Given that each of the following numbers.
i. 37 ii. 75 iii. 87 iv. 93 v. 667 vi. 677 vii. 559 viii. 2022
ix. 2021 x. 2027
The correct statement based of the number is ....
a. 37, 75 and 2021 are composite numbers b. 93, 559 and 2027 are prime numbers c. 87, 93 and 2027 are prime numbers d. 37, 677 and 2027 are prime numbers
Answer Key D
Given that each of the following prime factorisations.
I. 144=24×32 II. 216=23×33 III. 91125=36×53 IV. 21 952=26×73
V. 7056=24×32×72
The correct statement based of the information is ... . a.
√
144=12 and√
391125=45b.
√
3216=6 and√
391125=56 c.√
21952=56 and√
37056=14d.
√
7056=84 and√
91125=99Answer key: a.
√
144=12 and√
3 91125=45 Given that each of the following prime factorisations.
I. 576=¿ 26x32 II. 9801=34x112 III. 24 336=24x32x132 IV. 287 496=23x33x113
V. 1728 000=29×33×53
The correct statement based of the information is ...
a.
√
576=24 and√
31728 000=120b.
√
9801=33 and√
3287 496=66c.
√
24 336=156 and√
31728 000=60 d.√
576=12 and√
3 287 496=33Answer key : A
Erlan wants to repair a square table that has a perimeter of 120 cm. If one side of the table is damaged, how long is the side of the table that Erlan needs to repair ?
a. 30 cm b. 40 cm c. 50 cm d. 60 cm Answer key : A
Cheryl uses 385 one-centimetre cubes to make a cuboid. Each side of the cuboid is longer than 1 cm. The dimensions of the cuboid are . . . .
a. 3 cm × 5 cm × 7 cm b. 5 cm × 7 cm × 9 cm c. 3 cm × 5 cm × 11 cm d. 5 cm × 7 cm × 11 cm Answer key : D
Given that each of the following prime factorisations.
i. 28=22×7 ii. 42=2×3×7 iii. 56=23×7 iv. 84=22×3×7
The Highest Common Factor (HCF) of the 4 numbers respectively are ….
a. 28 b. 56 c. 84 d. 168
Answer key: A
Given that each of the following prime factorisations.
i. 42=2×3×7 ii. 50=2×52 iii. 84=22×3×7 iv. 90=2×32×5
The Lowest Common Multiple (LCM) of the 4 numbers respectively are ….
a. 42 b. 900
c. 6 000 d. 6 300 Answer key: D
There are 84 books, 56 pencils and 140 crayons available. If the books, pencils and crayons are to be divided equally among a number of children, how many children can receive the distribution ?
a. 24 children b. 28 children c. 30 children d. 32 children Answer key : B
Arkan visits the library every 6 days, Dimas every 4 days, while Emerald every 8 days. If on January 28 they visited the library together, on what date will they visit the library together again ?
b. 28 January c. 20 February d. 21 February e. 22 February Answer key : C
The temperature in a refrigerator is -12oC. When the power goes off, the temperature in the refrigerator rises 1oC every 10 minutes. Determine the temperature in the refrigerator if the power supply is off for 30 minutes !
a. 9 oC b. -9 oC c. 15 oC d. -15 oC Answer key : B
The value of –8 – [–4 x 15] + [11 x (–7)] is . . . a. 25
b. –25 c. 75 d. –75
Answer key : B
In a mathematics Olympiad, a correct answer is awarded 3 marks, but a wrong answer is awarded –1 mark (i.e 1 mark will be deducted). If no answer is given, 0 marks will be awarded. Albert took part in this Olympiad. There were 30 questions. He answered 17 questions correctly and 5 questions wrongly. How many marks did he score ?
a. 40 marks b. 42 marks
c. 44 marks d. 46 marks Answer key : D
The value of 3.5÷3 4+33
5×2
4 is . . . . a. 1 7
15 b. 2 3
15 c. 3 7
15 d. 7 1
15 Answer key : D
Jessi has 1 birthday cake to share with 3 of her friends. The first friend gets 0.36 parts, the second friend gets 0.27 parts, and the rest is given to the third friend. The cake portion for the 3rd friend is . . . .
a. 0.27 parts b. 0.36 parts c. 0.37 parts d. 0.63 parts Answer key : C
Mr. Justin, a syrup maker. It has 61
4 kg of sugar. Then bought another 41 2 kg.
