LAMPIRAN A : INSTRUMEN SERTIFIKASI DOSEN

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A. Kompetensi Pedagogik

1. Kesiapan memberikan kuliah dan/atau praktek/praktikum 2. Keteraturan dan ketertiban penyelenggaraan perkuliahan 3. Kemampuan menghidupkan suasana kelas

4. Kejelasan penyampaian materi dan jawaban terhadap pertanyaan di kelas 5. Pemanfaatan media dan teknologi pembelajaran

6. Pemanfaatan media dan teknologi pembelajaran 7. Pemberian umpan balik terhadap tugas

8. Kesesuaian materi ujian dan/atau tugas dengan tujuan mata kuliah 9. Kesesuaian nilai yang diberikan dengan hasil belajar

B. Kompetensi Profesional

10. Kemampuan menjelaskan pokok bahasan/topik secara tepat 11. Kemampuan memberi contoh relevan dari konsep yang diajarkan

12. Kemampuan menjelaskan keterkaitan bidang/topik yang diajarkan dengan bidang/topik lain

13. Kemampuan menjelaskan keterkaitan bidang/topik yang diajarkan dengan konteks kehidupan

14. Penguasaan akan isu-isu mutakhir dalam bidang yang diajarkan

15. Penggunaan hasil-hasil penelitian untuk meningkatkan kualitas perkuliahan 16. Pelibatan mahasiswa dalam penelitian/kajian dan atau

pengembangan/rekayasa/desain yang dilakukan dosen 17. Kemampuan menggunakan beragam teknologi komunikasi C. Kompetensi Kepribadian

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25. Kemampuan menerima kritik, saran, dan pendapat orang lain 26. Mengenal dengan baik mahasiswa yang mengikuti kuliahnya 27. Mudah bergaul di kalangan sejawat, karyawan, dan mahasiswa 28. Toleransi terhadap keberagaman mahasiswa

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1. f1= Kompetensi Pedagogik f1(A28, A1)  d = f1(A28)-f1(A1) d = 17

Berdasarkan kriteria quasi d > q

maka H(d) = 1

f1(A1, A28)  d = f1(A1)-f1(A28) d = -17

Berdasarkan kriteria quasi d < q

maka H(d) = 0

f2 = Kompetensi Profesional f2(A28, A1)  d = f2(A28)-f2(A1) d = 19

(4)

d = 16 Berdasarkan kriteria linier

d < p maka H(d) = 0.8

f3(A1, A28)  d = f3(A1)-f3(A28) d = -16

Berdasarkan kriteria linier d < p

maka H(d) = 0

f4 = Kompetensi Sosial

f4(A28, A1)  d = f4(A28)-f4(A1) d = 13

Berdasarkan kriteria biasa d > 0 maka H(d) = 1

f1(A1, A28)  d = f1(A1)-f1(A28) d = -13

Berdasarkan kriteria biasa d < 0

(5)

f1(A28, A2)  d = f1(A28)-f1(A2) d = 9

maka H(d) = 0

f1(A2, A28) d = f1(A2)-f1(A28) d = -9

maka H(d) = 0

(6)

d = -2 Berdasarkan kriteria linier

d < p maka H(d) = 0

f3(A2, A28) d = f3(A2)-f3(A28) d = 2

maka H(d) = 0.1

f4(A28, A2)  d = f4(A28)-f4(A2) d = 1

f4(A2, A28) d = f4(A2)-f4(A28) d = -1

(7)

f1(A28, A3)  d = f1(A28)-f1(A3) d = 17

maka H(d) = 1

f1(A3, A28)  d = f1(A3)-f1(A28) d = -17

maka H(d) = 0

(8)

d= 21 Berdasarkan kriteria linier

d < p maka H(d) = 1

f3(A3, A28)  d = f3(A3)-f3(A28) d = -21

maka H(d) = 0

f4(A28, A3)  d = f4(A28)-f4(A3) d = 10

f4(A3, A28)  d = f4(A3)-f4(A28) d = -10

(9)

f1(A28, A4)  d = f1(A28)-f1(A4) d = 23

maka H(d) = 1

f1(A4, A28)  d = f1(A4)-f1(A28) d = -23

maka H(d) = 0

(10)

