B. Kompetensi Profesional - Implementasi Metode Preference Rangking Organizational Method For Enrichment Evaluation (Promethee)Untuk Penentuan Kinerja Dosen (Studi Kasus : Fakultas Farmasi USU)

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A. Kompetensi Pedagogik

1. Kesiapan memberikan kuliah dan/atau praktek/praktikum 2. Keteraturan dan ketertiban penyelenggaraan perkuliahan 3. Kemampuan menghidupkan suasana kelas

4. Kejelasan penyampaian materi dan jawaban terhadap pertanyaan di kelas 5. Pemanfaatan media dan teknologi pembelajaran

6. Pemanfaatan media dan teknologi pembelajaran 7. Pemberian umpan balik terhadap tugas

8. Kesesuaian materi ujian dan/atau tugas dengan tujuan mata kuliah 9. Kesesuaian nilai yang diberikan dengan hasil belajar

B. Kompetensi Profesional

10.Kemampuan menjelaskan pokok bahasan/topik secara tepat 11.Kemampuan memberi contoh relevan dari konsep yang diajarkan

12.Kemampuan menjelaskan keterkaitan bidang/topik yang diajarkan dengan bidang/topik lain

13.Kemampuan menjelaskan keterkaitan bidang/topik yang diajarkan dengan konteks kehidupan

14.Penguasaan akan isu-isu mutakhir dalam bidang yang diajarkan

15.Penggunaan hasil-hasil penelitian untuk meningkatkan kualitas perkuliahan 16.Pelibatan mahasiswa dalam penelitian/kajian dan atau

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25.Kemampuan menerima kritik, saran, dan pendapat orang lain 26.Mengenal dengan baik mahasiswa yang mengikuti kuliahnya 27.Mudah bergaul di kalangan sejawat, karyawan, dan mahasiswa 28.Toleransi terhadap keberagaman mahasiswa

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1. f1= Kompetensi Pedagogik

f1(A28, A1)  d = f1(A28)-f1(A1)

d = 17 Berdasarkan kriteria quasi

d > q maka H(d) = 1

f1(A1, A28)  d = f1(A1)-f1(A28) d = -17

Berdasarkan kriteria quasi d < q

maka H(d) = 0

f2 = Kompetensi Profesional

f2(A28, A1)  d = f2(A28)-f2(A1)

(4)

d = 16 Berdasarkan kriteria linier

d < p maka H(d) = 0.8

f3(A1, A28)  d = f3(A1)-f3(A28)

d = -16 Berdasarkan kriteria linier

d < p maka H(d) = 0

f4 = Kompetensi Sosial

f4(A28, A1)  d = f4(A28)-f4(A1)

d = 13 Berdasarkan kriteria biasa

d > 0 maka H(d) = 1

f1(A1, A28)  d = f1(A1)-f1(A28)

d = -13 Berdasarkan kriteria biasa

(5)

f1(A28, A2)  d = f1(A28)-f1(A2)

d < q maka H(d) = 0

f1(A2, A28) d = f1(A2)-f1(A28)

d = -9 Berdasarkan kriteria quasi

d < q maka H(d) = 0

f2(A28, A2)  d = f2(A28)-f2(A2)

(6)

d < p maka H(d) = 0

f3(A2, A28) d = f3(A2)-f3(A28)

d < p maka H(d) = 0.1

f4(A28, A2)  d = f4(A28)-f4(A2)

d > 0 maka H(d) = 1

f4(A2, A28) d = f4(A2)-f4(A28)

(7)

f1(A28, A3)  d = f1(A28)-f1(A3)

d > q maka H(d) = 1

f1(A3, A28)  d = f1(A3)-f1(A28)

d < q maka H(d) = 0

f2(A28, A3)  d = f2(A28)-f2(A3)

