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Definition and Basic Properties of BMO

Dalam dokumen 250 (Halaman 131-137)

Exercises

7.1 Functions of Bounded Mean Oscillation

7.1.1 Definition and Basic Properties of BMO

Definition 7.1.1. For f a complex-valued locally integrable function on Rn, set f

BMO=sup

Q

1

|Q|

Q

f(x)Avg

Q

f dx,

where the supremum is taken over all cubes Q in Rn. The function f is called of bounded mean oscillation iff

BMO <∞and BMO(Rn)is the set of all locally integrable functions f on Rnwithf

BMO<∞.

Several remarks are in order. First it is a simple fact that BMO(Rn)is a linear space, that is, if f,g∈BMO(Rn)andλC, then f+g andλf are also in BMO(Rn) and

f+g

BMO f

BMO+g

BMO, λf

BMO = |λ|f

BMO. But BMOis not a norm. The problem is that iff

BMO=0, this does not imply that f =0 but that f is a constant. See Proposition 7.1.2. Moreover, every constant function c satisfiesc

BMO=0. Consequently, functions f and f+c have the same BMO norms whenever c is a constant. In the sequel, we keep in mind that elements of BMO whose difference is a constant are identified. Although BMO is only a seminorm, we occasionally refer to it as a norm when there is no possibility of confusion.

We begin with a list of basic properties of BMO.

Proposition 7.1.2. The following properties of the space BMO(Rn)are valid:

(1) Iff

BMO=0, then f is a.e. equal to a constant.

(2) L(Rn)is contained in BMO(Rn)andf

BMO2f

L.

(3) Suppose that there exists an A>0 such that for all cubes Q in Rnthere exists a constant cQsuch that

sup

Q

1

|Q|

Q|f(x)−cQ|dx≤A. (7.1.1) Then f∈BMO(Rn)andf

BMO2A.

(4) For all f locally integrable we have 1

2f

BMOsup

Q

1

|Q|inf

cQ

Q|f(x)−cQ|dx≤f

BMO.

(5) If f∈BMO(Rn), h∈Rn, andτh(f)is given byτh(f)(x) =f(x−h), thenτh(f) is also in BMO(Rn)and

τh(f)

BMO=f

BMO.

(6) If f ∈BMO(Rn)andλ >0, then the functionδλ(f)defined byδλ(f)(x) = fx)is also in BMO(Rn)and

δλ(f)

BMO=f

BMO.

(7) If f∈BMO then so is|f|. Similarly, if f,g are real-valued BMO functions, then so are max(f,g), and min(f,g). In other words, BMO is a lattice. Moreover,

|f|

BMO 2f

BMO, max(f,g)

BMO 3 2

f

BMO+g

BMO

, min(f,g)

BMO 3 2

f

BMO+g

BMO

.

(8) For locally integrable functions f define f

BMOballs=sup

B

1

|B|

B

f(x)Avg

B

f dx, (7.1.2) where the supremum is taken over all balls B in Rn. Then there are positive constants cn,Cnsuch that

cnf

BMO≤f

BMOballs≤Cnf

BMO.

Proof. To prove (1) note that f has to be a.e. equal to its average cNover every cube [−N,N]n. Since[−N,N]nis contained in[−N−1,N+1]n, it follows that cN=cN+1

for all N. This implies the required conclusion. To prove (2) observe that Avg

Q

f−Avg

Q

f 2 Avg

Q |f| ≤2f

L.

For part (3) note that

f−Avg

Q

f ≤ |f−cQ|+ Avg

Q

f−cQ ≤ |f−cQ|+ 1

|Q|

Q|f(t)−cQ|dt. Averaging over Q and using (7.1.1), we obtain thatf

BMO2A. The lower in- equality in (4) follows from (3) while the upper one is trivial. Property (5) is imme- diate. For (6) note that AvgQδλ(f) =AvgλQf and thus

1

|Q|

Q

fx)Avg

Q

δλ(f) dx= 1

|λQ|

λQ

f(x)Avg

λQ f dx.