d < p maka H(d) = 0.8

f3(A4, A28)  d = f3(A4)-f3(A28) d = -16

maka H(d) = 0

f4(A28, A4)  d = f4(A28)-f4(A4) d = 21

f4(A4, A28)  d = f4(A4)-f4(A28) d = -21

(11)

f1(A28, A5)  d = f1(A28)-f1(A5) d = 1

maka H(d) = 0

f1(A5, A28)  d = f1(A5)-f1(A28) d = -1

maka H(d) = 0

(12)

d < p maka H(d) = 0

f3(A5, A28)  d = f3(A5)-f3(A28) d = 2

maka H(d) = 0.1

f4(A28, A5)  d = f4(A28)-f4(A5) d = 7

f4(A5, A28)  d = f4(A5)-f4(A28) d = -7

(13)

f1(A28, A6)  d = f1(A28)-f1(A6) d = 26

maka H(d) = 1

f1(A6, A28)  d = f1(A6)-f1(A28) d = -26

maka H(d) = 0

(14)

d < p maka H(d) = 0.6

f3(A6, A28)  d = f3(A6)-f3(A28) d = -12

maka H(d) = 0

f4(A28, A6)  d = f4(A28)-f4(A6) d = 18

f4(A6, A28)  d = f4(A6)-f4(A28) d = -18

(15)

f1(A28, A7)  d = f1(A28)-f1(A7) d = 37

maka H(d) = 1

f1(A7, A28)  d = f1(A7)-f1(A28) d = -37

maka H(d) = 0

(16)

d < p maka H(d) = 1

f3(A7, A28)  d = f3(A7)-f3(A28) d = -32

maka H(d) = 0

f4(A28, A7)  d = f4(A28)-f4(A7) d = 19

f4(A7, A28)  d = f4(A7)-f4(A28) d = -19

(17)

f1(A28, A8)  d = f1(A28)-f1(A8) d = -3

maka H(d) = 0

f1(A8, A28)  d = f1(A8)-f1(A28) d = 3

maka H(d) = 0

f2 = Kompetensi Profesional f2(A28, A8)  d = f2(A28)-f2(A8) d = -1

(18)

d < p maka H(d) = 0

f3(A8, A28)  d = f3(A8)-f3(A28) d = 1

maka H(d) = 0.05

f4(A28, A8)  d = f4(A28)-f4(A8) d = 11

f4(A8, A28)  d = f4(A8)-f4(A28) d = -11

(19)

f1(A28, A9)  d = f1(A28)-f1(A9) d = 14

maka H(d) = 1

f1(A9, A28)  d = f1(A9)-f1(A28) d = -14

maka H(d) = 0

f2 = Kompetensi Profesional

F2(A28, A9)  d = f2(A28)-f2(A9) d = 25

(20)

d < p maka H(d) = 0.7

f3(A9, A28)  d = f3(A9)-f3(A28) d = -14

maka H(d) = 0

f4(A28, A9)  d = f4(A28)-f4(A9) d = 11

f4(A9, A28)  d = f4(A9)-f4(A28) d = -11

(21)

f1(A28, A10)  d = f1(A28)-f1(A10) d = 34

maka H(d) = 1

f1(A10, A28)  d = f1(A10)-f1(A28) d = -34

maka H(d) = 0

f2(A28, A10)  d = f2(A28)-f2(A10) d = 40

(22)

d < p maka H(d) = 1

f3(A10, A28)  d = f3(A10)-f3(A28) d = -29

maka H(d) = 0

f1(A28, A10)  d = f1(A28)-f1(A10) d = 10

f4(A10, A28)  d = f4(A10)-f4(A28) d = -10

(23)

f1(A28, A11)  d = f1(A28)-f1(A11) d = 15

maka H(d) = 1

f1(A11, A28)  d = f1(A11)-f1(A28) d = -15

maka H(d) = 0

f2(A28, A11)  d = f2(A28)-f2(A11) d = 14

(24)

d < p maka H(d) = 0.55

f3(A11, A28)  d = f3(A11)-f3(A28) d = -11

maka H(d) = 0

f4(A28, A11)  d = f4(A28)-f4(A11) d = -2

maka H(d) = 0

f4(A11, A28)  d = f4(A11)-f4(A28) d = 2

Berdasarkan kriteria biasa d > 0

(25)