(8)

d= 21 Berdasarkan kriteria linier

d < p maka H(d) = 1

f3(A3, A28)  d = f3(A3)-f3(A28)

d < p maka H(d) = 0

f4(A28, A3)  d = f4(A28)-f4(A3)

d > 0 maka H(d) = 1

f4(A3, A28)  d = f4(A3)-f4(A28)

(9)

f1(A28, A4)  d = f1(A28)-f1(A4)

d > q maka H(d) = 1

f1(A4, A28)  d = f1(A4)-f1(A28)

d < q maka H(d) = 0

f2(A28, A4)  d = f2(A28)-f2(A4)

(10)

d < p maka H(d) = 0.8

f3(A4, A28)  d = f3(A4)-f3(A28)

d < p maka H(d) = 0

f4(A28, A4)  d = f4(A28)-f4(A4)

d > 0 maka H(d) = 1

f4(A4, A28)  d = f4(A4)-f4(A28)

(11)

f1(A28, A5)  d = f1(A28)-f1(A5)

d < q maka H(d) = 0

f1(A5, A28)  d = f1(A5)-f1(A28)

d < q maka H(d) = 0

f2(A28, A5)  d = f2(A28)-f2(A5)

(12)

d < p maka H(d) = 0

f3(A5, A28)  d = f3(A5)-f3(A28)

d < p maka H(d) = 0.1

f4(A28, A5)  d = f4(A28)-f4(A5)

d > 0 maka H(d) = 1

f4(A5, A28)  d = f4(A5)-f4(A28)

(13)

f1(A28, A6)  d = f1(A28)-f1(A6)

d > q maka H(d) = 1

f1(A6, A28)  d = f1(A6)-f1(A28)

d < q maka H(d) = 0

f2(A28, A6)  d = f2(A28)-f2(A6)

(14)

d < p maka H(d) = 0.6

f3(A6, A28)  d = f3(A6)-f3(A28)

d < p maka H(d) = 0

f4(A28, A6)  d = f4(A28)-f4(A6)

d > 0 maka H(d) = 1

f4(A6, A28)  d = f4(A6)-f4(A28)

(15)

f1(A28, A7)  d = f1(A28)-f1(A7)

d > q maka H(d) = 1

f1(A7, A28)  d = f1(A7)-f1(A28)

d < q maka H(d) = 0

f2(A28, A7)  d = f2(A28)-f2(A7)

(16)

d < p maka H(d) = 1

f3(A7, A28)  d = f3(A7)-f3(A28)

d < p maka H(d) = 0

f4(A28, A7)  d = f4(A28)-f4(A7)

d > 0 maka H(d) = 1

f4(A7, A28)  d = f4(A7)-f4(A28)

(17)

f1(A28, A8)  d = f1(A28)-f1(A8)

d < q maka H(d) = 0

f1(A8, A28)  d = f1(A8)-f1(A28)

d < q maka H(d) = 0

f2(A28, A8)  d = f2(A28)-f2(A8)

(18)

d < p maka H(d) = 0

f3(A8, A28)  d = f3(A8)-f3(A28)

d < p maka H(d) = 0.05

f4(A28, A8)  d = f4(A28)-f4(A8)

d > 0 maka H(d) = 1

f4(A8, A28)  d = f4(A8)-f4(A28)

(19)

f1(A28, A9)  d = f1(A28)-f1(A9)

d > q maka H(d) = 1

f1(A9, A28)  d = f1(A9)-f1(A28)

d < q maka H(d) = 0

F2(A28, A9)  d = f2(A28)-f2(A9)

(20)

d < p maka H(d) = 0.7

f3(A9, A28)  d = f3(A9)-f3(A28)

d < p maka H(d) = 0

f4(A28, A9)  d = f4(A28)-f4(A9)

d > 0 maka H(d) = 1

f4(A9, A28)  d = f4(A9)-f4(A28)

