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Algebraic intersection of noodles and arcs

Dalam dokumen Graduate Texts in Mathematics (Halaman 136-146)

Homological Representations of the Braid Groups

3.6 Noodles vs. spanning arcs

3.6.2 Algebraic intersection of noodles and arcs

The intersection of a noodle N and a spanning arc α can be measured in terms of a so-calledalgebraic intersection N, α. This is an element of the ringZ[q±1, t±1] defined up to multiplication by monomialsqwtu with w∈Z and u 2Z Z. The algebraic intersection N, α depends on a choice of orientation on α, which we fix from now on. As above, we endow Σ with counterclockwise orientation. The orientations ofαand Σ allow us to speak of the “right” and “left” sides ofαinΣ. Pushingαslightly to the left (keeping the endpoints), we obtain a “parallel” oriented spanning arcαon (D, Q) with the same starting and terminal endpoints asαand disjoint fromαotherwise.

Slightly deformingN, we can assume thatNintersectsαtransversely inm≥0 pointsz1, . . . , zm(the numeration is arbitrary). We choose the parallel arcα very closely to α so that α meets N transversely in m points z1, . . . , zm, where each pairzi, zi is joined by a short subarc of N lying in the narrow strip onΣ bounded byα∪α; cf. Figure 3.9 below (the strip in question is shaded). Fori∈ {1, . . . , m}, letεi =±1 be the intersection sign ofN andα atzi (recall that both N andαare oriented). Thus, εi = +1 ifN crossesα atzi from left to right andεi =1 otherwise. Denote the starting endpoint and the terminal endpoint ofNbydandd, respectively. Fix arbitrary points

z∈α−∂α, z∈α−∂α

and fix pathsθ, θin Σ leading respectively fromd to z and fromdto z and having disjoint images (these paths are allowed to meet N, α, and α elsewhere).

Recall the spaceC of nonordered pairs of distinct points of Σ. For every pair i, j ∈ {1, . . . , m}, we define a loop ξi,j in C as follows. Let βi be an oriented embedded arc on α leading from z to zi (the orientation ofβi may be opposite to that of α). Let βj be an oriented embedded arc on α leading fromz to zj. Let γi,j and γi,j be disjoint oriented arcs inN leading from the points zi, zj N to the endpoints ofN. These oriented arcs are determined only by the position of the pointszi , zj onN and do not depend on the orientation of N. Recall the notation for paths in C introduced in Section 3.5.1. Consider the paths, θ},i, βj}, andi,j, γi,j}inC. They lead from{d, d} ∈ C to{z, z} ∈ C, from{z, z}to{zi, zj} ∈ C, and from {zi, zj}to{d, d}, respectively. The product of these three paths

ξi,j=, θ} {βi, βj} {γi,j, γi,j} (3.19) is a loop inC beginning and ending in{d, d}. Set

N, α= m i=1

m j=1

εiεjqw(ξi,j)tu(ξi,j)Z[q±1, t±1],

where w and u are the integral invariants of loops in C introduced in Sec- tion 3.5.1. The expression on the right-hand side does not depend on the numeration of points in N ∩α. Under a different choice of z, z, θ, θ, all loopsξi,j are multiplied on the left by one and the same loop inC of the form 1, ξ2}, whereξ1, ξ2 are loops inΣ. ThenN, αis multiplied by a monomial inq±1, t±2.

For example, if N is disjoint from α, then N, α = 0. IfN crossesαin only one point, thenm= 1 and N, α=qkt for somek, ∈Z.

We state two fundamental properties of the algebraic intersections of noo- dles and arcs.

Lemma 3.20.The algebraic intersection N, αis invariant under isotopies ofN andαin Σconstant on the endpoints.

Proof. It suffices to fixN and to prove thatN, αis invariant under isotopies of the spanning arcα. A generic isotopy of αin Σ can be split into a finite sequence of local moves of three types:

(i) an isotopy ofαinΣ keepingαtransversal toN,

(ii) a move pushing a small subarc of αacross a subarc ofN, (iii) an inverse to (ii).