f1(A28, A12)  d = f1(A28)-f1(A12) d = 32

maka H(d) = 1

f1(A12, A28)  d = f1(A12)-f1(A28) d = -32

maka H(d) = 0

f2= Kompetensi Profesional

f2(A28, A12)  d = f2(A28)-f2(A12) d = 23

(26)

d < p maka H(d) = 0.35

f3(A12, A28)  d = f3(A12)-f1(A28) d = -7

maka H(d) = 0

f4(A28, A12)  d = f4(A28)-f4(A12) d = 13

f4(A12, A28)  d = f4(A12)-f4(A28) d = -13

(27)

f1(A28, A13)  d = f1(A28)-f1(A12) d = 26

maka H(d) = 1

f1(A13, A28)  d = f1(A13)-f1(A28) d = -26

maka H(d) = 0

f2(A28, A13)  d = f2(A28)-f2(A13) d = 28

(28)

d < p maka H(d) = 1

f3(A13, A28)  d = f3(A13)-f3(A28) d = -24

maka H(d) = 0

f4(A28, A13)  d = f4(A28)-f4(A13) d = 26

f4(A13, A28)  d = f4(A13)-f4(A28) d = -26

(29)

f1(A28, A14)  d = f1(A28)-f1(A14) d = 13

maka H(d) = 1

f1(A14, A28)  d = f1(A14)-f1(A28) d = -13

maka H(d) = 0

f2(A28, A14)  d = f2(A28)-f12A14) d = 13

(30)

d < p maka H(d) = 0.15

f3(A14, A28)  d = f3(A14)-f3(A28) d = -3

maka H(d) = 0

f4(A28, A14)  d = f4(A28)-f4(A14) d = -2

maka H(d) = 0

f4(A14, A28)  d = f4(A14)-f4(A28) d = 2

(31)

f1(A28, A15)  d = f1(A28)-f1(A15) d = 10

maka H(d) = 0

f1(A15, A28)  d = f1(A15)-f1(A28) d = -10

maka H(d) = 0

f2(A28, A15)  d = f2(A28)-f2(A15) d = 9

(32)

d < p maka H(d) = 0

f3(A15, A28)  d = f3(A15)-f3(A28) d = 0

maka H(d) = 0

f4(A28, A15)  d = f4(A28)-f4(A15) d = 13

f4(A15, A28)  d = f4(A15)-f4(A28) d = -13

(33)

f1(A28, A16)  d = f1(A28)-f1(A16) d = 3

maka H(d) = 0

f1(A16, A28)  d = f1(A16)-f1(A28) d = -3

maka H(d) = 0

f2(A28, A16)  d = f2(A28)-f2(A16) d = 8

(34)

d < p maka H(d) = 0.4

f3(A16, A28)  d = f3(A16)-f3(A28) d = -8

maka H(d) = 0

44(A28, A16)  d = f4(A28)-f4(A16) d = 0

maka H(d) = 0

f4(A16, A28)  d = f4(A16)-f4(A28) d = 0

Berdasarkan kriteria quasi d < 0

(35)

f1(A28, A17)  d = f1(A28)-f1(A17) d = 3

maka H(d) = 0

f1(A17, A28)  d = f1(A17)-f1(A28) d = -3

maka H(d) = 0

f2(A28, A17)  d = f2(A28)-f2(A17) d = -6

(36)

d < p maka H(d) = 0

f3(A17, A28)  d = f3(A17)-f3(A28) d = 0

maka H(d) = 0

f4(A28, A17)  d = f4(A28)-f4(A17) d = 1

f4(A17, A28)  d = f4(A17)-f4(A28) d = -1

(37)

f1(A28, A18)  d = f1(A28)-f1(A18) d = 22

maka H(d) = 1

f1(A18, A28)  d = f1(A18)-f1(A28) d = -22

maka H(d) = 0

f2(A28, A18)  d = f2(A28)-f2(A18) d = 20

(38)

