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Final IMSO 2009 Essay

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IMSO 2009

ESSAY PROBLEMS

DIRECTORATE OF KINDERGARTEN AND PRIMARY DEVELOPMENT

DIRECTORATE GENERAL OF PRIMARY AND SECONDARY EDUCATION MANAGEMENT

MINISTRY OF NATIONAL EDUCATION

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Page 2 of 8

General Remarks

1.

A full mark for each problem is 3 points.

2.

When the student gives final answer only, the mark is 1

point.

1. Bob bought a coat and a shirt. The normal prices of both items are the same, but when Bob bought them, the shirt was discounted by 50% and the coat was discounted by 25%. If he bought them for $130 what was the normal price of the shirt?

2. The area of a rhombus is 36 cm2. One of its diagonals has length twice of the other diagonal. What is the length of the smaller diagonal of the rhombus?

Answer: $104

Let price = original price of one coat or one shirt.

50% x price + (100% - 25%) x price = 130... 1 point

50% x price + 75% x price = 130

125% price = 130

(5/4) price = 130... ... 1 point

Price = (4/5) x 130

= 104

The original price of the shirt is $104... 1 point

Answer: 6 cm

... 1 point

Area of rhombus 36 cm2 4a2 = 36 ... 1 point a2 = 9

a = 3

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Essay Yogyakarta, 8-14 November

Page 3 of 8

3. I plan to travel by car from City A to City B. I travel the first half of the distance with the speed of 30 km/hour. In order to get my average traveling speed of 40 km/hour, what speed should I take for the second half of the distance?

Answer:

Marking Scheme:

If the distance = 120 km.

2 hours T hour

A o---o---o B

60 km C 60 km

A half of the distance = 120/2 = 60 km.

Time needed from A to C = 60/30 = 2 hour. ………. 1point

In order get 40 km//hour from A to B:

120

40 = --- ……….……….………. ½ point

2 + T

3

1 = ---

2 + T

2 + T = 3

T = 1. ……….…….. 1 point

Speed at the next half of the distance is

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Page 4 of 8

Lambert’s mark is added, the mean value will be 69. When John’s mark is

added, the mean value will be 72. What will the mean value be, if Lambert’s and

John’s marks are both added?

5. Andy bought three packages of goods, each worth $ 35, $ 30, and $ 40. The first package contains 2 books, 1 pencil, and 1 eraser. The second package contains 1 book, 1 pencil, 2 erasers. The third package contains 3 books and 2 erasers. Andy wants to buy the fourth package containing 2 books, 1 pencil, and 3 erasers. What is the price of the fourth package?

Answer : Scheme:

Finding Lambert’s mark (1 point) Finding John’s mark (1 point)

Calculating the total mark sum of eleven students (½ point)

Calculating the mean (½ point)

Sum=70*9

Formulating the system of equations (1 point)

Finding the prices of a book, a pencil, and an eraser (½ point for each) Calculating the final answer (½ point)

Package # Books # Pencils # Erasers Price

 Secondly, combining (II) & (III) and comparing with (I): 2 Books + 3 Erasers = $35

 Combining first & second results: 5 erasers = $25 so Eraser = $5.

 The price of Package IV is $35 + 2 x price of eraser

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Essay Yogyakarta, 8-14 November

Page 5 of 8

6. The following figure shows a regular hexagon. On each side of the hexagon, there is an isosceles right triangle. One side forming a right angle is a side of the hexagon. Determine the angle x.

7. Bob and Ivan have tasks of mowing (cutting) grass in their yard. One day they do their work at the same time. After that, Bob works every 8 days, while Ivan every 6 days. Each time Bob works, he is paid $15 while Ivan gets $17.5. If they work again on the same day, how much money will each of them earn at the end of the day?