It is clear from the definitions that the moves of type (i) do not changeN, α. Any move of type (ii) adds two new intersection pointszm+1, zm+2to the set N∩α={z1, . . . , zm}. Assume for concreteness that the subarc ofN connect- ing zm+1 with zm+2 lies on the right of the arc α; see Figure 3.9. Clearly, the sign εi = ±1 is preserved under this move for i = 1, . . . , m. For all

i, j= 1, . . . , m, the loopsξi,j computed before and after the move are homo- topic to each other. Therefore such pairs (i, j) contribute the same expression to N, αbefore and after the move. For i= 1, . . . , m+ 2, the loopsξi,m+1 and ξi,m+2 are homotopic and the obvious equality εm+1 = −εm+2 implies that the contributions of the pairs (i, m+ 1), (i, m+ 2) cancel each other.

Similarly, for anyi = 1, . . . , m, the loops ξm+1,i and ξm+2,i are homotopic and the contributions of the pairs (m+ 1, i), (m+ 2, i) cancel each other.

ThereforeN, αis preserved under the move.

α α

N

α α

zm+1 zm+2

z

zm+1 zm+2

Fig. 3.9.Additional crossings

We say that a spanning arcαon (D, Q) can be isotopped off a noodleN if there is a continuous family of spanning arcs s}s[0,1] on (D, Q) such thatα0=αandα1is disjoint fromN. Such a familys}sis called anisotopy ofα. Note that the spanning arcsαs necessarily have the same endpoints.

Lemma 3.21.A spanning arc αcan be isotopped off a noodleN if and only ifN, α= 0.

Proof. If there is an isotopy s}s of α =α0 in Σ such that α1 is disjoint from N, then N, α = N, α1 = 0. The hard part of the lemma is the opposite implication. Applying a preliminary isotopy to α, we can assume that α intersects N transversely at a minimal number of points z1, . . . , zm

withm≥0. We assume thatm≥1 and show thatN, α = 0.

We keep the notation introduced above in the definition of N, α. For anyi, j∈ {1, . . . , m}, setwi,j=w(ξi,j)Zandui,j=u(ξi,j)Z. Then

N, α= m

i=1

m j=1

εiεjqwi,jtui,j. (3.20) Observe that

εi= (1)ui,i

for alli. Indeed, ifεi= +1, thenN crosses the arc αatzi from left to right and therefore the pathsγi,i, γi,i end respectively in d, d. Then ξi,i has the form1, ξ2}, whereξ1, ξ2are loops inΣ. In this case

ui,i=u(ξi,i) = 0 (mod 2).

Similarly, ifεi=1, then ui,i= 1 (mod 2). In both cases εi= (1)ui,i.

We shall use the lexicographic order on monomials qwtu with w, u Z.

More precisely, we writeqwtu≥qwtu with w, u, w, u Zif eitherw > w orw=wandu≥u. We say that an ordered pair (i, j) withi, j∈ {1, . . . , m} ismaximal (for givenN, α) if qwi,jtui,j qwk,ltuk,l for all k, l ∈ {1, . . . , m}. A maximal pair necessarily exists because the lexicographic order on the monomials is total. A maximal pair may be nonunique. We claim that

if (i, j)is maximal, thenui,i=uj,j. (3.21) This claim implies that every maximal pair (i, j) contributes the monomial

εiεjqwi,jtui,j = (1)ui,i(1)uj,jqwi,jtui,j =qwi,jtui,j

toN, α. All maximal pairs necessarily contribute the same monomial, which then occurs inN, αwith a positive coefficient. ThereforeN, α = 0.