d < p maka H(d) = 1

f3(A18, A28)  d = f3(A18)-f3(A28) d = -23

maka H(d) = 0

f4(A28, A18)  d = f4(A28)-f4(A18) d = 26

f4(A18, A28)  d = f4(A18)-f4(A28) d = -26

(39)

f1(A28, A19)  d = f1(A28)-f1(A19) d = 35

maka H(d) = 1

f1(A19, A28)  d = f1(A19)-f1(A28) d = -35

maka H(d) = 0

f2(A28, A19)  d = f2(A28)-f2(A19) d = 21

(40)

d < p maka H(d) = 0.65

f3(A19, A28)  d = f3(A19)-f3(A28) d = -13

maka H(d) = 0

f4(A28, A19)  d = f4(A28)-f4(A19) d = 11

f4(A19, A28)  d = f4(A19)-f4(A28) d = -11

(41)

f1(A28, A20)  d = f1(A28)-f1(A20) d = 23

maka H(d) = 1

f1(A20, A28)  d = f1(A20)-f1(A28) d = -23

maka H(d) = 0

f2(A28, A20)  d = f2(A28)-f2(A20) d = 24

(42)

d < p maka H(d) = 0.9

f3(A20, A28)  d = f3(A20)-f3(A28) d = -18

maka H(d) = 0

f4(A28, A20)  d = f4(A28)-f4(A20) d = 20

f4(A20, A28)  d = f4(A20)-f4(A28) d = -20

Berdasarkan kriteria quasi d < 0

(43)

f1(A28, A21)  d = f1(A28)-f1(A21) d = 17

maka H(d) = 1

f1(A21, A28)  d = f1(A21)-f1(A28) d = -17

maka H(d) = 0

f2(A28, A21)  d = f2(A28)-f2(A21) d = 14

(44)

d < p maka H(d) = 0.5

f3(A21, A28)  d = f3(A21)-f3(A28) d = -10

maka H(d) = 0

f4(A28, A21)  d = f4(A28)-f4(A21) d = 3

maka H(d) = 1

f4(A21, A28)  d = f4(A21)-f4(A28) d = -3

(45)

f1(A28, A22)  d = f1(A28)-f1(A22) d = 19

maka H(d) = 1

f1(A22, A28)  d = f1(A22)-f1(A28) d = -19

maka H(d) = 0

f2(A28, A22)  d = f2(A28)-f2(A22) d = 24

(46)

d < p maka H(d) = 0.75

f3(A22, A28)  d = f3(A22)-f3(A28) d = -15

maka H(d) = 0

f4(A28, A22)  d = f4(A28)-f4(A22) d = 17

maka H(d) = 1

f4(A22, A28)  d = f4(A22)-f4(A28) d = -17

(47)

f1(A28, A23)  d = f1(A28)-f1(A23) d = -3

maka H(d) = 0

f1(A23, A28)  d = f1(A23)-f1(A28) d = 3

maka H(d) = 0

f2(A28, A23)  d = f2(A28)-f2(A23) d = 5

(48)

d < p maka H(d) = 0.05

f3(A23, A28)  d = f3(A23)-f3(A28) d = -1

maka H(d) = 0

f4= Kompetensi Sosial

f4(A28, A23)  d = f4(A28)-f4(A23) d = 7

maka H(d) = 1

f4(A23, A28)  d = f4(A23)-f4(A28) d = -7

(49)

f1(A28, A24)  d = f1(A28)-f1(A24) d = 15

maka H(d) = 1

f1(A24, A28)  d = f1(A24)-f1(A28) d = -15

maka H(d) = 0

f2(A28, A24)  d = f2(A28)-f2(A24) d = 10

(50)

d < p maka H(d) = 0.35

f3(A24, A28)  d = f3(A24)-f3(A28) d = -7

maka H(d) = 0

f4(A28, A24)  d = f4(A28)-f4(A24) d = 5

maka H(d) = 1

f4(A24, A28)  d = f4(A24)-f4(A28) d = -5

(51)

f1(A28, A25)  d = f1(A28)-f1(A25) d = 13

maka H(d) = 1

f1(A25, A28)  d = f1(A25)-f1(A28) d = -13

maka H(d) = 0

f2(A28, A25)  d = f2(A28)-f2(A25) d = 20

(52)

