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Article

Oscillation Results for Higher Order Differential Equations

Choonkil Park1,,† , Osama Moaaz2,† and Omar Bazighifan2,†

1 Research Institute for Natural Sciences, Hanyang University, Seoul 04763, Korea

2 Department of Mathematics, Faculty of Science, Mansoura University, Mansoura 35516, Egypt;

[email protected] (O.M.); [email protected] (O.B.)

* Correspondence: [email protected]

† These authors contributed equally to this work.

Received: 22 December 2019; Accepted: 25 January 2020; Published: 3 February 2020 Abstract: The objective of our research was to study asymptotic properties of the class of higher order differential equations with ap-Laplacian-like operator. Our results supplement and improve some known results obtained in the literature. An illustrative example is provided.

Keywords:ocillation; higher-order; differential equations;p-Laplacian equations

1. Introduction

In this work, we are concerned with oscillations of higher-order differential equations with a p-Laplacian-like operator of the form

r(t)y(n−1)(t)p−2y(n−1)(t) 0

+q(t)|y(τ(t))|p−2y(τ(t)) =0. (1) We assume that p > 1 is a constant,r ∈ C1([t0,∞),R),r(t) > 0, q,τ ∈ C([t0,∞), R),q >

0, τ(t)≤t, limt→τ(t) =∞and the condition

η(t0) =∞, (2)

where

η(t):= Z

t

ds r1/(p−1)(s).

By a solution of (1) we mean a functiony ∈ Cn−1[Ty,∞), Ty ≥ t0, which has the property r(t)y(n−1)(t)p−2y(n−1)(t) ∈ C1[Ty,∞), and satisfies (1) on [Ty,∞). We consider only those solutionsyof (1) which satisfy sup{|y(t)| : t ≥ T} > 0, for allT > Ty. A solution of (1) is called oscillatory if it has arbitrarily large number of zeros on [Ty,∞), and otherwise it is called to be nonoscillatory; (1) is said to be oscillatory if all its solutions are oscillatory.

In recent decades, there has been a lot of research concerning the oscillation of solutions of various classes of differential equations; see [1–24].

It is interesting to study Equation (1) since thep-Laplace differential equations have applications in continuum mechanics [14,25]. In the following, we briefly review some important oscillation criteria obtained for higher-order equations, which can be seen as a motivation for this paper.

Elabbasy et al. [26] proved that the equation

r(t)y(n−1)(t)p−2y(n−1)(t) 0

+q(t)f(y(τ(t))) =0,

Axioms2020,9, 14; doi:10.3390/axioms9010014 www.mdpi.com/journal/axioms

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is oscillatory, under the conditions

Z t0

1

rp1(t)dt=∞;

additionally, Z

`0 ψ(s)− 1

ppφp(s)((n−1)!)p−1ρ(s)a(s)

((p−1)µsn−1)p−1 − (p−1)ρ(s) a1/(p−1)(s)ηp(s)

!

ds= +∞,

for some constantµ∈(0, 1)and

Z

`0 kq(s)τ(s)p−1

sp−1 ds=∞.

Agarwal et al. [2] studied the oscillation of the higher-order nonlinear delay differential equation

y(n−1)(t)α−1y(n−1)(t) 0

+q(t)|y(τ(t))|α−1y(τ(t)) =0.

whereα is a positive real number. In [27], Zhang et al. studied the asymptotic properties of the solutions of equation

hr(t)y(n−1)(t)αi

0

+q(t)yβ(τ(t)) =0‚ t≥t0. whereαandβare ratios of odd positive integers,βαand

Z

t0 r−1/α(s)ds<∞. (3)

In this work, by using the Riccati transformations, the integral averaging technique and comparison principles, we establish a new oscillation criterion for a class of higher-order neutral delay differential Equations (1). This theorem complements and improves results reported in [26]. An illustrative example is provided.

In the sequel, all occurring functional inequalities are assumed to hold eventually; that is, they are satisfied for alltlarge enough.

2. Main Results

In this section, we establish some oscillation criteria for Equation (1). For convenience, we denote thatF+(t):=max{0,F(t)},

B(t):= 1 (n−4)!

Z

t (θ−t)n−4

 R

θ q(s)τ(s)s p−1ds r(θ)

1/(p−1)

dθ

and

D(s):= r(s)δ(s)|h(t,s)|p pph

H(t,s)A(s)µ(n−2)!sn2 ip−1. We begin with the following lemmas.