(21)

f1(A28, A10)  d = f1(A28)-f1(A10)

d > q maka H(d) = 1

f1(A10, A28)  d = f1(A10)-f1(A28)

d < q maka H(d) = 0

f2(A28, A10)  d = f2(A28)-f2(A10)

(22)

d < p maka H(d) = 1

f3(A10, A28)  d = f3(A10)-f3(A28)

d < p maka H(d) = 0

f1(A28, A10)  d = f1(A28)-f1(A10)

d > 0 maka H(d) = 1

f4(A10, A28)  d = f4(A10)-f4(A28)

(23)

f1(A28, A11)  d = f1(A28)-f1(A11)

d > q maka H(d) = 1

f1(A11, A28)  d = f1(A11)-f1(A28)

d < q maka H(d) = 0

f2(A28, A11)  d = f2(A28)-f2(A11)

(24)

d < p maka H(d) = 0.55

f3(A11, A28)  d = f3(A11)-f3(A28)

d < p maka H(d) = 0

f4(A28, A11)  d = f4(A28)-f4(A11)

d < 0 maka H(d) = 0

f4(A11, A28)  d = f4(A11)-f4(A28)

(25)

f1(A28, A12)  d = f1(A28)-f1(A12)

d > q maka H(d) = 1

f1(A12, A28)  d = f1(A12)-f1(A28)

d < q maka H(d) = 0

f2= Kompetensi Profesional

f2(A28, A12)  d = f2(A28)-f2(A12)

(26)

d < p maka H(d) = 0.35

f3(A12, A28)  d = f3(A12)-f1(A28)

d < p maka H(d) = 0

f4(A28, A12)  d = f4(A28)-f4(A12)

d > 0 maka H(d) = 1

f4(A12, A28)  d = f4(A12)-f4(A28)

(27)

f1(A28, A13)  d = f1(A28)-f1(A12)

d > q maka H(d) = 1

f1(A13, A28)  d = f1(A13)-f1(A28)

d < q maka H(d) = 0

f2(A28, A13)  d = f2(A28)-f2(A13)

(28)

d < p maka H(d) = 1

f3(A13, A28)  d = f3(A13)-f3(A28)

d < p maka H(d) = 0

f4(A28, A13)  d = f4(A28)-f4(A13)

d > 0 maka H(d) = 1

f4(A13, A28)  d = f4(A13)-f4(A28)

(29)

f1(A28, A14)  d = f1(A28)-f1(A14)

d > q maka H(d) = 1

f1(A14, A28)  d = f1(A14)-f1(A28)

d < q maka H(d) = 0

f2(A28, A14)  d = f2(A28)-f12A14)

(30)

d < p maka H(d) = 0.15

f3(A14, A28)  d = f3(A14)-f3(A28)

d < p maka H(d) = 0

f4(A28, A14)  d = f4(A28)-f4(A14)

d < 0 maka H(d) = 0

f4(A14, A28)  d = f4(A14)-f4(A28)

(31)

f1(A28, A15)  d = f1(A28)-f1(A15)

d < q maka H(d) = 0

f1(A15, A28)  d = f1(A15)-f1(A28)

d < q maka H(d) = 0

f2(A28, A15)  d = f2(A28)-f2(A15)

(32)

d < p maka H(d) = 0

f3(A15, A28)  d = f3(A15)-f3(A28)

d < p maka H(d) = 0

f4(A28, A15)  d = f4(A28)-f4(A15)

d > 0 maka H(d) = 1

f4(A15, A28)  d = f4(A15)-f4(A28)

(33)

f1(A28, A16)  d = f1(A28)-f1(A16)

d < q maka H(d) = 0

f1(A16, A28)  d = f1(A16)-f1(A28)

d < q maka H(d) = 0

f2(A28, A16)  d = f2(A28)-f2(A16)

(34)

d < p maka H(d) = 0.4

f3(A16, A28)  d = f3(A16)-f3(A28)

d < p maka H(d) = 0

44(A28, A16)  d = f4(A28)-f4(A16)

d < 0 maka H(d) = 0

f4(A16, A28)  d = f4(A16)-f4(A28)

