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LANDAU-GINZBURG TYPE EQUATIONS IN THE SUB CRITICAL CASE

NAKAO HAYASHI, ELENA I. KAIKINA, AND PAVEL I. NAUMKIN

Abstract. We study the Cauchy problem for the nonlinear Landau-Ginzburg equation

tuαu+β|u|σu= 0, xRn, t >0, u(0, x) =u0(x), xRn, (0.1)

where α, β C with dissipation condition α > 0. We are interested in the subcritical case σ 0,n2

.We assume thatθ =

R

u0(x)dx

= 0 and δ(α, β)>0,where

δ(α, β) = β|α|n−n2σ

(2 +σ)|α|2+σα2

n 2 .

Furthermore we suppose that the initial datau0L1are such that (1 +|x|)au0 L1, with sufficiently small normε=(1 +|x|)au01, wherea(0,1).Also we assume thatσis sufficiently close to n2.Then there exists a unique solution of the Cauchy problem (0.1) such that

u(t, x)C((0,∞) ;L)C [0,);L1, satisfying the following time decay estimates for larget >0

u(t)t1σ.

Note that in comparison with the corresponding linear case the decay rate of the solutions of (0.1) is more rapid.

1. Introduction

This paper is devoted to the study of global existence and large time asymp- totic behavior of small solutions to the Cauchy problem for the complex Landau - Ginzburg equation

tu−αu+β|u|σu= 0, x∈Rn, t >0, u(0, x) =u0(x), x∈Rn

(1.1)

in the sub critical case σ∈ 0,n2

, whereα, β C andαsatisfies the dissipation conditionα >0. In the super critical caseσ > n2 the global existence result can be easily obtained for anyαand β,with α >0, since the nonlinear term decays rapidly enough |u|σuL1 Ctn2σ, when n2σ >1. In the so-called critical case σ= n2 and sub critical σ∈

0,n2

cases we can not expect a sufficient time decay of the nonlinear term for any α and β with α 0. Therefore we assume the

Date: April, 17, 2001.

1991Mathematics Subject Classification. 35Q35.

Key words and phrases. Dissipative Nonlinear Evolution Equation, Large Time Asymptotics, Landau-Ginzburg equation.

1

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conditionδ(α, β)>0, where

δ(α, β) = β|α|n−n2σ

(2 +σ)|α|2+σα2 n2.

We also suppose that the mean value of the initial dataθ≡ u0(x)dx = 0.The nonlinear term in equation (1.1) have no enough regularity to get smooth solutions in the higher order Sobolev spaces, so using smoothing properties of the linear evolution group we consider the initial value problem under the assumptions of rather small regularity on the initial data u0 L1. To estimate the remainder terms in the large time asymptotic formulas we assume that the initial data decay at infinity as |x|au0(x) L1 with somea (0,1). Existence and uniqueness of local solutions for problem (1.1) were proved (see, e.g., [5], [6], [15]). The blow-up phenomena for positive solutions to the semilinear parabolic equation

utu=u1+σ (1.2)

(note that equation (1.2) is a particular case of (1.1) if α = 1 and β =1) was obtained in paper [3] forσ∈

0,n2

, in [8] forσ= n2, n= 1,2, and in paper [14] for σ= n2, for anyn≥1.Global in time existence of small solutions to (1.2) was proved in [3] for the super critical caseσ > n2. Large time behavior of positive solutions was studied extensively for a particular case of (1.1) withα= 1 andβ = 1

utu=−u1+σ, σ >0 (1.3)

(see paper [12] for the super critical case σ > n2, [4] for the critical case σ = 2n and papers [1], [2], [7], [13] for the sub critical case σ

0,n2

). We describe in more details the results on the asymptotic behavior of solutions to the Cauchy problem for equation (1.3) in the sub critical case σ