Next, the sugar is made into syrup which is packaged into several bottles. Each bottle requires 1
4 kg of sugar. The number of bottles that Mr. Justin must provide is...
a. 41 bottles b. 42 bottles c. 43 bottles d. 44 bottles Answer key : C
The value of rounding round off to the nearest 100 and 1000 respectively off each of the following number namely:
i. 7275 (to the nearest 100) = 7300 and (to the nearest 1000) = 8000
ii. 655371 (to the nearest 100) = 655300 and (to the nearest 1000) = 650000 iii. 559733 (to the nearest 100) = 559800 and (to the nearest 1000) = 550000
iv. 3409725(to the nearest 100) = 3409700 and (to the nearest 1000) = 3410000 v. 555555 (to the nearest 100) = 555500 and (to the nearest 1000) = 555000 The correct statement based of the information is ....
a. i and ii b. i, ii and iii c. iii and v d. i and iv Answer key: D
The value of rounding off each of the following number as given in brackets.
i. 11.348 (2dp) = 11.34 ii. 133.3465 (3dp) = 133.35 iii. 1222.77789 (3dp) = 1222.778 iv. 12.348 (2dp) = 12.34
v. 12.3476 (3dp) = 12.35
The correct statement based of the information is . . . . a. ii, iii and iv
b. ii, iii and v c. i and v d. iv and v
Answer key: B
Given that significant figures each of the following.
i. 123 has 3 significant figures ii. 7063 has 3 significant figures iii. 0.10908 has 5 significant figures iv. 41.0320 has 5 significant figures v. 0.0500 has 3 significant figures
The correct statement based of the information is . . . . a. i, ii, iv
b. ii, iii, v c. i, iii, v d. ii, iv, v Answer key : C
A wallet costs 225 Thai bath. The conversion rate is 1 bath = S$ 0.041212. Estimate the price of the wallet in S$.
a. S$ 9 b. S$ 10 c. S$ 12 d. S$ 14 Answer key : A
Given the following linear expression.
1
4 x+6y−1 5
The number of terms, coefficients of variabel x , and constant terms respectively from the above algebraic expression is ….
a. 3, 1
4 , −1 5 b. 2, 6, 1
5 c. 3, 1
4 , 1 5 d. 3, 6, 1
4
Answer key: A
Given that x = 6 and y = −¿ 4 , the correct solution of algebraic expression 2x2 – y3 is . . . .
a. 135 b. 136 c. 157 d. 138
Answer key : B
The simplest form of the expressions 6x + ( −¿ 20y) + 7z – 8x – ( −¿ 25y) – 11z is . . . .
a. –2x – 5y – 4z b. 2x – 5y – 4z c. – 2x + 5y – 4z d. 2x + 5y – 4z Answer key : C
The simplest form of the expressions 2 3a−1
7b+2a−3
5b is . . . . a. 8
3a+26 35b b. 3
4a−15 26b c. 8
3a−26 35b d. 3
4a+15 26b Answer key : C
Given that expand each of the following expressions.
