LB-1
LAMPIRAN B NERACA ENERGI
Hasil perhitungan neraca panas pada Prarancangan Pabrik Propilen Glikol dari Propilen Oksida dan Air adalah sebagai berikut :
Kapasitas Produksi : 100.000 Ton/Tahun Waktu Operasi : 330 hari/tahun Basis Perhitungan : 1 jam operasi Satuan Operasi : kJ/jam
Temperatur Referensi : 25oC (298,15 K)
Entalpi bahan pada temperatur dan tekanan tertentu adalah : ΔH = ΔHT - ΔHf
Keterangan :
ΔH = Perubahan Entalpi
ΔHT = Entalpi bahan pada suhu T
ΔHf = Entalpi bahan pada suhu referensi (25oC)
(Himmelblau,ed.6,1996)
Entalpi bahan untuk campuran dapat dirumuskan sebagai berikut : ΔH = N. Cp. ΔT dengan ΔT = T – T0
(Himmelblau,ed.6,1996)
Dimana :
ΔH : perubahan Entalpi
Cp : Kapasitas panas (kJ/kmol.K) N : Mol senyawa (kmol)
T0 : Temperatur referensi (25oC) T : Temperatur senyawa (oC)
LB-2
B.1 Kapasitas Panas Komponen
CP∆T = ∫ CPdT
T
T0
CP cairan = ∫[A + BT + CT2 + DT3]
T
T0
dt
= A(T − T0) +B
2(T2− T02) +C
3(T3− T03) +D
4(T4− T04)
CP gas = ∫[A + BT + CT2+ DT3+ ET4]
T
T0
dt
= A(T − T0) +B
2(T2− T02) +C
3(T3− T03) +D
4(T4− T04) +E
5(T5− T05)
Keterangan :
Cp : Kapasitas panas (J/mol.K) A,B,C,D : Konstan
Tref : Temperatur referensi (298,15 K) T : Temperatur operasi (K)
Tabel B.1 Kapasitas Panas Cairan, CP (g) = A + BT + CT2 + DT3 (J/mol.K)
Komponen A B C D
Propilen Oksida 53.347 5.15E-01 -1.80E-03 2.78E-06 Air 92.053 -4.00E-02 -2.11E-04 5.35E-07 Propilen Glikol 118.614 6.73E-01 -1.84E-03 2.13E-06 Asam Sulfat 26.004 7.00E-01 -1.39E-03 1.03E-06
Tabel B.2 Kapasitas Panas Gas, CP (g) = A + BT + CT2 + DT3 + ET4 (J/mol.K)
Komponen A B C D E
Propilen Oksida 29,501 9,25E-02 2,56E-04 -2,99E-07 9,03E-11 Air 33,933 -8,42E-03 2,99E-05 -1,78E-08 3,69E-12 Propilen Glikol 14,404 3,26E-01 -7,87E-05 -1,24E-07 7,48E-11 Asam Sulfat 9,486 3,38E-01 -3,81E-04 2,13E-07 -4,69E-11 (Yaws, 1996)
LB-3
B.2 Perhitungan Neraca Panas pada Alat Proses 1. Pompa I (P-101)
Fungsi dari pompa 1 (P-101) yaitu untuk mengalirkan air yang berasal dari tangki penyimpanan dari tekanan 1 atm menjadi 3 atm sebelum diumpankan ke dalam reaktor CSTR (CSTR-100).
Gambar B.1 Pompa I (P-101)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q4 = Q5
Panas Masuk Alur 4 Tin : 303,15 K Tref : 298,15 K
N C3H6O : 0,0637 kmol/jam Q4 C3H6O : N × Cp × ∆T
: 0,0637 kmol/jam × 273,1032 kJ/kmol.K × (303,15 K – 298,15 K) : 86,9580 kJ/jam
Tin : 303,15 K Tref : 298,15 K
N H2O : 415,4345 kmol/jam Q4 H2O : N × Cp × ∆T
: 415,4345 kmol/jam × 459,7569 kJ/kmol.K × (303,15K – 298,15K) : 954.994,3866 kJ/jam
Qin total : 955.081,3446 kJ/jam
LB-4
Panas Keluar Alur 5 Tin : 303,17 K Tref : 298,15 K
N H2O : 415,4345 kmol/jam Q5 H2O : N × Cp × ∆T
: 415,4345 kmol/jam × 274,2209 kJ/kmol.K × (303,17K – 298,15K) : 87,6631 kJ/jam
Tin : 303,17 K Tref : 298,15 K
N C3H6O : 0,0637 kmol/jam Q5 C3H6O = N × Cp × ∆T
= 0,0637 kmol/jam × 461,5938 kJ/kmol.K × (303,17K – 298,15K)
= 962.645,2934 kJ/jam Qout total = 962.732,9566 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout total - Qin total
= 962.732,9566 kJ/jam – 955.081,3446 kJ/jam
= 7.651,6119 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 955.081,3446 kJ/jam + Q supply = 962.732,9566 kJ/jam + 5% Q supply
Q supply - 5% Q supply = 962.732,9566 kJ/jam – 955.081,3446 kJ/jam 0,95 Q supply = 7.651,6119 kJ/jam
Q supply = 8.054,3284 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x -8.054,3284 kJ/Jam Q loss = 402,7164 kJ/Jam
LB-5
Tabel B.3 Hasil Perhitungan Neraca Energi pada Pompa I (P-101)
Komponen Panas Masuk Panas Keluar
Q4 (kJ/jam) Q6 (kJ/jam)
Propilen Oksida 86,9580 87,6631
Air 954.994,3866 962.645,2934
Qsupply 8.054,3284
Qloss 402,7164
Total 963.135,6730 963.135,6730
2. Pompa II (P-102)
Fungsi dari pompa II (P-102) yaitu untuk mengalirkan propilen oksida yang berasal dari tangki penyimpanan dari tekanan 2 atm menjadi 3 atm sebelum diumpankan ke dalam reaktor CSTR (CSTR-100).