Lemma 1(Agarwal [1]). Let y(t) ∈ Cm[t0,∞) be of constant sign and y(m)(t) 6= 0on[t0,∞)which satisfies y(t)y(m)(t)≤0.Then,

(I)There exists a t1≥t0such that the functions y(i)(t), i=1, 2, ...,m−1are of constant sign on[t0,∞);

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(II)There exists a number k∈ {1, 3, 5, ...,m−1}when m is even, k∈ {0, 2, 4, ...,m−1}when m is odd, such that, for t≥t1,

y(t)y(i)(t)>0, for all i=0, 1, ...,k and

(−1)m+i+1y(t)y(i)(t)>0, for all i=k+1, ...,m.

Lemma 2(Kiguradze [15]). If the function y satisfies y(j)>0for all j=0, 1, ...,m,and y(m+1)<0,then m!

tmy(t)−(m−1)!

tm−1 y0(t)≥0.

Lemma 3(Bazighifan [7]). Let h∈Cm([t0,∞),(0,∞)).Suppose that h(m)(t)is of a fixed sign, on[t0,∞), h(m)(t)not identically zero, and that there exists a t1≥t0such that, for all t≥t1,

h(m−1)(t)h(m)(t)≤0.

If we havelim

t→h(t)6=0,then there exists tλ≥t0such that h(t)≥ λ

(m−1)!tm−1

h(m−1)(t), for everyλ∈(0, 1)and t≥tλ.

Lemma 4. Let n≥4be even, and assume that y is an eventually positive solution of Equation (1). If (2) holds, then there exists two possible cases for t≥t1,where t1≥t0is sufficiently large:

(C1) y0(t)>0,y00(t)>0, y(n−1)(t)>0, y(n)(t)<0, (C2) y(j)(t)>0,y(j+1)(t)<0for all odd integer

j∈ {1, 2, ...,n−3},y(n−1)(t)>0, y(n)(t)<0.

Proof. Letybe an eventually positive solution of Equation (1). By virtue of (1), we get

r(t)y(n−1)(t)p−2y(n−1)(t) 0

<0. (4)

From ([11] Lemma 4), we have thaty(n−1)(t)>0 eventually. Then, we can write (4) in the from

r(t)y(n−1)(t)p−1 0

<0, which gives

r0(t)y(n−1)(t)p−1+r(t) (p−1)y(n−1)(t)p−2y(n)(t)<0.

Thus,y(n)(t)<0 eventually. Thus, by Lemma1, we have two possible cases(C1)and(C2). This completes the proof.

Lemma 5. Let y be an eventually positive solution of Equation (1) and assume that Case(C1)holds. If

ω(t):=δ(t)

 r(t)

y(n−1)(t)p−1 yp−1(t)

, (5)

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whereδ∈C1([t0,∞),(0,∞)),then

ω0(t)≤ δ

+0 (t)

δ(t) ω(t)−δ(t)q(t)

τn−1(t) tn−1

p−1

− (p−1)µtn−2

(n−2)!(δ(t)r(t))1/(p−1)ω

p/(p−1)

(t). (6) Proof. Lety be an eventually positive solution of Equation (1) and assume that Case(C1) holds.

From the definition ofω, we see thatω(t)>0 fort≥t1, and

ω0(t) ≤ δ0(t)r

(t)y(n−1)(t)p−1 yp−1(t) +δ(t)

r(t)y(n−1)(t)p−1 0

yp−1(t)

δ(t)

(p−1)y0(t)r(t)y(n−1)(t)p−1

yp(t) .

Using Lemma3withm=n−1, h(t) =y0(t), we get y0(t)≥ µ

(n−2)!tn−2y(n−1)(t), (7)

for every constantµ∈(0, 1). From (5) and (7), we obtain

ω0(t) ≤ δ0(t)r(t)|(y(n1)(t))|p1

yp1(t) +δ(t)

r(t)|(y(n1)(t))|p10

yp1(t)

δ(t)(p−1)µt(n−2)!n2r(t)|(y(n1)(t))|p

yp(t) .

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By Lemma2, we have

y(t) y0(t) ≥ t

n−1. Integrating this inequality fromτ(t)tot, we obtain

y(τ(t)) y(t) ≥ τ

n−1(t)

tn−1 . (9)

Combining (1) and (8), we get

ω0(t) ≤ δ0(t)r(t)|(y(n1)(t))|p1

yp1(t)δ(t)q(t)(y(p1)(τ(t)))

yp1(t)

δ(t)(p−1)µt(n−2)!n2r(t)|(y(n1)(t))|p

yp(t) .