To prove (3.21), we first compute wi,j for anyi, j∈ {1, . . . , m}(not nec- essarily maximal). Let ηi be the loop inΣ obtained as the product of the pathθβi with the path going fromzi to d along N. Letηj be the loop inΣobtained as the product ofθβjwith the path going fromzj todalongN. We claim that

wi,j=w(ηi) +w(ηj). (3.22) Indeed, if the pathγi,j appearing in (3.19) ends atd, then the pathγi,j ends at d, the paths θβiγi,j and θβjγi,j are loops, andwi,j is the sum of their total winding numbers. Formula (3.22) follows in this case from the equalities ηi =θβi γi,j andηj =θβjγi,j. Assume thatγi,j ends atd. Thenγi,j ends atd,

ηi=θβi γi,jN1, ηj =θβjγi,jN ,

where N is viewed as a path from d to d. By definition, wi,j is the total winding number of the loopθβiγi,jθβjγi,j. This loop is homotopic inΣto the loop

θβiγi,jN1N θβjγi,jN N1=ηi N ηjN1. The loopηiN ηjN1is homologous toηiηj inΣ. Hence (3.22).

Inspecting the loops ηi and ηi, we observe that the difference between their homology classes [ηi],[ηi]∈H1(Σ;Z) is represented by the loop going from d to d alongN1, then from d to z alongθ, then from z to z along a path lying in the strip between α and α, and finally from z to d alongθ1. Therefore the difference [ηi][ηi] H1(Σ;Z) does not depend oni. This implies that the number

W =w(ηi)−w(ηi)Z

does not depend oni. Formula (3.22) implies that for alli, j= 1, . . . , m, wi,j =w(ηi) +w(ηj) +W . (3.23)

Suppose that the pair (i, j) is maximal. Thenwi,j is maximal among all the integerswk,l. By (3.23), both numbersw(ηi) andw(ηj) must be maximal among all the integersw(ηk). Then

w(ηi) =w(ηj) and wi,i=wi,j.

The maximality of (i, j) implies that ui,i ui,j. We claim that ui,i = ui,j. Fori=j, this is obvious and we assume thati=j.

Suppose, seeking a contradiction, thatui,i< ui,j. Letμbe the (embedded) subarc of α connecting zi and zj. Let ν be the (embedded) subarc of N connecting zi and zj. We orient μ from zi to zj and ν from zj to zi. The productμν is a loop onΣ based atzi. We distinguish two cases.

Case 1: The arcνapproachesαatzifrom the right (in other words,νdoes not pass through zi ). Then the loop μν does not pass through zi and we can consider its winding number,v∈Z, aroundzi. We claim thatv >0. To see this, we computevas follows. As was already observed, 2v=u({zi , μν}), whereuis the invariant of loops inCdefined in Section 3.5.1 andzistands for the constant path in the pointzi . Observe that βj ∼βiμ, where denotes the homotopy of paths inΣ−{zi}relative to the endpoints. The assumption thatν does not pass throughzi implies that

γi,i =γi,j and γi,i=ν1γi,j; see Figure 3.10. Then

ξi,j =, θ}{βi, βj}{γi,j, γi,j} ∼ {θ, θ}{βi, βi}{zi, μν}{γi,i, γi,i}. The latter loop is homologous inCto the loop

, θ}{βi , βi}{γi,i, γi,i}{zi, μν}=ξi,i{zi, μν}. Therefore,

2v=u({zi, μν}) =u(ξi,j)−u(ξi,i) =ui,j−ui,i. The assumptionui,i< ui,j implies thatv >0.

α

μ

zi ν zj

N

γi,j

γi,j zi

Fig. 3.10. Case 1: the pathsγi,j andγi,j

We can now bring one more loop into the picture. Consider the short subarc ofN connectingzi tozi in the strip betweenαandα. Pick a loopρ in a small neighborhood of this subarc such that

(i) ρbegins and ends inzi;

(ii) ρdoes not meetzi and winds clockwisev times aroundzi; (iii) ρhasv−1 transversal self-crossings;

(iv) ρmeetsμν only atzi (see Figure 3.11).

zi μ ν

ρ zj

zi

Fig. 3.11. The loopρforv= 3

Note that the winding number of the loop μνρ aroundzi is equal to 0.

