• Tidak ada hasil yang ditemukan

*?Ti2` 8

6Q` i, j ∈ F4- H2iSij :=|{l ∈ {1,2, . . . , n} | βl =

⎣i j

⎦}|X Ai Bb MQi /B{+mHi iQ b22 i?i i?2 ;2M2`iQ` Ki`Bt G M/ i?2 +Q/2 C `2 /2i2`KBM2/ 2tTHB+BiHv #v i?2 pHm2b Sij

7Q` HH i, j ∈F4X 6Q` +QMbi`m+iBQMb Q7 [mi2`M`v HBM2` +Q/2b- Bi bm{+2b iQ 2bi#HBb?2/

i?2 pHm2b SijX

Hi2`MiBp2Hv- H2i α1 =!

a11 a12 · · · a1n

"

M/ α2 =!

a21 a22 · · · a2n

"

X h?2M G M/ C +M #2 pB2r b G=

⎣α1

α2

⎦ M/

C ={0,α12,ωα12α1,ωα22α212,ωα122α121+ωα212α2, ωα1+ωα22α1+ωα2,ωα12α22α12α2},

`2bT2+iBp2HvX

"v BMbT2+iBQM- Bi Bb 2bBHv b22M i?i

ri(α1) = ri(ωα1) = ri(ω2α1) = *

i∈F4

*

j∈F4

Sij, U8XkV

ri(α2) = ri(ωα2) = ri(ω2α2) = *

i∈F4

*

j∈F4

Sij, U8XjV

ri(α12) =ri(ωα1+ωα2) =ri(ω2α12α2) = *

i∈F4

*

j∈F4,i̸=j

Sij, U8X9V

ri(α1+ωα2) = ri(ωα12α2) = ri(ω2α12) = *

i∈F4

*

j∈F4,i̸=ωj

Sij, U8X8V M/

ri(α12α2) = ri(ωα12) =ri(ω2α1+ωα2) =*

i∈F4

*

j∈F4,i̸2j

Sij. U8XeV

jd

G2iy0 =S11+Sωω +Sω2ω2, y1 =S2 +Sω1+Sω2ω- M/ y2 =Sω21+S+Sωω2X h?2M r2 ?p2

GG =

⎢⎢

⎣ '

i∈F4

'

j∈F4

Sij y0+ωy12y2

y02y1+ωy2 '

i∈F4

'

j∈F4

Sij

⎥⎥

⎦, U8XdV

r?2`2 i?2 +H+mHiBQM Bb /QM2 BM F4.

h?2 +QMbi`m+iBQM Bb BHHmbi`i2/ BM i?2 7QHHQrBM; 2tKTH2X

1tKTH2 8XRXRX G2iC #2 [mi2`M`v HBM2` +Q/2 Q7 H2M;i? 4/2i2`KBM2/ #vS10= S01 = S11 = S = 1 M/ S00 = S = S2 = S2 = Sω0 = Sω1 = Sωω = Sωω2 = Sω20 =Sω21 =Sω2ω =Sω2ω2 = 0X h?2M i?2 ;2M2`iQ` Ki`Bt Q7 C Bb Q7 i?2 7Q`K

G=

⎣1 0 1 1 0 1 1 ω

⎦.

*QMb2[m2MiHv- r2 ?p2

y0 = 1, y1 = 0, M/ y2 = 1.

AM F4, r2 ?p2

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 1.

"v U8XdV- Bi 7QHHQrb i?i

GG=

⎣ 1 1 +ω2 1 +ω 1

⎦=

⎣1 ω ω2 1

r?B+? BKTHB2b i?i rank(GG) = 1 M/ dim(HullH(C)) = 2−rank(GG) = 1 #v S`QTQbBiBQM kXkX9X

"v b2iiBM; k = 2 M/ q = 4 BM G2KK kXjX9- i?2 M2ti H2KK 7QHHQrbX G2KK 8XRXkX DH4(n,2,1)≤14n

5

2 7Q` HH BMi2;2`b n≥3X

j3

8Xk PTiBKH Zmi2`M`v GBM2` *Q/2b rBi? >2`@

KBiBM >mHH .BK2MbBQM PM2 rBi? n ≡ 1, 2, 4 (mod 5)

AM i?Bb b2+iBQM- r2 7Q+mb QM +QMbi`m+iBQMb Q7 QTiBKH [mi2`M`v HBM2` +Q/2b rBi?

