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Volume 1, Number1 (2010), 137 146

EQUICONVERGENCE THEOREMS

FOR STURMLIOVILLE OPERATORS

WITH SINGULAR POTENTIALS

(RATE OF EQUICONVERGENCE IN

W 2 θ

NORM)

I.V. Sadovnihaya

Communiated by M.Otelbaev

Keywords and phrases: equionvergene, SturmLioville operators, singular

potential.

Mathematis Subjet Classiation: 34L10, 34L20,47E05.

Abstrat.Westudy the SturmLiouville operator

Ly = l(y) = − d 2 y

dx 2 + q(x)y

with

Dirihlet boundary onditions

y(0) = y(π) = 0

in the spae

L 2 [0, π]

. We assume

that the potential has the form

q(x) = u (x)

, where

u ∈ W 2 θ [0, π]

with

0 < θ <

1/2

. Here

W 2 θ [0, π] = [L 2 , W 2 1 ] θ

is the Sobolev spae. We onsider the problem of

equionvergene in

W 2 θ [0, π]

norm of two expansions of a funtion

f ∈ L 2 [0, π]

.

The rst one is onstruted using the system of the eigenfuntions and assoiated

funtions of the operator

L

. The seond one is the Fourier expansion in the series

of sines. We show that the equionvergene holds for any funtion

f

in the spae

L 2 [0, π]

.

1 Introdution

In this paperwe deal with the SturmLiouville operator

Ly = l(y) = − d 2 y

dx 2 + q(x)y, (1)

with Dirihlet boundary onditions

y(0) = y(π) = 0

in the spae

L 2 [0, π]

. We

assume that the potential

q

is omplex-valued and has the form

q(x) = u (x)

,

where

u ∈ W 2 θ [0, π]

with

0 < θ < 1/2

. Here the derivative is treated in the

distributional sense, and

W 2 θ [0, π] = [L 2 , W 2 1 ] θ

is the Sobolev spae with frational

orderof smoothnessdened by interpolation.This lass of operatorswas dened in

the papers of A.M. Savhuk and A.A. Shkalikov [7℄[9℄. In partiular, itwas shown

there that

L

is bounded frombelowand has purely disretespetrum.

Weonsider the problemof equionvergene in

W 2 θ [0, π]

normof two expansion

of a funtion

f ∈ L 2 [0, π]

. The rst one is onstruted using the system of the

eigenfuntions and assoiated funtions of the operator

L

, while the seond one is

(2)

Theproblemofuniformequionvergene (i.e.inthenormofthespae

C[0, π]

)is

wellstudiedinthelassialtheoryofSturmLiouvilleoperatorsforregularpotentials

q ∈ L 1 (0, π)

. Inthe monograph of V.A.Marhenko [4℄the uniform equionvergene wasproved foranyfuntion

f ∈ L 2 [0, π]

.In 1991V.A. Il'in[2℄proved thisresult for

any

f ∈ L 1 [0, π]

. V.A. Vinokurov and V.A. Sadovnihii [10℄ proved a theorem on

the equionvergene for SturmLiouvilleoperatorswhose potentialisthe derivative

of a funtionof bounded variation (and alsofor any

f ∈ L 1 [0, π]

).

The problem of the rate of equionvergene (for regularpotentials) was studied

in the paper of A.M. Gomilko and G.V. Radzievskii [1℄. In the author's paper [5℄

results were obtained in the ase in whih

q = u

,

u ∈ W 2 θ [0, π]

with

0 < θ < 1/2

.

It wasshown that forany

f ∈ L 2 [0, π]

one an estimatethe rateof equionvergene uniformlyover the ball

u ∈ B θ,R = { v ∈ W 2 θ [0, π] : k v k W 2 θ 6 R }

. This result is new

even inthe lassialase

q ∈ L 2 [0, π]

.

In thispaperweproveequionvergene and obtainasimilarestimateof the rate

of equionvergene inthe norm of the spae

W 2 θ [0, π]

with

0 < θ < 1/2

.

2 Preliminary results

Webegin with the following results about operator (1).

Letus reallthat the operator

L

is bounded frombelow andhas purely disrete

spetrum.Let

{ λ n } 1

bethe sequene of alleigenvaluesof the operator

L

.Weshall

enumerate theeigenvalues insuh away that

| λ 1 | 6 | λ 2 | 6 . . .

