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Strong f -Randomness

Dalam dokumen I.1 Summary of Chapters (Halaman 84-89)

I. 3.1 (Partial) Recursive Functions and Sets

IV.1 Partial Randomness in h N

IV.1.2 Strong f -Randomness

A related variant of partial randomness can be defined similarly. First, from the measure-theoretic paradigm:

Definition IV.1.16(prefix-freef-weight inh). Theprefix-freef-weight of a set of stringsS⊆his defined by

pwtf(S) ∶=sup{dwtf(A) ∣prefix-freeA⊆S}.

Definition IV.1.17 (strongf-randomness inhN). A weakf-ML-test (in hN) is a uniformly r.e. sequence

⟨Akk∈Nof subsetesAk⊆h such that pwtf(Ak) ≤2k for allk∈N.

A weakf-ML-test⟨Akk∈N covers X∈hN ifX∈ ⋂k∈NJAkK. If X is covered by no weak f-ML-test, then X isstronglyf-random (in hN).

Like in{0,1}N, strongf-randomness inhN is associated with an analog of a priori complexity inh.

Definition IV.1.18(continuous semimeasure onh). Acontinuous semimeasure onhis a functionν∶h→ [0,1]such thatν(⟨⟩) =1 and for everyσ∈h,

ν(σ) ≥ ∑

i∈<h(∣σ∣)

ν(σ⟨i⟩).

A continuous semimeasureνisleft recursively enumerable, orleft r.e., if it is left r.e. as a functionh→R. A left r.e. continuous semimeasureν isuniversal if for every left r.e. continuous semimeasureξonh there existsc∈Nsuch thatξ(σ) ≤c⋅ν(σ)for allσ∈h.

Proposition IV.1.19. There exists a universal left r.e. semimeasure Mon h. Proof. The proof given in [6, Theorem 3.16.2] easily generalizes toh.

Definition IV.1.20 (a priori complexity in h). Fix a universal left r.e. semimeasure M. The a priori complexity of a stringσ∈h is defined by

KA(σ) =KAM(σ) ∶= −log2M(σ).

Akin to the well-definedness of prefix-free complexity, ifN were another universal left r.e. semimeasure, then KAMand KAN differ by at most a constant.

Definition IV.1.21(strongf-complexity inhN). X ∈hNisstronglyf-complex (inhN)if there exists ac∈N such that, for alln∈N,

KA(X↾n) ≥ (log1/2γ(X↾n)) ⋅f(X↾n) −c.

We will show that strong f-complexity is equivalent to strongf-randomness. Before doing so, we intro- duce a third approach to defining strongf-randomness/complexity, this time in terms of supermartingales as in the unpredictability paradigm.

Definition IV.1.22 (supermartingale). Asupermartingale (overh) is a functiond∶h→ [0,∞)such that

i<h(∣σ∣)

d(σ⟨i⟩) ≤h(∣σ∣)d(σ) for allσ∈h.

A supermartinagle disleft recursively enumerable, orleft r.e., if it is left r.e. as a functionh→ [0,∞).

Definition IV.1.23(f-success). Supposedis a left r.e. supermartingale andX∈hN. dis said to f-succeed onX if

lim sup

n

(d(X↾n) ⋅γ(X↾n)nf(Xn)) = ∞.

The following lemma reveals the close connection between continuous semimeasuresν and supermartin- galesdsuch thatd(⟨⟩) =1.

Lemma IV.1.24. Given ν∶h→ [0,1], letdν∶h→ [0,∞)be defined bydν(σ) ∶= ∣hσ∣ ⋅ν(σ)forσ∈h. (a) ν is left r.e. if and only if dν is left r.e.

(b) ν is a continuous semimeasure if and only ifdν is a supermartingale.

(c) ν is a universal left r.e. continuous semimeasure if and only ifdν is auniversal left r.e. supermartinagle, in the sense that ifdwere another left r.e. supermartingale then there is ac∈Nsuch thatd(σ) ≤c⋅dν(σ) for all σ∈h.