/BK2MbBQM 2 M/ >2`KBiBM ?mHH /BK2MbBQM QM2- M/ 2bi#HBb? i?2 2t+i pHm2b Q7 DH4(n,2,1) 7Q` `#Bi``v H2M;i?b n≥3 bm+? i?in ≡1,2,4 (mod 5)X

h?2Q`2K 8XkXRX G2i n ≥3 #2 M BMi2;2`X A7 n ≡1,2,4 (mod 5)- i?2M D4H(n,2,1) =

-4n 5

. .

S`QQ7X bbmK2 i?in ≡1,2,4 (mod 5)X 6`QK G2KK 8XRXk- Bi 7QHHQrb i?iDH4(n,2,1)≤ 14n

5

2X Ai `2KBMb iQ b?Qr i?2 2tBbi2M+2 Q7 3

n,2,14n

5

24

4 +Q/2 r?Qb2 >2`KBiBM ?mHH /BK2MbBQM Bb QM2X

q2 +QMbB/2` i?2 +QMbi`m+iBQMb BM i?2 7QHHQrBM; 3 +b2bX

*b2 RX n ≡ 1 (mod 5)X h?2M n = 5t+ 1 7Q` bQK2 TQbBiBp2 BMi2;2` tX "b2/ QM i?2 T`Biv Q7 t- r2 +QMbB/2` i?2 7QHHQrBM; irQ bm#+b2bX

*b2 RXRX t Bb 2p2MX 6Q` 1≤r≤n- H2i βr #2 i?2 2×1 Ki`Bt Qp2`F4 /2}M2/ #v

βr =

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

[0 1]T B7 1≤r≤ 2t, [0 ω]T B7 2t + 1≤r ≤ 2t2, [ω 0]T B7 2t2 + 1≤r≤ 3t2, [1 1]T B7 3t2 + 1≤r≤ 4t2, [ω2 ω2]T B7 4t2 + 1≤r≤ 5t2 [1 ω2]T B7 5t2 + 1≤r≤ 6t2, [ω2 ω]T B7 6t2 + 1≤r≤ 7t2, [ω2 1]T B7 7t2 + 1≤r≤ 8t2, [ω ω2]T B7 8t2 + 1≤r≤ 9t2, [1 0]T B7 9t2 + 1≤r≤ 10t2 + 1.

.

jN

G2iC #2 M [n,2]4 +Q/2 ;2M2`i2/ #v G=!

β1 β2 · · · βn

"

.

h?2M S01=S =Sω0 =S11 =Sω2ω2 =S2 =Sω2ω =Sω21 =Sωω2 = 2t- S10= 2t + 1- M/ Sij = 0 Qi?2`rBb2X Ai 7QHHQrb i?i

y0 =S11+Sωω +Sω2ω2 =t, y1 =S2 +Sω1+Sω2ω =t, M/

y2 =Sω21+S+Sωω2 =t.

AM F4- Bi +M #2 /2/m+2/ i?i

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

"v U8XdV- r2 ?p2

GG=

⎣1 0 0 0

r?B+? BKTHB2b i?i rank(GG) = 1X "v S`QTQbBiBQM kXkX9- C ?b >2`KBiBM ?mHH /BK2MbBQM 2−rank(GG) = 1X

"v i?2 /2}MBiBQM Q7 Sij M/ U8XkVĜU8XeV- Bi +M #2 /2/m+2/ i?i ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 1, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 1, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 1, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 1.