(35)

f1(A28, A17)  d = f1(A28)-f1(A17)

d < q maka H(d) = 0

f1(A17, A28)  d = f1(A17)-f1(A28)

d < q maka H(d) = 0

f2(A28, A17)  d = f2(A28)-f2(A17)

(36)

d < p maka H(d) = 0

f3(A17, A28)  d = f3(A17)-f3(A28)

d < p maka H(d) = 0

f4(A28, A17)  d = f4(A28)-f4(A17)

d > 0 maka H(d) = 1

f4(A17, A28)  d = f4(A17)-f4(A28)

(37)

f1(A28, A18)  d = f1(A28)-f1(A18)

d > q maka H(d) = 1

f1(A18, A28)  d = f1(A18)-f1(A28)

d < q maka H(d) = 0

f2(A28, A18)  d = f2(A28)-f2(A18)

(38)

d < p maka H(d) = 1

f3(A18, A28)  d = f3(A18)-f3(A28)

d < p maka H(d) = 0

f4(A28, A18)  d = f4(A28)-f4(A18)

d > 0 maka H(d) = 1

f4(A18, A28)  d = f4(A18)-f4(A28)

(39)

f1(A28, A19)  d = f1(A28)-f1(A19)

d > q maka H(d) = 1

f1(A19, A28)  d = f1(A19)-f1(A28)

d < q maka H(d) = 0

f2(A28, A19)  d = f2(A28)-f2(A19)

(40)

d < p maka H(d) = 0.65

f3(A19, A28)  d = f3(A19)-f3(A28)

d < p maka H(d) = 0

f4(A28, A19)  d = f4(A28)-f4(A19)

d > 0 maka H(d) = 1

f4(A19, A28)  d = f4(A19)-f4(A28)

(41)

f1(A28, A20)  d = f1(A28)-f1(A20)

d > q maka H(d) = 1

f1(A20, A28)  d = f1(A20)-f1(A28)

d < q maka H(d) = 0

f2(A28, A20)  d = f2(A28)-f2(A20)

(42)

d < p maka H(d) = 0.9

f3(A20, A28)  d = f3(A20)-f3(A28)

d < p maka H(d) = 0

f4(A28, A20)  d = f4(A28)-f4(A20)

d > 0 maka H(d) = 1

f4(A20, A28)  d = f4(A20)-f4(A28)

(43)

f1(A28, A21)  d = f1(A28)-f1(A21)

d > q maka H(d) = 1

f1(A21, A28)  d = f1(A21)-f1(A28)

d < q maka H(d) = 0

f2(A28, A21)  d = f2(A28)-f2(A21)

(44)

d < p maka H(d) = 0.5

f3(A21, A28)  d = f3(A21)-f3(A28)

d < p maka H(d) = 0

f4(A28, A21)  d = f4(A28)-f4(A21)

d > 0 maka H(d) = 1

f4(A21, A28)  d = f4(A21)-f4(A28)

(45)

f1(A28, A22)  d = f1(A28)-f1(A22)

d > q maka H(d) = 1

f1(A22, A28)  d = f1(A22)-f1(A28)

d < q maka H(d) = 0

f2(A28, A22)  d = f2(A28)-f2(A22)

(46)

d < p maka H(d) = 0.75

f3(A22, A28)  d = f3(A22)-f3(A28)

d < p maka H(d) = 0

f4(A28, A22)  d = f4(A28)-f4(A22)

d > 0 maka H(d) = 1

f4(A22, A28)  d = f4(A22)-f4(A28)

(47)

f1(A28, A23)  d = f1(A28)-f1(A23)

d < q maka H(d) = 0

f1(A23, A28)  d = f1(A23)-f1(A28)

d < q maka H(d) = 0

f2(A28, A23)  d = f2(A28)-f2(A23)