Gambar B.2 Pompa II (P-102)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q2 = Q6
Panas Masuk Alur 2 Tin : 298,15 K Tref : 298,15 K
N C3H6O : 164,5130 kmol/jam Q2 C3H6O : N × Cp × ∆T
: 164,5130 kmol/jam × 0 kJ/kmol.K × (298,15K – 298,15K) : 0 kJ/jam
LB-6
Tin : 298,15 K Tref : 298,15 K
N H2O : 1,6617 kmol/jam Q2 H2O : N × Cp × ∆T
: 1,6617 kmol/jam × 0 kJ/kmol.K × (298,15K – 298,15K) : 0 kJ/jam
Qin total : 0 kJ/jam
Panas Keluar Alur 6 Tin : 298,23 K Tref : 298,15 K
N C3H6O : 164,5130 kmol/jam Q6 C3H6O : N × Cp × ∆T
: 164,5130 kmol/jam × 4,2768 kJ/kmol.K × (298,23K – 298,15K) : 56,1898 kJ/jam
Tin : 298,23 K Tref : 298,15 K
N H2O : 1,6617 kmol/jam Q6 H2O : N × Cp × ∆T
: 1,6617 kmol/jam × 7,3641 kJ/kmol.K × (298,23K – 298,15K) : 0,9790 kJ/jam
Qout total : 57,1688 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 57,1688 kJ/jam – 0 kJ/jam
= 57,1688 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 0 kJ/Jam + Q supply = 57,1688 kJ/jam + 5% Q supply
LB-7
Q supply - 5% Q supply = 57,1688 kJ/jam – 0 kJ/Jam 0,95 Q supply = 57,1688 kJ/jam
Q supply = 60,1777 kJ/Jam Q loss = 5% dari Q supply Q loss = 5% x 60,1777 kJ/Jam Q loss = 3,0089 kJ/Jam
Tabel B.4 Hasil Perhitungan Neraca Energi pada Pompa II (P-102)
Komponen Panas Masuk Panas Keluar
Q2 (kJ/jam) Q6 (kJ/jam)
Propilen Oksida 0 56,1898
Air 0 0,9790
Qsupply 60,1777 0
Qloss 0 3,0089
Total 60,1777 60,1777
3. Pompa III (P-103)
Fungsi dari pompa III (P-103) yaitu untuk mengalirkan asam sulfat yang berasal dari tangki penyimpanan dari tekanan 1 atm menjadi 3 atm sebelum diumpankan ke dalam reaktor CSTR (CSTR-100).
Gambar B.3 Pompa III (P-103)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q3 = Q7
Panas Masuk Alur 3 Tin : 303,15 K
LB-8
Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q3 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 138,7171 kJ/kmol.K × (303,15K – 298,15K) : 100,8493 kJ/jam
Tin : 303,15 K Tref : 298,15 K
N H2O : 145,2575 kmol/jam Q3 H2O : N × Cp × ∆T
: 145,2575 kmol/jam × 459,7569 kJ/kmol.K × (303,15K – 298,15K) : 333.915,6670 kJ/jam
Qin total : 334.016,5163 kJ/jam
Panas Keluar Alur 7 Tin : 303,17 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q7 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 139,3066 kJ/kmol.K × (303,17 K – 298,15K) : 101,6830 kJ/jam
Tin : 303,17 K Tref : 298,15 K
N H2O : 145,2575 kmol/jam Q7 H2O : N × Cp × ∆T
: 145,2575 kmol/jam × 461,5938 kJ/kmol.K × (303,17K – 298,15K) : 336.590,8216 kJ/jam
Qout total : 336.692,5046 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 336.692,5046 kJ/jam – 334.016,5163 kJ/jam
LB-9
= 2.675,9884 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 334.016,5163 kJ/jam + Q supply = 336.692,5046 kJ/jam + 5% Q supply
Q supply - 5% Q supply = 336.692,5046 kJ/jam – 334.016,5163 kJ/jam 0,95 Q supply = 2.675,9884 kJ/jam
Q supply = 2.816,8298 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x 2.816,8298 kJ/Jam Q loss = 140,8415 kJ/Jam
Tabel B.5 Hasil Perhitungan Neraca Energi pada Pompa III (P-102)
Komponen Panas Masuk Panas Keluar
Q3 (kJ/jam) Q7 (kJjam)
Air 333.915,6670 336.590,8216
Asam Sulfat 100,8493 101,6830
Qsupply 2.816,8298
Qloss 140,8415
Total 336.833,3461 336.833,3461
4. Continuous Stirred Tank Reactor (CSTR-100)
Continuous Stirred Tank Reactor berfungsi tempat terjadinya reaksi antara Propilen Oksida dan Air dengan katalis asam Sulfat, Reaksi:
C3H6O + H2O → C3H8O2
LB-10
Gambar B.4 Continuous Stirred Tank Reactor (CSTR-100)
Neraca Panas Total
Panas Masuk = Panas Keluar Q5 + Q6 + Q7 = Q8
Panas Masuk Alur 5 Tin : 303,17 K Tref : 298,15 K
N C3H6O : 0,0637 kmol/jam Q5 C3H6O : N × Cp × ∆T
: 0,0637 kmol/jam × 274,2209 kJ/kmol.K × (303,17K – 298,15K) : 87,6631 kJ/jam
Tin : 303,17 K Tref : 298,15 K
N H2O : 415,4324 kmol/jam Q5 H2O : N × Cp × ∆T