Proof.

(a) This follows from the fact thathis recursive.

(b) Givenσ∈h, we have

i<h(∣σ∣)

dν⟨i⟩) = ∑

i<h(∣σ∣)

∣hσ

i⟩∣∣ ⋅ν(σ⟨i⟩) = ∣hσ∣+1∣ ⋅ ∑

i<h(∣σ∣)

ν(σ⟨i⟩) =h(∣σ∣) ⋅⎛

∣hσ∣ ⋅ ∑

i<h(∣σ∣)

ν(σ⟨i⟩)⎞

⎠ . By comparing the first and last expressions with the definitions of what it means for dν to be a supermartingale or for ν to be a continuous semimeasure shows that dν is a supermartinagle if and only ifν is a continuous semimeasure.

(c) Straight-forward.

Lemma IV.1.25. SupposeS andT are subsets of h.

(a) IfS⊆T, then dwtf(S) ≤dwtf(T)andpwtf(S) ≤pwtf(T).

(b) dwtf(S∪T) =dwtf(S) +dwtf(T) −dwtf(S∩T).

(c) pwtf(S∪T) ≤pwtf(S) +pwtf(T), with equality if the strings inS andT are pairwise incompatible.

Proof.

(a) Straight-forward.

(b) Straight-forward.

(c) IfP ⊆S∪T is prefix-free, thenP∩S andP∩T are prefix-free subsets ofS andT, respectively, so dwtf(P) ≤dwtf(P∩S) +dwtf(P∩T) ≤pwtf(S) +pwtf(T).

Taking the supremum among all prefix-freeP ⊆S∪T yields pwtf(S∪T) ≤pwtf(S) +pwtf(T).

If the strings in S and T are pairwise incompatible, then given prefix-free subsets A⊆S and B⊆T, A∩B= ∅and A∪B is a prefix-free subset ofS∪T, so

dwtf(A) +dwtf(B) =dwtf(A∪B) ≤pwtf(S∪T).

Taking the supremum among all prefix-freeA⊆S andB⊆T yields pwtf(S) +pwtf(T) ≤pwtf(S∪T).

Theorem IV.1.26. SupposeX∈hN. The following are equivalent.

(i) X is stronglyf-random.

(ii) X is stronglyf-complex.

(iii) dh does notf-succeed onX, wheredhis the universal left r.e. supermartingale corresponding to Mas in Lemma IV.1.24.

(iv) No left r.e. supermartingale f-succeeds on X.

Proof.

(i) ⇐⇒ (ii) SupposeX is stronglyf-random. LetSi= {σ∈h∣KA(σ) < (log1/2γ(σ)) ⋅f(σ) −i}. IfP⊆Si is prefix-free, then

dwtf(P) = ∑

σP

γ(σ)f(σ)≤ ∑

σP

γ(σ)(KA(σ)+i)⋅(logγ(σ)1/2)≤ 1 2i

σP

M(σ) ≤ 1

2iM(⟨⟩) ≤ 1 2i.

Thus, ⟨Sii∈N forms a weakf-ML test. BecauseX is strongly f-random,X is not covered by ⟨Sii∈N

and so there is ani∈Nsuch thatX∉JSiK, i.e., for everyn∈Nwe have KA(X↾n) ≥ (log1/2γ(X↾n)) ⋅ f(X↾n) −i, so X is stronglyf-complex.

If X is not stronglyf-random, then there is a weakf-ML test⟨Sii∈N which coversX. Uniformly in i∈ N, we letνi be defined by νi(σ) =pwtf({τ ∈Si ∣τ ⊇ σ}). νi is a continuous semimeasure; using Lemma IV.1.25 we have

νi(σ) =pwtf({τ∈Si∣τ⊇σ})

≥pwt ({τ∈Si∣τ⊃σ})

=pwtf

j<h(∣σ∣)

{τ∈Si∣τ⊇σ⟨j⟩}⎞

= ∑

j<h(∣σ∣)

pwtf({τ∈Si∣τ⊇σ⟨j⟩})

= ∑

j<h(∣σ∣)

νi⟨j⟩).