>2M+2- C ?b KBMBKmK r2B;?i 4t = /

4(5t+1) 5

0

= 14n

5

2X h?2`27Q`2- C Bb M QTiBKH [n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X

9y

*b2 RXkX t Bb Q//X 6Q` 1≤r ≤n- H2i βr #2 i?2 2×1Ki`Bt Qp2` F4 /2}M2/ #v

βr =

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

[0ω]T B7 1≤r≤ t+12 ,

[1 0]T B7 t+12 + 1≤r≤ 2(t+1)2 , [ω 0]T B7 2(t+1)2 + 1≤r ≤ 3(t+1)2 , [ω2 ω2]T B7 3(t+1)2 + 1≤r ≤ 4(t+1)2 , [ω2 ω]T B7 4(t+1)2 + 1≤r ≤ 5(t+1)2 , [ω ω2]T B7 5(t+1)2 + 1≤r ≤ 6(t+1)2 , [0 1]T B7 6(t+1)2 + 1≤r ≤ 7t+52 , [1 1]T B7 7t+52 + 1≤r ≤ 8t+42 , [1ω2]T B7 8t+42 + 1≤r ≤ 9t+32 , [ω2 1]T B7 9t+32 + 1≤r ≤ 10t+22 . G2iC #2 M [n,2]4 +Q/2 ;2M2`i2/ #v

G=!

β1 β2 · · · βn

"

.

h?2M S =S10=Sω0 =Sω2ω2 =Sω2ω =Sωω2 = t+12 - S01=S11 =S2 =Sω21 = t−12 - M/ Sij = 0 Qi?2`rBb2X Ai 7QHHQrb i?i

y0 =S11+Sωω +Sω2ω2 =t, y1 =S2 +Sω1+Sω2ω =t, M/

y2 =Sω21+S+Sωω2 =t.

AM F4- r2 ?p2

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

6`QK U8XdV- Bi +M #2 +QM+Hm/2/ i?i

GG=

⎣1 0 0 0

⎦.

9R

6`QK S`QTQbBiBQM kXkX9- Bi +M #2 +QM+Hm/2/ i?i C ?b >2`KBiBM ?mHH /BK2MbBQM 2−rank(GG) = 2−1 = 1X

lbBM; i?2 /2}MBiBQM Q7 Sij M/ U8XkVĜU8XeV- r2 ?p2

ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 1, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 1, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 1, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 1.

>2M+2- C ?b KBMBKmK r2B;?i 4t=/

4(5t+1) 5

0

=14n

5

2X *QMb2[m2MiHv- C Bb M QTiBKH [n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X 6`QK i?2 irQ bm#+b2b- Bi 7QHHQrb i?i

DH4(n,2,1) = -4n

5 .

7Q` HH n ≡1 (mod 5)X

*b2 kX n ≡ 2 (mod 5)X h?2M n = 5t + 2 7Q` bQK2 TQbBiBp2 BMi2;2` tX aBM+2 [mi2`M`v HBM2` +Q/2 C Bb /2i2`KBM2/ #v i?2 pHm2b Sij 7Q` HH i, j ∈ F4- BM i?2

`2KBMBM; T`ib- r2 ;Bp2 +QMbi`m+iBQMb Q7 HBM2` +Q/2b BM i2`Kb Q7 SijX >Qr2p2`- M 2tTHB+Bi 7Q`K Q7 Bib ;2M2`iQ` Ki`Bt G +M #2 /2i2`KBM2/ BM i?2 bK2 rv b *b2 RX q2 +QMbB/2` i?2 7QHHQrBM; irQ bm#+b2bX

*b2 kXR t Bb 2p2MX G2i S01 =Sω0 =Sω2ω2 =S2 =Sω2ω =Sωω2 = 2t, S = 2t −1, S10=S11=Sω21 = 2t + 1, M/ Sij = 0 Qi?2`rBb2. Ai +M #2 +QM+Hm/2/ i?i

y0 =S11+Sωω +Sω2ω2 =t+ 1, y1 =S2 +Sω1+Sω2ω =t, M/

y2 =Sω21+S+Sωω2 =t+ 1.

AM F4- Bi +M #2 /2/m+2/ i?i

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 1.

9k

"v U8XdV- r2 ?p2

GG =

⎣1 ω ω2 1

r?B+? BKTHB2b i?i rank(GGT) = 1 M/ dim(>mHHH(C)) = 1 #v S`QTQbBiBQM kXkX9X

"b2/ QM i?2 /2}MBiBQM Q7 Sij M/ U8XkVĜU8XeV- Bi +M #2 /2/m+2/ i?i ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 3, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t+ 1, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 1, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 2, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 1.

