ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
E E n n z z y y m m e e s s K K i i n n e e t t i i c c s s
B BY B Y Y
D D R R . . P P O O U U L L A A M M I I A A D D H H I I K K A A R R Y Y M M U U K K H H E E R R J J E E E E A A S S S S I I S S T T A A N N T T P P R R O O F F E E S S S S O O R R
D D E E P P A A R R T T M M E E N N T T O O F F Z Z O O O O L L O O G G Y Y
N N A A R R A A J J O O L L E E R R A A J J C C O O L L L L E E G G E E
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
Enzyme kinetics is the study of the chemical reactions that
are catalysed by enzymes. In enzyme kinetics, the reaction
rate is measured and the effects of varying the conditions of
the reaction are investigated. Studying an enzyme's kinetics in
this way can reveal the catalytic mechanism of this enzyme, its
role in metabolism, how its activity is controlled, and how
a drug or an agonist might inhibit the enzyme.
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Enzymes are usually protein molecules that manipulate other molecules—the enzymes' substrates. These target molecules bind to an enzyme's active site and are transformed into products through a series of steps known as the enzymatic mechanism:
E + S ⇄ ES ⇄ ES* ⇄ EP ⇄ E + P
These mechanisms can be divided into single-substrate and
multiple-substrate mechanisms. Kinetic studies on enzymes
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that only bind one substrate, such as triosphosphate
isomerase, aim to measure the affinity with which the enzyme
binds this substrate and the turnover rate. Some other
examples of enzymes are phosphofructokinase and
hexokinase, both of which are important for cellular
respiration (glycolysis).
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Michaelis–Menten kinetics is one of the best-known models
of enzyme kinetics. It is named after German
biochemist Leonor Michaelis and Canadian physician Maud
Menten. The model takes the form of an equation describing
the rate of enzymatic reactions, by relating reaction rate ὑ
(rate of formation of product[P]) to the concentration of
a substrate S [S]. Its formula is given by:
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
This equation is called the Michaelis–Menten equation.
Here, represents the maximum rate achieved by the system,
happening at saturating substrate concentration. The value of
the Michaelis constant is numerically equal to the substrate
concentration at which the reaction rate is half of V
maxZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
Michaelis–Menten saturation curve for an enzyme reaction showing
the relation between the substrate concentration and reaction rate.
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
D D e e r r i i v v a a t t i i o o n n o o f f t t h h e e M M i i c c h h a a e e l l i i s s - - M M e e n n t t e e n n E E q q u u a a t t i i o o n n : :
A simple model of enzyme action:
We would like to know how to recognize an enzyme that behaves
according to this model. One way is to look at the enzyme's kinetic
behaviour at how substrate concentration affects its rate. Therefore,
we want to know what rate law such an enzyme would obey. If a
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
newly discovered enzyme obeys the rate law derived from this model, then it's reasonable to assume that the enzyme reacts according to this model. It's not proof that the model is correct, but at least it tells us that kinetics does not rule it out.
For derivation of a rate law from this model.
For this model, let V
0be the initial velocity of the reaction. Then V
0= k
cat[ES]...(2)
The maximum velocity V
maxoccurs when the enzyme is saturated --
that is, when
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
all enzyme molecules are tied up with S, or [ES] = [E]
totalSo V
max= k
cat[E]
total...(3)
We want to express V
0in terms of measurable quantities, like [S]
and [E]
total, so we can see how to test the mechanism by
experiments in kinetics. So we must replace [ES] in (2) with
measurables.
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
During the initial phase of the reaction, as long as the reaction velocity remains constant, the reaction is in a steady state, with ES being formed and consumed at the same rate. During this phase, the rate of formation of [ES] equals its rate of consumption. According to model (1),
Rate of formation of ES = k
1[E][S].
Rate of consumption of ES = k
-1[ES] + k
cat[ES].
So in the steady state, k
-1[ES] + k
cat[ES] = k
1[E][S]...(4)
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Remember that we are trying to solve for [ES] in terms of measurables, so that we can replace it in (2). First, collect the kinetic constants in (4):
(k
-1+ k
cat) [ES] = k
1[E][S],
and (k
-1+ k
cat)/k
1= [E][S]/[ES]... (5)
To simplify (5), first group the kinetic constants by defining them as
K
m:
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
K
m= (k
-1+ k
cat)/k
1...(6) and then express [E] in terms of [ES] and [E]total:
[E] = [E]
total- [ES] ...(7) Substitute (6) and (7) into (5):
Km = ([E]
total- [ES]) [S]/[ES] ...(8) Solve (8) for [ES]: First multiply both sides by [ES]:
[ES] K
m= [E]
total[S] - [ES][S]
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
Then collect terms containing [ES] on the left:
[ES] K
m+ [ES][S] = [E]
total[S]
Factor [ES] from the left-hand terms:
[ES](K
m+ [S]) = [E]
total[S]
and finally, divide both sides by (K
m+ [S]):
[ES] = [E]
total[S]/(K
m+ [S]) ...(9)
Substitute (9) into (2): V
0= k
cat[E]
total[S]/(K
m+ [S]) ...(10)
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Recalling (3), substitute V
maxinto (10) for k
cat[E]
total:
V
0= V
max[S]/(K
m+ [S]) ...(11)
This equation expresses the initial rate of reaction in terms of a measurable quantity, the initial substrate concentration. The two kinetic parameters, V
maxand K
m, will be different for every enzyme- substrate pair.