, andweassume that

eah eigenvalue is repeated as many times as its algebrai multipliity. By

{ y n } 1

we denote the system of the eigenfuntions and assoiated funtions. We assume

that the funtion

y n

orresponds to the eigenvalue

λ n

and

k y n k L 2 = 1

if

y n

is an

eigenfuntion.

Statement 1 (A.M. Savhuk, A.A. Shkalikov). Let

u ∈ L 2 [0, π]

. Then the system

{ y n } 1

of theeigenfuntionsandassoiatedfuntionsof theoperator

L

forms aRiesz

basis in the spae

L 2 [0, π]

.

By the above there exists the biorthogonal system

{ w n } 1

, i.e.

(y n , w m ) = δ nm

where

(f, g) = R π

0

f (x)g(x)dx

. For more detailssee [5℄.

Let

l θ 2 =

 

 x = { x n } n=1 :

X ∞ n=1

| x n | 2 n

! 1/2

= k{ x n }k l 2 θ < ∞

 

 .

Wereall that for any

u ∈ W 2 θ [0, π]

with

0 < θ < 1/2 C 1 k{ u n }k l 2 θ 6 k u k W 2 θ 6 C 2 k{ u n }k l θ 2

where

u n = r 2

π (u(x), sin nx)

and

C 1 , C 2 > 0

are independent of

u

.

(3)

Statement 2 (A.M. Savhuk, A.A. Shkalikov). Let

R > 0

,

0 < θ < 1/2

, and

u ∈ B θ,R

. Then there exists a natural number 2

N = N θ,R

suh that for all

n > N

the eigenvalues

λ n

of the operator

L

are simple,

y n (x) = q

2

π sin nx + ϕ n (x), w n (x) = q

2

π sin nx + ψ n (x), y n (x) = n q

2

π cos nx + η n (x)

+ u(x) q

2

π sin nx + ϕ n (x)

, (2)

where the funtions

ϕ n

,

ψ n

and

η n

are suh that the sequene

{ γ n } n=N = {k ϕ n (x) k C + k ψ n (x) k C + k η n (x) k C } n=N ∈ l 2 θ

and its norm in this spae is bounded

by a quantity depending only on

θ

and

R

. Moreover for

n > N ψ n (x) = ψ n,0 (x) + ψ n,1 (x),

where

ψ n,0 (x) = α n sin nx + β n x cos nx − r 2

π Z x

0

u(t) sin n(x − 2t)dt, (3)

andthenumbers

α n

,

β n

andthefuntions

ψ n,1

aresuhthatthenormofthesequene

{| α n | + | β n |} n=N

in the spae

l 2 θ

is bounded by a quantity depending only on

θ

and

R

, and the sequene

{k ψ n,1 (x) k C } n=N

belongs to the spae

l 1 τ

for any

τ < 2θ

.

Statement 3. Let

R > 0

,

0 < θ < 1/2

and

u ∈ B θ,R

. Then there exists a natural

number

N = N θ,R

suh that for all

n > N

the operator

P n (u) : L 2 [0, π] → W 2 1 [0, π], P n (u) : f 7→

X n k=1

(f, w k )y k ,

is ontinuous on

B θ,R

, i.e. for any

u 0 ∈ B θ,R

k P n (u) − P n (u 0 ) k L 2 → W 2 1 → 0

as

k u − u 0 k W 2 θ → 0, u ∈ B θ,R .

This statement follows from the results of the paper [8℄ (Theorem 1.9) and

lassial theorems (see [3, Theorems IV.2.23 and IV.3.16℄). For detailed proof see

[6℄.

3 Main theorem

Theorem. Let

R > 0

,

0 < θ < 1/2

.Consideroperator(1)atinginthespae

L 2 [0, π]

with the homogeneous Dirihlet boundary onditions. Suppose that the omplex-

valued potential

q(x) = u (x)

, where

u(x) ∈ B θ,R

.

Let

{ y n (x) } n=1

be the system of the eigenfuntions and assoiated funtions of the operator

L

and

{ w n (x) } n=1

be the biorthogonal system.

2

Here andin thesequelwhen we write

N θ,R

,

C θ,R

etwemean that these quantities depend

onlyon

θ

and

R

.

(4)

For an arbitrary funtion

f ∈ L 2 [0, π]

denote

c n := (f(x), w n (x)), c n,0 := p

2/π(f (x), sin nx).