Thatνiis left r.e. follows from the fact thatSi is r.e. Observe that forτ∈Si we have dwtf(τ) ≤νi(τ).

Because νi(⟨⟩) =pwtf(Si) ≤2i for eachi, the mapν∶h→ [0,1]defined by ν(σ) ∶=

i=0

2iν2i(σ)

forσ∈h is a left r.e. semimeasure, and hence there is ac∈Nsuch thatν(σ) <c⋅M(σ)for allσ∈h. Then forσ∈S2i, we have

exp2(i− (log1/2γ(σ)) ⋅f(σ)) =2idwtf(σ) ≤2iν2i(σ) ≤ν(σ) <c⋅M(σ) =exp2(−(KA(σ) +log1/2c)) and hence

KA(σ) +i+log1/2c< (log1/2γ(σ)) ⋅f(σ).

Being covered by ⟨Sii∈Nand hence by⟨S2ii∈N as well,X is not strongly f-complex.

(ii) ⇐⇒ (iii) Letdh be the universal left r.e. supermartingale corresponding toM, as in Lemma IV.1.24.

Now observe that for anyX∈hNandn∈N,

dh(X↾n) ⋅µ(X↾n)1f(Xn)/n=M(X↾n) ⋅µ(X↾n)1⋅µ(X↾n)1f(Xn)/n

=exp2(−(KA(X↾n) − (log1/2γ(X↾n)) ⋅f(X↾n))).

Thus, lim sup

n

d0(X↾n) ⋅µ(X↾n)1f(Xn)/n= ∞ ⇐⇒ ∀c∃n(KA(X↾n) < (log1/2γ(X↾n)) ⋅f(X↾n) −c.

In other words,dh f-succeeds onX if and only ifX is not stronglyf-complex.

(iii) ⇐⇒ (iv) If no left r.e. supermartingale f-succeeds on X, then in particular dh does not f-succeed on X. Conversely, if dh does not f-succeed on X, then the universality of dh shows that no left r.e.

supermartingale f-succeeds onX.

Corollary IV.1.27. There exists a universal weak f-ML test, i.e., a weak f-ML test ⟨Sii∈N such that X∈hN is stronglyf-random inhN if and only ifX is not covered by⟨Sii∈N.

Proof. The proof of Theorem IV.1.26 shows that lettingSi= {σ∈h∣KA(σ) < (log1/2γ(σ)) ⋅f(σ) −i}yields a universal weakf-ML test.

Corollary IV.1.28. Suppose f(σ) =f˜(σ) for almost all σ. Then strong f-randomness is equivalent to strongf˜-randomness.

Proof. Supposef(σ) =f˜(σ)for all σ∈h for which∣σ∣ >N. Letc=maxσh,σ∣≤NKA(σ). Then for every i∈ N, KA(σ) ≥ (log1/2γ(σ)) ⋅f(σ) −c−i if and only if KA(σ) ≥ (log1/2γ(σ)) ⋅f˜(σ) −c−i for allσ ∈h. It follows that strongf-complexity and strong ˜f-complexity are equivalent, and so Theorem IV.1.26 shows strongf-randomness and strong ˜f-randomness are equivalent.

Remark IV.1.29. All of the above results hold withµreplaced by any computable measure onhN for which µ(σ) >0 for allσ∈h, with one adjustment – a supermartingaled f-succeeds on X with respect toµif and only if

lim sup

n

(d(X↾n) ⋅γ(X↾n)f(Xn)⋅ ∣hn1) = ∞.

Dalam dokumen I.1 Summary of Chapters (Halaman 84-89)