0,n2

. In paper [7] it was proved that if the initial data are nonnegative u0 0, u0 L1 and decay slowly at infinity as limx→±∞|x|2σu0(x) = +∞,then the solution of (1.3) has the asymptotic representation u(t, x) = t1σσ1σ +o

tσ1

as t → ∞ uniformly in domains

x∈Rn; |x| ≤C√

t with any C >0. On the other hand in paper [1], there were considered the nonnegative initial data decaying sufficiently rapidly at infinity, i.e. 0≤u0(x)≤Ce−bx2 for all x∈Rn,with some b, C >0. Then it was shown that the main term of the asymptotic behavior of solution has a self-similar character u(t, x) = tσ1w0

x t

+o

tσ1

as t → ∞ uniformly with respect to x∈Rn,wherew0(ξ) is a positive solution of the elliptic equation

w−1

2ξ∇w+w1+σ= 1 σw (1.4)

which decays rapidly at infinity: lim|ξ|→∞|ξ|σ2 w0(ξ) = 0.This result was improved in paper [2], where the intermediate case was considered: if the initial data are such thatu0L1, u0 = 0 and lim|x|→∞|x|σ2u0(x) =κ>0,then the solutions have the asymptotic representation u(t, x) =t1σwκ

x t

+o

tσ1

as t → ∞ uniformly with respect to x∈Rn,where wκ(ξ) is a positive solution of equation (1.4) such that lim|ξ|→∞|ξ|σ2wκ(ξ) =κ. Note that in these papers there was no restriction on the size of the initial data. The methods of these papers could not be applied for the case of complexα, β∈C,α >0 and as far as we know there are no results

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on the asymptotic behavior of solutions to the Cauchy problem (1.1) in the case of complex coefficientsα, β.

We propose here a different approach, developed in our previous papers [9], [10]

and [11], where we considered the critical caseσ=n2.The main idea is to transform equation (1.1) via a change of the dependent variableu=e−ϕ+v to the form

vt−αv+βe−σϕ

|v|σ1 θ

|v|σvdx

v= 0,

where the nonlinear term having zero mean value obtains better decay properties.

However we assume the smallness of the initial data and the restriction onσto be able to apply the contraction mapping principle.

To state our result precisely we give.

Notation and function spaces. The Fourier transformation= ˆφis defined by ˆφ(ξ) = 1

(2π)n/2

e−ixξφ(x)dx andF1φ(x) or ˇφ(x) is the inverse Fourier transform ofφ, i.e.

φ(x) =ˇ 1 (2π)n/2

eixξφ(ξ)dξ.

We denote by Lp for 1 ≤p≤ ∞, the usual Lebesgue space with a norm φp =

Rn(x)pdx1/p

if 1≤p <∞andφ= ess.supx∈Rn(x)|.Define byWp0,a= {φ∈Lp:xaφ∈Lp}weighted Sobolev space with a normφW0,ap =xaφLp, where x =

1 +x2. By C(I;B) we denote the space of continuous functions from a time interval Ito the Banach space B. Different positive constants could be denoted by the same letterC.

We defineθ= u0(x)dx>0. We suppose thatσ∈ 0,n2

is sufficiently close to n2.

In the present paper we prove the following result.

Theorem 1.1. Let α, β C, α >0, δ(α, β) >0. We assume that the initial data u0 W01,a, a∈(0,1) have a sufficiently small norm ε=xau01 and are such that θ = u0(x)dx with 0 < C < 1. We assume that n2 −ε3 <

σ < 2n. Then there exists a unique mild solution u(t, x) C

[0,∞) ;W01,a C((0,∞) ;L) of the Cauchy problem (1.1), satisfying the following time decay estimates

u(t)L ≤Cεtσ1

for large t >0. Furthermore there exist a number A and a functionV W10,a W0,a such that the asymptotic formula

u(t, x) =Atσ1V √x

t

elogt+O

tσ1−γ

, is valid fort→ ∞uniformly with respect tox∈Rn, whereω=η1

β|V|σV(y)dy, γ=12min

a,1n2σ

, V (ξ)is the solution of the integral equation V (ξ) = 1

(4πα)n2eξ

2

4α β

η(4πα)n2 1

0

dz z(1−z)n2

e

(ξ−yz)2

4α(1−z) F(y)dy, (1.5)

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whereη= 1σn 2σ

β|V (y)|σV(y)dy, F(y) =|V(y)|σV(y)−V(y)

|V(ξ)|σV (ξ)dξ.