(48)

d < p maka H(d) = 0.05

f3(A23, A28)  d = f3(A23)-f3(A28)

d < p maka H(d) = 0

f4= Kompetensi Sosial

f4(A28, A23)  d = f4(A28)-f4(A23)

d > 0 maka H(d) = 1

f4(A23, A28)  d = f4(A23)-f4(A28)

(49)

f1(A28, A24)  d = f1(A28)-f1(A24)

d > q maka H(d) = 1

f1(A24, A28)  d = f1(A24)-f1(A28)

d < q maka H(d) = 0

f2(A28, A24)  d = f2(A28)-f2(A24)

(50)

d < p maka H(d) = 0.35

f3(A24, A28)  d = f3(A24)-f3(A28)

d < p maka H(d) = 0

f4(A28, A24)  d = f4(A28)-f4(A24)

d > 0 maka H(d) = 1

f4(A24, A28)  d = f4(A24)-f4(A28)

(51)

f1(A28, A25)  d = f1(A28)-f1(A25)

d > q maka H(d) = 1

f1(A25, A28)  d = f1(A25)-f1(A28)

d < q maka H(d) = 0

f2(A28, A25)  d = f2(A28)-f2(A25)

(52)

d < p maka H(d) = 0.85

f3(A25, A28)  d = f3(A25)-f3(A28)

d < p maka H(d) = 0

f4(A28, A25)  d = f4(A28)-f4(A25)

d > 0 maka H(d) = 1

f4(A25, A28)  d = f4(A25)-f4(A28)

(53)

f1(A28, A26)  d = f1(A28)-f1(A26)

d > q maka H(d) = 1

f1(A26, A28)  d = f1(A26)-f1(A28)

d < q maka H(d) = 0

f2(A28, A26)  d = f2(A28)-f2(A26)

(54)

d < p maka H(d) = 0.9

f3(A26, A28)  d = f3(A26)-f3(A28)

d= -18 Berdasarkan kriteria linier

d < p maka H(d) = 0

f4(A28, A26)  d = f4(A28)-f4(A26)

d > 0 maka H(d) = 1

f4(A26, A28)  d = f4(A26)-f4(A28)

(55)

f1(A28, A27)  d = f1(A28)-f1(A27)

d < q maka H(d) = 0

f1(A27, A28)  d = f1(A27)-f1(A28)

d < q maka H(d) = 0

f2(A28, A27)  d = f2(A28)-f2(A27)

(56)

d < p maka H(d) = 0.65

f3(A27, A28)  d = f3(A27)-f3(A28)

d < p maka H(d) = 0

f4(A28, A27)  d = f4(A28)-f4(A27)

d > 0 maka H(d) = 1

f4(A27, A28)  d = f4(A27)-f4(A28)

(57)

f1(A28, A29)  d = f1(A28)-f1(A29)

d > q maka H(d) = 1

f1(A29, A28)  d = f1(A29)-f1(A28)

d < q maka H(d) = 0

f2(A28, A29)  d = f2(A28)-f2(A29)

(58)

d < p maka H(d) = 1

f3(A29, A28)  d = f3(A29)-f3(A28)

d < p maka H(d) = 0

f4(A28, A29)  d = f4(A28)-f4(A29)

d > 0 maka H(d) = 1

f4(A29, A28)  d = f4(A29)-f4(A28)

(59)

f1(A28, A30)  d = f1(A28)-f1(A30)

d > q maka H(d) = 1

f1(A30, A28)  d = f1(A30)-f1(A28)

d < q maka H(d) = 0

f2(A28, A30)  d = f2(A28)-f2(A30)

(60)

d= 24 Berdasarkan kriteria linier

d < p maka H(d) = 1

f3(A30, A28)  d = f3(A30)-f3(A28)

d < p maka H(d) = 0

f4(A28, A30)  d = f4 (A28)-f4(A30)

d > 0 maka H(d) = 1

f4(A30, A28)  d = f4(A30)-f4(A28)

