• Tidak ada hasil yang ditemukan

Pelajari tentang Functions and graphs

N/A
N/A
Hafifi Omar

Academic year: 2023

Membagikan "Pelajari tentang Functions and graphs "

Copied!
94
0
0

Teks penuh

(1)
(2)

Relations and Functions

A relation is a set of pairs of input and

output values. You can represent a relation in four different ways as shown.

Not allrelation are funcition

(3)

Relations and Functions

The domain of a relation is the set of inputs, also called x-coordinates, of the ordered

pairs.

The range is the set of outputs, also called y-coordinates, of the ordered pairs.

s input p

pOutput any y

possible

(4)

Relations and Functions

Function -A type of relation where there is exactly one output for every input. For every x there is exactly one y.

Is the relation a function?

I te l many to

function

I to many

N1497 1477

M

functionis not

(5)

Relations and Functions

A function is a relation in which each element of the domain corresponds with

exactly one element of the range.

You can use the vertical-line test to

determine whether a relation is a function.

The vertical-line test states that if a vertical line passes through more than one point on

the graph of a relation, then the relation is NOT a function.

5

(6)

Relations and Functions

If a vertical line passes through a graph at more than one point, there is more than one

value in the range that corresponds to one value in the domain.

6

p

(7)

Relations and Functions

Use the vertical line test. Which graph(s) represent functions?

Graph of a function

no amp e g notGraph of a function

Use Vertical line test

to determine if Graph is

(8)

Relations and Functions

A function rule is an equation that represents an output value in terms of an input value. You can write a function rule in function notation. Shown

below are examples of functions rules.

The independent variable, x, represents the input of the function. The dependent variable, f(x),

represents the output of the function.

a input of funnier

(9)

Function Notation

y 2x 3   f (x) 2x 3  

when x 1, y   when x 2, y   when x 3, y  

when x 4, y  

f (1)  f (2) 

f (3)  f (4) 

M 2 7 3

Replace hwithgiven Value 22 3

(10)

Other example:

Given

Evaluate:

. 5 ,

8

5 1

, 4 2

5

0 5

, 1 )

(

2

x x

x x

x x

x h

3 2

) 8 (

) 5 ( 8 )

5 (

h

h

h

PracticeMare

Piecewise f

fytica medlarMedical p

r

square

pas ca is

d 97 81317 at E

F

h C S

F

1 2

h s Undifine h s 5 5 2 4

31

h 8 868383512

(11)

The last thing we need to learn about functions for

this section is something about their domain. Recall domain meant "Set A" which is the set of values you plug in for x.

For the functions we will be dealing with, there are two "illegals":

1. You can't divide by zero (denominator (bottom) of a fraction can't be zero)

2. You can't take the square root (or even root) of a negative number

When you are asked to find the domain of a function, you can use any value for x as long as the value

How to find domain of function

must be realnumber

(12)

Find the domain for the following functions:

  x 2 x 1

f

Since no matter what value you

choose for x, you won't be dividing by zero or square rooting a negative number, you can use anything you want so we say the answer is:

All real numbers x.

  2 3

  x x x

g

If you choose x = 2, the denominator will be 2 – 2 = 0 which is illegal

because you can't divide by zero.

The answer then is:

All real numbers x such that x 2.

means does not equal illegal if this is

zero

Note: There is nothing wrong with the top = 0 just means the

fraction = 0

12

gen I has Nti o

n Sato 9

D n 213 Nosolution

Dg In1213

N 2 0

(13)

Let's find the domain of another one:

  x x 4

h

We have to be careful what x's we use so that the second

"illegal" of square rooting a negative doesn't happen. This means the "stuff" under the square root must be greater

than or equal to zero (maths way of saying "not negative").

Can't be negative so must be 0

0 4 

x

solve this

x  4

So the answer is:

stoopDha IF

p.mg az

a 4

224

É hens

In21

2 420 no

Ming actin

(14)

Find the domain of each function:

5 . 1

1  

y x

17 4

.

2 yx

9 .

3 yx

99 .