>2M+2- i?2 KBMBKmK r2B;?i Q7 C Bb 4t+ 1 = /

4(5t+2) 5

0 = 14n

5

2X b /2bB`2/- C Bb M QTiBKH[n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X

*b2 kXkX t Bb Q//X G2i S10 = S11 = Sω2ω2 = S2 = Sω2ω = Sω21 = Sωω2 = t+12 , S01=S =Sω0 = t−12 , M/ Sij = 0 Qi?2`rBb2. h?2M

y0 =S11+Sωω+Sω2ω2 =t+ 1, y1 =S2 +Sω1+Sω2ω =t+ 1, M/

y2 =Sω21+S+Sωω2 =t+ 1.

AM F4- r2 ?p2

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

"v U8XdV- Bi 7QHHQrb i?i

GG=

⎣1 0 0 0

⎦.

AM i?Bb +b2-rank(GGT) = 1M/dim(>mHHH(C)) = 2−rank(GGT) = 1#v S`QTQbBiBQM kXkX9X

9j

lbBM; i?2 /2}MBiBQM Q7 Sij M/ U8XkVĜU8XeV- r2 ?p2

ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 3, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t+ 2, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 1, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 1, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 1 r?B+? BKTHB2b i?iC ?b KBMBKmK r2B;?i 4t+ 1 =/

4(5t+2) 5

0

=14n

5

2X AM i?Bb +b2-C Bb M QTiBKH[n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X 6`QK i?2 irQ bm#+b2b- Bi 7QHHQrb i?i

DH4(n,2,1) = -4n

5 .

7Q` HH n ≡2 (mod 5)X

*b2 jX n ≡ 4 (mod 5)X h?2M n = 5t+ 4 7Q` bQK2 TQbBiBp2 BMi2;2` tX q2 +QMbB/2`

i?2 7QHHQrBM; irQ +b2b #b2/ QM i?2 T`Biv Q7 tX

*b2 jXRX t Bb 2p2MX G2i S =S10 =Sω0 =Sω2ω2 = Sωω2 =Sω2ω = 2t, S01 = S11 = S2 =Sω21 = 2t + 1, M/ Sij = 0 Qi?2`rBb2.h?2M

y0 =S11+Sωω+Sω2ω2 =t+ 1, y1 =S2 +Sω1+Sω2ω =t+ 1, M/

y2 =Sω21+S+Sωω2 =t+ 1.

AM F4- r2 ?p2

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

"v U8XdV- Bi +M #2 +QM+Hm/2/ i?i

GG=

⎣1 0 0 0

⎦.

Ai K2Mb i?irank(GGT) = 1M/C ?b >2`KBiBM ?mHH /BK2MbBQM QM2 #v S`QTQbBiBQM kXkX9X

99

6`QK i?2 /2}MBiBQM Q7Sij M/ U8XkVĜU8XeV- Bi +M #2 /2/m+2/ i?i ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 3, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t+ 4, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 3, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 3, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 3.

>2M+2- C ?b KBMBKmK r2B;?i 4t+ 3 = /

4(5t+4) 5

014n

5

2X h?2`27Q`2- C Bb M QTiBKH [mi2`M`v HBM2` [n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X

*b2 jXkX t Bb Q//X G2i S01 = S = Sω0 = S11 = Sω2ω2 = S2 = Sω2ω = Sω21 = Sωω2 = t+12 , S10= t21, M/ Sij = 0 Qi?2`rBb2.h?2M

y0 =S11+Sωω+Sω2ω2 =t+ 1, y1 =S2 +Sω1+Sω2ω =t+ 1, M/

y2 =Sω21+S+Sωω2 =t+ 1.