Then there exist a natural number

M = M θ,R

and a positive number

C = C θ,R

suh

that for all

m > M

and for all

f ∈ L 2 [0, π]

X m n=1

c n y n (x) − X m n=1

r 2

π c n,0 sin nx W 2 θ

6 C

 s X

n>m 1−θ

| c n,0 | 2 + k f k L 2

m θ(1 θ)

 . (4)

Proof.

Step 1 (operators

B m,N

and

B m

).

For given integers

m

,

m > N

, we introdue the operator

B m,N : L 2 [0, π] → W 2 θ [0, π]

dened by

B m,N f (x) :=

X m n=N

c n y n (x) − X m n=N

r 2

π c n,0 sin nx

and denote

B m,1 =: B m

. Then for any funtion

f ∈ L 2 [0, π]

the following equality

holds:

B m,N f (x) = X m n=N

r 2

π (f (t), ψ n (t)) sin nx+

+ X m n=N

r 2

π (f (t), sin nt)ϕ n (x) + X m n=N

(f(t), ψ n (t))ϕ n (x). (5)

Let

N = N θ,R

be the maximal of the positive integers dened in Statements 2

and 3.

Step 2 (estimation of the norm of the operator

B m,N

).

There existsapositive number

C θ,R

suhthatforallnatural

m

satisfying

m > N k B m,N (u) k L 2 → W 2 θ 6 C θ,R . (6)

Letusestimateeahtermoftheright-handsidein(5)separately.Byasymptoti

formulae (2)we have:

X m n=N

(f (t), ψ n (t)) sin nx W 2 θ

6 C 1 X m n=N

| (f (t), ψ n (t)) | 2 n

! 1/2

6

6 C 1

X m n=N

k f k 2 L 2 k ψ n k 2 L 2 n

! 1/2

6 C 2 k f k L 2 ,

where

C 1 , C 2 > 0

are independent of

f

. Consider the seond and the third terms.

We willshow that

{k ϕ n k W 2 θ } n=N ∈ l 2

provided that

0 < θ < 1/2

. Asymptotis (2)

implythe estimate

k ϕ n k W 2 θ 6 C 3 k ϕ n k 1 L 2 θ k ϕ n k θ W 2 1 6 C 4 k ϕ n k 1 L 2 θ k ϕ n k θ L 2 6

(5)

6 C 4 k ϕ n k 1 L 2 θ

 k η n k θ L 2 n θ + r 2

π

! θ

k u k θ L 2 + k uϕ n k θ L 2

 6 C 5 k ϕ n k 1 L 2 θ k η n k θ L 2 n θ + 1

=

= C 5 k ϕ n k L 2 n θ 1 − θ

( k η n k L 2 n θ ) θ + (n θ 1 ) θ

, (7)

where

C 3 , C 4 , C 5 > 0

are independent of

n

. Here we used the inequality

k f k W 2 1 6

√ π 2 + 1 k f k L 2

fullledforall

f ∈ W 2 1 [0, π]

satisfying

f(0) = 0

.NextweuseHolder's

inequality

X m n=N

(a 1 n θ b θ n ) 2 = X m n=N

(a 2 n ) 1 θ (b 2 n ) θ 6 X m n=N

a 2 n

! 1 − θ X m n=N

b 2 n

! θ

andnote thatthe sequenes

{k ϕ n k L 2 n θ } n=N

,

{k η n k L 2 n θ } n=N

,and

{ n θ 1 } n=1

belong

to

l 2

spae for any

0 < θ < 1/2

. Therefore (7) impliesthe inequality

X m

n=N

k ϕ n k 2 W 2 θ 6 C 6 , (8)

where

C 6 > 0

is independent of

m

and

N

. Then

X m n=N

(f (t), sin nt)ϕ n (x) W 2 θ

6 X m n=N

| f n |k ϕ n k W 2 θ 6 C 7 k f k L 2 , (9)

where

f n = (f (t), sin nt)

and

C 7 = √ C 6

.

For the lastterm of the right-handside in(5)wehave:

X m n=N

(f (t), ψ n (t))ϕ n (x) W 2 θ

6 X m n=N

k f k L 2 k ψ n k L 2 k ϕ n k W 2 θ 6

6 k f k L 2

X m n=N

k ψ n k 2 L 2

! 1/2 X m n=N

k ϕ n k 2 L 2

! 1/2

6 C 8 k f k L 2 , (10)

where

C 8 > 0

is independent of

m

and

N

, beause the onditions of our theorem

implythat

{k ψ n k L 2 } n=N ∈ l 2

.