d < p maka H(d) = 0.85

f3(A25, A28)  d = f3(A25)-f3(A28) d = -17

maka H(d) = 0

f4(A28, A25)  d = f4(A28)-f4(A25) d = 14

maka H(d) = 1

f4(A25, A28)  d = f4(A25)-f4(A28) d = -14

(53)

f1(A28, A26)  d = f1(A28)-f1(A26) d = 18

maka H(d) = 1

f1(A26, A28)  d = f1(A26)-f1(A28) d = -18

maka H(d) = 0

f2(A28, A26)  d = f2(A28)-f2(A26) d = 24

(54)

d < p maka H(d) = 0.9

f3(A26, A28)  d = f3(A26)-f3(A28) d= -18

maka H(d) = 0

f4(A28, A26)  d = f4(A28)-f4(A26) d = 8

maka H(d) = 1

f4(A26, A28)  d = f4(A26)-f4(A28) d = -8

(55)

f1(A28, A27)  d = f1(A28)-f1(A27) d = 3

maka H(d) = 0

f1(A27, A28)  d = f1(A27)-f1(A28) d = -3

maka H(d) = 0

f2(A28, A27)  d = f2(A28)-f2(A27) d = 6

(56)

d < p maka H(d) = 0.65

f3(A27, A28)  d = f3(A27)-f3(A28) d = -13

maka H(d) = 0

f4(A28, A27)  d = f4(A28)-f4(A27) d = 6

maka H(d) = 1

f4(A27, A28)  d = f4(A27)-f4(A28) d = -6

(57)

f1(A28, A29)  d = f1(A28)-f1(A29) d = 41

maka H(d) = 1

f1(A29, A28)  d = f1(A29)-f1(A28) d = -41

maka H(d) = 0

f2(A28, A29)  d = f2(A28)-f2(A29) d = 41

(58)

d < p maka H(d) = 1

f3(A29, A28)  d = f3(A29)-f3(A28) d = -23

maka H(d) = 0

f4(A28, A29)  d = f4(A28)-f4(A29) d = 25

maka H(d) = 1

f4(A29, A28)  d = f4(A29)-f4(A28) d = -25

(59)

f1(A28, A30)  d = f1(A28)-f1(A30) d = 28

maka H(d) = 1

f1(A30, A28)  d = f1(A30)-f1(A28) d = -28

maka H(d) = 0

f2(A28, A30)  d = f2(A28)-f2(A30) d = 27

(60)

d= 24 Berdasarkan kriteria linier

d < p maka H(d) = 1

f3(A30, A28)  d = f3(A30)-f3(A28) d = -24

maka H(d) = 0

f4(A28, A30)  d = f4 (A28)-f4(A30) d = 17

maka H(d) = 1

f4(A30, A28)  d = f4(A30)-f4(A28) d = -17

(61)

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<li><a href="#">Welcome, <?php echo $_SESSION['nama'];?></a></li>

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name="reg_pop" rel="prettyPhoto[gallery00]">Registration</a></li> <?php }?> </ul> </div> </div> <div class="section_bottom"> <div id="main_menu"> <ul> <li><a href="index.php">Home</a> </li>

<li><a href="#">Fakultas Farmasi</a> </li> </ul> </div> </div> </div> </div>  <?php if(isset($_GET['page'])){ $page=htmlentities($_GET['page']); }else{ $page="artikel"; } $file="$page.php"; $cek=strlen($page);

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</div> <div class="block_follow_us"> </div> </div> </div> </div>  </div>

<div id="apDiv1"><img src="layout/images/logo.png" width="600" height="73" /></div>  <div class="disp_none"> <div id="reg_popup"> <div class="sign_popup"> <h2>Registration</h2>

<h3>Register in to your account</h3>

</div> <div class="inp_line">

</div>

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<label>Password:</label>

</div>

<label>P. Studi:</label>

<option value="">---Program Studi---</option>

<option value="Sarjana Farmasi">Sarjana Farmasi</option> <option value="Ekstensi Sarjana Farmasi">Ekstensi Sarjan Farmasi</option>

<option value="D3 Analis Farmasi dan Makanan">D3 Analis Farmasi dan Makanan</option>

