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(1)

Chapter 2

Systems of Equations

& Inequalities

(2)

This chapter consists of 3 sections as follows:

2.1 System of Linear Equations in Two Variables

2.2 System of Linear Equations in more than Two Variables(Three Variables)

2.3 Inequalities

(3)

System of Linear 2.1

Equations in Two

Variables

(4)

1. Systems of Linear Equations

in Two Variables

(5)

A linear equation in two variables takes the form

. 8 2

, 6 2

y x

y x

, C By

Ax   B

A ,

Where are not both zero

Any collection of two or more equations is called a

system of equations. For example, the system of

two linear equations in two variables is a set as

(6)

Independent, inconsistent and dependent equations

Independent system

solution One

Inconsistent system Dependent system solution No

Many solution

y y y

x x x

Lines have different slopes

Lines have the

same slopes Lines are the

same

(7)

Methods for Solving

System of Linear Equations

(8)

I. Substitution Method

(9)

Solution

Example 1

Solve

400 06

. 0 05

. 0 .

23 5

6

, 1000 2

) ,

6 3

)

y x

y x

x y

b y

x a

6 3

) x  y 

a  y  3 x  6 ( 1 )

23 30

15

6    

 x x

equation second

in the

Substitute y  6 x  5 ( 3 x  6 )   23 7

21 

 x 3

 1

 x (1)

3 in substitute 1

find

To y x  6 5

3

3 1    

 

 

 y

equations original

both the satisfies

solution the

Check that

) 5 3 ,

( 1 point the

is solution

The 

(10)

) 1 ( 1000

2

) y  x  b

400 60

12 . 0 05

.

0   

 x x

equation second

in the Substitute y

400 )

1000 2

( 06 . 0 05

.

0   

 x x

 2000

 x (1) in 2000 substitute

find

To y x 

 2000  1000 5000

2 

 y

) 5000 ,

2000 (

point the

is

solution

The

(11)

Class Work

Solve the following systems of equations by substitution

. 1 2

, 9 3

)

 y x

y x

i

. 8 2

, 6 2

)

 y x

y x

ii

(12)

Exercise Page(798-799) 11

In Exercises 1 to 20,solve each system of equations by the substitution method .

 

  

 

 

 

 

5 3y

- 3x 4

5

1 3

3 11. 4

4 3

1 5

7. 6

5 2

6 3

5. 2

2 x

16 3y

- 1. 2x

x y

x y

x y

y x

y x

y x

y

x

(13)

II. Elimination Method

(14)

Solution

Example 3

Solve

12 2

3 .

1 2

, 2 3

2 ) ,

9 3

)

y x

y x

y x

b y

x a

10 5

1 2

9 3

)

 x

y x

y x

a

1 )

2 (

2  

 y

 2

 x

 3

 y

y y

x

x 2 in 2 1 to find use

Now   

) 3 , 2 ( point the

is solution

The 

(15)

30 5

24 4

6

6 9

6

y y x

y x

2 )

6 ( 3

2   

 x

 6

 y

16

2 

 x

x y

x

y 6 in first eqn. 2 3 2 to find use

Now    

equations original

both the satisfies

solution the

Check that

) 6 , 8 ( point the

is solution The

: 2 - by second the

and 3 by eqn first he

multiply t ,

eliminate

b)To x

 8

 x

(16)

Class Work

Find x, y by elimination method

. 1 5

3

, 5 3

4 )

 y x

y x

i

. 9 5

2

, 8 7

5 )

 y x

y x

ii

(17)

Exercise Page(798-799) 12

In Exercises 21 to 40,solve each system of equations by the elimination method .

 

 

 

 

9 4

2

11 6

29. 3

0

6 10

0 3

25. 5

12 4

5

21 7

23. 4

4

3 4

10 21. 3

y x

y x

y x

y x

y x

y x

y x

y

x

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