Property (7) is a consequence of the easy fact that |f| −Avg

Q

|f| f−Avg

Q

f +Avg

Q

f−Avg

Q

f .

Also, the maximum and the minimum of two functions can be expressed in terms of the absolute value of their difference. We now turn to (8). Given any cube Q in Rn, we let B be the smallest ball that contains it. Then|B|/|Q|=2nvn

√nn, where vnis the volume of the unit ball, and

1

|Q|

Q

f(x)Avg

B

f dx≤|B|

|Q|

1

|B|

B

f(x)Avg

B

f dx≤vn

√nn 2n f

BMOballs.

It follows from (3) that f

BMO21−nvn

√nnf

BMOballs. To obtain the reverse conclusion, given any ball B find the smallest cube Q that contains it and argue similarly using a version of (3) for the space BMOballs. Example 7.1.3. We indicate why L(Rn)is a proper subspace of BMO(Rn). We claim that the function log|x|is in BMO(Rn)but not in L(Rn). To prove that it is in BMO(Rn), for every x0Rnand R>0, we must find a constant Cx0,Rsuch that the average of|log|x|−Cx0,R|over the ball{x : |x−x0| ≤R}is uniformly bounded.

Since 1 vnRn

|x−x0|≤R

log|x| −Cx0,R dx= 1 vn

|z−R1x0|≤1

log|z| −Cx0,R+log R dz, we may take Cx0,R=CR1x0,1+logR, and things reduce to the case that R=1 and x0is arbitrary. If R=1 and|x0| ≤2, take Cx0,1=0 and observe that

|x−x0|≤1

log|x| dx≤

|x|≤3

log|x| dx=C.

When R=1 and|x0| ≥2, take Cx0,1=log|x0|. In this case notice that 1

vn

|x−x0|≤1

log|x| −log|x0| dx= 1 vn

|x−x0|≤1

log |x|

|x0|

dx≤log 2,

since when|x−x0| ≤1 and|x0| ≥2 we have that log||x|x

0|log|x|0x|+1

0| log32 and log|x|x|0|log|x|x0|

0|−1log 2. Thus log|x|is in BMO.

The function log|x|turns out to be a typical element of BMO, but we make this statement a bit more precise later. It is interesting to observe that an abrupt cutoff of a BMO function may not give a function in the same space.

Example 7.1.4. The function h(x) =χx>0log1xis not in BMO(R). Indeed, the prob- lem is at the origin. Consider the intervals(ε,ε), where 0<ε<12. We have that

(ε,ε)Avgh= 1 2ε

+ε

ε h(x)dx= 1 2ε

ε 0 log1

xdx=1+log1ε

2 .

But then 1 2ε

ε h(x)Avg

(ε,ε)h dx≥ 1 2ε

0

ε Avg

(ε,ε)h dx=1+log1ε

4 ,

and the latter is clearly unbounded asε0.

Let us now look at some basic properties of BMO functions. Observe that if a cube Q1is contained in a cube Q2, then

Avg

Q1

f−Avg

Q2

f 1

|Q1|

Q1

f−Avg

Q2

f dx

1

|Q1|

Q2

f−Avg

Q2

f dx

|Q2|

|Q1|f

BMO.

(7.1.3)

The same estimate holds if the sets Q1and Q2are balls.

A version of this inequality is the first statement in the following proposition.

For simplicity, we denote byf

BMOthe expression given byf

BMOballsin (7.1.2), since these quantities are comparable. For a ball B and a>0, aB denotes the ball that is concentric with B and whose radius is a times the radius of B.

Proposition 7.1.5. (i) Let f be in BMO(Rn). Given a ball B and a positive integer m, we have

Avg

B

f−Avg

2mB

f 2nmf

BMO. (7.1.4)

(ii) For anyδ >0 there is a constant Cn,δ such that for any ball B(x0,R)we have Rδ

Rn

f(x)AvgB(x0,R)f

(R+|x−x0|)n dx≤Cn,δf

BMO. (7.1.5)

An analogous estimate holds for cubes with center x0and side length R.