</select></div> </div>

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<a href="javascript:void(0)" id="show_settings_button"></a></div> </body> </html> 2. Isi_Kuesioner <?php if($_SESSION['nim']){ $nim= $_SESSION['nim']; $nip = $_GET['nip'];

$sql_dosen = mysql_query("SELECT * FROM dosen WHERE nip='$nip'"); $array_dosen = mysql_fetch_array($sql_dosen);

//validasi tidak boleh menginput nim yang sama dengan dosen yang sama pula $sql_cek_jawaban = mysql_query("SELECT * FROM jawab_kuesioner WHERE nip='$nip' and nim='$nim'");

if(mysql_num_rows($sql_cek_jawaban)){ ?>

<script language='javascript' type='text/javascript'> alert('Dosen ini sudah pernah anda input');

window.location='index.php'; </script>

<?php

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<div class="block_page_title">

<p class="title">Pengisian Kuesioner</p>

<p class="subtitle">Form Untuk Pengisian Kuesioner Dosen Farmasi</p>

</div>

<div class="block_back"><p><a href="index.php">Back to Home Page »</a></p></div> </div> <div class="separator_1"></div> <div class="block_two_columns"> <div class="column_3 fl"> <div class="block_general_text"> <h2>Data Dosen</h2> <div class="block_contact_form">

<p>NIP<span>:</span><?php echo $array_dosen['nip'];?></p> <p>Nama Lengkap <span>:</span><?php echo $array_dosen['nama_lengkap'];?></p>

<p>Departemen <span>:</span><?php echo $array_dosen['departemen'];?></p>

<p>Email <span>:</span><?php echo $array_dosen['email'];?></p>

<p> </p> <p> </p> <p><h3>Penilaian

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<div class="column_3 fr"> <div class="block_general_text"> <h2> </h2> <div class="block_contact_form">

<img src="admin/foto_dosen/<?php echo $array_dosen['foto'];?>" width="300" height="300" /> </div> </div> </div> </div> <div class="separator_4"></div>

<div class="line_1 w_lnk"><a href="#">Top</a></div> <div class="separator_4"></div>

<div class="block_one_column_type_1"> <div class="column_1">

<div class="block_general_text"> <h2>Form Pengisian Kuesioner</h2> <form method="post"

action="index.php?page=simpan_kuesioner">

<table border="0" cellpadding="0" cellspacing="0" class="table_type_1">

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<?php

$no =1;

$tampil = mysql_query("SELECT * FROM kriteria"); while($data = mysql_fetch_array($tampil)) { $id_kriteria = $data['id_kriteria']; $noo++; echo " <tr> <td colspan=2>         <strong>$noo. $data[nama_kriteria]</strong> </td> <td align=center><strong>1</strong></td> <td align=center><strong>2</strong></td> <td align=center><strong>3</strong></td> <td align=center><strong>4</strong></td> <td align=center><strong>5</strong></td> </tr>";

$hasil = mysql_query("SELECT * FROM kuesioner WHERE id_kriteria='$id_kriteria' ORDER BY id_kriteria ASC");

$i = 1; while($r = mysql_fetch_array($hasil)) { $id_kuesioner = $r['id_kuesioner']; $num++; echo "<tr> <td align=center>$no.</td> <td width='100%'>$r[isi_kuesioner]</td> <td align=center><input type='radio'

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</tr>"; $i++; $no++; } } ?> </table>

<table width="200" border="0" align="center" cellpadding="2" cellspacing="2"> <tr> <td> </td> </tr> <tr> <td>

<input type="hidden" name="jumMK" value="<?php echo $no-1; ?>" />

<input type="submit" name="kirim" id="kirim" value="simpan" /> 

</tr> </table>

</form>

<div class="line_1 w_lnk"><a href="#">Top</a></div> </div> </div> </div> </div> </div> <?php } } else {?>

<script language='javascript' type='text/javascript'> alert('Anda Harus Login Untuk Masuk Halaman ini');

window.location='index.php?page=login'; </script>

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<section id="main-content"> <section class="wrapper"> 