: 415,4324 kmol/jam × 461,5938 kJ/kmol.K × (303,17K-298,15K) : 962.645,2934 kJ/jam
Qin : 962.731,9776 kJ/jam Panas Masuk Alur 6
Tin : 298,23 K Tref : 298,15 K
LB-11
N C3H6O : 164,5130 kmol/jam Q6 C3H6O : N × Cp × ∆T
: 164,5130 kmol/jam × 4,2694 kJ/kmol.K × (298,23K – 298,15K) : 56,1898 kJ/jam
Tin : 298,23 K Tref : 298,15 K
N H2O : 1,6617 kmol/jam Q6 H2O : N × Cp × ∆T
: 1,6617 kmol/jam × 7,3641 kJ/kmol.K × (298,23K – 298,15K) : 0,9790 kJ/jam
Qin : 57,1688 kJ/jam
Panas Masuk Alur 7 Tin : 303,17 K Tref : 298,15 K
N H2O : 145,2575 kmol/jam Q7 H2O : N × Cp × ∆T
: 145,2575 kmol/jam × 461,5938 kJ/kmol.K × (303,17K-298,15K) : 336.590,8216 kJ/jam
Tin : 303,17 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q7 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 139,3066 kJ/kmol.K × (303,17K – 298,15K) : 101,6830 kJ/jam
Qin : 336.692,5046 kJ/jam Qin total : 1.299.481,6510 kJ/jam
LB-12
Panas Masuk Alur 8 Tin : 327,15 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q8 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 1.749,6358 kJ/kmol.K × (327,15K – 298,15K) : 12.342,5757 kJ/jam
Tin : 327,15 K Tref : 298,15 K
N H2O : 394,0204 kmol/jam Q8 H2O : N × Cp × ∆T
: 394,0204 kmol/jam × 2.651,1157 kJ/kmol.K × (327,15K-298,15K) : 30.600.744,5003 kJ/jam
Tin : 327,15 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q8 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 1.037,5400 kJ/kmol.K × (327,15K – 298,15K) : 4.375,9784 kJ/jam
Tin : 327,15 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q8 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 3.708,1678 kJ/kmol.K × (327,15K-298,15K) : 17.671.897,6337 kJ/jam
Qout : 48.289.359,6880 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
LB-13
= 48.289.359,6880 kJ/jam – 1.299.481,6510 kJ/jam
= 46.989.878,0370 kJ/jam
Menghitung panas reaksi :
Reaksi : C3H6O + H2O → C3H8O2
a. Menghitung Entalpi pada keadaan standar (ΔHR (327,15K))
Data ΔHR masing-masing komponen pada keadaan standar (298,15oK) dapat dilihat pada table B.6
Tabel B.6 ΔHR Entalpi Entalpi Standar Masing-Masing komponen Komponen ΔHf (kJ/kmol)
C3H6O -241.8
H2O -92.76
C3H8O2 -421.5
ΔHf = ΔHf produk – ΔHf reaktan
= -421,5 kJ/kmol – (-241,8+(-92,76)) kJ/kmol
= -86,94 kJ/kmol
Karena bernilai negatif sehingga reaksi bersifat eksotermis.
b. Menghitung entalpi pada kondisi operasi
Perubahan entalpi dari suhu 298,23 K ke 327,15 K dapat ditentukan dengan persamaan sebagai berikut :
∆HR(298,23) = ∆HR(298,15) + ∫ CPdT
T
T0
dengan:
∫ ∆CPdT
327,15K
298,23 K
= A(T − T0) +B
2(T2 − T02) +C
3(T3− T03) +D
4(T4− T04)
= 8.085,3856 kJ/kmol Sehingga entalpi pada keadaan operasi adalah :
LB-14
∆HR(298,23) = ∆HR(298,15) + ∫ CPdT
327,15 K
298,23 K
= 7.998,4456 kJ/kmol c. Menghitung Panas Reaksi
Jumlah CH3OH mula-mula (FAO) = 166,1747 kmol/jam Konversi = 99,85%
Maka panas reaksi :
Q reaksi = ΔHR(327,15) . FAO . X
= 7.998,4456 kJ/kmol x 164,5766 kmol/jam x 99,85%
= 1.314.382,7295 kJ/jam
d. Menghitung panas dan massa air pendingin Qin – Qout + Qreaksi – Qkon = Qacc
Qin – Qout + Qreaksi – Qkon = 0 Q cw = Qin – Qout + Qreaksi
=1.299.481,6510 kJ/jam – 48.289.359,6880 kJ/jam +1.314.382,7295 kJ/jam
= -45.675.495,3075 kJ/jam
Tabel B.7 Hasil Perhitungan Neraca Energi pada Continuous Stirred Tank Reactor (CSTR-100)
Komponen
Masuk (kJ.jam) Keluar
(kJ/jam)
ΔQ1 ΔQ2 ΔQ3
Propilen Oksida 56,1898 87,6631 12.342,5757
Air 0,9790 962.645.2934 336.590,8216 30.600.744,5003
Propilen Glikol 17.671.897,6337
Asam Sulfat 101,6830 4.374,9784
Qreaksi 1.314.382,7295
Qserap -45.675.495,3075
Total 2.613.864,3806 2.613.864,3806
LB-15
5. Heat Exchanger (E-101)
Fungsi dari heat exchanger (E-101) yaitu memanaskan komponen yang berasal dari keluaran reaktor (CSTR-100) dari suhu 54oC menjadi 90oC.