We organize our paper as follows. Section 2 is devoted to the proof of preliminary estimates in Lemmas 2.1 - 2.4. In Section 3 we prove Theorem 1.1 and the existence of solution V(ξ) to integral equation (1.5).

2. Preliminaries The solution of the linear Cauchy problem

ut−αu=f(t, x), x∈Rn, t >0, u(0, x) =u0(x), x∈Rn

can be written by the Duhamel formulau(t) =G(t)u0+t

0G(t−τ)f(τ)dτ ,where the Green operatorG is given by

G(t)φ=F1e−αξ2tˆφ(ξ) =

G(t, x−y)φ(y)dy, andG(t, x) = (4παt)n2 e−x2/4αt. Denoteϑ= (2π)n2 φˆ(0).

We first collect some preliminary estimates.

Lemma 2.1. The following estimates are true, provided that the right-hand sides are finite:

·bG(t)φ

p≤Ctn2(1q1p)t2b·bφ

q

and ifφ∈L1

|·|b(G(t)φ−ϑG(t))

p Ctb−a2 tn2(1q1p)·aφq +C|ϑ|tb2n2(11p)

for allt >0, where1≤q≤p≤ ∞, b∈[0, a], a∈(0,1).

Proof. Since xb ≤ x−ybyb, by virtue of the Young inequality with 1p =

1

q +1r1,we obtain ·bG(t)φ

p 1

(4πt|α|)n2 xb

e(x−y)28t (1α+α1)(y)|dy p

Ctn2

x−ybe(x−y)28t (α1+α1)yb(y)|dy p

Ctn2 ·be−Cx2/t

r

·bφ

q

Ctn2(1q1p)tb2·bφ

q

for all t > 0, where b 0,1 p ≤ ∞. Hence the first estimate of the lemma is true. The second estimate for the case t∈[0,1] follows from the first one and the

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inequality |·|bG(t)

p ≤Ctb2n2(11p). We now consider the caset 1. We write for any 0≤b≤a≤1

|x|b(G(t)φ−ϑG(t)) = 1 (4πtα)n2

|x|b

|y|a

e(x−y)24αt −e4αtx2

|y|aφ(y)dy.

(2.1)

Changing the dependent variablesx=ξ√

t andy=η√

t, applying the inequality

|ξ|b

|η|a

e(ξ−η)24α −eξ

2 4α

≤C|ξ−η|b+|η|b

|η|a e(ξ−η)24α +C|ξ|b

|η|aeξ

2 4α

C(1 +|ξ−η|)e−C(ξ−η)2+C|ξ|e−Cξ2 ≤Ce−C(ξ−η)2+Ce−Cξ2 for all|η| ≥1 and the estimate

e(ξ−η)24α −eξ

2 4α

≤C|η|e−C(ξ−η)2+C|η|e−Cξ2 for all|η| ≤1,we obtain

y∈Rsupn

|x|b

|y|a

e(x−y)24αt −e4αtx2

r

= tb−a2 +2rn sup

η∈Rn

|ξ|rb

|η|ra

e(ξ−η)24α −eξ

2 4α

r 1r

Ctb−a2 +2rn sup

η∈Rn e−C(ξ−η)2+e−Cξ2

dξ≤Ctb−a2 +2rn, (2.2)

where r∈[1,∞).The caser=is considered in the same way. Substitution of (2.2) into (2.1) via the Young inequality with 1p =1q +1r1,yields

|·|b(G(t)φ−ϑG(t))

p Ctn2 sup

y∈Rn

|x|b

|y|a

e(x−y)24αt −e4αtx2

r

|·|aφq

Ctb−a2 n2(1q1p)·aφq

for allt≥1 and 1≤p≤ ∞.Therefore the second estimate of the lemma is valid.

Lemma 2.1 is proved.

