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Lecture-27: Properties of Poisson point processes

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Lecture-27: Properties of Poisson point processes

1 Laplace functional

For a realization of a simple point process S, we observe that dN(x) =0 for allx ∈/S anddN(x) = δx1{x∈S}. Hence, for any function f:RdR, we have

Z

x∈Af(x)dN(x) =

i∈N

f(Si)1{Si∈A}=

Si∈A

f(Si).

Definition 1.1. TheLaplace functionalLof a point processS and associated counting process Nis defined for all non-negative function f :RdRas

LS(f),Eexp

− Z

Rd f(x)dN(x)

.

Remark1. For simple functionf(x) =ki=1ti1{x∈Ai}, we can write the Laplace functional LS(f) =Eexp

k i=1

ti Z

AidN(x)

!

=Eexp −

k i=1

tiN(Ai)

! ,

as a function of the vector(t1,t2, . . . ,tk), a joint Laplace transform of the random vector(N(A1), . . . ,N(Ak)). This way, one can compute all finite dimensional distribution of the counting processN.

Proposition 1.2. The Laplace functional of the Poisson process with intensity measureΛis LS(f) =exp

− Z

Rd(1−ef(x))(x)

.

Proof. For a bounded Borel measurable setA∈ B(Rd), considerg(x) =f(x)1{x∈A}. Then, LS(g) =Eexp(−

Z

Rdg(x)dN(x)) =Eexp(−

Z

Af(x)dN(x)). ClearlydN(x) =δx1{x∈S}and hence we can writeLS(g) =Eexp −S

i∈S∩Af(Si). We know that the probability ofN(A) =|S(A)|=npoints in setAis given by

P{N(A) =n}=eΛ(A)Λ(A)n n! .

Given there arenpoints in setA, the density ofnpoint locations are independent and given by fS1,...,Sn

N(A)=n(x1, . . . ,xn) =

n i=1

dΛ(xi)1{xi∈A}

Λ(A) . Hence, we can write the Laplace functional as

LS(g) =eΛ(A)

n∈Z+

Λ(A)n n!

n i=1 Z

Aef(xi)dΛ(xi) Λ(A) =exp

− Z

Rd(1−e−g(x))(x)

.

Result follows from taking increasing sequences of sets AkRdand monotone convergence theorem.

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1.1 Superposition of point processes

For simple point processesSkwith intensity measuresΛk and counting processNk, thesuperposition of point processes is defined asS=∪kSka simple point process with the counting processN=kNk

iff∑kNkis locally finite. IfSkare Poisson then, we know thatΛ=kΛk. Next, we will show that the superpositionSof Poisson processes is Poisson iff∑kΛkis locally finite.

Theorem 1.3. The superposition of independent Poisson point processes with intensitiesΛkis a Poisson point process with intensity measure∑kΛkif and only if the latter is a locally finite measure.

Proof. Consider the superpositionS=kSk of independent Poisson point processesSkRdwith in- tensity measuresΛk. We will prove only side of this theorem. We assume that∑kΛk is locally finite measure. It is clear that N(A) =kNk(A)is finite by locally finite assumption, for all bounded sets A∈B. In particular, we havedN(x) =kdNk(x)for all x ∈Rd. From the monotone convergence theorem and the independence of counting processes, we have for a non-negative function f :RdR,

LS(f) =Eexp − Z

Rd f(x)

k

dNk(x)

!

=

k

LSk=exp − Z

Rd(1−e−f(x))

k

Λk(x)

! .

1.2 Thinning of point processes

Consider a probabilityretention functionp:Rd→[0, 1]and a point processS. Thethinningof point processS:Ω→(Rd)Nwith the retention functionpis a point processSp:Ω→(Rd)Nsuch that

Sp= (Sn∈S:Y(Sn) =1),

whereY(Sn)is an independent indicator random variable at each pointSnandE[Y(Sn)Sn] =p(Sn). Theorem 1.4. The thinning of the Poisson point process of intensity measureΛwith the retention probability function p yields a Poisson point process of intensity measureΛ(p)with

Λ(p)(A) = Z

Ap(x)(x) for all bounded Borel measurable A⊆Rd.

Proof. LetA⊆Rdbe a bounded Boreal measurable set, and let f :RdRbe a non-negative function.

LetNpbe the associated counting process to the thinned point processSp. Hence, for any setA∈ B, we haveNp(A) =Si∈S(A)Y(Si). That is,

dNp(x) =

i∈N

δx1{x=Si}Y(Si). Therefore, for any non-negative functiong(x) = f(x)1{x∈A}, we can write

Z

x∈Rdg(x)dNp(x) = Z

x∈Af(x)dNp(x) =

Si∈A

f(Si)Y(Si).

Consider the Laplace functional of the thinned point processSpfor the non-negative functiong(x) = f(x)1{x∈A}, we can write the corresponding Laplace functional as

LSp(g) =EE[exp

− Z

Af(x)dNp(x)

N(A)] =

n∈Z+

P{N(A) =n}

n i=1

E[f(Si)Y(Si)Si∈A].

Here, we denote the points of the point process in subsetAasS(A) =S∩A. The first equality follows from the definition of Laplace functional and taking nested expectations. Second equality follows from the fact that the distribution of all points of a Poisson point process areiid. SinceYis a Bernoulli process independent of the underlying processSwithE[Y(Si)] =p(Si), we get

E[ef(Si)Y(Si)

Si∈S(A)] =E[ef(Si)p(Si) + (1−p(Si))Si∈S(A)]. 2

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From the distributionΛΛ(A)0(x) forx∈S(A)for the Poisson point processS, we get LSp(g) =eΛ(A)

n∈Z+

1 n!

Z

A

(p(x)ef(x)+ (1−p(x))(x) n

=exp

− Z

Rd(1−e−g(x))p(x)(x)

.

Result follows from taking increasing sequences of sets AkRdand monotone convergence theorem.

3

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