Gambar B.5 Heat Exchanger (E-101)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q8 = Q9
Panas Masuk Alur 8 Tin : 327,15 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q8 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 1.749,6358 kJ/kmol.K × (327,15K – 298,15K) : 12.342,5757 kJ/jam
Tin : 327,15 K Tref : 298,15 K
N H2O : 394,0204 kmol/jam Q8 H2O : N × Cp × ∆T
: 394,0204 kmol/jam × 2.651,1157 kJ/kmol.K × (327,15K-298,15K) : 30.600.744,5003 kJ/jam
Tin : 327,15 K Tref : 298,15 K
LB-16
N H2SO4 : 0,1454 kmol/jam Q8 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 1.037,5400 kJ/kmol.K × (327,15K - 298,15K) : 4.375,9784 kJ/jam
Tin : 327,15 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q8 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 3.708,1678 kJ/kmol.K × (327,15K-298,15K) : 17.671.879,6337 kJ/jam
Qin total : 48.289.359,6880 kJ/jam
Panas Keluar Alur 9 Tin : 363,15 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q9 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 4.403,7644 kJ/kmol.K × (363,15K - 298,15K) : 69.630,1884 kJ/jam
Tin : 363,15 K Tref : 298,15 K
N H2O : 398,0204 kmol/jam Q9 H2O : N × Cp × ∆T
: 398,0204 kmol/jam × 5.882,1124 kJ/kmol.K × (363,15K-298,15K) : 152.178.040,4015 kJ/jam
Tin : 363,15 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam
LB-17
Q9 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 3.047,5668 kJ/kmol.K × (363,15K-298,15K) : 28.803,1280 kJ/jam
Tin : 363,15 K Tref : 298,15 K
N C3H8O2 : 165,9253 kmol/jam Q9 C3H8O2 : N × Cp × ∆T
: 165,9253 kmol/jam × 8,972,5441 kJ/kmol.K × (363,15K-298,15K) : 96.770.167,0599 kJ/jam
Qout total : 248.118.230,5413 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 248.118.230,5413 kJ/jam – 48.289.359,6880 kJ/jam
= 199.828.870,8533 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 48.289.359,6880 kJ/jam + Q supply = 248.118.230,5413 kJ/jam + 5% Q supply Q supply - 5% Q supply = 248.118.230,5413 kJ/jam – 48.289.359,6880 kJ/jam 0,95 Q supply = 199.828.870,8533 kJ/jam
Q supply = 210.346.179,9923 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x 210.346.179,9923 kJ/Jam Q loss = 10.517.308,9923 kJ/Jam
Tabel B.8 Hasil Perhitungan Neraca Energi pada Heat Exchanger (E-101)
Komponen Panas Masuk Panas Keluar
Q8 (kJ/jam) Q9 (kJ/jam)
Propilen Oksida 12.342,5757 69.630,1884
LB-18
Air 30.600.744,5003 152.178.040,4015
Asam Sulfat 4.374,9784 28.803.1280
Propilen Glikol 17.871.897,6337 95.841.756,8235 Qsupply 210.346.179,9923
Qloss 10.517.308,9923
Total 258.635.639,5336 258.635.639,5336
6. Distilasi I (T-101)
Fungsi dari distilasi 1 (T-101) yaitu untuk memisahkan antara propilen oksida dan air dengan propilen glikol dan asam sulfat.
Gambar B.6 Distilasi I (T-101)
Neraca Panas Total
Panas Masuk = Panas Keluar Q9 = Q10 + Q11
Panas Keluar Alur 9 Tin : 363,15 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q9 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 4.403,7644 kJ/kmol.K × (363,15K - 298,15K) : 69.630,2884 kJ/jam
LB-19
Tin : 363,15 K Tref : 298,15 K
N H2O : 398,0204 kmol/jam Q9 H2O : N × Cp × ∆T
: 398,0204 kmol/jam × 5.882,1124 kJ/kmol.K × (363,15K-298,15K) : 152.178.040,4015 kJ/jam
Tin : 363,15 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q9 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 3.047,5668 kJ/kmol.K × (363,15K-298,15K) : 28.807,1280 kJ/jam
Tin : 363,15 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q9 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 8,972,5441 kJ/kmol.K × (363,15K-298,15K) : 95.841.756,8235 kJ/jam
Qint total : 248.118.230,5413 kJ/jam
Panas Keluar Atas Alur 10 Tin : 371,48 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q10 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 5.081,1613 kJ/kmol.K × (371,48K - 298,15K) : 90.641,2609 kJ/jam
LB-20
Tin : 371,48 K Tref : 298,15 K
N H2O : 398.0200 kmol/jam Q10 H2O : N × Cp × ∆T
: 398.0200 kmol/jam × 6619,2714 kJ/kmol.K × (371,48K -298,15K) : 193.204.834,1219 kJ/jam
Qout atas total : 193.295.475,3900 kkal/jam
Panas Keluar Bawah Alur 11 Tin : 460,8 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q11 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.234,6393kJ/kmol.K × (460,8 K -298,15K) : 981,6892 kJ/jam
Tin : 460,8 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q11 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 11.687,0547kJ/kmol.K × (460,8K- 298,15K) : 276.382,6861 kJ/jam
Tin : 460,8 K Tref : 298,15 K
N C3H8O2 : 165,9253 kmol/jam Q11 C3H8O2 : N × Cp × ∆T
: 164,3334kmol/jam × 25.928,9468kJ/kmol.K × (460,8 K -298,15K) : 693.041.199,6154 kJ/jam
Qout bawah total : 693.318.573,9907 kJ/jam Qout total : 618.160.628,8629 kJ/jam
LB-21
Neraca Energi Total :
Q total Masuk = Q total keluar - Q serap Q serap = Q total masuk – Q total keluar
= 248.118.230,5413 kJ/jam – 618.160.628,8629 kJ/jam
= -638.495.818,8394kJ/jam
Tabel B.9 Hasil Perhitungan Neraca Energi pada Distilasi 1 (T-101)
Komponen Panas Masuk Panas Keluar
Q9 (kJ/jam) Q10+Q11 (kJ/jam)
Qin 248.118.230,5413 0
Qout Atas 0 193.295.475,3900
Qout bawah 0 693.318.573,9907
Qserap 0 -638.495.818,8394
Total 248.118.230,5413 248.118.230,5413
7. Distilasi II (T-102)
Fungsi dari distilasi 1I (T-102) yaitu untuk memisahkan antara propilen glikol dan asam sulfat.