<section class="panel">

<header class="panel-heading">

Hasil Perhitungan Kuesioner Dosen dengan Menggunakan Metode Promthee

</header>

<div class="panel-body">

<div class="adv-table editable-table "> <div class="clearfix"> <div class="btn-group"> </div>

<p>Terima kasih anda telah menggunakan sistem kami</p><p> lihat <a href="index.php?page=hasil_kuesioner&hasil=sukses">

disini</a> hasil pilihan anda</p> <br><br>

<?php

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WHERE nip='$nip'")or die (mysql_error());

while($array_mahasiswa=mysql_fetch_array($sql_mahasiswa)){ $nim = $array_mahasiswa['nim'];

$sql_pedagogik = mysql_query("SELECT sum(a.jawaban) as jawaban_pedagogik from jawab_kuesioner a, kuesioner b, kriteria c WHERE

a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=1 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_pedagoik = mysql_fetch_array($sql_pedagogik); $nilai_pedagogik = $array_pedagoik['jawaban_pedagogik'];

$sql_profesional = mysql_query("SELECT sum(a.jawaban) as jawaban_profesional from jawab_kuesioner a, kuesioner b, kriteria c WHERE

a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=2 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_profoesional= mysql_fetch_array($sql_profesional); $nilai_profesional = $array_profoesional['jawaban_profesional']; ;?><?php $sql_kepribadian = mysql_query("SELECT sum(a.jawaban) as jawaban_kepribadian from jawab_kuesioner a, kuesioner b, kriteria c WHERE a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=3 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error());

$array_kepribadian = mysql_fetch_array($sql_kepribadian); $nilai_kepribadian = $array_kepribadian['jawaban_kepribadian'];

$sql_sosial = mysql_query("SELECT sum(a.jawaban) as jawaban_sosial from jawab_kuesioner a, kuesioner b, kriteria c

WHERE a.id_kuesioner=b.id_kuesioner and b.id_kriteria=c.id_kriteria and c.id_kriteria=4 and a.nip='$nip' and a.nim='$nim'") or die (mysql_error()); $array_sosial = mysql_fetch_array($sql_sosial);

$nilai_sosial = $array_sosial['jawaban_sosial']; ?>

<?php

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}

$leaving_flow = 0; $entering_flow = 0;

$sql_dosen2 = mysql_query("SELECT distinct(a.nip),b.* FROM jawab_kuesioner a, dosen b WHERE a.nip=b.nip and a.nip!='$nip' order by a.nip ASC");

while($array_dosen2=mysql_fetch_array($sql_dosen2)){

$cek_insert_total = mysql_query("SELECT * FROM total_kriteria WHERE nip='$nip' and total_pedagogik='$total_pedagogik' and

total_profesional='$total_profesional' and total_kepribadian='$total_kepribadian' and total_sosial='$total_sosial'");

if(mysql_num_rows($cek_insert_total)){ echo '';

} else {

$insert_total = mysql_query("INSERT INTO total_kriteria VALUES

('','$nip','$total_pedagogik','$total_profesional','$total_kepribadian','$total_sosial')"); }

$sql_total = mysql_query("SELECT * FROM total_kriteria WHERE nip='$array_dosen2[nip]' order by id_total_kriteria DESC LIMIT 1"); $array_total = mysql_fetch_array($sql_total);

$total_pedagogik2 = $array_total['total_pedagogik'];

$selisih_profesional = $total_profesional - $array_total['total_profesional']; $selisih_profesional2 = $selisih_profesional * -1;

$selisih_kepribadian = $total_kepribadian - $array_total['total_kepribadian']; $selisih_kepribadian2 = $selisih_kepribadian * -1;

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$quasi_pedagogik1 = 1; } else { $quasi_pedagogik1 = 0; } if($selisih_pedagogik2 > $nilai_q_pedagogik){ $quasi_pedagogik2 = 1; } else{ $quasi_pedagogik2 = 0; }

//mencari quasi pedagogik //mencari quasi profesional

$sql_kriteria_profesional = mysql_query("SELECT * FROM kriteria WHERE id_kriteria=2"); $array_kriteria_profesional = mysql_fetch_array($sql_kriteria_profesional); $nilai_p_profesional = $array_kriteria_profesional['nilai_p']; $nilai_q_profesional = $array_kriteria_profesional['nilai_q']; if($selisih_profesional > $nilai_q_profesional){ $quasi_profesional1 = 1; } else{ $quasi_profesional1 = 0; } if($selisih_profesional2 > $nilai_q_profesional){ $quasi_profesional2 = 1; } else{ $quasi_profesional2 = 0;

