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The Left and Right Regular Representation

Dalam dokumen Graduate Texts in Mathematics 235 (Halaman 72-76)

Harmonic Analysis

3.3 The Peter–Weyl Theorem

3.3.1 The Left and Right Regular Representation

The set of continuous functions on a compact Lie group G, C(G), is a Banach space with respect to the normfC(G) = supgG|f(g)|and the set of square in- tegrable functions, L2(G), is a Hilbert space with respect to the normfL2(G) =

G|f(g)|2 dg. Both spaces carry a left and right actionlgandrgofGgiven by

3.3 The Peter–Weyl Theorem 61 lgf

(h)= f(g1h) rgf

(h)= f(hg)

which, as the next theorem shows, are representations. They are called theleftand right regular representations.

Lemma 3.20.The left and right actions of a compact Lie group G on C(G)and L2(G)are representations and norm preserving.

Proof. The only statement from Definition 3.11 that still requires checking is con- tinuity of the map(g, f)lgf (sincergis handled similarly). Working inC(G) first, calculate

f1(g11h)f2(g21h)f1(g11h)f1(g21h)+f1(g21h)f2(g21h)

f1(g11h)f1(g21h)+ f1f2C(G).

Since f1is continuous on compactGand since the mapgg−1his continuous, it follows that++lg1f1lg2f2++

C(G)can be made arbitrarily small by choosing(g1, f1) sufficiently close to(g2, f2).

Next, working with fiL2(G), choose fC(G)and calculate the following:

++lg1f1lg2f2++

L2(G)=+++f1lg1 1 g2f2+++

L2(G)

f1f2L2(G)++++f2lg−1 1 g2f2+++

L2(G)

= f1f2L2(G)+++lg1f2lg2f2++

L2(G)

f1f2L2(G)+++lg1f2lg1f++

L2(G)

+++lg1flg2f++

L2(G)+++lg2flg2f2++

L2(G)

= f1f2L2(G)+2f2fL2(G)+++lg1flg2f++

L2(G)

f1f2L2(G)+2f2fL2(G)+++lg1flg2f++

C(G). Since f may be chosen arbitrarily close to f2 in theL2 norm and sinceGalready

acts continuously onC(G), the result follows.

The first important theorem identifies theG-finite vectors ofC(G)with the set of matrix coefficients, MC(G). Even though there are two actions ofGonC(G), i.e.,lgandrg, it turns out that both actions produce the same set ofG-finite vectors (Theorem 3.21). As a result, writeC(G)G-finunambiguously for the set ofG-finite vectors with respect to either action.

Theorem 3.21.(1)For a compact Lie group G, the set of G-finite vectors of C(G) with respect to left action, lg, coincides with set of G-finite vectors of C(G)with respect to right action, rg.

(2)C(G)G-fin=MC(G).

Proof. We first show thatC(G)G-fin, with respect to left action, is the set of matrix coefficients. Let fuV,v(g) = (gu, v)be a matrix coefficient for a finite-dimensional unitary representation V of G withu, vV andG-invariant inner product(·,·).

Then(lgfuV,v)(h)= (g−1hu, v)= (hu,gv)so thatlgfuV,v = fuV,gv. Hence{lgfuV,v | gG} ⊆ {fuV,v |vV}. SinceV is finite dimensional, fuV,vC(G)G-fin, and thus MC(G)C(G)G-fin.

Conversely, let fC(G)G-fin. By definition, there is a finite-dimensional sub- module,VC(G), with respect to the left action so that fV. Sinceg f =g f, V = {v|vV}is also a finite-dimensional submodule ofC(G). Write(·,·)for the L2norm restricted toV. The linear functional onV that evaluates functions ateis continuous, so there existsv0V so thatv(e)=(v, v0)forvV. In particular,

f(g) =lg−1f(e) = (lg−1f, v0) = (f,lgv0). In particular, f = fvV

0,fMC(G).

ThusC(G)G-finMC(G)and part (2) is done (with respect to the left action).

For part (1), let f be a leftG-finite vector inC(G). By the above paragraph, there is a matrix coefficient, so f = fuV,v. Thus(rgf)(h)=(hgu, v)so thatrgf = fguV,v. Since{gu|gG}is contained in the finite-dimensional spaceV, it follows that the set of leftG-finite vectors are contained in the set of rightG-finite vectors.