4 yx 2

Nts 20 D

at

s

22 5

42

III L

Nta 20

Do a 2 a N 9920

x 2 99

(15)

The sum f + g

f g   x f     x g x

This just says that to find the sum of two functions, add them together. You should simplify by finding like terms.

  x 2 x

2

3 g   x 4 x

3

1

f

1 4

3

2

2

 

3

g x x

f

4 2

4

3

2

x x

Combine like terms & put in

descending

(16)

The difference f - g

f g   x f     x g x

To find the difference between two functions, subtract the first from the second. CAUTION: Make sure you

distribute the – to each term of the second function. You should simplify by combining like terms.

  x 2 x

2

3 g   x 4 x

3

1

f 2

2

3 4

3

1

g x x

f

1 4

3

2

2

 

3

x x

Distribute negative

2 2

4

3

2

x x

(17)

The product f • g

f g   x f     x g x

To find the product of two functions, put parenthesis around them and multiply each term from the first

function to each term of the second function.

  x 2 x

2

3 g   x 4 x

3

1

f g 2 x

2

3  4 x

3

1

f

3 12

2

8

5

2

3

x x x

FOIL

Good idea to put in descending order

but not required.

(18)

The quotient f / g

   

  x

g

x x f

g

f  

 

To find the quotient of two functions, put the first one over the second.

  x 2 x

2

3 g   x 4 x

3

1

f

1 4

3 2

3 2

 

x x g

f

Nothing more you could do

here. (If you can reduce these you should).

(19)

Adding and Subtracting Functions

   

g - f and g

f Find

. 12 2

g and

8 3

f Let

x x x

x

ft g 1 I ate C D SCD 4

fca 3ns

3ex a 8 323ats

i

y Cftg ca fc iltgC D

tcaestgagII 3E.us

32 8 tan 12

(20)

Multiplying / Dividing Functions

   





g Find f

. 1 g

and 1 - f

Let x x2 x x

  ( )

and f x g x

f

Caz

IS

f N gcn x I

(21)

Domain of (f + g)(x):

Domain of (f - g)(x):

Domain of (f ∙g)(x):

Domain of : {x|g(x)≠0}

g

f D

D

g

f D

D

g

f D

D

) (x g

f 



DfDg

the set of

all real numbers common to the domain of f and g

Domain of (f/g)(x) consists of the

numbers x for which g(x)≠0 that are in the domain of

both f and g

Domain of Function

(22)

Let f and g be two functions defined as

) )(

( ) (

) )(

( ) (

x g f b

x g f a

2 ) 1

(

x x

f .

) 1

(

x x x

and g

) ( )

(

) )(

( ) (

g x d f

x g f c





Determine domain of the following.

find domain of f andg

Df at 23 Dg at

for natl goa Fi o

DgMDg NE230 Df NER unto ng

Tgif

Dg x2 13

no nCnt2 n at at 2,011

Find

T

Domain

gon

ng

o

n o

(23)

You should be familiar with the shapes of these basic

functions. We'll learn them in this section.

(24)

Odd and Even Functions

A function f is even if

f(

x) = f(x) for all x in its domain.

A function f is odd if

f(

x) =

f(x) for all x in its domain.

Vertical line of

reflection at x = 0

Point of rotational symmetry

f N n an

n ens an

not cnaans

(25)

2

-7 -6 -5 -4 -3 -2 -1 0 1 3 4 5 6 7 8 7

1 2 3 4 5 6 8

-2 -3 -4 -5 -6 -7

So for an even function, for every point (x, y) on the graph, the point (-x, y) is also on the graph.

Even functions have y-axis Symmetry

(26)

Constant Functions

f(x) = b, where b is a real number

The domain of these functions is all real numbers.

The range will only be b

f(x) = 3 f(x) = -1 f(x) = 1

Would constant functions be even or odd or neither?

x

f ( x ) b

straightlinepassingthrough

gexist

(27)

Equations that can be written f(x) = mx + b

The domain of these functions is all real numbers.

slope y-intercept

Passingthroughyexist

(28)

Identity Function

f(x) = x, slope 1, y-intercept = 0

The domain of this function is all real numbers.

The range is also all real numbers

f(x) = x

Would the identity function be even or odd or neither?

