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1 Relation to Feynman’s parton model

Remember (No. 16):

The cross section for inelastic electron-proton scattering was expressed in Eq.(1.1) of No. 16, in terms of the hadronic tensor Wµν (defined in Eq.(1.3) of No. 16). Then Wµν was parametrized in terms of structure functions, see Eqs.(1.11), (1.12) of No. 16, to get more explicit forms for the cross section.

(1) What is the form of the hadronic tensor for a point particle?

Use Eq.(1.3) of No. 16 for the spin averaged case, and insert the currentJF Iµ of a point particle.

We get 1 2

X

s

Wµν

!

point

= Ep 2

Z

d3p0δ(4)(p0−p−q) M2 EpEp0

X

s,s0

(u(~p0, s0µu(~p, s)) (u(~p0, s0νu(~p, s))(1.1) To perform the integration, use the identity used in No. 15:

Z d3p0 2Ep0 =

Z

d4p0δ

p02−M2 θ(p00)

By using the definition of the Bjorken variablex=−q2/(2p·q), and performing the spin sums as in No. 16, Eq.(1.1) becomes

1 2

X

s

Wµν

!

point

= M2

2p·qδ(x−1) X

s,s0

(u(~p0, s0µu(~p, s)) (u(~p0, s0νu(~p, s))

= 1

2p·qδ(x−1)

p0µpν+p0νpµ−gµν p0·p−M2

= 1

2δ(x−1)

−gµν+ p0µpν+p0νpµ p·q

(1.2) where we used p0 ·p−M2 = p·q in the last step. (Note that the scattering on a point particle must be elastic, therefore p2 = M2.) Now compare (1.2) with the parametrization in terms of structure functions, see Eq.(1.15) of No. 16:

1 2

X

s

Wµν

!

point

=F1point(x, Q2)

−gµν +qµqν q2

+ F2point(x, Q2) p·q

pµ−p·q

q2 qµ pν − p·q q2 qν

Using here p·q =−q2/2 (because the scattering on point particle is elastic), and qµ =p0µ−pµ, this becomes

1 2

X

s

Wµν

!

point

= −gµνF1point(x, Q2) + p0µpν +p0νpµ 2(p·q)

F1point(x, Q2) + 1

2F2(x, Q2)

+ p0µp0ν +pµpν 2(p·q)

−F1point(x, Q2) + 1

2F2(x, Q2)

(1.3)

(2)

Comparing (1.2) and (1.3), we obtain for the structure functions of a point particle 1: F1point(x, Q2) = 1

2δ(x−1), F2point(x, Q2) =δ(x−1) = 2x F1point(x, Q2) (1.4) Note: The delta-function δ(x −1) just expressed the condition of elastic scattering on the point particle. Because a point particle has no structure, the structure functions are independent of Q2.

The same calculation as above can be done for the full hadronic tensorWpointµν of a point particle (not spin averaged):

(Wµν)point = Ep Z

d3p0δ(4)(p0−p−q) M2 EpEp0

X

s0

(u(~p0, s0µu(~p, s)) (u(~p0, s0νu(~p, s))

= M2

p·qδ(x−1)X

s0

(u(~p0, s0µu(~p, s)) (u(~p, s)γνu(~p0, s0))

= 1

2δ(x−1)

−gµν+p0µpν +p0νpµ

p·q +iM µνσλqσSλ p·q

(1.5) We compare this with the parametrization in terms of the structure functions F1point, F2point, g1point, g2point, see Eq.(1.15) and (1.16) of No. 16. The results for F1point and F2point are given in Eq.(1.4), and for g1point, g2point we obtain

gpoint1 (x, Q2) = 1

2δ(x−1), g2point(x, Q2) = 0 (1.6)

1The relationF2= 2x F1expresses that the “point particle” considered here has spin 1/2.

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(2) Experimental data on the proton structure function F2(x, Q2) for Q2 >1.5 GeV2:

We see:F2 is almost independent ofQ2, i.e., F2(x, Q2)'F2(x). This is called the Bjorken scaling.

The data for F1 (not shown here) indicate that also F1 depends only on x for large Q2, and that there is the following relation between F1(x) and F2(x):

F2(x)'2x F1(x) (1.7)

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We will show in lecture No. 18 that scaling and relation (1.7) can be explained naturally in the Bjorken limit: The Bjorken limit (B.L.) is defined by

Q2 → ∞, p·q → ∞, x= Q2

2(p·q) fixed (1.8)

The B.L. is only a “theoretical tool” to derive Feynman’s parton model, which gives simple expres- sions and physical interpretations of structure functions. The experimental data show scaling and the relation (1.7) already forQ2 >2 GeV2 and p·q >1 GeV2. For very small values of x, however, the data show a strong violation of scaling.