Hence, this loop lifts to an appropriate covering of the complement of{zi}. We now describe this lift in more detail.

Let D = D− {zi} and p : D D be the universal (infinite cyclic) covering. Letμ: [0,1]→D be an arbitrary lift ofμ(so that=μ). There is a unique liftν: [0,1]→D ofν such thatν(0) =μ(1). Consider also the unique liftρ: [0,1]→D of ρsuch thatρ(0) = ν(1). By abuse of notation, we shall denote the pathsμ, ν, ρ,μ,ν, ρand their images by the same letters.

Since the winding number ofμνρaround zi is zero, the pathμνρis a loop.

Our choice ofρensures thatρis an embedded arc inDmeeting μνonly at the endpoints. However, the embedded arcsμandνinDmay meet in several points besides their common endpointμ(1) = ν(0). Let a be the first point ofμthat lies also onν(possiblya=μ(1)). Letμa be the initial segment ofμ going fromμ(0) toa. Letνa be the final segment ofνgoing froma toν(1).

Set

δ=μaνaρ .

The construction of the loopδensures that it has no self-crossings. This loop parametrizes an embedded circle inD denoted by the same symbol δ. We identify D with the half-open strip R×[0,1) R2 so that the orientation inDinduced by the counterclockwise orientation inDis identified with the counterclockwise orientation inR2. The Jordan curve theorem implies thatδ bounds an embedded diskB⊂D.

We verify now that the loopδencirclesB counterclockwise. LetC be the component ofD−ρsurroundingzi . We check first thatC∩p(B) =. Indeed, suppose that there is a pointb∈B such thatp(b)∈C. We can connect the pointp(b) to any other pointb ofC by an arc inC. This arc lifts to an arc inD beginning inb. The latter arc never meetsδ, since its projection to D never meetsμ, ν, orρ. Hence this lifted arc lies in the interiorB=B−∂B of B, and its terminal endpoint projects tob. Thus, C ⊂p(B). SinceB is compact, so is p(B). On the other hand, it is clear that C is not contained in a compact subset of D. This contradiction shows that C ∩p(B) = . Observe now thatClies on the right ofρ. IfB lies on the right ofρ⊂δ, then necessarilyC∩p(B)=, a contradiction. Thus,B lies on the left of ρand ofδ. Hence,δ goes counterclockwise aroundB.

We claim that B∩p1(Q) = . Indeed, being a compact subset ofD, the disk B may contain only a finite number of points of the (discrete) set p1(Q) D. Observe that the pathsμ, ν, ρ lie in Σ =D−Qand do not meet Q. Therefore ∂B∩p1(Q) = , so that B∩p1(Q) B. The loop δ=∂Bis homologous inB−p1(Q) to the sum of small loops encircling the points of B∩p1(Q) counterclockwise. The latter loops are projected by p homeomorphically onto small loops encircling certain points of Q counter- clockwise. Therefore,

card(B∩p1(Q)) =w(p◦δ),

wherew(p◦δ) is the total winding number of the loop p◦δin Σaround the points ofQ. We have

p◦δ=μaνaρ ,

where μa =p(μa) is the initial segment ofμ going from zi to p(a) alongα, and νa = p(νa) is the final segment of ν going from p(a) to zi along N. Then p(a) N ∩α, so that p(a) = zk for some k = 1, . . . , n. Since ρ is contractible inΣ, the loopμaνaρis homotopic toμaνa inΣ and

w(μaνaρ) =w(μaνa).

Recall the loops ηk, ηi in Σ based at the terminal endpoint d of N. The difference between their homology classes [ηk],[ηi]∈H1(Σ;Z) depends neither on the choice of the pathθ nor on the choice of its terminal endpointz ∈α.