Weproved inequality (6). Step 2is ompleted.

Step 3 (estimation of the norm of the operator

B m

).

There existsapositive number

C θ,R

suhthatfor allnatural

m

satisfying

m > N k B m (u) k L 2 → W 2 θ 6 C θ,R . (11)

Obviously the operator

B m (u)

an berepresented asthe sum:

B m (u) = B N − 1 (u) + B m,N (u) = P N − 1 (u) − P N − 1 (0) + B m,N (u),

(6)

where

P n (u)

is the operator dened in statement 3. Hene

k B m (u) k L 2 → W 2 θ 6 2 sup

v ∈ B θ,R

k P N − 1 (v) k L 2 → W 2 θ + k B m,N (u) k L 2 → W 2 θ 6 6 2 sup

v ∈ B θ,R

k P N − 1 (v) k L 2 → W 2 1 + k B m,N (u) k L 2 → W 2 θ .

Let

0 < θ 1 < θ

, say

θ 1 = θ 2

. Bystatement3 thefuntion

k P N − 1 (v ) k L 2 → W 2 1 : B θ 1 ,R → R

is ontinuous on

B θ 1 ,R

. It is known that the ball

B θ,R

is a ompat subset of

B θ 1 ,R

. Therefore the funtion

k P N − 1 (v ) k L 2 → W 2 1

is bounded on

B θ,R

by a onstant

depending only on

θ

and

R

. This, together with inequality (6), imply (11). Step 3

is ompleted.

Step 4 (proof of the equionvergene).

Let

f ∈ L 2 [0, π]

. Then

m lim →∞ k B m f k W 2 θ = 0. (12)

First let us hek that the system

{ y k } 1

of the eigenfuntions and assoiated funtions is minimal in the spae

W 2 θ [0, π]

. Assume the onverse. Then

y n ∈ span { y k } k 6 =n

(here the losure is taken subjet to

W 2 θ [0, π]

norm) for some natural

number

n

. Therefore

y n ∈ span { y k } k 6 =n

, where the losure is taken subjet to

L 2 [0, π]

norm. It means that the system

{ y k } 1

is not minimal inthe spae

L 2 [0, π]

ontradition with statement 1. Next, we proved (see (8)) that the system

{ y k } 1

is lose to the orthogonal basis

{ p

2/π sin kx } 1

in the spae

W 2 θ [0, π]

. Let

us now onsider the orthonormal basis

nq 2

π (1 + k 2 ) θ/2 sin kx o ∞ 1

and the system

{ (1 + k 2 ) θ/2 y k } 1

in

W 2 θ [0, π]

. We see that these two systems are also lose in the

spae

W 2 θ [0, π]

.Itanbeeasilyproved thatthe system

{ (1 + k 2 ) θ/2 y k } 1

isminimal

inthe spae

W 2 θ [0, π]

.Hene, this system formsthe Baribasis inthe spae

W 2 θ [0, π]

and onsequently the system

{ y k } 1

is totalin this spae.

Let usonsider the image ofthe funtion

y k

underthe map

B m

:

(B m y k )(x) = X m n=1

(y k (x), w n (x))y n (x) − 2 π

X m n=1

(y k (x), sin nx) sin nx.

Therst term ofthe right-handsideinthe lastequalityisequalto0for

m < k

and

is equalto

y k (x)

for

m > k

.The seondone is the partialsum of the Fourier series

for the funtion

y k

. Reallthat the funtion

y k ∈ W 2 1

. This implies that its Fourier

series onverges to

y k

in

W 2 1

norm. Consequently this series onverges to

y k

in the

spae

W 2 θ

. This yields that (12) holds for any funtion

f ∈ span { y k }

. To onlude

the proof of the Step 4, it remains to apply ompleteness of the system

{ y k }

and

inequality(11).

Nowletusproveinequality(4).Let

g k (x) = P k n=1

c n y n (x)

,where

k > N

.Itislear

that for any funtion

f ∈ L 2 [0, π]

and any natural number

m

k B m f k W 2 θ 6 k B m (f − g k ) k W 2 θ + k B m g k k W 2 θ . (13)

(7)

Step 5 (estimation of the norm of

B m (f − g k )

in the spae

W 2 θ [0, π]

).