Lemma 2.2. Let the functionf(t, x)have the zero mean valuefˆ(t,0) = 0and the norm

sup

t>0 sup

1≤s≤ptν+n2(11s)tλ2·λf(t)

s=fF

be finite, where1≤p≤ ∞, λ∈(0,1), ν∈(0,1).We also suppose that the function g(t)is such thatg(t) 12tµ for allt >0,whereµ >0is such thatµ+ν <1 +λ2. Then the following inequality is valid

·b t

0 g1(τ)G(t−τ)f(τ) p

≤Ctb2t1−ν−µ−n2(1p1)fF, for allt >0, whereb∈[0, λ].

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Proof. Since ˆf(t,0) = 0 we have |x|bG(t)f = |x|b

G(t)f−(2π)n2 fˆ(0)G(t) with anyb∈[0, λ].Applying the second estimate of Lemma 2.1 we obtain

|·|bG(t−τ)f(τ)

p≤Ct−τb−λ2 (t−τ)n2(1q1p)·λf(τ) (2.3) q

for all 0< τ < t, where 0 b≤ λ≤1, 1 ≤q ≤p≤ ∞. Therefore by virtue of (2.3) we get

|·|b t

0 g1(τ)G(t−τ)f(τ) p

C t2

0 t−τb−λ2 (t−τ)n2(11p)|·|λf(τ)

1τ−µ +C

t

2t

t−τb−λ2 |·|λf(τ)

pτ−µ

CfF 2t

0 t−τb−λ2 (t−τ)n2(11p)τ−ντλ2−µ +CfF

t

t2

t−τb−λ2 τ−ν−n2(11p)τλ2−µ

CfFtb−λ2 tn2(11p) t

2

0

τ−ντλ2−µ +CfFtλ2 t−ν−n2(11p) t

2t

t−τb−λ2

Ctb2t1−ν−µ−n2(11p)fF (2.4)

for allt >0, where 1≤p≤ ∞,0≤b≤λ.Lemma 2.2 is proved.

Denoteζ= θσσ2

n2

(4π)n2σ(1n2σ)δ(α, β).Since n2−ε3< σ < 2n andθσ≥Cεσ≥Cεn2, we can suppose thatζ= θσσ2

n2

(4π)n2σ(1n2σ)δ(α, β)≥Cεn231.

Lemma 2.3. We assume thatv˜W01,awitha∈(0,1)and sufficiently small norm

˜vW0,a

1 =ε and v(0) = (2πn2 θ ≥Cε > 0. Let the function v(t, x) satisfy the estimates v(t)1+σ≤Cεt2(1+σ) andv(t)− G(t) ˜v1+σ≤Cε1+σt2(1+σ) for all t >0.Then the following inequality is valid

1 + σ θ

t

0

β|v|σv(τ , x)dx≥ 1

2t1n2σ (2.5)

for allt >0.

Proof. Applying Lemma 2.1 we get

G(t) ˜v−θG(t)1+σ≤Cεt2(1+σ) ta2 , then via the assumption

v(t)− G(t) ˜v1+σ≤Cε1+σt2(1+σ)

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we have by the H¨older inequality |v|σv−θ1+σ|G|σG

1≤ |v|σv− |G(t) ˜v|σG(t) ˜v1 +|G(t) ˜v|σG(t) ˜v−θ1+σ|G|σG

1

C

vσ1+σ+G(t) ˜vσ1+σ

v− G(t) ˜v1+σ +C

G(t) ˜vσ1+σ+θσGσ1+σ

G(t) ˜v−θG1+σ

1+2σtn2σ+1+σtn2σta2 for allt >0. By a direct computation we obtain

β|G|σG(t, x)dx =

β

(4πt)n2σ+n2 |α|n2σαn2

ex8t2σ(α1+α1)4x2dx

= 2n2tn2σ (4π)n2σ

 β|α|n−n2σ

(2 +σ)|α|2+σα2 n2



= 2n2tn2σ

(4π)n2σδ(α, β). Therefore we get

σ θ

β|v|σv(t, x)dx−θσσ2n2tn2σ

(4π)n2σ δ(α, β)