(61)

1. Menu Utama

<?php ob_start(); session_start(); include 'admin/koneksi.php'; ?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

src="layout/js/jquery-ui-1.8.16.custom.min.js"></script>

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</div>

<h3>Register in to your account</h3>

(65)

<div class="field"><input type="password"

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$sql_dosen = mysql_query("SELECT * FROM dosen WHERE nip='$nip'"); $array_dosen = mysql_fetch_array($sql_dosen);

//validasi tidak boleh menginput nim yang sama dengan dosen yang sama pula $sql_cek_jawaban = mysql_query("SELECT * FROM jawab_kuesioner WHERE nip='$nip' and nim='$nim'");

if(mysql_num_rows($sql_cek_jawaban)){ ?>

<script language='javascript' type='text/javascript'> alert('Dosen ini sudah pernah anda input');

window.location='index.php'; </script>

<?php

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$no =1;

$tampil = mysql_query("SELECT * FROM kriteria");

while($data = mysql_fetch_array($tampil)) {

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</tr>";

<script language='javascript' type='text/javascript'> alert('Anda Harus Login Untuk Masuk Halaman ini');

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<section id="main-content">

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WHERE nip='$nip'")or die (mysql_error());

while($array_mahasiswa=mysql_fetch_array($sql_mahasiswa)){ $nim = $array_mahasiswa['nim'];

$sql_pedagogik = mysql_query("SELECT sum(a.jawaban) as jawaban_pedagogik from jawab_kuesioner a, kuesioner b, kriteria c WHERE

a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=1 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_pedagoik = mysql_fetch_array($sql_pedagogik); $nilai_pedagogik = $array_pedagoik['jawaban_pedagogik'];

$sql_profesional = mysql_query("SELECT sum(a.jawaban) as jawaban_profesional from jawab_kuesioner a, kuesioner b, kriteria c WHERE

a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=2 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_profoesional= mysql_fetch_array($sql_profesional); $nilai_profesional = $array_profoesional['jawaban_profesional'];

;?><?php $sql_kepribadian = mysql_query("SELECT sum(a.jawaban) as jawaban_kepribadian from jawab_kuesioner a, kuesioner b, kriteria c WHERE a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=3 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_kepribadian = mysql_fetch_array($sql_kepribadian); $nilai_kepribadian = $array_kepribadian['jawaban_kepribadian'];

$sql_sosial = mysql_query("SELECT sum(a.jawaban) as jawaban_sosial from jawab_kuesioner a, kuesioner b, kriteria c

WHERE a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=4 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error()); $array_sosial = mysql_fetch_array($sql_sosial);

$nilai_sosial = $array_sosial['jawaban_sosial']; ?>

<?php

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$leaving_flow = 0; $entering_flow = 0;

$sql_dosen2 = mysql_query("SELECT distinct(a.nip),b.* FROM jawab_kuesioner a, dosen b WHERE a.nip=b.nip and a.nip!='$nip' order by a.nip ASC");

while($array_dosen2=mysql_fetch_array($sql_dosen2)){

$cek_insert_total = mysql_query("SELECT * FROM total_kriteria WHERE nip='$nip' and total_pedagogik='$total_pedagogik' and

total_profesional='$total_profesional' and total_kepribadian='$total_kepribadian' and total_sosial='$total_sosial'");

if(mysql_num_rows($cek_insert_total)){ echo '';

} else {

$insert_total = mysql_query("INSERT INTO total_kriteria VALUES

('','$nip','$total_pedagogik','$total_profesional','$total_kepribadian','$total_sosial')");

}

$sql_total = mysql_query("SELECT * FROM total_kriteria WHERE nip='$array_dosen2[nip]' order by id_total_kriteria DESC LIMIT 1"); $array_total = mysql_fetch_array($sql_total);