If you put any real

number in this function, you get the same real number “back”.

x

f ( x )

linepassingthroughorigin

(29)

Square Function

f(x) = x2

The domain of this function is all real numbers.

Would the square function be even or odd or neither?

x

f x n

neven even f

n odd odd f

(30)

Cubic Function

f(x) = x3

The domain of this function is all real numbers.

The range is all real numbers

Would the cube function be even or odd or neither?

f ( x )

x

(31)

Square Root Function

The domain of this function is

Would the square root function be even or odd or neither?

  x x

f

x : x 0

(32)

Absolute Value Function

The domain of this function is all real numbers.

The range is

Would the

absolute value function be even or odd or neither?

  x x

f

f ( x ) : f ( x ) 0

x

(33)

Reciprocal Function

The domain of this function is all NON-ZERO real numbers.

Would the

reciprocal function be even or odd or neither?

  x x

f 1

x : x 0

(34)
(35)

VERTICAL TRANSLATIONS

Basic graph: f

 

x x2

   









x y

   









x y

 

x 1 x2 1

f

   









x y

 

x 3 x2 3

f

  x x

2

f

As you can see,

a number added or

subtracted from a function will cause a vertical

shift or

translation in the function.

existstay sexistshiftup

byinnit

(36)

VERTICAL TRANSLATIONS

Basic graph: f

 

x x

 

x 2 x 2

f So the graph

f(x) + k, where k is any real

number is the graph of f(x) but vertically shifted by k. If

k is positive it will shift up. If k is negative it will shift down

   









x y

   









x y

   









x y

 x 4 x 4

f

 x x

f

D NER

R 92watfrom4 a

movingupward

(37)

 

x x2

f

   









x y

As you can see, a number

added or

subtracted from the x will cause

a horizontal shift or

translation in the function but opposite way of

the sign of the number.

HORIZONTAL TRANSLATIONS

   









x y

   









x

y

f   x x

2

x 1

 

x 1

2

f

x 2

 

x 2

2

f

Basic graph:

(38)

HORIZONTAL TRANSLATIONS

 

x x3

f

   









x y

   









x y

   









x

x 1

 

x 1

3 y

f f  x x3

x 3  x 33

f

So the graph

f(x-h), where h is any real number is

the graph of f(x) but horizontally

shifted by h.

Notice the negative.

(If you set the stuff in parenthesis = 0 & solve it will tell you how to shift

along x axis).

shift right 3

Basic graph:

(39)

   









x y

    







x y

    







x y

We could have a function that is transformed or translated both vertically AND horizontally.

 

x x

f

 

x x 2

f

up 3

left 2

Step 1: Basic graph:

Step 2: Graph:

 x x

f

 x (x2) f

 x (x2) 3

f bysunit

moveleftaunit

mm

D 22 2 RY233

(40)

and

If we multiply a function by a non-zero real number it has the affect of either stretching or compressing the function because it causes the function value (the y value) to be multiplied by that number.

Let's try some functions from our library of functions multiplied by non-zero real numbers to see this.

DILATION

(41)

Basic graph: f

 

x x

So the graph

a f(x), where a

is any real number GREATER THAN 1, is the

graph of f(x) but vertically

stretched or dilated by a

factor of a.

   









x y

   









x y

   









x y

 x x

f

 

x x

f 2

2 4 f  x 4 x

Notice for any x on the graph, the new (red) graph has a y value that is 2 times as much as the

original (blue) graph's y value.

f x

email

I

kSens k71

basicgraph

(42)

So the graph

a f(x), where a

is 0 < a < 1, is the graph of

f(x) but vertically compressed or dilated by a

factor of a.

   









x y

   









x y

   









x y

Notice for any x on the graph, the new (green) graph has a y value that is 1/4 as much as te original (blue)

graph's y value.

 x x

f 4

1 4

1

What if the value of a was positive but less than 1?

 x x

f

 x x

f 2

1 2

1

Basic graph: f

 

x x

graphverticallycompress compressp andbecome

furtherthenyexist

x Xx

(43)
(44)

So the graph - f(x) is a reflection about the x-axis of the graph of f(x).

