PROGRAM GEMPUR KECEMERLANGAN SIJIL PELAJARAN MALAYSIA 2018 NEGERI PERLIS

PROGRAM GEMPUR KECEMERLANGAN

SIJIL PELAJARAN MALAYSIA 2018

NEGERI PERLIS

SIJIL PELAJARAN MALAYSIA 2018

3472/2(PP)

MATEMATIK TAMBAHAN

Kertas 2

Peraturan Pemarkahan Ogos

UNTUK KEGUNAAN PEMERIKSA SAHAJA

Peraturan pemarkahan ini mengandungi 16 halaman bercetak

1(a)

and b and solve simultaneous equations for k

Collinear

2 ( ) 2 1 5

At maximum point, 200 100 2

Height of the highest pole 1 5 1

At maximum point, 200 100 2

Height of the highest pole,

( )

3 2πx+2πy=16π P1 and πx2+πy2 =34π P1

8

x= −y or y= −8 x P1

2 2

*(8−y) +y =34 or x2+*(8−x)2 =34 K1

Solve the quadratic equation

2

51.3 48.2 52.0 47.3 45.0 52.4 6

x = + + + + + or

Luqman

51.3 48.2 52.0 47.3 45.0 52.4 6

4(b) Luqman N1

Luqman’s achievement is more consistent N1 2 7

5(a) Use

cos(AB)=cosAcosB sinAsinB

3 3 3 3

cos cos sin sin

4x 4x− 4x 4x or

Shape of positive cosine graph at least 1 cycle P1 1

Sketch the straight line with *gradient or *y-intercept and straight line

6(a) _Find δ

7(b) Find the area of rectangular shape OR Integrate 1 2 4 d

(a)(i) Use 10Cr(0.65) (0.35)r 10 r

−

K1

Write P X( = +8) P X( = +9) P X( =10) P1

0.2616 N1 3

(ii) σ2 =960(0.35)(0.65) K1

218.4 N1 2

(b)(i) 140 150

225

Z = − K1

Find the probability in the correct region

( * 0.667)

P Z  −

0.2523 // 0.25239 // 0.2524 N1 2

(ii) Find the probability in the correct region

( 0.667) ( 2)

P Z  −P Z 

0.2295 // 0.22964 // 0.2296 K1

*0.2295(27) K1

6 N1 3 10

9(a)

x 3 5 6 9 10 12

10

log y 0.37 0.22 0.15 – 0.09 – 0.16 – 0.31 ₁

(b) Plot log₁₀ y against x

(Correct axes and uniform scales) K1

6 *points plotted correctly N1

Line of best fit N1

(Refer graph on page 15)

3 N1

9

(b)(i) Use distance formula for WJ or WK

11(c) 2

the *inequalities involves x and y

Draw correctly all four *straight lines N1

Note: Accept dotted lines

Region shaded correctly N1

(Refer graph on page 16)

3

(c) Minimum point (30, 30) N1

Substitute any points in shaded *region K1

into 8 000x+4 000y

360 000 N1 3 10

(a)(i) ACB= 58 P1

13 34

sin 58 sin 85

AP+ ₌

  K1

15.94 // 15.944 N1 3

(ii) PQ2 =132+142−2(13)(14) cos 37 K1

8.62 N1 2

(b) 1

1

(13 *15.94)(34) sin 37 2

A = +  OR ₂ 1(13)(14) sin 37 2

A =  K1

1 2

*A −*A K1

241.31241.35 N1 3

(c)(i)

Note: A C B' ' ' obtuse angle N1 1

(ii) A C B' ' ' 122=  N1 1 10

37°

14(a) Substitute t=5 and v=0

Solve simultaneous equation to find m and n

1

15(a)

15

3900

100 130

P  = K1

3 000 N1 2

(b) Use 16/15 18/16

16/15

100

I I

I =  K1

108, 147, 156, 125 N2 (All correct) N1 (Only 3 correct) 3

(c)(i) W =600 : 400 : 300 : 200 or Implied (seen) P1

18/15

*600(*108) *400(*147) *300(*156) *200(*125) *600 *400 *300 *200

I = + + +

+ + + K1

130.27 // 130.267 N1 3

(ii) 18

100 *130.27 900 000

P _{ =}

K1

1 172 430 N1 2 10

– 0.2

2 4 6 8 10 12 14

–0.1 0 0.1 0.2 0.3 0.4 0.5 0.6

×

×

×

×

×

×

(3, 0.37)

(5, 0.22)

(6, 0.15)

(9, –0.09)

(10, –0.16)

(12, –0.31)

– 0.3

–

10

10 20 30 40 50 60 70 20

30 40 50 60 70 80

x (Factory S) 0

y = 50

R

x

=

60

(30, 30)

PERATURAN PEMARKAHAN TAMAT