(iii) There exists a constant Cnsuch that for all f∈BMO(Rn)we have

sup

yRn

sup

t>0

Rn|f(x)(Pt∗f)(y)|Pt(x−y)dx≤Cnf

BMO. (7.1.6)

Here Pt denotes the Poisson kernel introduced in Chapter 2.

(iv) Conversely, there is a constant Cnsuch that for all f∈L1loc(Rn)for which

Rn

|f(x)|

(1+|x|)n+1dx<we have

Cnf

BMOsup

yRn

sup

t>0

Rn|f(x)(Pt∗f)(y)|Pt(x−y)dx. (7.1.7) Proof. (i) We have

Avg

B

f−Avg

2B

f = 1

|B| B

f(t)Avg

2B

f dt

2n

|2B|

2B

f(t)Avg

2B

f dt

2nf

BMO.

Using this inequality, we derive (7.1.4) by adding and subtracting the terms Avg

2B

f, Avg

22B

f, . . . , Avg

2m1B

f.

(ii) In the proof below we take B(x0,R)to be the ball B=B(0,1)with radius 1 centered at the origin. Once this case is known, given a ball B(x0,R)we replace the function f by the function f(Rx+x0). When B=B(0,1)we have

Rn

f(x)Avg

B

f (1+|x|)n dx

B

f(x)Avg

B

f (1+|x|)n+δ dx+

k=0

2k+1B\2kB

f(x)Avg

2k+1B

f + Avg

2k+1B

f−Avg

B

f (1+|x|)n+δ dx

B

f(x)Avg

B

f dx +

k=0

2−k(n+δ) 2k+1B

f(x)Avg

2k+1B

f + Avg

2k+1B

f−Avg

B

f dx

≤vnf

BMO+

k=0

2−k(n+δ)

1+2n(k+1)

(2k+1)nvnf

BMO

=Cn,δf

BMO.

(iii) The proof of (7.1.6) is a reprise of the argument given in (ii). Set Bt=B(y,t).

We first prove a version of (7.1.6) in which the expression(Pt∗f)(y)is replaced by AvgBt f . For fixed y,t we have

Rn

t f(x)Avg

Bt

f (t2+|x−y|2)n+12

dx

Bt

t f(x)Avg

Bt

f (t2+|x−y|2)n+12 dx

+

k=0

2k+1Bt\2kBt

t f(x)Avg

2k+1Bt

f + Avg

2k+1Bt

f−Avg

Bt

f (t2+|x−y|2)n+12 dx

Bt

f(x)Avg

Bt

f

tn dx

+

k=0

2−k(n+1) tn

2k+1Bt

f(x) Avg

2k+1Bt

f + Avg

2k+1Bt

f−Avg

Bt

f dx

≤vnf

BMO+

k=0

2−k(n+1)

1+2n(k+1)

(2k+1)nvnf

BMO

=Cnf

BMO.

(7.1.8)

Using the inequality just proved, we also obtain

Rn

(Pt∗f)(y)Avg

Bt

f Pt(x−y)dx = (Pt∗f)(y)Avg

Bt

f

Rn

Pt(x−y) f(x)Avg

Bt

f dx

≤Cnf

BMO,

which, combined with the inequality in (7.1.8), yields (7.1.6) with constant 2Cn. (iv) Conversely, let A be the expression on the right in (7.1.7). For|x−y| ≤t we have Pt(x−y)≥cnt(2t2)n+12 =cnt−n, which gives

A≥

Rn|f(x)(Pt∗f)(y)|Pt(x−y)dx≥cn tn

|x−y|≤t|f(x)(Pt∗f)(y)|dx.

Proposition 7.1.2 (3) now implies that f

BMO2A/(vncn).

This concludes the proof of the proposition.

Dalam dokumen 250 (Halaman 131-137)