(The new graph is obtained by

"flipping“ or reflecting the function over the

x-axis)

   









x y

What if the value of a was negative?

   









x y

 

x x

f

 x x

f

Notice any x on the new (red) graph has a y value that is the negative of the original

(blue) graph's y value.

Basic graph: f

 

x x

Noredreal

Noexpression a realnumber

(45)

   









x y

 

x x3

f

There is one last transformation we want to look at.

   









x y

Notice any x on the new (red) graph has an x value that is the negative of the original (blue) graph's x value.

 x x3

f

   

x x 3

f So the graph

f(-x) is a reflection about the y-axis of the graph of f(x).

(The new graph is obtained by

"flipping“ or reflecting the function over the

y-axis)

Basic graph:

(46)

Summary of Transformations So Far

horizontal translation of h (opposite sign of number

with the x)

If a > 1, then vertical dilation or stretch by a factor of a

vertical translation of k If 0 < a < 1, then vertical dilation or compression by a factor of a

f(-x) reflection about y-axis

Do reflections BEFORE vertical and horizontal translations

If a < 0, then reflection about the x-axis (as well as being dilated by a factor of a)

b k

h f x

a  

 

  ( )

horizontal dilation by a factor of b

(47)

Graph

using transformations

 

1

2 1

x

x f

We know what the graph would look like if it was

from our library of functions.  

x x

f 1

   









x y

   









x y

   









x y

   









x y

   







x y

 x x

f 1  

x x

f 1   1 1

x x

f   1

2 1

x x

f

t

D n 2

R y 1

(48)

The Composition Function

f g   x fg   x

This is read “f composition g

and means to copy the f

function down but where ever you see an x, substitute in the g function.

 

x 2x2 3 g

 

x 4x3 1

f

( )

2 ( ) 3 2

4 1

3

) )(

( f g x f g x g x 2 x3 2

5 16

32 3

2 16

32 63    63

x x x x

1. Evaluate the inner function g(x) first.

2. Then use your answer as the input of the outer function f(x).

g

(49)

g f   x gf   x

This is read “g composition f

and means to copy the g

function down but where ever you see an x, substitute in the f function.

  x 2 x

2

3 g   x 4 x 1

f

 

2 31 8 13

4

1 )

( 4

) ( )

)(

(

2

2

   

x x

x f

x f

g x

f g

1. Evaluate the inner function f(x) first.

2. Then use your answer as the input of the outer function g(x).

(50)

f f   x ff   x

This is read “f composition f” and means to copy the f

function down but where ever you see an x, substitute in the f function. (So sub the function into itself).

  x 2 x

2

3 g   x 4 x

3

1

f

2 33

2

2

2

x

f

fla

(51)

Example – Composition of Functions

g f

 

x g

f

 

x

 

x g(x 2) (x 2)2

g

49 )

7

( 

2

 

x 2 and

 

.Find

  

5

f

Let  xg xx2 gf

Method 1:

g f

  

5 5 2

2

Method 2:

g f

 

x g

f

 

x

 

f 5

g(5 2)

g

49 )

7

( 

2

) (7

g

(52)

Let’s try some

 

and

 

7 .Find

  

2

Let f x x3 g x x2 g f

gof x gtf n

fix 7

x 7

N't 7 gof 2 2 t 7

71

g f a gtfo f 27 238

g 87 8 7

(53)

INVERSE

FUNCTIONS

(54)
(55)

Verifying Inverse Function

Show that each function is an inverse of the other:

   

3 ) 2

( and 2

3 ) ( . 2

5 and 5 .

1

x x g x

x f

x x g x

x f

(56)
(57)

Find the inverse of   Answer:

x x

f

2

4  

2 4

1 2

x

x f

(58)

To be a one-to-one function, each y value could only be paired with one x. Let’s look at a couple of graphs.

Look at a y value (for

example y = 3)and see if there is only one x value on the graph for it.

This is a many-to-one function

For any y value, a horizontal line will only intersection the graph once so will only have one x value

This then IS a one-to-one

Gambar

Graph of a function
Step 2: Graph:
graph of f(x)  but vertically
graph vertically compress compress p and become
+5

Referensi

Dokumen terkait