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From (9) and (10), we obtain

ω0(t)≤ δ

0+(t)

δ(t) ω(t)−δ(t)q(t)

τn−1(t) tn−1

p−1

− (p−1)µtn−2

(n−2)!(δ(t)r(t))1/(p−1)ω

p/(p−1)(t). (11)

It follows from (11) that

δ(t)q(t)

τn−1(t) tn−1

p−1

δ

0+(t)

δ(t) ω(t)−ω0(t)− (p−1)µtn−2

(n−2)!(δ(t)r(t))1/(p−1)ω

p/(p−1)(t).

This completes the proof.

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Lemma 6. Let y be an eventually positive solution of Equation (1) and assume that Case(C2)holds. If

ψ(t):=σ(t)y

0(t)

y(t), (12)

whereσ∈C1([t0,∞),(0,∞)),then

σ(t)B(t)≤ −ψ0(t) +σ

0(t)

σ(t)ψ(t)− 1 σ(t)ψ

2(t). (13)

Proof. Letybe an eventually positive solution of Equation (1) and assume that Case(C2)holds. Using Lemma2, we obtain

y(t)≥ty0(t). Thus we find thaty/tis nonincreasing, and hence

y(τ(t))≥y(t)τ(t)

t . (14)

Sincey>0, (1) becomes

r(t)y(n−1)(t)p−1 0

+q(t)yp−1(τ(t)) =0.

Integrating that equation fromt to∞, we see that

t→lim

r(t)y(n−1)(t)p−1

−r(t)y(n−1)(t)p−1+ Z

t q(s)yp−2(τ(s)) =0. (15) Since the function r

y(n−1)p−1

is positive h

r>0 andy(n−1)>0i

and nonincreasing

r

y(n−1)p−10

<0

!

, there exists a t2 ≥ t0 such that r

y(n−1)p−1

is bounded above for all t≥t2, and so limt→

r(t)y(n−1)(t)p−1

=c≥0. Then, from (15), we obtain

−r(t)y(n−1)(t)p−1+ Z

t q(s)yp−2(τ(s))≤ −c≤0.

From (14), we obtain

−r(t)y(n−1)(t)p−1+ Z

t q(s)y(s)p−1τ(s)p−1 sp−1 ds≤0.

It follows fromy0(t)>0 that

−y(n−1)(t) + y(t) r1/(p−1)(t)

Z t q(s)

τ(s) s

p−1

ds

!1/(p−1)

≤0.

Integrating the above inequality fromt to∞for a total of(n−3)times, we get

y00(t) + R

t (θ−t)n−4

R

θ q(s)

τ(s) s

p1

ds r(θ)

!1/(p−1) dθ

(n−4)! y(t)≤0. (16)

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From the definition ofψ(t), we see thatψ(t)>0 fort≥t1, and

ψ0(t) =σ0(t)y

0(t)

y(t) +σ(t)y

00(t)y(t)−(y0(t))2

y2(t) . (17)

It follows from (16) and (17) that

σ(t)B(t)≤ −ψ0(t) +σ

0(t)

σ(t)ψ(t)− 1 σ(t)ψ

2(t). This completes the proof.

Definition 1. Let

D={(t,s)∈R2:t≥s≥t0}and D0={(t,s)∈R2:t>s≥t0}. We say that a function H∈C(D,R)belongs to the class<if

(i1) H(t,t) =0for t≥t0,H(t,s)>0, (t,s)∈D0.

(i2)H has a nonpositive continuous partial derivativeH/s on D0with respect to the second variable.

Theorem 1. Let n ≥ 4 be even. Assume that there exist functions H,H ∈ <, δ,A,σ,A ∈ C1([t0,∞),(0,∞))and h,h∈C(D0,R)such that

s(H(t,s)A(s)) =H(t,s)A(s)δ

0(t)

δ(t) +h(t,s). (18) and

s(H(t,s)A(s)) =H(t,s)A(s)σ

0(t)

σ(t) +h(t,s). (19) If

lim sup

t→

1 H(t,t0)

Z t t0

"

H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1

−D(s)

#

ds=∞, (20)

for some constantµ∈(0, 1)and lim sup

t→

1 H(t,t0)

Z t

t0 H(t,s)A(s)σ(s)B(s)− σ(s)|h(t,s)|2 4H(t,s)A(s)

!

ds=∞, (21)

then every solution of (1) is oscillatory.