AM F4- Bi +M #2 /2/m+2/ i?i

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

"v U8XdV- r2 ?p2

GG=

⎣1 0 0 0

r?B+? BKTHB2b i?i rank(GGT) = 1 M/ dim(>mHHH(C)) = 2−rank(GGT) = 1X TTHvBM; i?2 /2}MBiBQM Q7Sij M/ U8XkVĜU8XeV- r2 ?p2

ri(α1) = ri(ωα1) =ri(ω2α1) = 4t+ 3, ri(α2) = ri(ωα2) =ri(ω2α2) = 4t+ 4, ri(α12) = ri(ωα1+ωα2) = ri(ω2α12α2) = 4t+ 3, ri(α1+ωα2) =ri(ωα12α2) =ri(ω2α12) = 4t+ 3, M/

ri(α12α2) =ri(ωα12) = ri(ω2α1+ωα2) = 4t+ 3 98

r?B+? BKTHB2b i?i wt(C) = 4t+ 3 = /

4(5t+4) 5

014n

5

2X *QMb2[m2MiHv- C Bb M QTiBKH [n,2,14n

5

2]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X 6`QK i?2 irQ bm#+b2b- Bi +M #2 +QM+Hm/2/ i?i

DH4(n,2,1) = -4n

5 .

7Q` HH n ≡4 (mod 5)X

1tKTH2 8XkXkX G2i t = 2X "v h?2Q`2K 8XkXR M/ t Bb 2p2M- r2 ?p2 i?i S01 = S = Sω0 = S11 = Sω2ω2 = S2 = Sω2ω = Sω21 = Sωω2 = 1, S10 = 2 M/ Sij = 0 Qi?2`rBb2X G2iC #2 [mi2`M`v HBM2` +Q/2 Q7 H2M;i? 11 rBi? ;2M2`iQ` Ki`Bt

G=

⎣1 1 0 0 ω 1 ω2 1 ω2 ω2 ω 0 0 1 ω 0 1 ω2 ω2 ω 1 ω2

⎦.

h?2M "v h?2Q`2K 8XkXR- Bi +M #2 /2/m+2/ i?i

y0 =t, y1 =t, M/ y2 =t.

AM F4- r2 ?p2

*

i∈F4

*

j∈F4

Sij = 1 M/ *

i∈F4

*

j∈F4

Sij = 0.

"v U8XdV- Bi 7QHHQrb i?i

GG=

⎣1 0 0 0

r?B+? BKTHB2b i?i rank(GG) = 1 M/ dim(HullH(C)) = 2−rank(GG) = 1 #v S`QTQbBiBQM kXkX9X h?2M C Bb M QTiBKH[11,2,8]4 +Q/2 rBi? ?mHH /BK2MbBQM QM2X

8Xj "QmM/b QM D

4H

(n, 2, 1) rBi? n ≡ 0, 3 (mod 5)

AM i?Bb b2+iBQM- r2 7Q+mb QM i?2 irQ `2KBMBM; +b2b r?2`2 n ≡ 0,3 (mod 5)X 6Q` i?2b2 +b2b- r2 T`QpB/2 ;QQ/ HQr2` M/ mTT2` #QmM/b QM i?2 KBMBKmK r2B;?i Q7 [n,2]4 +Q/2b rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X S`2+Bb2Hv- mTT2` M/ HQr2` #QmM/b QMDH4(n,2,1)`2 ;Bp2M rBi? i?2 ;T QM2X

9e

h?2Q`2K 8XjXRX G2i n #2 TQbBiBp2 BMi2;2`X A7 n ≡0,3 (mod 5)- i?2M i?2`2 2tBbib M [n,2,14n

5

2−1]4 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X

S`QQ7X bbmK2 i?i n ≡0,3 (mod 5)X q2 +QMbB/2` i?2 7QHHQrBM; irQ +b2bX

*b2 RX n ≡0 (mod 5)X h?2Mn−1≡4 (mod 5)M/n = 5t7Q` bQK2 TQbBiBp2 BMi2;2`

tX "v h?2Q`2K 8XkXR- i?2`2 2tBbib M [n−1,2,/

4(n1) 5

0]4 +Q/2C rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X G2i G#2 ;2M2`iQ` Ki`Bt 7Q` C M/ H2i C #2 [mi2`M`v HBM2`

+Q/2 ;2M2`i2/ #v G = [0 G]X aBM+2 -4(n−1)

5 .

=

-4(5t−1) 5

.

= 4t−1 =

-4(5t) 5

.

−1 = -4n

5 .