Gambar B.7 Distilasi II (T-102) Neraca Panas Total
Panas Masuk = Panas Keluar Q12 = Q13 + Q14
Panas Masuk Alur 12 Tin : 460,8 K Tref : 298,15 K
LB-22
N H2O : 0,0004 kmol/jam Q12 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.238,6214 kJ/kmol.K × (460,8 K -298,15K) : 982,2560 kJ/jam
Tin : 460,8 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q12 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 25.938,0757 kJ/kmol.K × (460,8 K - 298,15K) : 276.598,2793 kJ/jam
Tin : 439,75 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q12 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 25.938,0757 kJ/kmol.K × (460,8K-298,15K) : 693.415.513,1026 kJ/jam
Qin total : 693.769.093,6380 kJ/jam
Panas Keluar Atas Alur 13 Tin : 460,8 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q13 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.232,3876 kJ/kmol.K × (460,8 K -298,15K)
Q : 981,3686 kJ/jam
Tin : 460,8 K Tref : 298,15 K
N C3H6O2 : 164,3329 kmol/jam
LB-23
Q13 C3H6O2 : N × Cp × ∆T
: 164,3329 kmol/jam × 25.923,7851 kJ/kmol.K × (460,8 K - 298,15K)
: 692.784.841,0702 kJ/jam Qout atas total : 692.785.822,4388 kJ/jam
Panas Keluar Bawah Alur 14 Tin : 547,35 K Tref : 298,15 K
N C3H6O2 : 0,0004 kmol/jam Q14 C3H6O2 : N × Cp × ∆T
: 0,0004 kmol/jam × 43.023,5719 kJ/kmol.K × (547,35 K -298,15K) : 4.564,3398 kJ/jam
Tin : 547,35 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q14 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 22.075,9318 kJ/kmol.K × (547,35 K - 298,15K) : 799.896,7657 kJ/jam
Qout bawah : 804.461,1055 kJ/jam
Qout total : 693.590.283,5443 kJ/jam
Neraca Energi Total :
Q total Masuk = Q total keluar - Q serap Q serap = Q total masuk – Q total keluar
= 693.769.093,6380 kJ/jam – 693.590.283,5443 kJ/jam
= 178.810,0936
LB-24
Tabel B.10 Hasil Perhitungan Neraca Energi pada Distilasi II (T-102)
Komponen Panas Masuk Panas Keluar
Q12 (kJ/jam) Q13+Q14 (kJ/jam)
Qin 693.769.093,6380 0
Qout Atas 0 692.785.822,4388
Qout bawah 0 804.461,1055
Qserap 0 178.810,0936
Total 693.769.093,6380 693.769.093,6380
8. Heat Exchanger II (E-102)
Fungsi Heat Exchanger II (E-102) yaitu untuk mendinginkan produk atas yang berasal dari distilasi II untuk direcycle kembali dari suhu 98,3oC menjadi 30oC.
Gambar B.8 Heat Exchanger II (E-102)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q24 = Q28
Panas Masuk Alur 24 Tin : 371,5 K Tref : 298,15 K
N C3H6O : 0,0611 kmol/jam Q24 C3H6O : N × Cp × ∆T
: 0,0611 kmol/jam × 5.082,4646 kJ/kmol.K × (371,5 K- 298,15 K) : 22.769,8734 kkal/jam
LB-25
Tin : 371,5 K Tref : 298,15 KN
N H2O : 99,9389 kmol/jam Q24 H2O : N × Cp × ∆T
: 99,9389 kmol/jam × 6.620,6640 kJ/kmol.K × (371,5 K - 298,15 K) : 48.532.497,1939 kJ/jam
Qin total : 48.555.267,0673 kJ/jam
Panas Keluar Alur 28 Tin : 303,15 K Tref : 298,15 K
N C3H6O : 0,0611 kmol/jam Q28 C3H6O : N × Cp × ∆T
: 0,0611 kmol/jam × 273,1032 kJ/kmol.K × (303,15 K - 298,15 K) : 83,4039 kJ/jam
Tin : 303,15 K Tref : 298,15 K
N H2O : 99,9389 kmol/jam Q28 H2O : N × Cp × ∆T
: 99,9389 kmol/jam × 459,7569 kJ/kmol.K × (303,15 K - 298,15 K) : 229.738,0241 kJ/jam
Qout total : 229.821,4281 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 229.821,4281 kJ/jam – 48.555.267,0673 kJ/jam
= -48.325.445,6392 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
LB-26
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 48.555.267,0673 kJ/jam + Q supply = 229.821,4281 kJ/jam + 5% Q supply
Q supply - 5% Q supply = 229.821,4281 kJ/jam – 48.555.267,0673 kJ/jam 0,95 Q supply = -50.868.890,1465 kJ/jam
Q supply = -50.868.890,1465 kJ/jam Q loss = 5% dari Q supply
Q loss = 5% x -50.868.890,1465 kJ/jam Q loss = -2.543.444,5073 kJ/Jam
Tabel B.11 Hasil Perhitungan Neraca Energi pada Heat Exchanger II (E-102)
Komponen Panas Masuk Panas Keluar
Q24 (kJ/jam) Q28 (kJ/jam)
Propilen Oksida 22.769,8734 83,4039
Air 48.532.497,1939 229.738,0241
Qsupply -50.868.890,1465 0
Qloss 0 -2.543.444,5073
Total -2.313.623,0793 -2.313.623,0793
9. Heat Exchanger III (E-103)
Fungsi Heat Exchanger III (E-103) yaitu untuk mendinginkan produk bawah yang berasal dari distilasi II yaitu asam sulfat dari suhu 274,2oC menjadi 30oC.