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$sql_kriteria_kepribadian = mysql_query("SELECT * FROM kriteria WHERE id_kriteria=3"); $array_kriteria_kepribadian = mysql_fetch_array($sql_kriteria_kepribadian); $nilai_p_kepribadian = $array_kriteria_kepribadian['nilai_p']; $nilai_q_kepribadian = $array_kriteria_kepribadian['nilai_q']; if($selisih_kepribadian > $nilai_p_kepribadian){ $quasi_kepribadian1 = 1; }

else if($selisih_kepribadian < $nilai_p_kepribadian and $selisih_kepribadian >= $nilai_q_kepribadian){

$quasi_kepribadian1 = $selisih_kepribadian / $nilai_p_kepribadian; } else{ $quasi_kepribadian1 = 0; } if($selisih_kepribadian2 > $nilai_p_kepribadian){ $quasi_kepribadian2 = 1; }

else if($selisih_kepribadian2 < $nilai_p_kepribadian and $selisih_kepribadian2 >= $nilai_q_kepribadian){

$quasi_kepribadian2 = $selisih_kepribadian2 / $nilai_p_kepribadian; }

else{

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$quasi_sosial1 = 0; } if($selisih_sosial2 > $nilai_q_sosial){ $quasi_sosial2 = 1; } else{ $quasi_sosial2 = 0; }

//mencari quasi profesional ?> <?php $hasil_1 = ($quasi_pedagogik1+$quasi_profesional1+$quasi_kepribadian1+$quasi_sosial1) / 4; $hasil_2 = ($quasi_pedagogik2+$quasi_profesional2+$quasi_kepribadian2+$quasi_sosial2) / 4;

$leaving_flow = ($leaving_flow + $hasil_1) / mysql_num_rows($sql_dosen2); $entering_flow = ($entering_flow + $hasil_2) / mysql_num_rows($sql_dosen2) ; $net_flow = $leaving_flow - $entering_flow;

} ;

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} else {

$insert_net = mysql_query("INSERT INTO hasil_kuesioner VALUES ('','$nip','$leaving_flow','$entering_flow','$net_flow')"); } } ?> <?php if($_GET['hasil']=="sukses"){?> <div class="space15"></div>

<table class="table table-striped table-hover table-bordered"> <thead> <tr> <th>Peringkat</th> <th>NIM</th> <th>Nama Dosen</th> <th>Leaving Flow</th> <th>Entering Flow</th>

<th>Net Flow=Leaving Flow-Entering Flow</th> </tr>

</thead> <tbody> <?php

$result = mysql_query("SELECT a.*,b.* FROM dosen a, hasil_kuesioner b WHERE a.nip=b.nip ORDER BY b.net_flow DESC");

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<?php $i++; } ?> </tbody> </table> <?php } ?> </div> </div> </section>  </section> </section> <script> jQuery(document).ready(function() { EditableTable.init(); }); </script>

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DATA PRIBADI

Nama Lengakap : Abdul Qodir Sihotang, A.Md Tempat dan Tanggal Lahir : Medan, 13 Juni 1987

Alamat Rumah : Jl. Ayahanda Gg. Tabib No. 8 Medan

Kec. Medan Petisah, Kel. Sei Putih Barat 20118 Telepon / HP : (061)4559046 / 085270653357

E-mail : abdul.qodir.sihotang@usu.ac.id

Instansi Tempat Bekerja : Tenaga Penunjang Administrasi Akademik pada Sub Bagian Akademi Fakultas Farmasi USU

Alamat Kantor : Jalan Tri Dharma No.5, Pintu 4, Kampus USU

Medan 20155

Telepon / Faksimile : (061) 8223558 / (061) 8219775

DATA PENDIDIKAN

SD : SD Negeri 060834 Medan Tamat : 1999

SLTP : SLTP Negeri 19 Medan Tamat : 2002

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