Analisis Gaya Reaksi, SFD, dan BMD pada Balok Ditumpu Tiga

+

-

A

B C

300

NFD

255 A

B C

5 m 5 m

25 kN/m 12 m

90 kN/m

Reaksi Perletakan

ΣMC = 0

RVA. 10 - (

25. 12

²

2 ¿−90. 5=0

RVA = 225 kN (ke atas) ΣV = 0

RVA + RVC – 90 = 0 225 + RVC – 90 = 0 NFD

NA – NB = RVA NA – NB = 225 kN NB – NC = RHC NB – NC = -300KN

300

225

135

A

B C

+

SFD SFD

DA = 0

DA-6 m = 25 . 6 = 150 kN DB = 25. 12 = 300 kN DB – P1 = RVA = 225 Kn P1 – DC = 225 – 90 = 135

DC = 135 + RVC = 135 – 135 = 0 BMD

MA = 0

MA-2 m =

− 25 x 2

²

2 =¿

-50 kNm MA-4 m =

− 25 x 4

²

2 =¿

^{-200 kNm}

MA-6 m =

− 25 x 6

²

2 =¿

-450 kNm MA-8 m =

− 25 x 8

²

2 =¿

-800 kNm MA-10 m =

−25 x 10

²

2 =¿

-1250 kNm MB =

− 25 x 12

²

2 = ¿

-1800 kNm MP1 = -1800 + RVA. 5 = -675 kNm MC = -1800 + RVA. 10 – P1. 5 = -675 kNm

1800

1800

A

B C

-

BMD -