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Phase Transformation of Materials Phase Transformation of Materials

Eun Eun Soo Soo Park Park

Office: 33-316

Telephone: 880-7221 Email: [email protected]

Office hours: by an appointment

2009 fall

09.17.2009

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Equilibrium in Heterogeneous Systems

In X0, G0β > G0α > G1 α + β 로 분리 두상의 화학 포텐셜 일치

α1 β1

α4 β4

μ

B

a

Aα

=a

Aβ

a

Bα

=a

Bβ

Ge

Contents for previous class

μ

A

μ

A

=

μ

B

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Contents for today’s class

- Binary phase diagrams

1) Simple Phase Diagrams

2) Systems with miscibility gap 4) Simple Eutectic Systems

3) Ordered Alloys

5) Phase diagrams containing intermediate phases

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1.5 Binary phase diagrams

1) Simple Phase Diagrams

(4) T1 > Tm(A) >T2 > Tm(B) >T3

가정: (1) completely miscible in solid and liquid.

(2) Both are ideal soln.

(3) Tm(A) > Tm(B)

Draw GL and GS as a function of composition XB

at T1, Tm(A), T2, Tm(B), and T3.

= 0 ΔHmixS

= 0 ΔHmixL

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1) Simple Phase Diagrams 가정: (1) completely miscible in solid and liquid.

(2) Both are ideal soln.

(3) Tm(A) > Tm(B)

(4) T1 > Tm(A) >T2 > Tm(B) >T3

1.5 Binary phase diagrams

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2) Systems with miscibility gab

= 0 ΔHmixL

congruent minima

> 0 ΔHmixS

How to characterize Gs mathematically

in the region of miscibility gap between e and f ? 1.5 Binary phase diagrams

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Regular Solutions

Reference state

Pure metal GA0 =GB0 = 0

) ln

ln

( A A B B

B A B

B A

AG X G X X RT X X X X

X

G = + + Ω + +

G2 = G1 + ΔGmix

Gmix = Hmix - TSmix

Hmix -TSmix

Ideal Solutions

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2) Systems with miscibility gab

= 0

ΔHmixL ΔHmixS > 0

congruent minima

When A and B atoms dislike each other,

In this case, the free energy curve at low temperature has a region of negative curvature,

This results in a ‘miscibility gap’ of α′ and α″ in the phase diagram 1.5 Binary phase diagrams

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ΔHm>>0 and the miscibility gap extends to the melting temperature.

(when both solids have the same structure.)

4) Simple Eutectic Systems ΔHmixL = 0 ΔHmixS >> 0

1.5 Binary phase diagrams

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(when each solid has the different crystal structure.)

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1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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(4) 1.5 Binary phase diagrams

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1.5 Binary phase diagrams

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(4) 1.5 Binary phase diagrams

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3) Ordered Alloys ΔHmixL = 0 ΔHmixS < 0

ΔHmix < 0 A atoms and B atoms like each other.

What would happen when ΔHmix<< 0?

The ordered state can extend to the melting temperature.

How does the phase diagram differ from the previous case?

.

.

congruent maxima 1.5 Binary phase diagrams

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Regular Solutions

Reference state

Pure metal GA0 =GB0 = 0

) ln

ln

( A A B B

B A B

B A

AG X G X X RT X X X X

X

G = + + Ω + +

G2 = G1 + ΔGmix

Gmix = Hmix - TSmix

Hmix -TSmix

Ideal Solutions

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Intermediate Phase

* Solid solution

Æ random mixing Æ entropy

negative enthalpy ↓

넓은 조성 범위 Î G ↓

* Compound : AB, A2B…

Æ entropy

Æ covalent, ionic contribution.

Æ enthalpy more negative

좁은 조성 범위 Î G

< 0 ΔHmixS

<< 0 ΔHmixS

1.5 Binary phase diagrams

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5) Phase diagrams containing intermediate phases

1.5 Binary phase diagrams

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5) Phase diagrams containing intermediate phases

1.5 Binary phase diagrams

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Peritectoid: two other solid phases transform into another solid phase upon cooling

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α

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The Gibbs Phase Rule

In chemistry, Gibbs' phase rule describes the possible number of degrees of freedom (F) in a closed system at equilibrium, in terms of the number of separate phases (P) and the number of chemical components (C) in the system. It was deduced from thermodynamic principles by Josiah Willard Gibbs in the 1870s.

In general, Gibbs' rule then follows, as:

F = C P + 2 (from T, P).

From Wikipedia, the free encyclopedia

1.5 Binary phase diagrams

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2

2 3 2 1

1

1

1 single phase F = C - P + 1

= 2 - 1 + 1

= 2

can vary T and composition independently

2 two phase

F = C - P + 1

= 2 - 2 + 1

= 1

can vary T or composition

3 eutectic point F = C - P + 1

= 2 - 3 + 1

= 0

can’t vary T or composition For Constant Pressure,

P + F = C + 1

The Gibbs Phase Rule

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The Gibbs Phase Rule

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재 료 설 계

σ/E=

10-4

10-3

10-2

10-1 σ2/E=C Elastomers Polymers

Foams

wood

Engineering Polymers Engineering

Alloys

Engineering Ceramics

Engineering Composites Porous

Ceramics

Strength σy (MPa)

Youngsmodulus, E (GPa)

< Ashby map >

0.1 1 10 100 1000 10000

0.01 0.1

1 10 100 1000

Metallic glasses

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재 료 설 계

composite Metals

Polymers

Ceramics

Metallic Glasses

Elastomers

Menu of engineering materials

High GFA

High plasticity

higher strength

lower Young’s modulus high hardness

high corrosion resistance good deformability

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재 료 설 계 주 제 제안

이번 학기에 깊이있게 조사해보고 싶은 재료 3 가지와 그 이유를 각 1 page 씩 정 리 하 여 24 일 까 지 제 출 하 시 오 . Ex) stainless steel/ Carbon nanotube/

Bio-material/ Dendrimer etc.

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Degree of freedom (number of variables that can be varied independently)

The Gibbs Phase Rule

= the number of variables – the number of constraints

Referensi

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