Proof. Let y be a nonoscillatory solution of Equation (1) on the interval [t0,∞). Without loss of generality, we can assume thatyis an eventually positive. By Lemma4, there exist two possible cases fort≥t1, wheret1≥t0is sufficiently large.

Assume that(C1)holds. From Lemma5, we get that (6) holds. Multiplying (6) byH(t,s)A(s) and integrating the resulting inequality fromt1tot, we have

Z t

t1 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1 ds

≤ − Z t

t1 H(t,s)A(s)ω0(s)ds+ Z t

t1 H(t,s)A(s)δ

0(s)

δ(s)ω(s)ds

− Z t

t1 H(t,s)A(s) (p−1)µsn−2

(n−2)!(δ(s)r(s))1/(p−1)ω

p/(p−1)

(s)ds

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Thus Z t

t1 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1 ds

≤H(t,t1)A(t1)ω(t1)− Z t

t1

s(H(t,s)A(s))−H(t,s)A(s)δ

0(t) δ(t)

ω(s)ds

− Z t

t1 H(t,s)A(s) (p−1)µsn−2

(n−2)!(δ(s)r(s))1/(p−1)ω

p/(p−1)

(s)ds

This implies Z t

t1 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1 ds

≤ H(t,t1)A(t1)ω(t1) + Z t

t1|h(t,s)|ω(s)d(s) (22)

− Z t

t1 H(t,s)A(s) (p−1)µsn−2

(n−2)!(δ(s)r(s))1/(p−1)ω

p/(p−1)(s)ds.

Using the inequality

βUVβ−1−Uβ ≤(β−1)Vβ, β>1, U≥0 andV≥0, (23) withβ= p/(p−1),

U=

(p−1)H(t,s)A(s) µs

n−2

(n−2)!

(p−1)/p

ω(s) (δ(s)r(s))1/p and

V=

p−1 p

p−1

|h(t,s)|p−1

δ(s)r(s)

(p−1)H(t,s)A(s)(n−2)!µsn2 p−1

(p−1)/p

,

we get

|h(t,s)|ω(s)−H(t,s)A(s) (p−1)µsn−2

(n−2)!(δ(s)r(s))1/(p−1)ω

p/(p−1)

δ(s)r(s)

H(t,s)A(s)(n−2)!µsn2 p−1

|h(t,s)|

p p

,

which with (23) gives Z t

t1 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1

−D(s)

!

ds ≤ H(t,t1)A(t1)ω(t1)

≤ H(t,t0)A(t1)ω(t1).

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Then

1 H(t,t0)

Z t

t0 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1

−D(s)

! ds

≤A(t1)ω(t1) + Z t1

t0 A(s)δ(s)q(s)

τn−1(s) sn−1

p−1 ds

<∞,

for someµ∈(0, 1), which contradicts (20).

Assume that Case (C2)holds. From Lemma 6, we get that (13) holds. Multiplying (13) by H(t,s)A(s), and integrating the resulting inequality fromt1tot, we have

Z t

t1 H(t,s)A(s)σ(s)B(s)ds ≤ − Z t

t1H(t,s)A(s)ψ0(s)ds+ Z t

t1 H(t,s)A(s)σ

0(s) σ(s)ψ(s)ds

− Z t

t1

H(t,s)A(s) σ(s) ψ

2(s)ds

= H(t,t1)A(t1)ψ(t1)− Z t

t1

H(t,s)A(s) σ(s) ψ

2(s)ds

− Z t

t1

s(H(t,s)A(s))−H(t,s)A(s)σ

0(t) σ(t)

ψ(s)ds.

Then Z t

t1 H(t,s)A(s)σ(s)B(s)ds ≤ H(t,t1)A(t1)ψ(t1) + Z t

t1|h(t,s)|ψ(s)d(s)

− Z t

t1

H(t,s)A(s) σ(s) ψ

2(s)ds.

Hence we have Z t

t1 H(t,s)A(s)σ(s)B(s)−σ(s)|h(t,s)|2 4H(t,s)A

!

ds ≤ H(t,t1)A(t1)ψ(t1)

≤ H(t,t0)A(t1)ψ(t1). This implies

1 H(t,t0)

Z t

t0 H(t,s)A(s)σ(s)B(s)−σ(s)|h(t,s)|2 4H(t,s)A

! ds

≤ A(t1)ψ(t1) + Z t

t0 A(s)σ(s)B(s)ds< which contradicts (21). Therefore, every solution of (1) is oscillatory.

