Then, ξn weak converges to ξ∞ in L2p and strongly converges to ξ∞ in L1p, which implies kd(A0
0,Φ0)ξ∞kLp
1 = 0 andkξ∞kLp
1 = 1. As Ker d(A0
0,Φ0) = 0, we haveξ∞ = 0, contradictingkξ∞kLp
1 =1.
We have the following corollary:
Corollary 1.6.9. If over the cylindrical end, (A0,Φ0) converges in L1p norm to (Aρ,Φρ)and(Aρ,Φρ)is an irreducible flatSL(2;C)connection, thenKerd(A0
0,Φ0) = 0.
Proof. As before, we denoted0 := d(0A
0,Φ0). By Kato inequality, we know forξ ∈Ω0, we have the pointwise estimate
d|ξ| ≤ |dA0ξ| ≤ |d0(ξ)|.
Therefore, ξ ∈ Kerd0 implies |ξ| is a constant. In addition, by Lemma 1.6.8, we knowξ = 0 overY × (T −1,T +1)whenT is large enough, therefore, we haveξ is
identically zero.
Proposition 1.6.10. If the limiting connection ρis irreducible, then forT is large enough, there is a constant C such that for any section ξ ∈gP, with d0ξ ∈ Lp(Y × [T,+∞))and∇0d0ξ ∈ Lp(Y × [T,+∞)), we have
(1)|ξ| →0at the cylindrical end andsup|ξ| ≤C(kd0ξkLp
1(Y×[T,+∞))), (2) Either|g(x) −1| →0or|g(x)+1| →0asx tends to infinity in X.
Proof. (1) For an integerk >T+1, over a bandBk :=Y × (k −1,k +1), we have kξkC0(Bk) ≤ kξkLp
2(Bk) ≤Ckd0ξkLp
1(Bk). The statement follows immediately.
(2) Denote by gk the restriction of g to the band Bk. After identifying different bands withY3× (−1,1), we can consider {gk} a sequence of gauge transformation overY3× (−1,1)withk∇0d0gkkLp, k∇0gkkLpconverging to zero. As the pointwise norm of g is always 1, by Rellich lemma,gk strongly converges tog∞ in L1pwhich impliesd0g∞ =0. By our assumption, we haveg∞ = ±1.
Now, we can define a framed quotient space as follows:
Definition 1.6.11. We defineBp,λf r as the following weighted framed moduli space:
Bp,λf r = Cp,λf r/Gp,λf r.
In addition, we have the following definition of the moduli space:
Definition 1.6.12. The framed moduli spaceMp,λf r,ρ(X)is defined as follows:
Mf r,ρ
p,λ (X)= {(A,Φ) ∈ Cp,λf r|KW(A,Φ)=0}/Gp,λf r. (1.55) We have the following basic properties of the framed moduli space:
Proposition 1.6.13. (1) For any(A,Φ) ∈ Mp,λf r,ρ satisfies the Nahm pole boundary condition.
(2) Any(A,Φ) ∈ Mp,λf r,ρ converges toρinL1pnorm.
Proof. (1) is an immediate consequences of Proposition 1.6.2. (2) is a consequence
of the definition ofCp,λf r.
Slicing Theorem
Now we study the local properties of the moduli space and we will assign a suitable norm to the Kuranishi complex (1.7).
Define(Ω0, λ,k,p)as follows:
(Ω0, λ,k,p):= yλH0k,p(Ω0(gP)).
Here the notation yλH0k,p(Ω0(gP))means the completion of the smooth sections of Ω0(gP)in the norm yλH0k,p. Similarly, we define
(Ω1×Ω1, λ,k,p):= yλH0k,p(Ω1(gP) ×Ω1(gP)) and
(Ω2×Ω0, λ,k,p):= yλH0k,p(Ω2(gP) ×Ω0(gP)).
Now we rewrite the Kuranishi complex (1.7) at the point (A0,Φ0) with respect to the new norm as follows:
0→ (Ω0, λ+1+1 p,2,p)
d(A0
0,Φ0)
−−−−−−→ (Ω1×Ω1, λ+1 p,1,p)
L(A
0,Φ0)
−−−−−−→ (Ω2×Ω0, λ+1
p−1,0,p) → 0, (1.56)
Here we only consideredλ ∈ [1− 1p,1).
We have the following Proposition for the operatord(0A
0,Φ0): Proposition 1.6.14. The operatord(A0
0,Φ0): d(0A
0,Φ0) : yλ+1+1pH02,p(Ω0(gP)) → yλ+1pH01,p(Ω1(gP) ×Ω1(gP)) is a closed operator.
Proof. see Appendix 2.
Corollary 1.6.15. yλ+1pH02,p(Ω1(gP)×Ω1(gP))= Imd(A0
0,Φ0)⊕(Kerd(A0,?
0,Φ0)∩yλ+1pH01,p)
Proof. Letx =(x1,x2) ∈ Ω1(gP) ×Ω1(gP), by definition ofd(0A
0,Φ0), we have hd(0A
0,Φ0)ξ,xi= hdA0ξ,x1i+h[Φ0, ξ],x2i whereh, imeans theL2inner product.