−1,

Bi 7QHHQrb i?i C Bb M [n,2,/

4(n−1) 5

0]2 = [n,2,14n

5

2−1]2 +Q/2 rBi? >2`KBiBM ?mHH /BK2MbBQM QM2X

*b2 kX n ≡ 3 (mod 5)X h?2M n−1≡2 (mod 5) M/ n = 5t+ 37Q` bQK2 TQbBiBp2 BMi2;2`tX "v h?2Q`2K 8XkXR- i?2`2 2tBbib M[n−1,2,/

4(n−1) 5

0]4+Q/2CrBi? >2`KBiBM

?mHH /BK2MbBQM QM2X G2i G #2 ;2M2`iQ` Ki`Bt 7Q` C M/ H2i C #2 [mi2`M`v HBM2` +Q/2 ;2M2`i2/ #v G = [0 G]X aBM+2

-4(n−1) 5

.

=

-4(5t+ 2) 5

.

= 4t+ 1 =

-4(5t+ 3) 5

.

−1 = -4n

5 .

−1,

Bi +M #2 2bBHv b22M i?i C Bb M [n,2,/

4(n−1) 5

0

]2 = [n,2,14n

5

2−1]2 +Q/2 rBi? >2`@

KBiBM ?mHH /BK2MbBQM QM2X

1tKTH2 8XjXkX "v 1tKTH2 8XkXk- r2 ?p2 i?iC Bb HBM2` +Q/2 rBi? T`K2i2`b [11,2,8]4 ;2M2`i2/ #v

G=

⎣1 1 0 0 ω 1 ω2 1 ω2 ω2 ω 0 0 1 ω 0 1 ω2 ω2 ω 1 ω2

⎦.

G2i G = [0 G]X "v h?2Q`2K 8XkXR- r2 ?p2 i?i G ;2M2`i2b M QTiBKH [10,2,7]3

+Q/2 rBi? ?mHH /BK2MbBQM QM2X

*Q`QHH`v 8XjXjX G2i n #2 TQbBiBp2 BMi2;2`X A7 n ≡0,3 (mod 5) i?2M -4n

5 .

−1≤D4H(n,2,1)≤ -4n

5 .

. 9d

S`QQ7X q?BH2 i?2 HQr2` #QmM/ Bb ;Bp2M BM h?2Q`2K 8XjXR- i?2 mTT2` #QmM/ Bb ;m`M@

i22/ #v G2KK 8XRXkX

*QMbi`m+iBQMb M/ #QmM/b QM [mi2`M`v HBM2` +Q/2b rBi? /BK2MbBQM irQ M/

>2`KBiBM ?mHH /BK2MbBQM QM2 ?p2 #22M bim/B2/X PTiBKH [mi2`Mv [n,2]4 +Q/2b rBi? >2`KBiBM ?mHH /BK2MbBQM QM2 ?p2 #22M +QMbi`m+i2/ 7Q` HH H2M;i?b n ≥3 bm+?

i?i n ≡ 1,2,4 (mod 5)X :QQ/ HQr2` M/ mTT2` #QmM/b QM i?2 KBMBKmK r2B;?i Q7 [mi2`Mv [n,2]4 +Q/2b rBi? >2`KBiBM ?mHH /BK2MbBQM QM2 ?p2 #22M ;Bp2M 7Q` HH H2M;i?b n≡0,3 (mod 5)X h?2 #Qp2 `2bmHib `2 bmKK`Bx2/ b 7QHHQrbX

h?2Q`2K 8XjX9X G2i n ≥3 #2 M BMi2;2`X h?2M DH4(n,2,1) =

-4n 5

. 7Q` HH n≡1,2,4 (mod 5)

M/ -

4n 5

.

−1≤DH4(n,2,1)≤ -4n

5

. 7Q` HH n≡0,3 (mod 5).

"b2/ QM Qm` BMbT2+iBQM- r2 T`QTQb2 i?2 7QHHQrBM; +QMD2+im`2X

*QMD2+im`2 8XjX8X DH4(n,2,1) =14n

5

2−1 7Q` HH TQbBiBp2 BMi2;2`b n≡0,3 (mod 5)X

93

*?Ti2` e

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