$total_pedagogik2 = $array_total['total_pedagogik'];

$selisih_profesional = $total_profesional - $array_total['total_profesional']; $selisih_profesional2 = $selisih_profesional * -1;

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$quasi_pedagogik1 = 1;

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id_kriteria=3");

$array_kriteria_kepribadian = mysql_fetch_array($sql_kriteria_kepribadian); $nilai_p_kepribadian = $array_kriteria_kepribadian['nilai_p'];

$nilai_q_kepribadian = $array_kriteria_kepribadian['nilai_q'];

if($selisih_kepribadian > $nilai_p_kepribadian){ $quasi_kepribadian1 = 1;

}

else if($selisih_kepribadian < $nilai_p_kepribadian and $selisih_kepribadian >= $nilai_q_kepribadian){

$quasi_kepribadian1 = $selisih_kepribadian / $nilai_p_kepribadian; }

else{

$quasi_kepribadian1 = 0;

}

if($selisih_kepribadian2 > $nilai_p_kepribadian){ $quasi_kepribadian2 = 1;

}

else if($selisih_kepribadian2 < $nilai_p_kepribadian and $selisih_kepribadian2 >= $nilai_q_kepribadian){

$quasi_kepribadian2 = $selisih_kepribadian2 / $nilai_p_kepribadian; }

else{

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$quasi_sosial1 = 0;

}

if($selisih_sosial2 > $nilai_q_sosial){ $quasi_sosial2 = 1;

} else{

$quasi_sosial2 = 0;

}

//mencari quasi profesional

?>

<?php $hasil_1 =

($quasi_pedagogik1+$quasi_profesional1+$quasi_kepribadian1+$quasi_sosial1) / 4;

$hasil_2 =

($quasi_pedagogik2+$quasi_profesional2+$quasi_kepribadian2+$quasi_sosial2) / 4;

$leaving_flow = ($leaving_flow + $hasil_1) / mysql_num_rows($sql_dosen2); $entering_flow = ($entering_flow + $hasil_2) / mysql_num_rows($sql_dosen2) ;

$net_flow = $leaving_flow - $entering_flow;

} ;

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$insert_net = mysql_query("INSERT INTO hasil_kuesioner VALUES ('','$nip','$leaving_flow','$entering_flow','$net_flow')");

} }

?>

<?php if($_GET['hasil']=="sukses"){?> <div class="space15"></div>

<table class="table table-striped table-hover table-bordered"> <thead>

<tr>

<th>Peringkat</th>

<th>NIM</th> <th>Nama Dosen</th> <th>Leaving Flow</th> <th>Entering Flow</th>

<th>Net Flow=Leaving Flow-Entering Flow</th> </tr>

</thead> <tbody> <?php

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<?php

$i++; }

?> </tbody> </table>

<?php } ?>

</div> </div> </section>  </section>

</section> <script>

jQuery(document).ready(function() { EditableTable.init();

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DATA PRIBADI

Nama Lengakap : Abdul Qodir Sihotang, A.Md Tempat dan Tanggal Lahir : Medan, 13 Juni 1987

Alamat Rumah : Jl. Ayahanda Gg. Tabib No. 8 Medan

Kec. Medan Petisah, Kel. Sei Putih Barat 20118 Telepon / HP : (061)4559046 / 085270653357

E-mail : [email protected]

Instansi Tempat Bekerja : Tenaga Penunjang Administrasi Akademik pada Sub Bagian Akademi Fakultas Farmasi USU

Alamat Kantor : Jalan Tri Dharma No.5, Pintu 4, Kampus USU

Medan 20155

Telepon / Faksimile : (061) 8223558 / (061) 8219775

DATA PENDIDIKAN

SD : SD Negeri 060834 Medan Tamat : 1999

SLTP : SLTP Negeri 19 Medan Tamat : 2002

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