Gambar B.9 Heat Exchanger III (E-103) Neraca Panas Total
Panas Masuk = Panas Keluar
Q16 = Q22
LB-27
Panas Masuk Alur 16 Tin : 547,4 K Tref : 298,15 K
N C3H8O2 : 0,0004 kmol/jam Q16 C3H8O2 : N × Cp × ∆T
: 0,0004 kmol/jam × 43.028,7857 kJ/kmol.K × (547,4K-298,15K) : 4.565,3585 kJ/jam
Tin : 547,4 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q16 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 22.079,2486 kJ/kmol.K × (547,4 K - 298,15 K) : 800.098,5452 kJ/jam
Qin total : 804.663,9038 kJ/jam
Panas Keluar Alur 22 Tin : 303,15 K Tref : 298,15 K
N C3H8O2 : 0,0004 kmol/jam Q22 C3H8O2 : N × Cp × ∆T
: 0,0004 kmol/jam × 601,4041 kJ/kmol.K × (303,15 K -298,15 K) : 1,2802 kJ/jam
Tin : 303,15 K Tref : 298,15 K
N H2O : 0,1454 kmol/jam Q22 H2O : N × Cp × ∆T
: 0,1454 kmol/jam × 138,7171 kJ/kmol.K × (303,15 K -298,15 K) : 100,8493 kJ/jam
Qout total : 102,1295 kJ/jam
LB-28
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 102,1295 kJ/jam - 804.663,9038 kJ/jam
= -804.561,7743 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 804.663,9038 kJ/jam + Q supply = 102,1295 kJ/jam + 5% Q supply
Q supply - 5% Q supply = 102,1295 kJ/jam – 804.663,9038 kJ/jam 0,95 Q supply = -804.561,7743 kJ/jam
Q supply = -846.907,1308 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x -846.907,1308 kJ/Jam Q loss = -42.345,3565 kJ/Jam
Tabel B.12 Hasil Perhitungan Neraca Energi pada Heat Exchanger (E-104)
Komponen Panas Masuk Panas Keluar
Q16 (kJ/jam) Q22 (kJ/jam)
Propilen Glikol 4.565,3585 1,2802
Asam Sulfat 800.098,5452 100,8493
Qsupply -846.907,1308
Qloss -42.345,3565
Total -42.243,2271 -42.243,2271
10. Heat Exchanger IV (E-104)
Fungsi dari heat exchanger IV (E-104) yaitu mendinginkan produk propilen glikol untuk disimpan ke dalam tangki penyimpanan dari suhu 187,6oC menjadi 33oC.
LB-29
Gambar B.10 Heat Exchanger IV (E-104)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q15 = Q19
Panas Masuk Alur 15 Tin : 460,8 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q15 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.234,3779 kJ/kmol.K × (460,8 K-298,15K) : 981,6519 kkal/jam
Tin : 460,8 K Tref : 298,15 K
N C3H8O2 : 164,3329 kmol/jam Q15 C3H8O2 : N × Cp × ∆T
: 164,3329 kmol/jam × 25.928,3476 kJ/kmol.K × (460,8K-298,15K) : 693.009.846,9154 kJ/jam
Qin total : 693.010.828,5673 kJ/jam
Panas Keluar Alur 19 Tin : 306,15 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q19 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 735,1100 kJ/kmol.K × (306,15 K -298,15K)
LB-30
: 2,4936 kJ/jam
Tin : 306,15 K Tref : 298,15 K
N C3H8O2 : 164,3329 kmol/jam Q19 C3H8O2 : N × Cp × ∆T
: 164,3329 kmol/jam × 970,1311 kJ/kmol.K × (306,15 K -298,15K) : 1.275.396,0346 kJ/jam
Qout total : 1.275.398,5281 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout - Qin
= 1.275.396,0346 kJ/jam – 693.010.828,5673 kJ/jam
= -691.735.430,0392 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 693.010.828,5673 kJ/jam + Q supply = 1.275.396,0346 kJ/jam + 5% Q supply Q supply - 5% Q supply = 1.275.396,0346 kJ/jam – 693.010.828,5673 kJ/jam 0,95 Q supply = -691.735.430,0392 kJ/jam
Q supply = -728.142.557,9360 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x -728.142.557,9360 kJ/Jam Q loss = -36 407 127,8968 kJ/Jam
Tabel B.13 Hasil Perhitungan Neraca Energi pada Heat Exchanger IV (E-104)
Komponen Panas Masuk Panas Keluar
Q15 (kJ/jam) Q19 (kJ/jam) Propilen Oksida
Air 981,6519 2,4936
Asam Sulfat
LB-31
Propilen Glikol 693.009.846,9154 1.275.396,0346 Qsupply -728.142.557,9360
Qloss -36 407 127,8968
Total -35131729,3687 -35131729,3687
11. Pompa IV (P-104)
Fungsi dari pompa IV (P-104) yaitu untuk mengalirkan air yang berasal dari distilasi I dari tekanan 1 atm menjadi 2 atm.