Taking z = zi, one immediately deduces from the definition of ηk, ηi that [ηk][ηi] = [μaνa]. Therefore,

w(μaνa) =w(ηk)−w(ηi). To sum up, we have

card(B∩p1(Q)) =w(p◦δ) =w(μaνaρ) =w(μaνa) =w(ηk)−w(ηi). Sincew(ηi) is maximal, card(B∩p1(Q))0. HenceB∩p1(Q) =.

We shall need a few simple facts concerning the covering p: D D. The group of covering transformations ofpis an infinite cyclic group gener- ated by the covering transformationg :D →D corresponding to the loop encircling zi counterclockwise. The set p1(N) consists of an infinite num- ber of disjoint closed intervals inD with boundary on∂D. These intervals can be numerated by integers so that the action ofg shifts the index by 1.

This implies that any nontrivial covering transformationD→Dmaps each component of p1(N) to a different component of p1(N). The same facts hold for the setp1(α)⊂Dwith the only difference that its components are closed intervals lying in the interior ofD.

We claim that under our assumptions the pairN, αhas a digon. This would imply that the intersectionN∩αis not minimal. The latter contradicts our choice of α in its isotopy class. Therefore, the assumption ui,i < ui,j must have been false, so thatui,i=ui,j.

We now construct a digon forN, α. Suppose first that B∩p1(N)= or B∩p1(α)=

(or both). Observe that the circleδ=∂B is formed by three embedded arcs:

the arcμalying onp1(α), the arcνalying onp1(N), and the arcρmeeting the setp1(N)∪p1(α) only in its two endpoints. Note that the boundary of the one-manifoldp1(N) is contained in∂Dand lies therefore outside ofB.

IfB∩p1(N)=, thenB∩p1(N) is a finite set of disjoint embedded arcs with endpoints onμa. At least one of these arcs bounds together with a subarc ofμa a diskD1⊂Bwhose interior does not meetp1(N). IfB∩p1(N) =, then we set D1 =B. Similarly, the boundary of p1(α) D is contained inp1(Q) and lies outside of B. If the interiorD1 of D1 meetsp1(α), then they meet along a finite number of disjoint embedded arcs with endpoints onp1(N)∩∂D1. At least one of these arcs bounds together with a subarc of p1(N)∩∂D1 an embedded disk D2 D1 whose interior does not meet p1(α). IfD1∩p1(α) =, then we setD2=D1. In any case, the boundary ofD2is formed by an arc onp1(N) and an arc onp1(α), while the interior D2 ofD2does not meetp1(N ∪α). Then

D2∩g(∂D2) =∅,

for any nontrivial covering transformation g : D D of the coveringp : D D. The properties of the sets p1(N) and p1(α) mentioned above imply that∂D2∩g(∂D2) =. This implies that eitherD2∩g(D2) =orD2is contained in the interior of the diskg(D2). In the latter case,g1(D2)⊂D2, which contradicts the fact thatD2 does not meetp1(N∪α). We conclude that D2 ∩g(D2) = . Thus, the disk D2 does not meet its images under nontrivial covering transformations of the coveringp:D→D. Hence, the restriction ofptoD2 is injective. This implies thatp(D2) is a digon forN, α inΣ.

It remains to construct a digon for the pairN, αwhenB∩p1(N∪α) =. The setp1(ρ) consists ofv copies of the lineRembedded inD; these lines meet each other at an infinite number of points (see Figure 3.12, wherev= 3).