Answer:

Day 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

Bob v v v v

Ivan v v v v v

x

Answer:

Internal angle of hexagonal is 1200 ... 1 point Internal angle of right triangle are 900 dan 450 ... 1 point Determining of angle x is 360-1200-900- 450=1050 ... 1 point

They meet again at 24th day. At this time: ………1 point

Bob’s work 4 times ……… ½ point

Ivan’s work 5 times ……… ½ point

Hence

Bob’s earn = 4 x $15 = $ 60 ……… ½ point

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Mum’s kitchen scale is set incorrectly, but otherwise it works fine. When she

weighs a bag of sugar, it shows 1.5 kg. When she weighs a bag of flour, it shows 1.3 kg. However, when she weighs both items together, it shows 2.5 kg. If she weighs a piece of butter of weight 0.3 kg, what number does the scale show?

9. Alan, Billy, Candy, and David are queuing (lining up) in alphabetical order. Alan is in the 7th position from the front while David is in the 9th position from the back. The number of persons between Alan and Billy is the same as those between Candy and David. In total, there are 48 persons in the queue, and six of them are between Billy and Candy. How many persons are there between Alan and Candy?

Answer:

From A to D, there are all together 48-14=34 persons. ……… 1 point

Since the number of persons between A and B is the same as those between C and D, the number

of persons between A and B is: 34 6 2 2

-- =12 ………... 1 point

The number of persons between A and C is 12+7=19 ……… 1 point

10. A rectangle has two axes of symmetry, the vertical axis and the horizontal axis. If the rectangle is folded with respect to the vertical axis, we obtain a rectangle

Answer:

Solution: 0.6 kg

Observe that kg is the real weight of the bag of sugar. In a similar way,

kg is the real weight of the bag of flour. So the scale shifts 0.3 kg to the

right. Hence, the scale shows kg for the butter.

Scheme:

Finding the real weight of sugar or flour ………..1 point

Finding the shift of the scale ………..1 point

Finding the weight of the butter on the scale …………..1 point

A B D

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Essay Yogyakarta, 8-14 November

Page 7 of 8

with perimeter 40 cm. If the rectangle is folded with respect to the horizontal axis, we obtain a rectangle with perimeter 50 cm. What is the original perimeter of the rectangle? reach B. On the other hand, Brad walked at 4 km/hour, then took Jake's bicycle, and rode at 10 km/hour to reach B. If they started to travel and arrived at B at the same time, how many minutes did Jake leave his bike before it was used by Brad?

Answer:

 Suppose Jake was cycling for x km, then walked for (9-x) km

 Jake was cycling at 8 km/h and walking with speed of 5 km/h, so the time needed by Jake to get the

town B is 5

 Because of Brad and Jake start traveling and arrive at B at the same time, then it must satisfies

5

 This means that Jake has cycled for 4 km before leaving his bike and then walk for 5 km to reach B. Because he was cycling with a speed of 8 km/hour, so it take 4/8 = 1/2 hours. (½ point)

 Because Brad walk at 4 km/hour, so he walked on foot for 4/4 = 1 hour before he was cycling to reach B ……… (½ point)

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Page 8 of 8

A

E C

B D

F triangle CDF?

13. Tom has a contract to dig out some foundations and it must be done in 30 days. His own machine, which he wishes to use as much as possible, would take 50 days to do all the work. He can hire a bigger machine which would finish the job in 21 days. There is only enough room for one machine at a time. What is the least number of days for which he must hire the bigger machine?

Answer:

Area ADC = ½ x AD X BC = ½ x 4 x 25 = 50 cm2 ... 1 point

Area ADF = ½ x AD x BE = ½ x 4 x 8 = 16 cm2 ... 1 point

Area DFC = area ADC – area ADF = 34 cm2 ... 1 point

Answer:

Performance of small machine is 1/50

Performance of big machine is 1/21 ………..…… 1 point

big machine 14 days 15 days

rest of work 1 – 14/21 = 1/3 1 - 15/21 = 2/7

small machine

needed 1/3 . 50 = 16,66 2/7. 50 = 14,3 ………… 1 point

total day needed 14+16,66 = 30,66 days 15+14,3 = 29,3 days

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