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EE539: Analog Integrated Circuit Design; HW5

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EE539: Analog Integrated Circuit Design; HW5

Nagendra Krishnapura ([email protected]) due on 31 Mar. 2007

+ Vi

Vo CL Iref(=Itail/10)

can be in either direction

Figure 1: Unity gain buffer with an opamp

0.18µm technology parameters: VT n = 0.5V; VT p = 0.5V;Kn = 300µA/V2; Kp = 75µA/V2; AV T = 3.5mV µm; Aβ = 1%µm; Vdd = 1.8V; Lmin = 0.18µm, Wmin = 0.24µm; Ignore body effect unless mentioned otherwise.

1. Design a single stage single ended opamp with a dc gain of 40 using an nMOS differential pair. The ap- plication is a unity gain buffer with 0.5 Vpp (±0.25V around the common mode) swing. The unity gain buffer should have a 3 dB bandwidth of 100 MHz, with CL = 10pF. All parasitic poles and zeros should be at at least twice the unity gain frequency.

Report the following and show simulation results where appropriate.

(a) Input common mode range (b) Output voltage range

(c) Open loop and closed loop frequency responses (d) An estimate of poles and zeros of the cir-

cuit (open and closed loop)

(e) DC sweep of the buffer with input varying from 0 to Vdd

(f) Transient response of the unity gain buffer with a +0.1 V step and a -0.1 V step (use 0.1 ns rise/fall times). Report the slew rate and com- pare it with the theoretical value. (If you don’t

see slewing, increase the step amplitude until you do)

(g) Input referred noise spectral density-identify 1/f noise corner if applicable.

(h) Power consumption

(i) Show a schematic with all sizes and operating points (gm,gds,VGS-VT,ID) of all transistors and the node voltages.

Do not use an ideal current source in the tail. You can use one ideal reference current source of 1/10th the tail current for bias generation (Fig. 1).

Try to determine as many parameters as possible from the specifications and choose sensible start- ing points for the others. Try to adjust the chan- nel lengths so thatgds contributions from nMOS and pMOS sides are equal (This is not the only possible choice. Other choices may be preferable to optimize other figures of merit-e.g. noise. This is a suggested starting point for simplicity). Choose an appropriate common mode voltage.

Maximize the output voltage swing and reduce the power consumption during the design.

2. Fig. 2(a) shows a macromodel of an opamp with two non dominant poles. Determine the transfer func- tion of the opamp, its dc gain, poles and zeros, and the unity gain frequency. Determine the values for Adc = 500, ωu = 100MHz, p2 = 200MHz, p3 = 400M Hz. Simulate the unit step response of the circuit. Use a 10ps risetime for the input step.

Plot the step response in the following cases (In each case all other parameters have their nomi- nal values). a) ωu = {100,200}MHz, p2 =

1

(2)

2

+ +

gm1 R1 C1

1.0 R2

C2

+1.0 R3

C3 1.0

1GΩ

+ +

gm1 R1 C1

1.0 R2

C2

+1.0 R3

C3 1GΩ

+ 0.5 0.5

Vcmref outp

outn + out

-

+

-

+

+ + - Vi

Vo

Vcmref=1V R

R

R R

R

R

Vcm+/-Vi/2 Vocm+/-Vo/2 (a)

(b)

(c) (d)

Figure 2: Problem 3

u, p3 = 4ωu. b) ωu = {100,200}MHz c) p2 = p3 = {150,200,300,1000}MHz, d) p2 = {100,200,300}MHz, p3 = ∞, e) Adc = {20,50,100,500}. Explain the results.

Fig. 2(c) shows a macromodel of a fully differential opamp with two non dominant poles. Vcmref con- trols the output common mode. Determine the val- ues forAdc= 500,ωu= 100MHz,p2= 300MHz, p3 = 400M Hz. Simulate the response of the am- plifier in Fig. 2(d) to a differential unit step. Use Vcmref = 1V andVcm = 0.5V. PlotVop, Vonand verify that they have expected values.

Plot the differential and common mode step re- sponse1 in the following cases (In each case all other parameters have their nominal values). a) ωu = {100,200}MHz, p2 = 3ωu, p3 = 4ωu. b) ωu = {100,200}MHz c) p2 = p3 = {150,200,300,1000}MHz, d) p2 = {100,200,300}MHz, p3 = ∞, e) Adc = {20,50,100,500}. Explain the results.

3. gm1 = 20µS,gds1 = 1µS,gm2 = 80µS,gds2 = 1µS, GL = 1µS, Cgs1 = 10fF, Cgs2 = 40fF,

1While measuring the differential step response, the common mode voltage is held constant; While measuring the common mode step re- sponse, the differential voltage is zero

gds2 Cgd2

Cgs2 gm2

gm1 gds1 Cgs1

+

-

out

+

CL Vi

Vo

Rc GL GL GL

Figure 3: Problem 3

Cgd2 = 250fF, CL = 1pF,Rc = 12.5kΩ. Sim- ulate the circuit for the following cases: Vary each ofCgs1,Cgs2,Cgd2,CL,GL,Rc, from0.1×their nominal value to 10×their nominal value, with 2 steps per decade. In each case keep all the other com- ponents at their nominal values.

Plot the unit step response and loop gain (overlaid on the same plot for each case). Comment on the results.

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