Integrating by parts, we have
hdA0ξ,x1i= hξ,d?A
0x1i −
∫
∂Xtr(ξ∧?x1).
Asξ ∈ yλ+1pH02,p(Ω0(gP))andx1 ∈ yλ+1pH01,p(Ω1(gP) ×Ω1(gP)), we havex1|∂X =0 andξ|∂X =0. Therefore,
hd(A0
0,Φ0)ξ,xi= hξ,d(0A,?
0,Φ0)xi.
Supposex ∈Coker d(A0
0,Φ0), then for∀ξ ∈ yλ+1p+1H02,p, we obtainhd(0A
0,Φ0)ξ,xi= 0.
As λ > −1, integrating by parts, we have hξ,d(0A,?
0,Φ0)xi = 0. Thus d(A0,?
0,Φ0)x = 0.
Combining this with Proposition 1.6.14, we finish the proof.
Fixe a reference connection pair(A0,Φ0) ∈ Cp,λf r and > 0. We set:
T(A,Φ), :={(a,b) ∈Ω1(gP) ×Ω1(gP) | d(0,?A,Φ)(a,b)=0,k(a,b)k
yλ+1pH01,p < }. (1.57) Thus we have a natural map p :T(A,Φ), → Bp,λf r, which is induced by the inclusion ofT(A,Φ), intoCp,λf r composed with quotienting by the gauge groupGpf r,λ.
We have the following slicing theorem for the moduli spaceBp,λf r.
Theorem 1.6.16. Given a point(A,Φ) ∈ Cp,λf r, denote by[(A,Φ)] ∈ Bp,λf r the equiv- alence class under the projection map. For small > 0,
(1) if(A,Φ)is irreducible, thenT(A,Φ), is a homeomorphism to a neighborhood of [(A,Φ)]inBp,λf r.
(2) if(A,Φ)is reducible, thenT(A,Φ),/Γ(A,Φ)is a homeomorphism to a neighborhood of[(A,Φ)]inBp,λf r.
Proof. Consider the map
S :T(A,Φ), × GP/{±1} → CP,
S(A+a,Φ+b,g)= g(A+a,Φ+b). (1.58) The map has derivative ata =0,b=0,g= 1 as:
DS:Kerd(A,Φ)0,? ×Ω0(gP) →Ω1(gP) ×Ω1(gP),
(a,b, ξ) → (a,b)+d(0A,Φ)(ξ). (1.59) By Corollary 1.6.15, we knowDSis always surjective.
(1) If (A,Φ)is irreducible, then DS is injective, by the implicit function theorem, we know for small enough,Sis a homeomorphism.
(2) If(A,Φ)is reducible, thenDShas kernelH(A,Φ)0 .LetH(A,Φ)0⊥ be the orthogonal of H(A,Φ)0 with respect to theL2inner product. Then this time the restriction map
S:T(A,Φ),×exp(H(A,Φ)0⊥ )/{±1} → CP
is a local diffeomorphism. In addition, the multiplication mapΓ(A,Φ)×exp(H(0A,Φ)⊥ ) → GP at the identity will have derivative 1. Thus for g ∈ GP close to 1, there exist l ∈ Γ(A,Φ) and m ∈ exp(H(0⊥A,Φ)) such that g = ml and the splitting is unique.
Therefore, we get a homeomorphism from T(A,Φ),/Γ(A,Φ) to a neighborhood of [(A,Φ)]inBp,λf r.
Kuranishi Model
Given(A0,Φ0)a solution to the Kapustin-Witten equations, all the other solutions within the sliceT(A,Φ), are given by the setZ(Ψ)of zeros of the map
T(A,Φ), Ψ
−→ yλ+1p−1Lp(Ω2(gP) ×Ω0(gP)),
Ψ(a,b)=KW(A0+a,Φ0+b)=L1(a,b)+{(a,b),(a,b)}. (1.60)
By Theorem 1.5.9,DΨis a Fredholm operator and for the homology associated to the Kuranishi complex, we have the following identification:
H(A,Φ)2 K erL?∩yλ+1p−1Lp, H(A,Φ)1 K erL ∩ (K er d(A0,?
0,Φ0)∩yλ+1pH01,p). (1.61) Therefore, we have the following Kuranishi picture of the moduli space:
Proposition 1.6.17. [18, Proposition 8] For any solution(A,Φ)withKW(A,Φ)= 0, for sufficiently small, there is a map ρ from a neighborhood of the origin in the harmonic spaceH(1A,Φ)to the harmonic spaceH(A,Φ)2 such that if(A,Φ)is irreducible, a neighborhood of[(A,Φ)] ∈ Mp,λf r is carried by a diffeomorphism onto
Z(ρ)= ρ−1(0) ⊂ H(A,Φ)1
and if(A,Φ)is reducible, then a neighborhood of[(A,Φ)]is modelled on Z(ρ)/Γ(A,Φ).