There exists a positive number

C θ,R

suh that for all natural

k

,

m

satisfying

k, m > N

and for all

f ∈ L 2 [0, π]

k B m (f − g k ) k W 2 θ 6 C θ,R

 X ∞ n=k+1

| c n,0 | 2

! 1/2

+ k f k L 2

k θ

 . (14)

By asymptotiformula(2) wehave:

k f(x) − g k (x) k L 2 =

X ∞ n=k+1

c n y n (x) 6

6

X ∞ n=k+1

2

π (f (x), sin nx) sin nx L 2

+

X ∞ n=k+1

r 2

π (f (x), ψ n (x)) sin nx L 2

+

+

X ∞ n=k+1

r 2

π (f (x), sin nx)ϕ n (x) L 2

+

X ∞ n=k+1

(f (x), ψ n (x))ϕ n (x) L 2

6

6

 X

n=k+1

| c n,0 | 2

! 1/2

+

X ∞ n=k+1

| (f(x), ψ n (x)) | 2

! 1/2 

 ×

×

1 + X

n=k+1

k ϕ n k 2 L 2

! 1/2 

 6

6

 X

n=k+1

| c n,0 | 2

! 1/2

+ k f k L 2

k θ

1 + C θ,R

k θ

. (15)

Now inequality (14) follows from (15) and (11). Step 5is ompleted.

Next we estimate the seond term in (13). For a given natural

m

,

m > k

, we

introdue the operator

S m : W 2 1 [0, π] → W 2 θ [0, π]

dened by

S m h(x) = 2/π

X ∞ n=m+1

(h(t), sin nt) sin nx .

Notethat

B m g k (x) = g k (x) − 2 π

X m n=1

(g k (t), sin nt) sin nx = S m g k (x) .

(The expression

S m g k (x)

is well dened, sine all eigenfuntions and assoiated funtionsof the operator

L

belong to the spae

W 2 1 [0, π]

.) Therefore

k B m g k k W 2 θ 6 k S m (g k − g N ) k W 2 θ + k S m g N k W 2 θ . (16)

(8)

Step 6 (estimation of the norm of

S m (g k − g N )

in the spae

W 2 θ [0, π]

).

There existsa positive number

C θ,R

suh thatforallnatural

k, m

satisfying

m >

k > N

and for all

f ∈ L 2 [0, π]

k S m (g k − g N ) k W 2 θ 6 C θ,R k f k L 2 m θ 1 k 1 θ . (17)

First let usreall that

y n (x) = p

2/π sin nx + ϕ n (x)

(see (2)) and represent the

left-hand side of inequality (17) as follows:

k S m (g k (x) − g N (x)) k W 2 θ =

X k n=N +1

c n S m y n (x) W 2 θ

=

X k n=N +1

c n S m ϕ n (x) W 2 θ

.

Notethat 3

X k n=N+1

| c n | 2 6 X ∞ n=N+1

| c n | 2 6

6 2 2 π

X ∞ n=N+1

| (f (x), sin nx) | 2 + X ∞ n=N+1

| (f (x), ψ n (x)) | 2

!

6 C θ,R (1) k f k 2 L 2 ,

Therefore

X k n=N +1

c n S m ϕ n (x) W 2 θ

6

X k n=N+1

| c n | 2

! 1/2 k X

n=N +1

k S m ϕ n (x) k 2 W 2 θ

! 1/2 6

6 q

C θ,R (1) k f k L 2

X k n=N +1

k S m ϕ n (x) k 2 W 2 θ

! 1/2

.

Furthermore

k S m ϕ n (x) k W 2 θ 6 C θ,R (2)

X ∞ j=m+1

(j + 1) | (ϕ n (x), sin jx) | 2

! 1/2

=

= C θ,R (2)

X ∞ j=m+1

j + 1

j 2 | (ϕ n (x), cos jx) | 2

! 1/2

6 C θ,R (2) m θ 1 k ϕ n (x) k W 2 1 . (18)

Here we applied integration by parts and boundary onditions

ϕ n (0) = ϕ n (π) = 0

. By asymptoti formulae (2) we obtain

ϕ n (x) = nη n (x) + u(x)y n (x)

, where

{k η n (x) k L 2 + n θ 1 } ∈ l θ 2

. Consequently

k ϕ n (x) k L 2 6 (n k η n (x) k L 2 + k u(x)y n (x) k L 2 ) = n 1 θ τ n ,

3

Here

C θ,R (1)

andin thesequel

C θ,R (j)

with

j = 2, 3...

aresomepositivequantitiesdependingonly

on

θ

and

R

.