(3) Idea of Feynman’s parton model (most naive version):

The dominant process for inelastic electron-hadron scattering at large Q2 is elastic scattering on point-like constituents (partons).

electron hadron

q

k k’

(p) +q

pi

pi

hadrons (p+q)

For elastic scattering on quarki (with 4-momentum pi and mass p2i =m2i) we have 2 (pi+q)2 =m2i ⇒ Q2

2(pi·q) = 1 (1.9)

This means: The Bjorken variable of the quark is equal to 1.

Ifzi is the 4-momentum fraction of partoni, thenpi =zip, wherep=P

ipi is the total 4-momentum of the hadron. Then we get from (1.9)

Q2

2zi(p·q) = 1⇒zi = Q2

2(p·q) =x (1.10)

This means: Only the quark with momentum fraction zi =x can interact with the electron!

Because the quark is point-like, the structure function (F2) of quarki with charge ei is (see (1.4)) F2i =e2i δ

Q2

2(pi·q)−1

=e2i δ x

zi

−1

=e2i ziδ(x−zi) = x e2i δ(x−zi) (1.11)

2Hereilabels the flavor of the quark: i=u, d, . . ..

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Then the total structure function F2 of the hadron must be given by F2(x, Q2) =X

i

Z 1

0

dziqi(zi)F2i (1.12)

where qi(z) is the probability to find quark i with momentum fraction z inside the proton, i.e., the

“momentum distribution function” of the quark. By using (1.11), we get for the structure function of the proton:

F2 =X

i

Z 1

0

dz qi(z)x e2i δ(x−z) =x X

i

e2i qi(x) (1.13)

The same calculation can be done also for the structure function F1: From Eq.(1.4), for quark i we haveF1i = 2z1

iF2i = 12e2i δ(x−zi), and therefore F1 of the proton is given by F1(x, Q2) =X

i

Z 1

0

dziqi(zi)F1i = 1 2

X

i

e2i qi(x) (1.14)

We see: The structure functions in the parton model, given by Eqs. (1.13) and (1.14), are independent of Q2, which means Bjorken scaling, and satisfy the relation

F2(x) = 2x F1(x) (1.15)

Extension of the naive parton model:

First, let us denote theu-quark distribution simply by u(x)≡qu(x) and the d-quark distribution by d(x)≡qd(x).

The proton (p) consists of two “valence (v)” u-quarks3with chargeeu = 2/3, and one “valence d-quark”

with charge ed =−1/3. We then get the following structure function of the proton in the extended parton model:

F2(p)(x) = x 4

9u(p)v (x) + 1

9d(p)v (x)

+ (sea quark contributions) (1.16) whereu(p)v (x) is the momentum distribution of the valenceu- quark in the proton, and d(p)v (x) is the momentum distribution of the valence d - quark in the proton. The normalizations are

Z 1

0

dx u(p)v (x) = 2,

Z 1

0

dx d(p)v (x) = 1 (1.17)

Note: “Valence” quark contributions are dominant for large x (x > 0.5)), while “sea” quark and gluon contributions are dominant for small x.

3In addition to the three “valence” quarks (momentum distributionqv(x)), there are also “sea” quarks and anti- quarks in the proton (momentum distributionqs(x) andqs(x)), because of the spontaneous creation and annihilation of quark-antiquark pairs from the vacuum. (Generally,qs(x) =qs(x).) Therefore, the total quark distributions are q(x) =qv(x) +qs(x), and the antiquark distributions areq(x) =qs(x). We will see later that the functionsq(x) and q(x) are defined in field theory (in terms of field operators), and thereforeqv(x) is defined byqv =q(x)q(x).

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Relations (1.17) are called the “number sum rules”: Sea quarks and gluons do not contribute to baryon number and charge, and therefore the relations (1.17) are satisfied only by the valence quark distributions. However, (sea quarks + gluons) carry a part of the total momentum of the proton, i.e., they contribute to the “momentum sum rule”:

Z 1

0

dx x u(p)v (x) +d(p)v (x)

+ (sea quark contributions) + (gluon contributions) = 1 (1.18) For the neutron (one valence u-quark and two valence d-quarks) we obtain

F2(n)(x) = x 4

9u(n)v (x) + 1

9d(n)v (x)

+ (sea quark contributions)

= x 4

9d(p)v (x) + 1

9u(p)v (x)

+ (sea quark contributions) (1.19) In the last relation above, we assumed “flavor symmetry”:

u(p)v (x) =d(n)v (x), d(p)v (x) =u(n)v (x) (1.20) The contributions of “sea” quarks to Eq.(1.16) and Eq.(1.19) are almost the same, and cancel if we take the differenceF2(p)(x)−F2(n)(x):

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The left graph clearly shows that the valence quark distributions have a peak around x ' 1/3, as expected.

From the experimental data ofF2(x) for the proton and neutron (and other data), one can extract all quark distribution functions (right graph). The gluon distribution function (g(x)) is still very uncertain, but seems to be very large at small values ofx.

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