=

σ θ

β|v|σv(t, x)dx−σ θθ1+σ

β|G|σG(t, x)dx

C

θ |v|σv−θ1+σ|G|σG

1≤Cε2σtn2σ+σtn2σta2 for allt >0, whence

σ θ

t

0

β|v|σv(τ , x)dx− θσσ2n2 (4π)n2σ

1n2σδ(α, β)t1n2σ

=

σ θ

t

0

β|v|σv(τ , x)dx−ζt1n2σ

2σ t

0 τn2σ+σ t

0 τn2στa2

σζt1n2σ+σt1n2σ−a2 1 2ζt1n2σ for allt >0. Thus we get

σ θ

t

0

β|v|σv(τ , x)dx≥1

2ζt1n2σ. (2.6)

Estimate (2.6) implies (2.5), sinceζ≥1.Lemma 2.3 is proved.

Lemma 2.4. Let the function f(x) have the zero mean value fˆ(0) = 0 and the norm

·afp+·af1

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be finite, where a∈(0,1), 1≤p≤ ∞.Then the following inequalities are valid

ξa 1

0

dz z(1−z)n2

dye

(ξ−yz)2

4α(1−z) f(y) p

≤C·af1+afp

and

ξa 1

0

dz (1−z)n2

1 z t

tz dye(ξ−y

z)2

4α(1−z) f(y) p

Cta2

·af1+·afp for allt >0, where1≤p≤ ∞.

Proof. By the Young inequality for convolutions we get ξa

e

(ξ−yz)2

4α(1−z) f(y)dy p

ξ−y√ za

eC(ξ−y

z)2

1−z |f(y)|dy p

+

eC(ξ−y

z)2

1−z ya|f(y)|dy p

ξae

2 1−z

1fp+ e

2 1−z

1·afp(1−z)n2 ·bf

p

for allz∈1

2,1 ,since

φ

· −y√ z

f(y)dy p

= z2pn

φ(· −y)f y

√z

dy p

Cz2pn φ1 f

√· z

p

≤Cφ1fp. Therefore

ξa

1

12

1 z(1−z)n2

e

(ξ−yz)2

4α(1−z) f(y)dydz p

C 1

12

(1−z)n2 ξa

e(ξ−y

z)2

4α(1−z) f(y)dy p

dz≤C·afp (2.7)

and

ξa 1

12

dz (1−z)n2

1 z t

tz dye

(ξ−yz)2

4α(1−z) f(y) p

Ct1 1

12

(1−z)n2 ξa

e

(ξ−y z)2

4α(1−z) f(y)dy p

dz

Ct1·afp, (2.8)

where 1≤p≤ ∞.

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Via the condition

f(y)dy= 0,we write ξa

e(ξ−y

z)2

4α(1−z) f(y)dy p

=

ξa e(ξ−y

z)2

4α(1−z) −e ξ

2 4α(1−z)

f(y)dy p

ξa ξ−y√

za e(ξ−y

z)2

4α(1−z)

f(y)dy p

+

ξ−y√ za

e

(ξ−y z)2

4α(1−z) − ξae ξ

2 4α(1−z)

f(y)dy p

Cza2

e−C(ξ−y

z)2ya|f(y)|dy p

+Cza2

e−C(ξ−y

z)2+e−Cξ2

ya|f(y)|dy p

Cza2 ·af1e−Cξ2

p≤Cza2·af1 for allz∈

0,12 , since

φ

· −y√ z

f(y)dy p

= z2pn

φ(· −y)f y

√z

dy p

Cz2pn φp f

√· z

1≤Czn2(1p1)φpf1

pf1.