Gambar B.11 Pompa IV (P-104)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q10 = Q23
Panas Masuk Alur 10 Tin : 371,48 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q10 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 5081,1616 kJ/kmol.K × (371,48 K – 298,15 K) : 90.641,2703 kJ/jam
Tin : 371,48 K Tref : 298,15 K
N H2O : 398,0200 kmol/jam Q10 H2O : N × Cp × ∆T
: 398,020 kmol/jam × 6619,2717 kJ/kmol.K × (371,48K – 298,15K) : 193.204.852,2075 kJ/jam
LB-32
Qin total : 193.295.493,4778 kJ/jam
Panas Keluar Alur 23 Tin : 371,50 K Tref : 298,15 K
N H2O : 398,020 kmol/jam Q23 H2O : N × Cp × ∆T
: 398,020 kmol/jam × 6620,6640 kJ/kmol.K × (371,50 K – 298,15K) : 193.287.088,6659 kJ/jam
Tin : 371,50 K Tref : 298,15 K
N C3H6O : 0,2433 kmol/jam Q23 C3H6O : N × Cp × ∆T
: 0,2433 kmol/jam × 5082,4646 kJ/kmol.K × (371,50 K – 298,15K) : 90.684,03217 kJ/jam
Qout total : 193.377.772,6981 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout total - Qin total
= 193.377.772,6981 kJ/jam – 193.295.493,4778 kJ/jam
= 82.279,2203 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 193.295.493,4778 kJ/jam + Q supply = 193.377.772,6981 kJ/jam + 5% Q supply Q supply - 5% Q supply = 193.377.772,6981 kJ/jam – 193.295.493,4778 kJ/jam 0,95 Q supply = 82.279,2203 kJ/jam
Q supply = 86.609,7056 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% 86.609,7056 kJ/Jam
LB-33
Q loss = 4330,7056 kJ/Jam
Tabel B.14 Hasil Perhitungan Neraca Energi pada Pompa IV (P-104)
Komponen Panas Masuk Panas Keluar
Q10 (kJ/jam) Q23 (kJ/jam)
Propilen Oksida 90.641,2703 90.684,03217
Air 193.204.852,2075 193.287.088,6659
Qsupply 86.609,7056
Qloss 4330,7056
Total 193.382.103,1834 193.382.103,1834
12. Pompa V (P-105)
Fungsi dari pompa V (P-105) yaitu untuk mengalirkan keluaran bawah distilasi I dari tekanan 1 atm menjadi 2 atm.
Gambar B.12 Pompa V (P-105)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q11 = Q12
Panas Masuk Alur 11 Tin : 460,80 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q11 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 25.928,9468 kJ/kmol.K × (460,80K- 298,15K)
: 693.041.199,6154 kJ/jam Tin : 460,80 K
LB-34
Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q11 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.234,6393 kJ/kmol.K × (460,80K – 298,15K) : 981,6892 kJ/jam
Tin : 460,80 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q11 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 11.687,0547 kJ/kmol.K × (460,80 K - 298,15K) : 276.392,6861 kJ/jam
Qin total : 693.318.573,9907 kJ/jam
Panas Keluar Alur 12 Tin : 460,85 K Tref : 298,15 K
N C3H8O2 : 164,3334 kmol/jam Q12 C3H8O2 : N × Cp × ∆T
: 164,3334 kmol/jam × 25.938,0757 kJ/kmol.K × (460,85K- 298,15K)
: 693.491.513,1026 kJ/jam
Tin : 460,85 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q12 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.238,6214 kJ/kmol.K × (460,85 K– 298,15K) : 982,2560 kJ/jam
Tin : 460,85 K
LB-35
Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q12 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 11.692,2685 kJ/kmol.K × (460,85 K - 298,15K) : 276.598,2793 kJ/jam
Qout total : 693.769.093,6380 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout total - Qin total
= 693.769.093,6380 kJ/jam – 693.318.573,9907 kJ/jam
= 450.519,6473 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 693.318.573,9907 kJ/jam + Q supply = 693.769.093,6380 kJ/jam + 5% Q supply Q supply - 5% Q supply = 693.769.093,6380 kJ/jam – 693.318.573,9907 kJ/jam 0,95 Q supply = 450.519,6473 kJ/jam
Q supply = 474.231,2077 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% 474.231,2077 kJ/Jam Q loss = 23.711,5604 kJ/Jam
Tabel B.15 Hasil Perhitungan Neraca Energi pada Pompa V (P-105)
Komponen Panas Masuk Panas Keluar
Q11 (kJ/jam) Q12 (kJ/jam)
Air 981,6892 982,2560
Propilen Glikol 693.041.199,6154 693.491.513,1026
Asam Sulfat 276.392,6861 276.598,2793
Qsupply 474.231,2077
Qloss 23.711,5604
Total 693.792.805,1983 693.792.805,1983
LB-36
13. Pompa VI (P-106)
Fungsi dari pompa VI (P-106) yaitu untuk mengalirkan keluaran atas distilasi II dari tekanan 1 atm menjadi 1,5 atm.