(9)

where

k{ τ n }k l 2 6 C θ,R (3)

.Therefore,

k S m ϕ n (x) k W 2 θ 6 C θ,R (4) m θ 1 n 1 θ τ n .

This impliesthat the rst term in(16) satises the followinginequality:

k S m (g k − g N ) k W 2 θ 6 C θ,R (5) k f k L 2

X k n=1

m 2 n 2 τ n 2

! 1/2

6 C θ,R (6) k f k L 2 m θ 1 k 1 θ .

Step 6 isompleted.

Step 7 (estimation of the norm of

S m g N

in the spae

W 2 θ [0, π]

).

Finallyweonsidertheseondtermin(16).Weshallestimatethenorm

k S m g N k C

inthe same way as in(18):

k S m g N (x) k C 6 C θ,R (7) m θ 1 k g N (x) k L 2 6 C θ,R (7) m θ 1 k g N k W 2 1 .

Sine

k P N (u) k L 2 → W 2 1 6 C θ,R

(see Step 3) and

g N = P N f

we have

k g N k W 2 1 6 C θ,R k f k L 2

.Therefore,

k S m g N k C 6 C θ,R (8) k f k L 2 m θ 1 . (19)

Hene inequalities(16), (17) and (19) imply that

k B m g k k C 6 C θ,R (9) k f k L 2 m θ 1 k 1 θ . (20)

Let us put

k = [m 1 θ ] + 1

for any naturalnumber

m > N 2

. Inequalities (13), (14)

and (20) implyinequality(4).

(10)

Referenes

[1℄ A.M. Gomilko,G.V.Radzievskii, The equionvergene ofthe series in the eigenfuntions of

ordinaryfuntional-dierential operators. DokladyRoss.Akad. Nauk.Matematika,316,no.

2(1991),265269(in Russian).

[2℄ V.A.Il'in,Equionvergeneofthetrigonometriseriesandtheexpansionineigenfuntionsof

the one-dimensional Shrodinger operator with the omplex-valued

L 1

-potential.Di. Uravn., 27,no.4(1991),577597(inRussian).

[3℄ T. Kato, Perturbation theory for linear operators. Springer Verlag, Berlin-Heidelberg-New

York,1966.

[4℄ V.A. Marhenko, SturmLiouville operators and their appliations. Naukova dumka, Kiev,

1977(inRussian).

[5℄ I.V.Sadovnihaya,Onthe rate of equionvergeneof expansionsin the trigonometri series

andin the eigenfuntions of SturmLiouvilleoperator with the distributional potential.Di.

Uravn., 44,no.5(2008),656664(inRussian).

[6℄ A.M.Savhuk,Uniformasymptotiformulaefor eigenfuntionsofSturmLiouvilleoperators

withsingular potentials. arXiv0801.1950,2008.

[7℄ A.M. Savhuk, A.A. Shkalikov, SturmLiouville operators with singular potentials. Mat.

zametki,66,no.6(1999),897912(in Russian).

[8℄ A.M.Savhuk,A.A.Shkalikov,SturmLiouvilleoperatorswithdistributionpotentials.Trudy

MosowMathematialSoiety,64(2003),159219(inRussian).

[9℄ A.M. Savhuk, A.A.Shkalikov,On eigenvalues of SturmLiouville operators with potentials

fromSobolev spaes.Mat.zametki, 80,no.6(2006),864884(inRussian).

[10℄ V.A.Vinokurov,V.A.Sadovnihy,The uniformequionvergene ofthe Fourierseriesinthe

eigenfuntions of the rst boundary value problem and of the trigonometri Fourier series.

DokladyRoss.Akad.Nauk.Matematika,380,no.6(2001),731735(inRussian).

IrinaSadovnihaya

FaultyofComputationalMathematisand Cybernetis

M.V.LomonosovMosowStateUniversity

Leninskiegory

119991Mosow,Russia

E-mail:ivsadyandex.ru

Reeived:14.10.2009

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