Equation (11), the Michaelis-Menten equation, describes the kinetic
behavior of an enzyme that acts according to the simple model (1).
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Equation (11) is of the form y = ax/(b + x)
This is the equation of a rectangular hyperbola, just like the saturation equation for the binding of dioxygen to myoglobin.
Equation (11) means that, for an enzyme acting according to the
simple model (1), a plot of V
0versus [S] will be a rectangular
hyperbola. When enzymes exhibit this kinetic behavior, unless we
find other evidence to the contrary, we assume that they act
according to model (1), and call them Michaelis-Menten enzymes.
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Another form;
For the enzyme catalyzed reaction:
E + S --k1--> ES complex --k3--> E + P ... <--k2--
V= k3*[ES]
Rate of formation of ES = k1 * [E]*[S]
Rate of breakdown of ES = (k2 + k3) * [ES]
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At steady state, the formation and the breakdown are equal. This steady state would only be temporary.
k1 * [E]*[S] = (k2 + k3) * [ES]
rearranging:
[ES] = [E]*[S] / ( (k2 + k3)/(k1))
We can lump these constants to make a new constant called KM = (k2+k3)/k1
[ES] = [E][S]/ K
MZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
[ET] = [E] + [ES] (The total amount of enzyme equals the free and that bound to substrate)
Substituting in [ET] - [ES] for [E]
[ES] = ([ET] - [ES]) [S]/ KM
Solving for [ES] leads to [ES] = ([ET] (([S]/ KM)/(1 + [S]/ KM )) Which simplifies to
[ES] = ([ET] *([S]/([S] + KM )
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Multiplying both sides by the kinetic constant k3 gives the velocity of the reaction
v = k3 * [ES] = k3*[ET] *(([S]/([S] + KM )
and substituting Vmax for k3*[ET] leads to the familiar form of the Michaelis Menten Equation
v = Vmax *[S]/([S] + KM )
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L L i i n n e e w w e e a a v v e e r r – – B B u u r r k k p p l l o o t t : :
The Lineweaver–Burk plot (or double reciprocal plot) is a graphical representation of the Lineweaver–Burk equation of enzyme kinetics, described by Hans Lineweaver and Dean Burk in 1934.
D D e e r r i i v v a a t t i i o o n n : :
The plot provides a useful graphical method for analysis of
the Michaelis–Menten equation, as it is difficult to determine
precisely the V
maxof an enzyme-catalysed reaction:
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
Taking the reciprocal gives:
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
where V is the reaction velocity (the reaction rate), K
mis
the Michaelis–Menten constant, V
maxis the maximum reaction
velocity, and [S] is the substrate concentration.
ZOOLOGY: SEM- III, PAPER- C7T: FUNDAMENTALS OF BIOCHEMISTRY, UNIT 5: ENZYMES
An example of a Lineweaver-Burk plot.
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Use:
The Lineweaver–Burk plot was widely used to determine important
terms in enzyme kinetics, such as K
mand V
max, before the wide
availability of powerful computers and non-linear
regression software. The y-intercept of such a graph is equivalent to
the inverse of V
max; the x-intercept of the graph represents −1/K
m. It
also gives a quick, visual impression of the different forms
of enzyme inhibition.
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The double reciprocal plot distorts the error structure of the data, and it is therefore unreliable for the determination of enzyme kinetic parameters. Although it is still used for representation of kinetic data, non-linear regression or alternative linear forms of the Michaelis–Menten equation such as the Hanes-Woolf plot or Eadie–Hofstee plot are generally used for the calculation of parameters.
When used for determining the type of enzyme inhibition, the
Lineweaver–Burk plot can distinguish competitive, non-
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competitive and uncompetitive inhibitors. Competitive inhibitors
have the same y-intercept as uninhibited enzyme (since V
maxis
unaffected by competitive inhibitors the inverse of V
maxalso doesn't
change) but there are different slopes and x-intercepts between the
two data sets. Non-competitive inhibition produces plots with the
same x-intercept as uninhibited enzyme (K
mis unaffected) but
different slopes and y-intercepts. Uncompetitive inhibition causes
different intercepts on both the y- and x-axes.
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Enzyme Inhibition displayed using Lineweaver-Burk
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T T H H A A N N K K Y Y O O U U