The arcsμa, νalie in the component ofD−ρadjacent to∂D≈S1except for the pointsμa(0) =νa(1) =zi. Therefore the arcsμaa lie in the component ofD−p1(ρ) adjacent to∂DRexcept for the points μa(0) =μ(0) and

νa(1) = ν(1) lying on p1(zi) p1(ρ). Clearly, νa(1) = gv(μa(0)), where g:D→Dis the generator of the group of covering transformations chosen above andv >0 is the winding number of the loopμν aroundzi. The diskB bounded byδ=μaνaρhas to include the area between the arcμaνaandp1(ρ) (this area is shaded in Figure 3.12). Observing Figure 3.12, one immediately concludes that forv 2, this area must meet g(μaνa). This contradicts the assumption B∩p1(N ∪α) = . It follows that v = 1, so that p1(ρ) is just a line and B is the area between this line and the arc μaνa. Then B projects injectively toD, the loopρbounds a small disk containingzi, and the union of this disk withp(B) is a digon forN, α. This completes the proof of the equalityui,i=ui,j in Case 1.

⎧⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

g a

p1(ρ)

μ ν

∂D

D

Fig. 3.12.The casev= 3

Case 2: The arc ν approaches α at zi from the left (in other words, ν passes throughzi). Let us slightly push the arc ν near zi to Σ− {zi } so that zi lies on the left side of the resulting arc. Denote by ν this new arc, also leading fromzj tozi. The loopμν does not pass throughziand we can consider its winding number,v, aroundzi. We claim thatv >0. Observe first that the pointzi splitsν into two subarcsν1 andν2, whereν1 leads fromzj

to zi and ν2 leads from zi to zi. We have γi,j =ν2γi,i and γi,i =ν11γi,j; see Figure 3.13. As in Case 1, we haveβj ∼βiμ. Therefore,

ξi,j =, θ}{βi, βj}{γi,j, γi,j} ∼ {θ, θ}{βi, βi}{ν2, μν1}{γi,i, γi,i}. The latter loop is homologous inCto the loop

, θ}{βi , βi}{γi,i, γi,i}{ν2, μν1}=ξi,i2, μν1}.

It is easy to deduce from the definitions and the construction of ν that u(2, μν1}) =u({zi , μν})1 = 2v−1. Therefore,

2v−1 =u(2, μν1}) =u(ξi,j)−u(ξi,i) =ui,j−ui,i.

The assumptionui,i < ui,j implies that v >0. The rest of the proof of the equalityui,i=ui,j goes as in Case 1 with the difference that instead ofν one should everywhere useν.

α μ

zi

zj

N γi,j

zi

γi,i

ν1 ν2

Fig. 3.13.Case 2: the pathsγi,i andγi,j

Analogous arguments prove that uj,j =ui,j for any maximal pair (i, j).

This can also be deduced from the results above using the following symmetry for the loopsξi,j defined by (3.19), wherei, j is an arbitrary (not necessarily maximal) pair of elements of the set{1, . . . , m}. Let us write

ξi,j=ξi,j(N, α, z, z+, θ, θ),

stressing the dependence on the data in the parentheses. We will use simi- lar notation for wi,j = w(ξi,j) and ui,j = u(ξi,j). Consider the noodle −N obtained from N by reversing the orientation. Similarly, consider the span- ning arcs−α,−α on (D, Q) obtained fromα, α, respectively, by reversing the orientation. It is clear that−α lies on the left of −α, so that we can set (−α) = −α. The noodle−N crosses−α and (−α) = −α in the same points as before and we numerate them in the same way, except thatzi

becomeszi and vice versa (for alli). It follows from the definitions that ξi,j(N, α, z, z, θ, θ) =ξj,i(−N,−α, z, z, θ, θ)

for all i, j. This implies similar formulas for wi,j and ui,j. Now, if the pair (i, j) is maximal for (N, α), then the pair (j, i) is maximal for (−N,−α) and by the results above,

ui,j(N, α, z, z, θ, θ) =uj,i(−N,−α+, z, z, θ, θ)

=uj,j(−N,−α+, z, z, θ, θ)

=uj,j(N, α, z, z, θ, θ).

We conclude that ui,i = ui,j = uj,j for any maximal pair (i, j). This

proves (3.21) and the lemma.

Dalam dokumen Graduate Texts in Mathematics (Halaman 136-146)