Thus

ξa 1

2

0

1 z(1−z)n2

e(ξ−y

z)2

4α(1−z) f(y)dydz p

1

2

0

dz z(1−z)n2

ξa

e(ξ−y

z)2

4α(1−z) f(y)dy p

C 12

0

dz

z1a2(1−z)n2 ·af1≤C·af1 (2.9)

and

ξa 12

0

dz (1−z)n2

1 z− t

tz e

(ξ−yz)2

4α(1−z) f(y)dy p

1

2

0

dz (1−z)n2

1 z t

tz ξa

e

(ξ−y z)2

4α(1−z) f(y)dy p

C 12

0

za2 (1−z)n2

1 z t

tz

dz·af1≤Cta2 ·af1, (2.10)

where 1 p ≤ ∞. Collecting estimates (2.7) - (2.10), we get the results of the lemma. Lemma 2.4 is proved.

3. Proof of Theorem 1.1

The local existence of solutions for the Cauchy problem (1.1) can be obtained by the standard contraction mapping principle (for the proof see [5], [6], [16]).

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Theorem 3.1. Let the initial datau0W10,a.Then for someT >0there exists a unique solutionu(t, x)C

[0, T);W10,a

C((0, T) ;L)of the Cauchy problem (1.1). Moreover if the initial data are sufficiently small·au01 ≤ε, then there exists a time T 1 such that the solution u(t, x) of the Cauchy problem (1.1) satisfy the estimates

1≤p≤∞sup sup

b∈[0,a] sup

t∈(0,T]tσ12pn t2b·bu(t)

p2ε.

In order to get desired a-priori estimates of local solutions we make a change of the dependent variableu(t, x) =e−ϕ(t)+(t)v(t, x),then we get from (1.1)

vt−αv+βe−σϕ|v|σv−(ϕ −iψ)v= 0.

(3.1)

Now let us demand that the real-valued functionsϕ(t) andψ(t) satisfy the following condition

βe−σϕ|v|σv−(ϕ −iψ)v dx= 0, hence via equation (3.1) we get dtd

v(t, x)dx= 0 for allt >0. Therefore βe−σϕ

|v|σvdx= (ϕ −iψ) (2π)n2 v(0,0).

If we chooseϕ(0) = 0 and ψ(0) = arg ˆu0(0) we have ˆ

v(t,0) = ˆv(0,0) =eϕ(0)−iψ(0)uˆ0(0)≡ |ˆu0(0)| ≡ θ (2π)n2 >0 and we obtain the equations

ϕ (t) = 1θe−σϕ β

|v|σvdx , ψ (t) =1θe−σϕ

β

|v|σvdx (3.2) .

Thus we need to solve the following system



vt−αv+βe−σϕ

|v|σ1θ

|v|σvdx v= 0, ϕ = 1θe−σϕ

β|v|σvdx , v(0, x) = ˜v(x), ϕ(0) = 0, (3.3)

where the initial data

˜

v(x) =u0(x) exp

−iarg

u0(x)dx

=u0(x) exp (−iarg ˆu0(0)). Multiplying the second equation of system (3.3) by the factor eσϕ(t), then inte- grating with respect to timet >0 and making a change of the dependent variable eσϕ(t)=g(t),we get an integral equation

v=A(v), (3.4)

where

A(v) (t) =G(t) ˜v−β t

0 g1(τ)G(t−τ)f(τ) and

f(τ) = |v|σv(τ)−v(τ) θ

|v|σv(τ , x)dx, g(τ) = 1 + σ

θ τ

0

β|v|σv(t, x)dxdt.

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We define v0 = G(t) ˜v and successive approximations vk+1 = A(vk) for k = 0,1,2, ...We prove thatAis a contraction mapping in the set

X =

v∈C

[0,∞);W01,a

C((0,∞);L) :

1≤p≤∞sup sup

b∈[0,a]sup

t>0tn2(1p1)tb2·bv(t)

p2ε

.

We prove that the mapping A transforms the setX into itself, also we prove the estimates

vk X; vk(t)− G(t) ˜v1+σ≤Cε1+σt2(1+σ) , (3.5)

gk(t)1

2t1n2σ, (3.6)

fk(t, x)dx= 0,

vk(t, x)dx=θ (3.7)

for all t > 0 and k 0, where fk(t) = |vk|σvk(t) vkθ(t)

|vk|σvk(t, x)dx and gk

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