Gambar B.13 Pompa VI (P-106)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q13 = Q15
Panas Masuk Alur 13 Tin : 460,77 K Tref : 298,15 K
N C3H8O2 : 164,3329 kmol/jam Q13 C3H8O2 : N × Cp × ∆T
: 164,3329 kmol/jam × 25.923,7852 kJ/kmol.K × (460,77K- 298,15K)
: 692.784.841,0702 kJ/jam Tin : 460,77 K
Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q13 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.232,3876 kJ/kmol.K × (460,77K – 298,15K) : 981,3686 kJ/jam
Qin total : 692.785.822,4388 kJ/jam
Panas Keluar Alur 15 Tin : 460,79 K Tref : 298,15 K
LB-37
N C3H8O2 : 164,3329 kmol/jam Q15 C3H8O2 : N × Cp × ∆T
: 164,3329 kmol/jam × 25.923,7852 kJ/kmol.K × (460,79K- 298,15K)
: 693.009.846,9154 kJ/jam
Tin : 460,79 K Tref : 298,15 K
N H2O : 0,0004 kmol/jam Q15 H2O : N × Cp × ∆T
: 0,0004 kmol/jam × 14.234,3779 kJ/kmol.K × (460,79 K– 298,15K) : 981,6520 kJ/jam
Qout total : 693.010.828,5673 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout total - Qin total
= 693.010.828,5673 kJ/jam – 692.785.822,4388 kJ/jam
= 225.006,1285 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 692.785.822,4388 kJ/jam + Q supply = 693.010.828,5673 kJ/jam + 5% Q supply Q supply - 5% Q supply = 693.010.828,5673 kJ/jam – 692.785.822,4388 kJ/jam 0,95 Q supply = 225.006,1285 kJ/jam
Q supply = 236.848,5563 kJ/Jam Q loss = 5% dari Q supply
Q loss = 5% x 236.848,5563 kJ/Jam Q loss = 11.842,4278 kJ/Jam
LB-38
Tabel B.16 Hasil Perhitungan Neraca Energi pada Pompa V (P-105)
Komponen Panas Masuk Panas Keluar
Q13 (kJ/jam) Q15 (kJ/jam)
Air 981,3686 981,6520
Propilen Glikol 692.784.841,0702 693.009.846,9154
Asam Sulfat 0 11.842,4278
Qsupply 236.848,5563 0
Qloss 0 23.711,5604
Total 693.022.670,9952 693.022.670,9952
14. Pompa VII (P-107)
Fungsi dari pompa VII (P-107) yaitu untuk mengalirkan keluaran bawah distilasi I dari tekanan 1 atm menjadi 1,5 atm.
Gambar B.14 Pompa VII (P-107)
Neraca Panas Total
Panas Masuk = Panas Keluar
Q14 = Q16
Panas Masuk Alur 14 Tin : 547,35 K Tref : 298,15 K
N C3H8O2 : 0,0004 kmol/jam Q14 C3H8O2 : N × Cp × ∆T
: 0,0004 kmol/jam × 43.023,5719 kJ/kmol.K × (547,35K- 298,15K)
: 4.564,3398 kJ/jam
LB-39
Tin : 547,35 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q14 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 22.075,9318 kJ/kmol.K × (547,35K – 298,15K) : 799.896,7657 kJ/jam
Qin total : 804.461,1055 kJ/jam
Panas Keluar Alur 16 Tin : 547,37 K Tref : 298,15 K
N C3H8O2 : 0,0004 kmol/jam Q16 C3H8O2 : N × Cp × ∆T
: 0,0004 kmol/jam × 43.028,7857 kJ/kmol.K × (547,37K- 298,15K)
: 4.565,3585 kJ/jam
Tin : 547,35 K Tref : 298,15 K
N H2SO4 : 0,1454 kmol/jam Q16 H2SO4 : N × Cp × ∆T
: 0,1454 kmol/jam × 22.079,2486 kJ/kmol.K × (547,37K – 298,15K) : 800.098,5452 kJ/jam
Qout total : 804.663,9038 kJ/jam
𝑑𝑄
𝑑𝑇 = Qout total - Qin total
= 804.663,9038 kJ/jam – 804.461,1055 kJ/jam
= 202,7982 kJ/jam
Neraca Energi Total :
H bahan masuk + Q supply = Hbahan bakar + Q loss
LB-40
Asumsi Q loss = 5% dari Q supply (kehilangan maksimum = 10%: Ulrich, hal 432) 804.461,1055 kJ/jam + Q supply = 804.663,9038 kJ/jam + 5% Q supply
Q supply - 5% Q supply = 804.663,9038 kJ/jam – 804.461,1055 kJ/jam 0,95 Q supply = 202,7982 kJ/jam
Q supply = 213,4719 kJ/Jam Q loss = 5% dari Q supply Q loss = 5% x 213,4719 kJ/Jam Q loss = 10,6736 kJ/Jam
Tabel B.17 Hasil Perhitungan Neraca Energi pada Pompa V (P-105)
Komponen Panas Masuk Panas Keluar
Q14 (kJ/jam) Q16 (kJ/jam)
Propilen Glikol 4.564,3398 4.564,3398
Asam Sulfat 799.896,7657 799.896,7657
Qsupply 213,4719 0
Qloss 0 213,4719
Total 804.674,5773 804.674,5773