In the next theorem, we establish new oscillation results for Equation (1) by using the comparison technique with the first-order differential inequality:

Theorem 2. Let n ≥ 2 be even and r0(t) > 0. Assume that for some constant λ ∈ (0, 1), the differential equation

ϕ0(t) + q(t) r(τ(t))

λτn1(t) (n−1)!

!p−1

ϕ(τ(t)) =0 (24) is oscillatory. Then every solution of (1) is oscillatory.

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Proof. Let (1) have a nonoscillatory solutiony. Without loss of generality, we can assume thaty(t)>0 fort≥t1, wheret1≥t0is sufficiently large. Sincer0(t)>0, we have

y0(t)>0, y(n−1)(t)>0 andy(n)(t)<0. (25) From Lemma3, we get

y(t)≥ λt

n−1

(n−1)!r1/p−1(t)r

1/p−1

(t)y(n−1)(t), (26)

for everyλ∈(0, 1). Thus, if we set

ϕ(t) =r(t)hy(n−1)(t)ip−1>0, then we see thatϕis a positive solution of the inequality

ϕ0(t) + q(t) r(τ(t))

λτn1(t) (n−1)!

!p−1

ϕ(τ(t))≤0. (27) From [22] (Theorem 1), we conclude that the corresponding Equation (24) also has a positive solution, which is a contradiction.

Theorem2is proved.

Corollary 1. Assume that (2) holds and let n≥2be even. If

t→liminf Z t

τ(t)

q(s) r(τ(s))

τn

1

(s)p−1ds> ((n−1)!)p−1

e , (28)

then every solution of (1) is oscillatory.

Next, we give the following example to illustrate our main results.

Example 1. Consider the equation

y(4)(t) + γ t4y

9 10t

=0, t≥1, (29)

whereγ>0is a constant. We note that n=4, r(t) =1, p=2, τ(t) =9t/10and q(t) =γ/t4. If we set H(t,s) =H(t,s) = (t−s)2,A(s) = A(s) =1,δ(s) =t3,σ(s) =t, h(t,s) = (t−s) 5−3ts−1 and h(t,s) = (t−s) 3−ts−1

then we get

η(s) = Z

t0

1

r1/(p−1)(s)ds=∞ and

B(t) = 1 (n−4)!

Z t

(θ−t)n−4

 R

θ q(s)τ(s)s p−1ds r(θ)

1/(p−1)

dθ

= 3γ/

20t2 .

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Hence conditions (20) and (21) become

lim sup

t→

1 H(t,t0)

Z t

t0 H(t,s)A(s)δ(s)q(s)

τn−1(s) sn−1

p−1

−D(s)

! ds

=lim sup

t→

1 (t−1)2

Z t 1

729γ

1000t2s−1+729γ

1000s−729γ 500 t− s

2µ

25+9t2s−2−30ts−1 ds

= (ifγ>500/81) and

lim sup

t→

1 H(t,t0)

Z t

t0 H(t,s)A(s)σ(s)B(s)− σ(s)|h(t,s)|2 4H(t,s)A(s)

! ds

=lim sup

t→

1 (t−1)2

Z t 1

3γ

20t2s−1+3γ 20s−3γ

10t− s 4

9−630ts−1+t2s−2 ds

= (ifγ>5/3).

Thus, by Theorem1, every solution of Equation (29) is oscillatory ifγ>500/81.

3. Conclusions

In this work, we have discussed the oscillation of the higher-order differential equation with a p-Laplacian-like operator and we proved that Equation (1) is oscillatory by using the following methods:

1. The Riccati transformation technique.

2. Comparison principles.

3. The Integral averaging technique.

Additionally, in future work we could try to get some oscillation criteria of Equation (1) under the conditionR

t0 1

r1/(p1)(t)dt<∞. Thus, we would discuss the following two cases:

(C1) y(t)>0, y(n−1)(t)>0, y(n)(t)<0, (C2) y(t)>0, y(n−2)(t)>0, y(n−1)(t)<0.

Author Contributions:The authors claim to have contributed equally and significantly in this paper. All authors have read and agreed to the published version of the manuscript.

Funding:The authors received no direct funding for this work.

Acknowledgments:The authors thank the reviewers for for their useful comments, which led to the improvement of the content of the paper.

Conflicts of Interest:The authors declare no conflict of interest.

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