Conversely, let f be a rightG-finite vector. As before, pick a finite-dimensional submodule,VC(G), with respect to the left action so that fV. Write(·,·)for theL2norm restricted toV. The linear functional onV that evaluates functions ate is continuous so there existsv0V, so thatv(e)=(v, v0)forvV. In particular, f(g)=rgf(e)= (rgf, v0). In particular, f = ffV,v0MC(G), so that the set of rightG-finite vectors is contained in the set of leftG-finite vectors.

Based on our experience with the canonical decomposition, we hopeC(G)G-fin

decomposes under theleftaction into terms isomorphic to HomG(Eπ,C(G)G-fin)Eπ

for [π]∈ G. In this case, lg acts trivially on HomG(Eπ,C(G)G-fin)so thatEπ car- ries the entire left action. However, Theorem 3.21 says that C(G)G-finis actually aG ×G-module under the action((g1,g2)f) (g) =

rg1lg2f

(g) = f(g−12 gg1).

In light of Theorem 3.9, it is therefore reasonable to hope HomG(Eπ,C(G)G-fin) will carry the right action. This, of course, requires a different action on HomG(Eπ,C(G)G-fin) than the trivial action defined in §2.2.1. Towards this end and with respect to the left action on C(G)G-fin, define a second action of G on HomG(Eπ,C(G)G-fin)and HomG(Eπ,C(G))by

(gT) (x)=rg(T x) (3.22)

for gG,xEπ, and T ∈ HomG(Eπ,C(G)). To verify this is well defined, calculate

lg1((g2T) (x))=lg1rg2(T x)=rg2lg1(T x)=rg2(T(g1x))=((g2T) (g1x)) , so that g2T ∈ HomG(Eπ,C(G)). If T ∈ HomG(Eπ,C(G)G-fin), then g2T ∈ HomG(Eπ,C(G)G-fin)as well by Theorem 3.21.

3.3 The Peter–Weyl Theorem 63 The next lemma is a special case ofFrobenius Reciprocityin §7.4.1. It does not depend on the fact thatEπ is irreducible.

Lemma 3.23.With respect to the left action of a compact Lie group G on C(G)G-fin

and the action onHomG(Eπ,C(G)G-fin)given by Equation 3.22, HomG(Eπ,C(G))=HomG(Eπ,C(G)G-fin)∼=Eπ

as G-modules. The intertwining map is induced by mapping T∈HomG(Eπ,C(G)G-fin) toλTEπwhere

λT(x)=(T(x)) (e) for xEπ.

Proof. Let T ∈ HomG(Eπ,C(G)G-fin) and define λT as in the statement of the lemma. This is aG-map since

(gλT) (x)=λT(g1x)=(T(g1x))(e)=(lg−1(T x))(e)=(T x)(g)

=(rg(T x))(e)=((gT)(x))(e)=λgT(x), soT =λgTforgG.

We claim that the inverse map is obtained by mapping λEπto Tλ∈HomG(Eπ,C(G)G-fin)

by

(Tλ(x)) (h)=λ(h−1x) forhG. To see that this is well defined, calculate

(lg(Tλ(x)))(h)=(Tλ(x)) (g−1h)=λ(h−1gx)=(Tλ(gx)) (h)

so thatlg(Tλ(x)) = Tλ(gx). This shows thatTλis aG-map and, since Eπ is finite dimensional, Tλ(x)C(G)G-fin. To see that this operation is the desired inverse, calculate

λTλ(x)=(Tλ(x))(e)=λ(x)

and

TλT(x)

(h)=λT(h1x)=(T(h1x))(e)=(lh−1(T x))(e)=(T x)(h). Hence HomG(Eπ,C(G)G-fin)∼=Eπ.

To see HomG(Eπ,C(G)G-fin)=HomG(Eπ,C(G)), observe that the mapTλT is actually a well-defined map from HomG(Eπ,C(G))toEπ. Since the inverse is still given byλTλandTλ∈HomG(Eπ,C(G)G-fin), the proof is finished.

Note that ifEπ inherits an invariant inner product from Eπ in the usual fashion, the above isomorphism need not be unitary with respect to the inner product on HomG(Eπ,C(G))given in Lemma 3.17. In fact, they can be off by a scalar multiple determined by dimEπ. The exact relationship will be made clear in §3.4.

Dalam dokumen Graduate Texts in Mathematics 235 (Halaman 72-76)