VALIDASI PERHITUNGAN LINGKUP VOLUME GLASSWARE (PIPET VOLUME)

VALIDASI PERHITUNGAN LINGKUP VOLUME GLASSWARE (PIPET VOLUME)

Koreksi

Volume : 25 mL

Massa = Massa isi- Massa kosong 1. Massa = 24,951 – 0,000 = 24,951 g 2. Massa = 24,948 – 0,000 = 24,948 g 3. Massa = 24,945 – 0,000 = 24,945 g 4. Massa = 24,948 - 0,000 = 24,948 g 5. Massa = 24,953 – 0,000 = 24,953 g Rata-rata UUT (𝑋) =

^{∑ X𝑛}

𝑛

=

24,951+24,948+24,945+24,948+24,953 5

= 24,949 g

Standar deviasi = √

^{∑(X𝑛− 𝑋̅)2}

𝑛−1

= √

(24,951−24,949)²+(24,948−24,949)²+(24,945−24,949)²+(24,948−24,949)²+(24,953−24,949)² 5−1

= √

0,000004+0,000001+0,000016+0,000001+0,000016 4

= 0,00308220700148448822512509619073 g

perhitungan salah/tidak sesuai

perhitungan benar

Suhu air terkoreksi = 19,8 °C Tekanan Udara terkoreksi = 1000 hPa Suhu udara terkoreksi = 20,6 °C

Faktor Z = (1 − (

^{𝜌 𝑢𝑑𝑎𝑟𝑎}

𝜌 𝐴𝑇

) ) × (

¹

𝜌 𝑎𝑖𝑟− 𝜌 𝑢𝑑𝑎𝑟𝑎

) × { 1 − 𝛾(𝑡 − 20) }

= ( 1 − (

^0,0011814₈

)) × (

0,9982422 − 0,0011814¹

) × {1 − (0,0000099 × (19,8 − 20))}

= 0,999852325 × 1,0029478643629355401395782483877 × 1,00000198

= 1,0028017395805787370238605308723 mL/g

V

20

= 𝑋 × 𝐹𝑎𝑘𝑡𝑜𝑟 𝑍

= 24,949 × 1,0028017395805787370238605308723

= 25,018900600795858910008296384733 mL Koreksi = V

20

– Volume uji

= 25,018900600795858910008296384733 - 25

= 0,018900600795858910008296384733 mL

Ketidakpastian

Volume Uji : 25 mL Komponen Penyumbang

Ketidakpastian Satuan Distribusi U Pembagi Vi Ui

(U/Pembagi) Ci UiCi (UiCi)² (UiCi)⁴/Vi

Massa air tertimbang U1 = standar deviasi; U2 = LoP

timbangan;

𝐶 = {

^{(𝜌𝐴𝑇−𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇(𝜌_𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})²

} × {1 − 𝛾(20 − 𝑡)}

g Normal

0,003082207 0014844882 2512509619

073

√2

1000

0,0021802140 567690442568 043658793

1,005753 8802985

300

0,002192758 7474768658 2753997016

603

4,80819092463 6313438194727 1648203 × 10^-6

2,3118699967755 00677309913898

8718 × 10^-14 g Rektangular 0,0002 2 × √3

Densitas udara

𝐶 = ∆𝑅 × {

^{(𝜌𝐴𝑇−𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇(𝜌_𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})²

} × {1 − 𝛾(20 − 𝑡)}

g/cm³ Rektangular 0,00011814 √3 1000

6,8208160802 062387819110 836928501×

10^-5

- 0,051293

4478952 232

- 3,498631742

1295925596 2986472418

31× 10^-6

1,22404240670 3674784931293 9221898× 10^-11

1,4982798134089 24390072825317

3688× 10^-25

Densitas aquades Nilai U sudah diasumsikan

SNSU

𝐶 = −∆𝑅 × {

^{(𝜌𝐴𝑇−𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇(𝜌𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})²

} × {1 − 𝛾(20 − 𝑡)}

g/cm³ Rektangular 0,00005 1 1000 0,00005 0,051293 4478952

232

0,000002564 6723947611

6

6,57754449244 9943315413444 5456 × 10^-12

4,3264091550158 58241622229073

4403× 10^-26

Densitas massa acuan U = 10% × ρ AT 𝐶 = ∆𝑅 × { ^{(𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇²(𝜌_𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})} × {1 − 𝛾(20 − 𝑡)}

g/cm³ Rektangular 0,8 √3 1000 0,4618802153 517006116073 1902440157

- 0,000000

9442014 579

- 4,361079727

1024167872 3952285150

36× 10^-7

1,90190163861 4369007808×

10^-13

3,6172298429640 21888950389256

763× 10^-29

Pengaruh suhu

°C

Normal 0,5 2 60

U1 = U95 termohigrometer ; U2 = selisih suhu awal dan

akhir;

𝐶 = −∆𝑅 × { ^{(𝜌𝐴𝑇−𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇(𝜌_𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})} × 𝛾

°C

Rektangular 0,4 2 × √3 1000 0,2753785273 643051010302 904385436

0,000000 5063135 9581329

8

1,394278923 9959199592 7819165890

87× 10^-7

1,94401371789 9220346425058 4124303 × 10^-14

3,7724051065092 60597209592589

2749× 10^-31

Koefisien muai volume U = 0,1 × 𝛾;

𝐶 = ∆𝑅 × { ^{(𝜌𝐴𝑇−𝜌𝑈𝑑𝑎𝑟𝑎)}

𝜌_𝐴𝑇(𝜌_𝑎𝑖𝑟−𝜌_{𝑈𝑑𝑎𝑟𝑎})} × (20 − 𝑡)

/

°C

Rektangular 0,00000099 √3 1000

5,7157676649 772950686405 729269694×

10^-7

- 0,010228

5574911 777

- 5,846405816

7434781733 3273567323 82 × 10^-9

3,41804609740 5197608983588 3680643 × 10^-17

1,1683039123986 90162096435781

936× 10^-36

Meniskus mL Normal 0,0022 √5 4

9,8386991009 990746642003 641424176×

10^-4

1

9,838699100 9990746642 0036414241

76× 10^-4

0,000000968 2,34256× 10^-13

Sums,∑(𝑈_𝑖𝐶_𝑖)²,∑^{(𝑈𝑖𝐶𝑖)4}

𝑉_𝑖 ; mL 5,77620995226

9354426289048 1123445e-6

2,5737470146607 81208231137962

3902 × 10^-13

Ketidakpastian baku gabungan, (Uc=√∑(𝑈𝑖𝐶_𝑖)²); mL 0,0024033747007633567137297265

0497 Derajat kebebasan efektif, Veff = ^𝑈𝑐

4

∑^{(𝑈𝑖𝐶𝑖)4} 𝑉𝑖

; mL 129,634347209113629230442137531

08

Faktor cakupan, k-student’s untuk Veff dan CL 95 % 1,96

Ketidak pastian bentangan, U = k.uc; mL 0,0047106144134961791589102639

4974