1. – (4 – x ) = – 4 – x 2. – (x + 5) = x + 5
3. 5 – b (– 6w + 2x) = 5 + 6bw – 2bx 4. – 6 (3a – 4b) = 24b + 18a
The correct statement based of the information is . . . .
a. 4 b. 3 c. 2 d. 1
Answer key : B
Given that factorice each of the following expressions 1. 12x + 9 = 3 (4x – 3)
2. – 25y – 35 = 5 (5y – 7) 3. – 6pq + 6 pr = 6p (q + r)
4. 8ax + 12a – 4az = 4a (2x + 3 – z)
The correct statement based of the information is . . . . a. 1
b. 2 c. 3 d. 4
Answer key : D
Zander is x years old. Zander’s uncle is now four times as old as Zander will be in 5 years. Find the age of Zander’s uncle now.
a. (4x + 20) years old b. (3x + 10) years old c. (x + 10) years old d. (4x + 10) years old Answer key : A
The solution of the equation 3(5 – h) – 2 (h – 2) = –1 is . . . a. 1
b. 2 c. 3 d. 4
Answer key : D
The correct solution from the linear equation 3 5m=1
2m+1
2 is . . . . a. 1
b. 3 c. 5 d. 7
Answer key : C
The solution of the equation 2a−3
4 =a−3
3 is . . . . a. 1
2 b. −11
2 c. 12
3 d. 21 2
Answer key : B
The sum of 4 consecutive odd number is 56. Find the greatest of the 4 number.
a. 11 b. 13 c. 15 d. 17
Answer key : D
A man is six times as old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born
a. 25 years old b. 27 years old c. 29 years old d. 30 years old Answer key : A
Given that each of the following numbers
i. 13 ii. 33 iii. 59 iv. 133 v. 173 vi. 333 vii.357 viii. 383 ix. 941 x. 987
The correct statement based of the number is ....
a. 13, 33 and 333 are composite number b. 59, 357 and 941 are prime number c. 33, 173 and 987 are composite number d. 13, 173 and 383 are prime number Answer Key : D
Given that four number r, s, t, and u. Find a formula for average A of the four number a. A = rstu
b. A = r + s + t + u c. A = rstu
4 d. A = r+s+t+u
4 Answer key : D
If k = p+2q
3 , the value of p when k = 8 and q = 1
2 is . . . . a. 21
b. 22 c. 23
d. 24
Answer key : C
The figure show a circle on page review exercise The correct statement based of the information is . . . a. The coordinates of point C is (4, -3)
b. The x-coordinate of point G is -4 c. The same y-coordinate as J is G d. The coordinates of point H is (-4, 3) Answer key : C
The equation of a function is y=4x+5 . The value of x when y = 125 is . . . . a. 30
b. 32,5 c. 35 d. 37,5
Answr key : A
The solution of the equation 30+7y=−2y−6 is …..
a. -6 b. 6 c. -4 d. -8
Answer key: C
The equation of a function is y=2
3x−11
2 . The value of y when x = 6 is . . . . a. 1
2 b. 3 2 c. 2 1
2
d. 3 1 2
Answer key : C
Mr. Hary has a rectangular plot of a land. The plan is that the land will be used for build library. If described simply in cartesian coordinates, the coordinates of Mr. Hary’s land are A(-3, -1), B(2, -1), C(2, 2) and H(. . . . , . . . .). The coordinates of point H is . . . a. (-3, 2)
b. (2, -3) c. (-1, -3) d. (-2, -1) Answer key : A
Given a graph as below
The gradient of the line is . . . . a. -5
b. 5 c. −2
10 d. 6
Answer key : B
Given that the gradient = −1
2 ; y-intercept = 0, the correct statement of the equation of line is . . . .
a. y = 1 2 x b. y = 1
2 c. y = −1
2 x d. y = −1
2 x+1 Answer key : C
The flaq-down fare of a taxi is $6. Given that a passenger is charged $0.50 for each kilometre the taxi travels, find the amount of money the passenger has to pay if the taxi covers a distance of 4 km.
a. $4 b. $6 c. $8 d. $10
Answer key : C
Given that each of the following prime factorisations.
i. 15=3×5 ii. 60=22×3×5 iii. 75=3×52
The HCF and LCM of the 3 numbers respectively are ….
e. 15 and 300 f. 300 and 15 g. 30 and 160
h. 18 and 30
Answer key: a. 15 and 300
Value of
[
−34 +(
−52) ]÷132 is ….
a. −211 8 b. 211
8
c. 1
21 d. - 1
21
Answer key: a. −211 8
